file1 = fullfile(pwd,'folder','toto.txt');
file2 = fullfile(pwd,'folder','toto2.txt.sav');
movefile(file1,file2)
=>this creates a folder named toto2.txt.sav
whereas I'm looking for renaming the file in the same directory
any idea ?
Check the documentation:
Renaming a File in the Current Folder
In the current folder, rename myfunction.m to oldfunction.m:
movefile('myfunction.m','oldfunction.m')
Thus:
o=pwd
cd('folder')
movefile('toto.txt','toto2.txt.sav')
cd(o);
Was looking for this as well. Now on a windows machine if I want to rename all files in a folder, I do:
system('rename *.* *.sav')
Related
Okay so I want to know how I would go about doing this, using grep to locate .txt files named "cocacola1", "cocacola2", "cocacola3" & then copying them to another directory. So searching for files named "cocacola" &/even if it contains other characters within the file name to then copy them to another directory/location.
You can just use unix find. Assuming the files you're searching for are in 'source' and you want to copy to 'destination':
find source -name '*cocacola*' -exec cp {} destination \;
I put the wildcard '*' before and after cocacola since you said other characters might exist in the file name.
Suppose I have a directory structure like
C:\Users\Desktop\abc\d
I want to rar archive the abc folder so that the structure of rar is:
abc\d
When I try using powershell to archive, winrar replicates the full path inside the archive, like:
\Users\Desktop\abc\d
I dont want the full path to be created inside the archive
Here's the script:
https://gist.github.com/saurabhwahile/50f1091fb29c2bb327b7
What am I doing wrong?
Use the command line:
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc"
Rar.exe is the console version of WinRAR stored in same directory as WinRAR.exe. You can use this command line also with WinRAR.exe if you want to see the compression process in a graphic window.
a is the command and means add files to archive.
-r is a switch to recursively add all files and subdirectories including empty subdirectories to the archive.
-ep1 is another switch which results in execluding base directory.
For this command line the base directory is "C:\Users\Desktop\" and therefore the created archive Test.rar contains only abc and all files and subdirectories in directory abc which is what you want.
One more hint: Using the command line
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc\"
results in adding all files and subdirectories of directory abc to the archive, but without directory name abc being also stored in the archive. The backslash at end makes this difference.
In other words: On using switch -ep1 everything up to last backslash in file/directory specification is not added to the archive.
For more information about available switches see the text file Rar.txt in the program files directory of WinRAR.
example
There is a file "sample.rar".
Folder structure is: "rising\dawn\ and here there are many (folders1, folders2 and file1, file2)" in this archive.
i have used following command
7z.exe x "sample.rar" "rising\dawn\*" -oi:\delete
The result is:
all files and folders in "rising\dawn\" are extracted to "i:\delete" folder but the empty parent folders "rising\dawn\" are also created in destination folder.
e.g. destination looks:
i:\delete\rising\dawn\folder1\file1.bmp
i:\delete\rising\dawn\folder2\subfolder
i:\delete\rising\dawn\file1.txt
i:\delete\rising\dawn\file2.txt
i don't want "rising\dawn\" empty folders to be created but the folder structure there onwards must be as is in the archive.
i want the result:
i:\delete\folder1\file1.bmp
i:\delete\folder2\subfolder
i:\delete\file1.txt
i:\delete\file2.txt
at last i found a way out solution. thanks to the winrar support. i have accepted it as an answer below.
if you find the question useful don't forget to click the up-vote button.
Finally this gave me the result.
Thanks to winrar support.
rar x -ep1 sample.rar rising\dawn\* d:\e\delete\
i have tried other answers given here, this is the only correct answer.
don't forget to upvote.
You can extract the archive normally and
1) move the lower level folder/files to where you would like it, then
2) remove the extra top level archive folders.
Code to do so will depend on the exact task.
Using e command instead of x and add -r option works well.
Like this:
7z.exe e -r "sample.rar" "rising\dawn\*" -oi:\delete
My executable version is "7-Zip [64] 9.20 2010-11-18",
And the platform is Windows 8.1.
This command line eliminates unnecessary parent folders and preserves the hierarchy of folders.
You need to use the e command rather than the x command:
7z.exe e "sample.rar" "scholar\update\*" -oi:\delete
Using e instead of x means 7zip will extract all matching files into the same folder (as specified via the -so switch, or the current directory if this isn't specified) rather than preserving the folder structure from inside the archive.
So i had this issue that occurred when I ran a Matlab script. Here is an a simple example that illustrates it:
So its important to outline the file structure:
MainFolder
script.m
SubFolder
a1.csv
a2.csv
a3.csv
now say i have a script like this:
-> script.m
dir
it would simply print out the files in the folder.
Now the wierd thing, if i run the script in the Subfolder like this:
>>script
it will do this:
>> a1.csv a2.csv a3.csv
but if i do this in the folder:
>>run('C:\Users\....\MainFolder\script.m')
it will only print out
>> script.m
So obviously it is acting as if i ran it form MainFolder rather than SubFolder.
What is the point of this functionality?
The dir command shows the directory contents of Matlab's current directory, not that of where the script is located. So the script showed you the directory contents of wherever you happened to be in the Matlab command prompt when you called that script.
To get what you want, use this in the script:
dir(fileparts(mfilename('fullpath')))
Use pwd to see current dir
Use cd to change directory
Use path to see if your project folders are included in the path
Use which to see you are calling the right *.m file (in case there is multiple .m files with same name on the path)
I need to write a batch file that copies a file to a new folder and renames it.
At the moment, my batch file consists of only this command:
COPY ABC.PDF \\Documents
As you can see, it only copies the file ABC.pdf to the network folder Documents.
However I need to change this so it renames the file ABCxxx.pdf, where xxx is a text variable that I would like to set somewhere in the batch file.
For example, if xxx = _Draft, then file would be renamed ABC_Draft.pdf after it is copied.
Make a bat file with the following in it:
copy /y C:\temp\log1k.txt C:\temp\log1k_copied.txt
However, I think there are issues if there are spaces in your directory names. Notice this was copied to the same directory, but that doesn't matter. If you want to see how it runs, make another bat file that calls the first and outputs to a log:
C:\temp\test.bat > C:\temp\test.log
(assuming the first bat file was called test.bat and was located in that directory)
type C:\temp\test.bat>C:\temp\test.log