How would I get the last section after the last "/"?
/{ct6yr356-051t-55e2-b89r-546454ab922}/location/Missouri/costcenter/TXX1/Sales Orders on Queue.rdl
Sales Orders on Queue <-- The part I want to extract. There are always six of '/' and .rdl at the end.
The language is T-SQL.
Got what I needed.
;WITH R as (
SELECT '/{ct6yr356-051t-55e2-b89r-546454ab922}/location/Missouri/costcenter/TXX1/Sales
Orders on Queue.rdl' as VARIABLE
) SELECT SUBSTRING(VARIABLE, START,
CHARINDEX('.rdl', SUBSTRING(VARIABLE, START, LEN(VARIABLE)))-1
) FROM (SELECT CHARINDEX('/', R.VARIABLE,
CHARINDEX('/', R.VARIABLE, CHARINDEX('/', R.VARIABLE, CHARINDEX('/', R.VARIABLE, CHARINDEX('/', R.VARIABLE) +1) +1) +1)
+1) + 1 as START, R.*
FROM R
) R
Related
I can't replace every 2 characters of a string with a '.'
select STUFF('abcdefghi', 3, 1, '.') c3,STUFF('abcdefghi', 5, 1,
'.') c5,STUFF('abcdefghi', 7, 1, '.') c7,STUFF('abcdefghi', 9, 1, '.')
c9
if I use STUFF I should subsequently overlap the strings c3, c5, c7 and c9. but I can't find a method
can you help me?
initial string:
abcdefghi
the result I would like is
ab.de.gh.
the string can be up to 50 characters
Create a numbers / tally / digits table, if you don't have one already, then you can use this to target each character position:
with digits as ( /* This would be a real table, here it's just to test */
select n from (values(1),(2),(3),(4),(5),(6),(7),(8),(9),(10))x(n)
), t as (
select 'abcdefghi' as s
)
select String_Agg( case when d.n%3 = 0 then '.' else Substring(t.s, d.n, 1) end, '')
from t
cross apply digits d
where d.n <Len(t.s)
Using for xml with existing table
with digits as (
select n from (values(1),(2),(3),(4),(5),(6),(7),(8),(9),(10))x(n)
),
r as (
select t.id, case when d.n%3=0 then '.' else Substring(t.s, d.n, 1) end ch
from t
cross apply digits d
where d.n <Len(t.s)
)
select result=(select '' + ch
from r r2
where r2.id=r.id
for xml path('')
)
from r
group by r.id
You can try it like this:
Easiest might be a quirky update ike here:
DECLARE #string VARCHAR(100)='abcdefghijklmnopqrstuvwxyz';
SELECT #string = STUFF(#string,3*A.pos,1,'.')
FROM (SELECT TOP(LEN(#string)/3) ROW_NUMBER() OVER(ORDER BY (SELECT NULL))
FROM master..spt_values) A(pos);
SELECT #string;
Better/Cleaner/Prettier was a recursive CTE:
We use a declared table to have some tabular sample data
DECLARE #tbl TABLE(ID INT IDENTITY, SomeString VARCHAR(200));
INSERT INTO #tbl VALUES('')
,('a')
,('ab')
,('abc')
,('abcd')
,('abcde')
,('abcdefghijklmnopqrstuvwxyz');
--the query
WITH recCTE AS
(
SELECT ID
,SomeString
,(LEN(SomeString)+1)/3 AS CountDots
,1 AS OccuranceOfDot
,SUBSTRING(SomeString,4,LEN(SomeString)) AS RestString
,CAST(LEFT(SomeString,2) AS VARCHAR(MAX)) AS Growing
FROM #tbl
UNION ALL
SELECT t.ID
,r.SomeString
,r.CountDots
,r.OccuranceOfDot+2
,SUBSTRING(RestString,4,LEN(RestString))
,CONCAT(Growing,'.',LEFT(r.RestString,2))
FROM #tbl t
INNER JOIN recCTE r ON t.ID=r.ID
WHERE r.OccuranceOfDot/2<r.CountDots-1
)
SELECT TOP 1 WITH TIES ID,Growing
FROM recCTE
ORDER BY ROW_NUMBER() OVER(PARTITION BY ID ORDER BY OccuranceOfDot DESC);
--the result
1
2 a
3 ab
4 ab
5 ab
6 ab.de
7 ab.de.gh.jk.mn.pq.st.vw.yz
The idea in short
We use a recursive CTE to walk along the string
we add the needed portion together with a dot
We stop, when the remaining length is to short to continue
a little magic is the ORDER BY ROW_NUMBER() OVER() together with TOP 1 WITH TIES. This will allow all first rows (frist per ID) to appear.
I'm using SQL Server 2000 (80). So, it's not possible to use the LAG function.
I have a code a data set with four columns:
Purchase_Date
Facility_no
Seller_id
Sale_id
I need to identify missing Sale_ids. So every sale_id is a 100% sequential, so the should not be any gaps in order.
This code works for a specific date and store if specified. But i need to work on entire data set looping looping through every facility_id and every seller_id for ever purchase_date
declare #MAXCOUNT int
set #MAXCOUNT =
(
select MAX(Sale_Id)
from #table
where
Facility_no in (124) and
Purchase_date = '2/7/2020'
and Seller_id = 1
)
;WITH TRX_COUNT AS
(
SELECT 1 AS Number
union all
select Number + 1 from TRX_COUNT
where Number < #MAXCOUNT
)
select * from TRX_COUNT
where
Number NOT IN
(
select Sale_Id
from #table
where
Facility_no in (124)
and Purchase_Date = '2/7/2020'
and seller_id = 1
)
order by Number
OPTION (maxrecursion 0)
My Dataset
This column:
case when
Sale_Id=0 or 1=Sale_Id-LAG(Sale_Id) over (partition by Facility_no, Purchase_Date, Seller_id)
then 'OK' else 'Previous Missing' end
will tell you which Seller_Ids have some sale missing. If you want to go a step further and have exactly your desired output, then filter out and distinct the 'Previous Missing' ones, and join with a tally table on not exists.
Edit: OP mentions in comments they can't use LAG(). My suggestion, then, would be:
Make a temp table that that has the max(sale_id) group by facility/seller_id
Then you can get your missing results by this pseudocode query:
Select ...
from temptable t
inner join tally N on t.maxsale <=N.num
where not exists( select ... from sourcetable s where s.facility=t.facility and s.seller=t.seller and s.sale=N.num)
> because the only way to "construct" nonexisting combinations is to construct them all and just remove the existing ones.
This one worked out
; WITH cte_Rn AS (
SELECT *, ROW_NUMBER() OVER(PARTITION BY Facility_no, Purchase_Date, Seller_id ORDER BY Purchase_Date) AS [Rn_Num]
FROM (
SELECT
Facility_no,
Purchase_Date,
Seller_id,
Sale_id
FROM MyTable WITH (NOLOCK)
) a
)
, cte_Rn_0 as (
SELECT
Facility_no,
Purchase_Date,
Seller_id,
Sale_id,
-- [Rn_Num] AS 'Skipped Sale'
-- , case when Sale_id = 0 Then [Rn_Num] - 1 Else [Rn_Num] End AS 'Skipped Sale for 0'
, [Rn_Num] - 1 AS 'Skipped Sale for 0'
FROM cte_Rn a
)
SELECT
Facility_no,
Purchase_Date,
Seller_id,
Sale_id,
-- [Skipped Sale],
[Skipped Sale for 0]
FROM cte_Rn_0 a
WHERE NOT EXISTS
(
select * from cte_Rn_0 b
where b.Sale_id = a.[Skipped Sale for 0]
and a.Facility_no = b.Facility_no
and a.Purchase_Date = b.Purchase_Date
and a.Seller_id = b.Seller_id
)
--ORDER BY Purchase_Date ASC
I'm having difficult time with T-SQL and I was wondering if somebody could me point me to the right track.
I have the following variable called #input
DECLARE #input nvarchar(100);
SET #input= '27364 - John Smith';
-- SET #input= '27364 - John Andrew Smith';
I need to split this string in 3 parts (ID,Firstname and LastName) or 4 if the string contains a MiddleName. For security reason I cannot use functions.
My aproach was use Substring and Charindex.
SET #Id = SUBSTRING(#input, 1, CASE CHARINDEX('-', #input)
WHEN 0
THEN LEN(#input)
ELSE
CHARINDEX('-', #input) - 2
END);
SET #FirstName = SUBSTRING(#input, CASE CHARINDEX(' ', #input)
WHEN 0
THEN LEN(#input) + 1
ELSE
CHARINDEX(' ', #input) + 1
END, 1000);
SET #LastName = SUBSTRING(#input, CASE CHARINDEX(' ', #input)
WHEN 0
THEN LEN(#input) + 1
ELSE
CHARINDEX('0', #input) + 1
END, 1000);
Select #PartyCode,#FirstName,#LastName
I am stuck because I don't know how to proceed and also the code has to be smart enough to add a fourth split if Middlename exists.
Any thoughts?
Thanks in advance
Hopefully this is part of a normalization project. This data is breaking 1NF and one really should avoid that...
Try it like this
The advantages
typesafe values
ad-hoc SQL
set based
If you want you might use a CASE WHEN to check if the last part is NULL and place Part2 into Part3 in this case...
DECLARE #input table(teststring nvarchar(100));
INSERT INTO #input VALUES
(N'27364 - John Smith'),(N'27364 - John Andrew Smith');
WITH Splitted AS
(
SELECT CAST(N'<x>' + REPLACE(REPLACE(REPLACE(REPLACE(REPLACE(teststring,N' - ',N' '),N'&',N'&'),N'<',N'<'),N'>',N'>'),N' ',N'</x><x>') + N'</x>' AS XML) testXML
FROM #input
)
SELECT testXML.value('/x[1]','int') AS Number
,testXML.value('/x[2]','nvarchar(max)') AS Part1
,testXML.value('/x[3]','nvarchar(max)') AS Part2
,testXML.value('/x[4]','nvarchar(max)') AS Part3
FROM Splitted
The result
Number Part1 Part2 Part3
27364 John Smith NULL
27364 John Andrew Smith
SQL Server 2016 has a new built-in function called STRING_SPLIT()
Assuming creating built-in functions, but CLR functions are not allowed:
CREATE FUNCTION dbo.WORD_SPLIT
(
#String AS nvarchar(4000)
)
RETURNS TABLE
AS
RETURN
(
WITH Spaces AS
(
SELECT Spaced.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY (SELECT 1)) AS ordinal
FROM STRING_SPLIT(#String, ' ') AS Spaced
)
, Tabs AS
(
SELECT Tabbed.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY s.ordinal, (SELECT 1)) AS ordinal
FROM Spaces AS s
CROSS APPLY STRING_SPLIT(s.[value], ' ') AS Tabbed
)
, NewLines1 AS
(
SELECT NewLined1.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY t.ordinal, (SELECT 1)) AS ordinal
FROM Tabs AS t
CROSS APPLY STRING_SPLIT(t.[value], CHAR(13)) AS NewLined1
)
, NewLines2 AS
(
SELECT NewLined2.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl1.ordinal, (SELECT 1)) AS ordinal
FROM NewLines1 AS nl1
CROSS APPLY STRING_SPLIT(nl1.[value], CHAR(10)) AS NewLined2
)
SELECT LTRIM(RTRIM(nl2.[value])) AS [value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl2.ordinal, (SELECT 1)) AS ordinal
FROM NewLines2 AS nl2
WHERE LTRIM(RTRIM(nl2.[value])) <> ''
)
GO
Usage:
-- Not Normailized
SELECT i.*, split.[value], split.[ordinal]
FROM #input AS i
CROSS APPLY dbo.WORD_SPLIT(i.teststring) AS split
-- Normalized
;WITH Splitted AS
(
SELECT split.[value], split.[ordinal]
FROM #input AS i
CROSS APPLY dbo.WORD_SPLIT(i.teststring) AS split
)
SELECT *
FROM (SELECT [value], 'part' + CONVERT(nvarchar(20), [ordinal]) AS [parts] FROM Splitted) AS s
PIVOT (MAX([value]) FOR [parts] IN ([part1], [part2], [part3], [part4])
Or assuming that, per-security, you are not allowed to make schema changes:
WITH Splitting AS
(
SELECT teststring AS [value]
FROM #input
)
WITH Spaces AS
(
SELECT Spaced.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY (SELECT 1)) AS ordinal
FROM Splitting AS sp
CROSS APPLY STRING_SPLIT(sp.[value], ' ') AS Spaced
)
, Tabs AS
(
SELECT Tabbed.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY s.ordinal, (SELECT 1)) AS ordinal
FROM Spaces AS s
CROSS APPLY STRING_SPLIT(s.[value], ' ') AS Tabbed
)
, NewLines1 AS
(
SELECT NewLined1.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY t.ordinal, (SELECT 1)) AS ordinal
FROM Tabs AS t
CROSS APPLY STRING_SPLIT(t.[value], CHAR(13)) AS NewLined1
)
, NewLines2 AS
(
SELECT NewLined2.[value], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl1.ordinal, (SELECT 1)) AS ordinal
FROM NewLines1 AS nl1
CROSS APPLY STRING_SPLIT(nl1.[value], CHAR(10)) AS NewLined2
)
, Splitted AS
(
SELECT LTRIM(RTRIM(nl2.[value])) AS [teststring], ROW_NUMBER() OVER (PARTITION BY 1 ORDER BY nl2.ordinal, (SELECT 1)) AS ordinal
FROM NewLines2 AS nl2
WHERE LTRIM(RTRIM(nl2.[value])) <> ''
)
SELECT *
FROM (SELECT [value], 'part' + CONVERT(nvarchar(20), [ordinal]) AS [parts] FROM Splitted) AS s
PIVOT (MAX([value]) FOR [parts] IN ([part1], [part2], [part3], [part4])
Hopefully helpful!
I have a requirement wherein I have to take in the data between two special characters only. The first one and the second character.
Ex: KVN REG#HENDRI#AEP: 6256765058812#KERG00101258#875303069817#THT914000
Here I need the data between first # and the second one. I gathered data from different sources and wrote a query. I just want to know a simpler form of the query, wherein I need not to have to put the rownum function.
Query:
select b.name as v_custname
from ( select a.*, rownum rnum
from (SELECT regexp_substr(token, '[^:]+', 1, 1) name
FROM (
SELECT regexp_substr(s, '[^\#]+', 1, lvl) token, lvl
FROM (
SELECT s, LEVEL lvl FROM (select 'KVN REG#HENDRI#AEP: 6256765058812#KERG00101258#875303069817#THT914000' s from dual)
CONNECT BY LEVEL < LENGTH(s) - LENGTH(REPLACE(s, '#'))
)
) ) a
where rownum <= 2 ) b
where rnum >= 2;
You can do this with just instr and substr():
with sample_data as (
select 'KVN REG#HENDRI#AEP: 6256765058812#KERG00101258#875303069817#THT914000' as token
from dual
)
select substr(token,
instr(token, '#') + 1,
instr(token, '#', 1, 2) - instr(token, '#') - 1
)
from sample_data
instr(token, '#') + 1 finds the first occurrence of #
instr(token, '#', 1, 2) finds the second occurrence of #
substr() takes the first position plus a length to be extracted. The length you need is the second position minus the first position.
How can I split a string in characters and add a new line after each character in PostgreSQL
For example
num desc
1 Hello
2 Bye
num desc
1 H
e
l
l
o
2 B
y
e
select num, regexp_split_to_table(descr,'')
from the_table
order by num;
SQLFiddle: http://sqlfiddle.com/#!15/13c00/4
The order of the characters is however not guaranteed and achieving that is a bit complicated.
Building on Erwin's answer regarding this problem:
select case
when row_number() over (partition by id order by rn) = 1 then id
else null
end as id_display,
ch_arr[rn]
from (
select *,
generate_subscripts(ch_arr, 1) AS rn
from (
select id,
regexp_split_to_array(descr,'') as ch_arr
from data
) t1
) t2
order by id, rn;
Edit:
If you just want a single string for each id, where the characters are separated by a newline, you can use this:
select id,
array_to_string(regexp_split_to_array(descr,''), chr(10))
from data
order by id