Restkit Dynamic mapping for random keys - iphone

I've an issue that "Could not find an object mapping for keyPath:" while mapping the dynamic key.
JSON response is :
{
5471 = {
ImageCount = 0;
InventoryID = "3453dfdsfgt456t3";
MakeName = aaa;
ModelName = "a1";
StockNumber = 5471;
Year = 2012;
};
5516 = {
ImageCount = 0;
InventoryID = "fg456tgev65464b4v";
MakeName = bbb;
ModelName = b1;
StockNumber = 5516;
Year = 2002;
};
5567 = {
ImageCount = 0;
InventoryID = "fdg54646ghy67u65";
MakeName = ccc;
ModelName = c1;
StockNumber = 5567;
Year = 2008;
};
}
The above keyPath value that 5567,5516,5471 is random value.How could is define key?
My class code is in below:
Class:
#interface CategoryPic : NSObject
#property(nonatomic,strong)NSString *imageCount_pic;
#property(nonatomic,strong)NSString *inventoryID_pic;
#property(nonatomic,strong)NSString *makeName_pic;
#property(nonatomic,strong)NSString *modelName_pic;
#property(nonatomic,strong)NSString *stockNumber_pic;
#property(nonatomic,strong)NSString *year_pic;
#end
- (void)viewDidLoad{
RKObjectMapping* new = [RKObjectMapping mappingForClass:[CategoryPic class]];
[new mapKeyOfNestedDictionaryToAttribute:#"stockid"];
[new mapKeyPath:#"(stockid).ImageCount" toAttribute:#"imageCount_pic"];
[new mapKeyPath:#"(stockid).InventoryID" toAttribute:#"inventoryID_pic"];
[new mapKeyPath:#"(stockid).MakeName" toAttribute:#"makeName_pic"];
[new mapKeyPath:#"(stockid).ModelName" toAttribute:#"modelName_pic"];
[new mapKeyPath:#"(stockid).StockNumber" toAttribute:#"stockNumber_pic"];
[new mapKeyPath:#"(stockid).Year" toAttribute:#"year_pic"];
[[NewSingelton class].objectManager.mappingProvider setMapping:new forKeyPath:#"stockid"];
}

I would transform this into an array and use the random number as one of the fields.
NSMutableArray *result = [NSMutableArray array];
NSMutableDictionary *entry = [NSMutableDictionary dictionary];
for (NSString *key in jsonObject.allKeys) {
entry = [NSMutableDictionary dictionaryWithDictionary:jsonObject[key]];
[entry addEntriesFromDictionary:#{#"randomNumber" : key}];
[result addObject:[NSDictionary dictionaryWithDictionary:entry];
}
Or, if your data sample is any indication, just throw this key away as it is the same as StockNumber anyway.

stockid should exist as a property on CategoryPic so that the value is saved somewhere. If the number always matches StockNumber then you can use stockNumber_pic and remove that line mapping.

Related

Dictionary Value retrieve

In my application ,the dictionary value contains following content.How to retrieve the each and store it new array
contryArray(
{
checka0 = Thailand;
checka1 = Brazil;
checka10 = Marocco;
checka11 = Thailand;
checka12 = Jordan;
checka13 = Colombia;
checka14 = Kuwait;
checka3 = Mexico;
checka4 = "Saoudi Arabia";
checka5 = Chili;
checka7 = Australia;
checka8 = Malta;
checka9 = "South Africa";
checkb0 = havana;
checkb1 = Santos;
checkb10 = Casablanca;
checkb11 = Bangkok;
checkb12 = Aqaba;
checkb13 = Havana;
checkb14 = Shuwaikh;
checkb3 = Veracruz;
checkb4 = Jeddah;
checkb5 = "San Antonio";
checkb7 = Maersk;
checkb8 = Maraxklokk;
checkb9 = Durban;
checkc0 = 1;
checkc1 = "0.7";
checkc10 = 1;
checkc11 = "1.2";
checkc12 = 1;
checkc13 = "1.4";
checkc14 = 1;
checkc3 = "0.9";
checkc4 = "0.8";
checkc5 = "0.9";
checkc7 = "2.7";
checkc8 = "0.8";
checkc9 = "0.9";
}
For ex: checka0-checka14 in one array, Here the problem is checka2 and checka6 is not available, Im new bee in xcode,Please help me to retrieve
Your question is not clear. Possibly you need to get all keys in your dictionary and separating each item with specific word in it(checka/checkb/checkc).
If that is the case then,
You will get all the keys using:
NSArray *dictKeys = [yourDictionary allKeys];
You can implement this in multiple ways, one of them:
For storing it in same array:
for (NSString *key in [yourDictionary allKeys])
{
[yourArray addObject:[yourDictionary objectForKey:key]];
}
For storing it in seperate arrays:
for (NSString *key in [yourDictionary allKeys])
{
if([key rangeOfString:#"checka"].location != NSNotFound)
{
//add checka to first array
[yourFirstArray addObject:[yourDictionary objectForKey:key]];
}
else if([key rangeOfString:#"checkb"].location != NSNotFound)
{
//add checkb to second array
[yourSecondArray addObject:[yourDictionary objectForKey:key]];
}
...
}
if contryArray is your dictionary then access it as follow
[contryArray valueForKey:#"checka0"];
and go on adding this values to another array
You can use the following code:
- (void)filterDictionary:(NSDictionary *)dict
{
NSArray *allKeys = [dict allKeys];
NSMutableArray *allValues = [[NSMutableArray alloc]init];
for(id key in allKeys)
{
id value = [dict valueForKey:key];
[allValues addObject:[value stringValue]];
}
}

Sorting array of multiple dictionaries

My array contains three dictionaries per object of the array.
{
avg = {
avg1 = 50;
avg2 = 60;
};
posts = {
alcoholContent = 450;
name = "BBB";
origin = United States;
};
reviews = {
rev1 = "Test review 1";
rev2 = "Test review 2";
};
}
{
avg = {
avg1 = 30;
avg2 = 20;
};
posts = {
alcoholContent = 550;
name = "AAA";
origin = United States;
};
reviews = {
rev1 = "Test review 1";
rev2 = "Test review 2";
};
}
I want to sort array acceding by key "name" (of post dictionary).
How can I do it?
I tried normal sorting methods using sort descriptors, but did not work
Try sortUsingComparator:
[array sortUsingComparator:^NSComparisonResult(id obj1, id obj2) {
NSDictionary *dict1 = obj1;
NSDictionary *dict2 = obj2;
NSString *string1 = [[dict1 objectForKey:#"posts"] objectForKey:#"name"];
NSString *string2 = [[dict2 objectForKey:#"posts"] objectForKey:#"name"];
return [string1 compare:string2];
}];

Merge two NSDIctionay in one NSDictonary

I want to merge two NSDictionary in one NSDictionary.
my first DIctionary
BreakFast Dates Dic {
"2012-07-24" = "27";
"2012-08-03" = "98";
"2012-08-06" = "4203";
"2012-08-23" = "0";
"2012-08-24" = "0";
"2012-09-11" = "36";
"2012-09-19" = "450";
"2012-09-24" = "36";
Goals = 3;
}
my second Dictonary
Dinner Dates Dic {
"2012-08-03" = "100";
"2012-08-27" = "0";
"2012-09-19" = "270";
Goals = 4;
}
i want to merge both dictionary into one. like if in breakfast i have "2012-09-19" and same date i have in dinner. i want to separate both values by comma (,) .
my resultant dictionary should be like this.
combine {
"2012-07-24" = "27,0";
"2012-08-03" = "98,100";
"2012-08-06" = "4203,0";
"2012-08-23" = "0,0";
"2012-08-24" = "0,0";
"2012-09-11" = "36,0";
"2012-09-19" = "450,270";
"2012-09-24" = "36,0";
Goals = 3,4;
}
NSMutableDictionary *combined = [objectDelegate.dataBreakFastSummary mutableCopy];
for(NSString *key in [combined allKeys])
{
NSString *breakfastDate = [objectDelegate.dataBreakFastSummary valueForKey:key];
NSString *dinnerDate = [objectDelegate.dataDinnerSummary objectForKey:key];
if(dinnerDate){
[combined setObject:[NSString stringWithFormat:#"%#,%#",breakfastDate, dinnerDate] forKey:key];
} else {
[combined setObject:[NSString stringWithFormat:#"%#,0",breakfastDate] forKey:key];
}
}
NSLog(#"Combine %#",combined);

sorting array of nested NSDictionary containing an array

Im quite new to iOS and objective.. heres my question..
if my array looks like this:
myArray = {
parentdict = {
childdict = {
aname = "Aname";
bname - "Bname";
cname = "Cname";
};
childarray = {
{
counter = "1";
close = "25236";
},
{
counter = "2";
close = "12458";
};
};
};
},
{
parentdict = {
childdict = {
aname = "Aname";
bname - "Bname";
cname = "Cname";
};
childarray = {
{
counter = "1";
close = "28556";
},
{
counter = "2";
close = "12118";
};
};
};
},
{
parentdict = {
childdict = {
aname = "Aname";
bname - "Bname";
cname = "Cname";
};
childarray = {
{
counter = "1";
close = "24356";
},
{
counter = "2";
close = "155628";
};
};
};
};
basically its an array of nested dictionary and inside one of the dictionary contains an array of dictionary (childarray) if i want to sort myArray by #"close" of array index 1, which is the one next to counter 2, exactly how should i do this?..(perhaps i should use NSSortDescriptor?)
thanks for the reply
You have presented your structure in the JSON format. I assume it is for sake of presenting it to the audience here. If you are actually starting with JSON string, you will have to convert it to nested NSArrayies and NSDictionaryies using some third-party libs or iOS 5 built-in classes..
Assuming you already have your top level NSArray* myArray, give it a try to the following code:
NSArray* myArray = // ... this is your array
NSArray* sorted_array = [myArray sortedArrayUsingComparator:^NSComparisonResult(id obj1, id obj2) {
NSDictionary* left = obj1;
NSDictionary* right = obj2;
NSDictionary* left_parent_dict = [left objectForKey: #"parentdict"];
NSDictionary* right_parent_dict = [right objectForKey: #"parentdict"];
NSArray* left_child_array = [left_parent_dict objectForKey: #"childarray"];
NSArray* right_child_array = [right_parent_dict objectForKey: #"childarray"];
NSDictionary* left_child_first = [left_child_array objectAtIndex: 1];
NSDictionary* right_child_first = [right_child_array objectAtIndex: 1];
NSString* left_close = [left_child_first objectForKey: #"close"];
NSString* right_close = [right_child_first objectForKey: #"close"];
NSNumber* left_val = [NSNumber numberWithInt: [left_close intValue]];
NSNumber* right_val = [NSNumber numberWithInt: [right_close intValue]];
return [left_val compare: right_val];
} ];
You will need, of course, to add some checks which I omitted for simplicity.
If you want to get descending order modify the last statement to:
return [right_val compare: left_val];
I would also suggest you considering SQL database for complex data structures as pointed out by Niko.
Sorting an array can be quite complex, especially when the array contains nested objects. May be you should create an SQLite database
You should use iOS 5.0's built in JSON API. [Here's a link to a great tutorial.] (http://www.raywenderlich.com/5492/working-with-json-in-ios-5). JSON is really easy to work with. And that site also has great tutorials on Core Data (iOS's SQLite API) here. There are two more parts to that tutorial as well.
Try this
[array sortUsingComparator:(NSComparator)^(id obj1, id obj2){
int firstValue = [[obj1 objectForKey:#"someKey"] intValue];
int secondValue = [[obj2 objectForKey:#"someKey"] intValue];
int valueDiff = firstValue - secondValue;
return (valueDiff == 0) ? NSOrderedSame : (valueDiff < 0) ? NSOrderedAscending : NSOrderedDescending;
}];

How to get values from unknown key in NSDictionary iphone?

I have one more big problem while parse the values from Webservice response. I dont know the key for the values in the webservice response. For example,
class = (
{
"ObjectiveC" =
(
{
"brief_desc" = "ObjectiveC";
date = "2008-02-27";
"event_status" = Attended;
},
{
"brief_desc" = "ObjectiveC";
date = "2008-03-05";
"event_status" = Attended;
},
{
"brief_desc" = "ObjectiveC";
date = "2008-03-12";
"event_status" = Missed;
},
);
},
{
"Java" = (
{
"brief_desc" = "Java";
date = "2008-02-27";
"event_status" = Attended;
},
{
"brief_desc" = "Java";
date = "2008-03-05";
"event_status" = Attended;
},
{
"brief_desc" = "Java";
date = "2008-03-12";
"event_status" = Missed;
},
);
}
);
In this response even we dont know the keys "ObjectiveC" and "Java". The keys("ObjectiveC and Java") should be change in every response retured. How to get values of key (Unknown key)? How can i parse this response and get the values?
I would enumerate through the keys to get the value. Here is an example of enumeration in objective-c.
NSEnumerator *enumerator = [myDictionary keyEnumerator];
id key;
while ((key = [enumerator nextObject])) {
//assuming value will be string
NSString *valueForKey = [myDictionary valueForKey:key];
//assuming value is another dictionary
NSDictionary *subDictionary = [myDictionary objectForKey:key];
}
And if you don't know the keys of the sub dictionaries, you can enumerate through those as well.
NSDictionary has - (NSArray *)allKeys and - (NSArray *)allValues. One of those might help
NSDictionary * lessonDict = [[NSDictionary alloc] initWithObjectsAndKeys:#"Key", #"Value", #"Key 2", #"Value 2", nil];
NSArray *values = [lessonDict allValues];
NSArray *keys = [lessonDict allKeys];
NSLog(#"Keys: %#",keys);
NSLog(#"Values: %#",values);