How to swap `NSMutableDictionary` key and values in place? - iphone

I have a NSMutableDictionary and I want to swap values & keys. i.e, after swapping values becomes keys and its corresponding keys with become values All keys and values are unique. Looking for an in place solution because size is very big . Also, the keys and values are NSString objects

NSMutableDictionary *d = [NSMutableDictionary dictionaryWithDictionary:#{
#"key1" : #"value1",
#"key2" : #"value2"}];
for (NSString *key in [d allKeys]) {
d[d[key]] = key;
[d removeObjectForKey:key];
}
NSLog(#"%#", d); // => { value1 : key1,
// value2 : key2 }
Assumptions
unique values (as they will become keys)
values conform to NSCopying (same as above)
no value is equal to any key (otherwise colliding names will be lost in the process)

Here is another way to invert dictionary. The simplest for me.
NSArray *keys = dictionary.allKeys;
NSArray *values = [dictionary objectsForKeys:keys notFoundMarker:[NSNull null]];
[dictionary removeAllObjects]; // In case of huge data sets release the contents.
NSDictionary *invertedDictionary = [NSDictionary dictionaryWithObjects:keys forKeys:values];
[dictionary setDictionary:invertedDictionary]; // In case you want to use the original dictionary.

EDIT: I had written a few lines of codes to get the OP started into the task of creating his own algorithm. The answer was not well received so I have crafted a full implementation of an algorithm that does what he asks, and goes one step further.
Advantages:
Makes no assumptions regarding the contents of the dictionary, for example, the values need not conform to the 'NSCopying' protocol
Transverses the whole hierarchy of a collection, swapping all the keys
It's fast since it uses recursion and fast enumeration
Does not alter the contents of the original dictionary, it creates a brand new one
Code has been implemented through categories to both collections:
#interface NSDictionary (Swapping)
- (NSDictionary *)dictionaryBySwappingKeyWithValue;
#end
#interface NSDictionary (Swapping)
- (NSDictionary *)dictionaryBySwappingKeyWithValue
{
NSMutableDictionary *mutableDictionary = [NSMutableDictionary dictionaryWithCapacity:self.count];
[self enumerateKeysAndObjectsUsingBlock:^(id key, id value, BOOL *stop) {
id newKey = nil;
if ([value isKindOfClass:[NSDictionary class]]) {
newKey = [value dictionaryBySwappingKeyWithValue];
} else if ([value isKindOfClass:[NSArray class]]) {
newKey = [value arrayBySwappingKeyWithValue];
} else {
newKey = value;
}
if (![newKey conformsToProtocol:#protocol(NSCopying)]) {
newKey = [NSValue valueWithNonretainedObject:newKey];
}
mutableDictionary[newKey] = key;
}];
return [NSDictionary dictionaryWithDictionary:mutableDictionary];
}
#end
and...
#interface NSArray (Swapping)
- (NSArray *)arrayBySwappingKeyWithValue;
#end
#implementation NSArray (Swapping)
- (NSArray *)arrayBySwappingKeyWithValue
{
NSMutableArray *mutableArray = [NSMutableArray arrayWithCapacity:self.count];
[self enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
if ([obj isKindOfClass:[NSDictionary class]]) {
NSDictionary *newDict = [obj dictionaryBySwappingKeyWithValue];
mutableArray[idx] = newDict;
} else if ([obj isKindOfClass:[NSArray class]]) {
NSArray *newArray = [obj arrayBySwappingKeyWithValue];
mutableArray[idx] = newArray;
} else {
mutableArray[idx] = obj;
}
}];
return [NSArray arrayWithArray:mutableArray];
}
#end
As an example, assume you have a dictionary with the following structure:
UIView *view = [[UIView alloc] init];
NSDictionary *dict = #{#"1" : #"a",
#"2" : #[ #{ #"5" : #"b" } ],
#"3" : #{#"6" : #"c"},
#"7" : view};
NSDictionary *newDict = [dict dictionaryBySwappingKeyWithValue];
Printing the newDict object in the console will give you this output:
(lldb) po mutableDictionary
{
a = 1;
({b = 5;}) = 2;
{c = 6;} = 3;
"<30b50617>" = 7;
}
As you can see, not only have the keys and values been swapped at the first level of the hierarchy, but deep inside each collection.
"<30b50617>" represents the UIView object wrapped inside a NSValue. Since UIView does not comply to the NSCopying protocol, it needs to be handled this way if you want it to be a key in your collection.
Note: Code was done in a couple of minutes. Let me know if I missed something.

for (NSString *key in [myDictionary allKeys]) {
NSString *value = [responseDataDic objectForKey:key];
[myDictionary removeObjectForKey:key];
[myDictionary addObject:key forKey:value];
}
Assumption:
No key = value;
Complexity:
No extra space required. Will loop through once and replace all key value pairs.

NSArray* allKeys = [theDict allKeys];
NSArray* allValues = [theDict allValues];
NSMutableDictionary* newDict = [NSMutableDictionary dictionaryWithObjects:allKeys forKeys:allValues];

Related

Modifying content from new dictionary also modifies the parent dictionary data

As I have a requirement to add similar objects into the array, I have created new dictionary in such a way.
NSMutableDictionary* existingStepDict = [[[arrayForSteps objectAtIndex:0] mutableCopy] autorelease];
[arrayForSteps addObject:existingStepDict];
[existingStepDict release];
Now, what happens here is that later when I change something in any one of the dictionary, the other one also gets updated. I require both these dictionaries to behave independently.
For that I went through Deep-copy of dictionaries whose code is like this.
NSMutableDictionary* existingStepDict = [[[arrayForSteps objectAtIndex:0] mutableCopy] autorelease];
NSMutableDictionary* destination = [NSMutableDictionary dictionaryWithCapacity:0];
NSDictionary *deepCopy = [[NSDictionary alloc] initWithDictionary:existingStepDict copyItems: YES];
if (deepCopy) {
[destination addEntriesFromDictionary: deepCopy];
[deepCopy release];
}
//add Properties array to Steps Dictionary
[arrayForSteps addObject:destination];
But this too didn't reflect the difference. I know I am making some minor mistake here.
But could some one help me getting my result?
Thanks a lot!
There's an easy way to get a full deepcopy of an NSDictionary o NSArray using the NSCoding (serialization) protocol.
- (id) deepCopy:(id)mutableObject
{
NSData *buffer = [NSKeyedArchiver archivedDataWithRootObject:mutableObject];
return [NSKeyedUnarchiver unarchiveObjectWithData: buffer];
}
In this way you can duplicate any object plus all the obects it contains in a single step.
when I need a mutable deep copy of a NSDictionary I create a Category with this method:
- (NSMutableDictionary *)mutableDeepCopy
{
NSMutableDictionary *returnDict = [[NSMutableDictionary alloc] initWithCapacity:[self count]];
NSArray *keys = [self allKeys];
for (id key in keys) {
id oneValue = [self valueForKey:key];
id oneCopy = nil;
if ([oneValue respondsToSelector:#selector(mutableDeepCopy)]) {
oneCopy = [oneValue mutableDeepCopy];
} else if ([oneValue respondsToSelector:#selector(mutableCopy)]) {
oneCopy = [oneValue mutableCopy];
}
if (oneCopy == nil) {
oneCopy = [oneValue copy];
}
[returnDict setValue:oneCopy forKey:key];
}
return returnDict;
}
EDIT
and searching the web I found this, I haven't tested
NSMutableDictionary *mutableCopy = (NSMutableDictionary *)CFPropertyListCreateDeepCopy(kCFAllocatorDefault, (CFDictionaryRef)originalDictionary, kCFPropertyListMutableContainers);

Creating an Array of values from an Array of Dictionaries

The question sounds weird but I'm getting an array of dictionaries as parsed result.
Something like this:
parsed content: (
{
"name" = "John";
"lastname" = "Doe";
"foo" = "bar";
}
What would be the suggestion for best way to create an array of values??
Like this?
- (void)flattenDictionary:(NSDictionary *)d intoKeys:(NSMutableArray *)keys andValues:(NSMutableArray *)values {
for (id key in [d allKeys]) {
[keys addObject:key];
[values addObject:[d valueForKey:key]];
}
}
- (void)flattenDictionaries:(NSArray *)arrayOfDictionaries {
NSMutableArray *keys = [NSMutableArray array];
NSMutableArray *values = [NSMutableArray array];
for (NSDictionary *d in arrayOfDictionaries) {
[self flattenDictionary intoKeys:keys andValues:values];
}
NSLog(#"now we have these values %#", values);
NSLog(#"corresponding to these keys %#", keys);
}
You can get the values with:
NSArray *values = dictionary.allValues;
Or, loop through it:
[dictionary enumerateKeysAndObjectsUsingBlock:^(id key, id object, BOOL *stop) {
    NSLog(#"%# = %#", key, object);
}];
To do that loop through them and create an array.

Convert NSMutableArray to NSDictionary in order to use objectForKey?

I have an NSMutableArray that looks like this
{
"#active" = false;
"#name" = NAME1;
},
{
"#active" = false;
"#name" = NAME2;
}
Is there a way to convert this to an NSDictionary and then use objectForKey to get an array of the name objects? How else can I get these objects?
There is a even shorter form then this proposed by Hubert
NSArray *allNames = [array valueForKey:#"name"];
valueForKey: on NSArray returns a new array by sending valueForKey:givenKey to all it elements.
From the docs:
valueForKey:
Returns an array containing the results of invoking
valueForKey: using key on each of the array's objects.
- (id)valueForKey:(NSString *)key
Parameters
key The key to retrieve.
Return Value
The value of the retrieved key.
Discussion
The returned array contains NSNull elements for each object that returns nil.
Example:
NSArray *array = #[#{ #"active": #NO,#"name": #"Alice"},
#{ #"active": #NO,#"name": #"Bob"}];
NSLog(#"%#\n%#", array, [array valueForKey:#"name"]);
result:
(
{
active = 0;
name = Alice;
},
{
active = 0;
name = Bob;
}
)
(
Alice,
Bob
)
If you want to convert NSMutableArray to corresponding NSDictionary, just simply use mutableCopy
NSMutableArray *phone_list; //your Array
NSDictionary *dictionary = [[NSDictionary alloc] init];
dictionary = [phone_list mutableCopy];
This is an Array of Dictionary objects, so to get the values you would:
[[myArray objectAtIndex:0]valueForKey:#"name"]; //Replace index with the index you want and/or the key.
This is example one of the exmple get the emplyee list NSMutableArray and create NSMutableDictionary.......
NSMutableArray *emloyees = [[NSMutableArray alloc]initWithObjects:#"saman",#"Ruchira",#"Rukshan",#"ishan",#"Harsha",#"Ghihan",#"Lakmali",#"Dasuni", nil];
NSMutableDictionary *dict = [NSMutableDictionary dictionary];
for (NSString *word in emloyees) {
NSString *firstLetter = [[word substringToIndex:1] uppercaseString];
letterList = [dict objectForKey:firstLetter];
if (!letterList) {
letterList = [NSMutableArray array];
[dict setObject:letterList forKey:firstLetter];
}
[letterList addObject:word];
} NSLog(#"dic %#",dict);
yes you can
see this example:
NSDictionary *responseDictionary = [[request responseString] JSONValue];
NSMutableArray *dict = [responseDictionary objectForKey:#"data"];
NSDictionary *entry = [dict objectAtIndex:0];
NSString *num = [entry objectForKey:#"num"];
NSString *name = [entry objectForKey:#"name"];
NSString *score = [entry objectForKey:#"score"];
im sorry if i can't elaborate much because i am also working on something
but i hope that can help you. :)
No, guys.... the problem is that you are stepping on the KeyValue Mechanism in cocoa.
KeyValueCoding specifies that the #count symbol can be used in a keyPath....
myArray.#count
SOOOOOO.... just switch to the ObjectForKey and your ok!
NSMutableDictionary *myDictionary = [NSMutableDictionary dictionaryWithObjectsAndKeys:#"theValue", #"#name", nil];
id kvoReturnedObject = [myDictionary valueForKey:#"#name"]; //WON'T WORK, the # symbol is special in the valueForKey
id dictionaryReturnedObject = [myDictionary objectForKey:#"#name"];
NSLog(#"object = %#", dictionaryReturnedObject);

NSArray of many NSDictionary. What is the best way to find a NSDictionary with necessary value for given key?

Now I'm trying the following and it works.
- (void)findDictionaryWithValueForKey:(NSString *)name {
for (NSDictionary * set in myArray) {
if ([[set objectForKey:#"title"] isEqualToString:name])
\\do something
}
}
EDIT:
I've added one extra argument to the post of bshirley. Now it looks more flexible.
- (NSDictionary *)findDictionaryWithValue:(NSString*)name forKey:(NSString *)key {
__block BOOL found = NO;
__block NSDictionary *dict = nil;
[self.cardSetsArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
dict = (NSDictionary *)obj;
NSString *title = [dict valueForKey:key];
if ([title isEqualToString:name]) {
found = YES;
*stop = YES;
}
}];
if (found) {
return dict;
} else {
return nil;
}
}
Here's one possible implementation using newer API. (I also modified the method to actually return the value). Provided mostly to demonstrate that API. The assumption is that the title is unique to one dictionary within your array.
- (NSDictionary *)findDictionaryWithValueForKey:(NSString *)name {
// ivar: NSArray *myArray;
__block BOOL found = NO;
__block NSDictionary *dict = nil;
[myArray enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
dict = (NSDictionary *)obj;
NSString *title = [dict valueForKey:#"title"];
if ([title isEqualToString:name]) {
found = YES;
*stop = YES;
}
}];
if (found) {
return dict;
} else {
return nil;
}
}
Use filteredArrayUsingPredicate: method of the array to get all the dictionaries that satisfy your requirement.
NSPredicate * predicate = [NSPredicate predicateWithFormat:#" title MATCHES[cd] %#", name];
NSArray * matches = [myArray filteredArrayUsingPredicate:predicate];
Now matches is the array of dictionaries that have the title key equal to name.
- (void)findDictionaryWithValueForKey:(NSString)name {
for (NSDictionary * set in myArray) {
NSString *s=[NSString stringWithFormat:#"%#",[set objectForKey:#"title"]];
if ([s isEqualToString:name])
\\do something
}
OR
if (s == name])
\\do something
}
}
I will also suggest this way,it would be better if you use a break statement,
- (void)findDictionaryWithValueForKey:(NSString)name {
for (NSDictionary * set in myArray) {
if ([[set objectForKey:#"title"] isEqualToString:name])
\\do something
break;
}
}
As per the NSArray documentation,
valueForKey:
Returns an array containing the results of invoking valueForKey: using key on each of the array's objects.
- (id)valueForKey:(NSString *)key
Parameters
key
The key to retrieve.
Return Value
The value of the retrieved key.
Discussion
The returned array contains NSNull elements for each object that returns nil.
Availability
* Available in Mac OS X v10.3 and later.
EDIT:
try this,
[myArray valueForKey:#"name"];
//this will return array of values, but this actually differ from what to want

Problem with sorting NSDictionary

I need to sort a NSDictionary of dictionaries. It looks like:
{//dictionary
RU = "110.1"; //key and value
SG = "150.2"; //key and value
US = "50.3"; //key and value
}
Result need to be like:
{//dictionary
SG = "150.2"; //key and value
RU = "110.1"; //key and value
US = "50.3"; //key and value
}
I am trying this:
#implementation NSMutableDictionary (sorting)
-(NSMutableDictionary*)sortDictionary
{
NSArray *allKeys = [self allKeys];
NSMutableArray *allValues = [NSMutableArray array];
NSMutableArray *sortValues= [NSMutableArray array];
NSMutableArray *sortKeys= [NSMutableArray array];
for(int i=0;i<[[self allValues] count];i++)
{
[allValues addObject:[NSNumber numberWithFloat:[[[self allValues] objectAtIndex:i] floatValue]]];
}
[sortValues addObjectsFromArray:allValues];
[sortKeys addObjectsFromArray:[self allKeys]];
[sortValues sortUsingDescriptors:[NSArray arrayWithObject:[[[NSSortDescriptor alloc] initWithKey:#"floatValue" ascending:NO] autorelease]]];
for(int i=0;i<[sortValues count];i++)
{
[sortKeys replaceObjectAtIndex:i withObject:[allKeys objectAtIndex:[allValues indexOfObject:[sortValues objectAtIndex:i]]]];
[allValues replaceObjectAtIndex:[allValues indexOfObject:[sortValues objectAtIndex:i]] withObject:[NSNull null]];
}
NSLog(#"%#", sortKeys);
NSLog(#"%#", sortValues);
NSLog(#"%#", [NSMutableDictionary dictionaryWithObjects:sortValues forKeys:sortKeys]);
return [NSMutableDictionary dictionaryWithObjects:sortValues forKeys:sortKeys];
}
#end
This is the result of NSLog:
1)
{
SG,
RU,
US
}
2)
{
150.2,
110.1,
50.3
}
3)
{
RU = "110.1";
SG = "150.2";
US = "50.3";
}
Why is this happening? Can you help me with this problem?
NSDictionary are unsorted by nature. The order of the objects as retrieved by allKeys and allValues will always be undetermined. Even if you reverse engineer the order it may still change in the next system update.
There is however more powerful alternatives to allKeys that are used to retrieve the keys in a defined and predictable order:
keysSortedByValueUsingSelector: - Useful for sorting in ascending order according to the compare: method of the value objects.
keysSortedByValueUsingComparator: - New in iOS 4, use a block to do the sort inline.
WOW. Thanx, PeyloW! It's what i needed! I also find this code and it helps me to reorder results:
#implementation NSString (numericComparison)
- (NSComparisonResult) floatCompare:(NSString *) other
{
float myValue = [self floatValue];
float otherValue = [other floatValue];
if (myValue == otherValue) return NSOrderedSame;
return (myValue < otherValue ? NSOrderedAscending : NSOrderedDescending);
}
- (NSComparisonResult) intCompare:(NSString *) other
{
int myValue = [self intValue];
int otherValue = [other intValue];
if (myValue == otherValue) return NSOrderedSame;
return (myValue < otherValue ? NSOrderedAscending : NSOrderedDescending);
}
#end
a NSDictionary is not ordened, so it doens't matter in what order you construct a NSDIctionary.
a NSArray is ordened. If you want to have the NSDictionary ordened in memory, you should somehow make a NSArray of key value pairs. You can also return two NSArrays with corresponding indeces.
If you only want to iterate over the elements way, you can iterate over a sorted array of keys (this is what koregan suggests).