I'm working on paging functionality using a range query. I'm using this test query in the mongo shell:
> var params = {$query: {_id: {$lt: ObjectId("52b06166eff887999c6efbd9")}}, $orderby: {_id: -1}, $maxScan: 3}
> params
{
"$query" : {
"_id" : {
"$lt" : ObjectId("52b06166eff887999c6efbd9")
}
},
"$orderby" : {
"_id" : -1
},
"$maxScan" : 3
}
> db.events.find(params)
I'd like to be able to pass the serialized params object to a web service (as a URL query string). However, the ObjectId class is only available inside the shell. Is there a way to specify an ObjectId as part of a query when not in the shell? I've tried the following as the value of $lt without success:
'ObjectId("52b06166eff887999c6efbd9")'
'new ObjectId("52b06166eff887999c6efbd9")'
{"$oid" : "52b06166eff887999c6efbd9"}
Generally speaking, this abstraction is handled by whatever MongoDB driver you use. If you are using an actual driver, you can do queries on _id without using ObjectId()
Mongoose / Node.js Example:
People.find({ _id : "Valid ObjectID String" }, function(e, person) {
console.log(e, person);
});
If you do still need the ObjectId helper, generally you are able to reference it in whatever native driver you need.
What you are doing in your last examples is passing your objectId as a string (first two examples) or as a dictionary third example. So surely it does not work.
You can pass just a string '52b06166eff887999c6efbd9' as a parameter and then when you receive it you can construct normal ObjectId on the server. For example in php you can construct it in the following way new MongoId('your string');
Related
I have a collection called dealers as follows.
{
"_id" : ObjectId("5b9ba196cd5f5af83bb0dc71"),
"name" : "SOME COMPANY",
"outletID" : "GS0061920",
"companyID" : "GC0050397"
}
I have about 5000 documents in this collection where outletID and companyID properties are empty.
I would like to update both of these properties for all documents in this collection with incremental values.
I'm not sure how I should go about this.
Note: MongoDB 3.4 is in use.
Assuming you are running on mongodb shell. You can use the following:
> var counter = 1;
> db.collection.find().forEach(
function(elem) {
db.myColl.update(
{ "outletID" : null, "companyID" : null},
{$set:{ outletID: counter , companyID: counter }
});
counter++;
});
The mongo shell is an interactive JavaScript interface. I have used JS for the task. counter is a simple variable which is used to update values. $set is used to update the fields.
The $set operator replaces the value of a field with the specified value. You can find more data in its official documentation.
I created a sample data and tested my function. Hope it works fine.
I am working on a nodejs/express app with Mongodb on the backend. In one of my API calls, depending on the presence of a particular querystring parameter or the other I want to issue a query to Mongodb with either a $gt or a $lt.
In some cases we want to ask for everything less than the tokenId using $lt, but in other cases we want everything greater than the tokenId using $gt. How do we do that without duplicating the queries?
Here's an example query:
collection.find({'film_id': {$in : genre}, '_id': {$lt: tokenId}}).sort({'_id': -1}).limit(25).toArray(function(error, films)
Is there a way to dynamically create the query without actually doing 2 different queries?
Build up your query object programmatically:
var query = {'film_id': {$in : genre}};
if (param) {
query._id = {$lt: tokenId};
} else {
query._id = {$gt: tokenId};
}
collection.find(query).sort({'_id': -1}).limit(25).toArray(function(error, films);
Update
Now that Node.js 4+ supports computed property names, you can create query in one step as:
var query = {
film_id: {$in: genre},
_id: {[param ? '$lt' : '$gt']: tokenId}
};
The Above code may not work. The above dynamic query will be resolved to following Ex. Token is an integer 35.
collection.find("_id":"{$gt: 35}")
.sort({'_id': -1}).limit(25).toArray(function(error, films);
resulting in Error
The correct syntax should be:
collection.find("_id":{$gt: 35}).
The double "" quotes should not be there.
I am inserting json file into Mongodb(with Scala/Play framework) and the same getting/downloading it into my view page for some other requirement, but this time it is coming with one "_id" parameter in the json file.
But I need only my actual json file only that is not having any any "_id" parameter. I have read the Mongodb tutorial, that by default storing it with one _id for any collection document.
Please let me know that how can I get or is there any chance to get my actual json file without any _id in MongoDB.
this is the json result which is storing in database(I don't need that "_id" parameter)
{
"testjson": [{
"key01": "value1",
"key02": "value02",
"key03": "value03"
}],
"_id": 1
}
If you have a look at ReactiveMongo dev guide and to its API, you can see it support projection in a similar way as the MongoDB shell.
Then you can understand that you can do
collection.find(selector = BSONDocument(), projection = BSONDocument("_id" -> 0))
Or, as you are using JSON serialization:
collection.find(selector = Json.obj(), projection = Json.obj("_id" -> 0))
You can use this query in the shell:
db.testtable.find({},{"_id" : false})
Here we are telling mongoDB not to return _id from the collection.
You can also use 0 instead of false, like this:
db.testtable.find({},{"_id" : 0})
for scala you need to convert it in as per the driver syntax.
Just a quick question about something I've just experienced and I'm still thinking about why:
mongos> db.tickets.count({ "idReferenceList" : { "$in" : [ { "$oid" : "53f1f09f2cdcc8f339e5efa2"} , { "$oid" : "5409ae2e2cdc31c5aa0ce0a5"}]}});
0
mongos> db.tickets.count({ "idReferenceList" : { "$in" : [ ObjectId("53f1f09f2cdcc8f339e5efa2") , ObjectId("5409ae2e2cdc31c5aa0ce0a5")]}});
2
I thought that both $oid and ObjectId spelling formats where exactly the same for MongoDB. Does anyone know why with the first query return 0 results and with the second one is returning 2 (the right answer)?
Furthermore, I'm using Morphia framework which uses MongoDB Java driver to interact with MongoDB. I've realised that there exists a problem by searching with $in operator in ObjectIds arrays over fields that are not _id by executing this lines of code:
List< ObjectId > fParams = new ArrayList< ObjectId >();
fParams.add(...);
Query<Ticket> query = genericDAO.createQuery();
query.field("idReferenceList").in(fParams);
result = genericDAO.find(query).asList();
Thank you very much in advance.
Regards,
Luis Cappa
Both these formats are valid representations of an object id in MongoDB, according to the documentation,
http://docs.mongodb.org/manual/reference/mongodb-extended-json/
and they represented differently in the two modes,
Strict Mode mongo Shell Mode
----------- ----------------
{ "$oid": "<id>" } ObjectId( "<id>" )
So, to query fields which contain objectid, from the shell/console mode, you need to use ObjectId("<id>").
Which is the syntax to be followed in the mongo shell mode.
Hence the query:
db.tickets.count({ "idReferenceList" : { "$in" : [ ObjectId("53f1f09f2cdcc8f339e5efa2") , ObjectId("5409ae2e2cdc31c5aa0ce0a5")]}});
would return you row count.
Now to do it via the Java API,
You need to do it as below:
String[] ids = {"53f1f09f2cdcc8f339e5efa2","5409ae2e2cdc31c5aa0ce0a5"};
ObjectId[] objarray = new ObjectId[ids.length];
for(int i=0;i<ids.length;i++)
{
objarray[i] = new ObjectId(ids[i]);
}
BasicDBObject inQuery = new BasicDBObject("$in", objarray);
BasicDBObject query = new BasicDBObject("idReferenceList", inQuery);
DBCursor cursor = db.collection.find(query);
while(cursor.hasNext())
{
DBObject doc = cursor.next();
// process the doc.
}
I faced the same issue.
I resolved like this way.
db.collection('post').find({ 'postIds': { $elemMatch: { $in:
deletedPosts.map(_post => {ObjectId(_post._id)}) } } })
When I have two MongoDB documents like this...
db.test.insert( {"value" : "10123"} );
db.test.insert( {"value" : "160"} );
The result of a query like:
db.test.find({"value" :{$gt : "12"} });
is..
{ "_id" : ObjectId("4c6d1b92304326161b678b89"), "value" : "160" }
It's obvious, that a string comparison is made, so that my first value is not returned.
Is there any way to cast within the query?
Something like:
db.test.find({ (int) "value" :{$gt : 12} });
would be great. A query like
db.test.find({"value" :{$gt : 12} }); // without the quotes around "12"
returns nothing.
You can use the following JavaScript expression:
db.test.find("this.value > 12")
This uses JavaScript's automatic conversion from string to number.
I have a similar workaround, i find that if you can use the mongo shell, you can write an statement to do this in javascript, but capable of using indexes.
var myItems = []
var it = db.test.find({},{value:1})
while (it.hasNext()){
var item = it.next();
if(parseInt(item.value) > 12)
myItems.push(item);
}
If you want this to run faster than previus solution, you have to ensure the index on the value field.
Type casting in MongoDB is available after version >= 4.0. Check MongoDB's aggregation operator $convert and similar operators. Since you wanted to convert string to int you can use $toInt:
db.collection.find({ $expr: { $gt: [ { $toInt: "$value" }, 12 ] } })
Test : mongoplayground
Note :
Here we're converting value which is a string field to int on the fly & Since it got converted to int - we're comparing it to input of type int. Your output documents will still have original type for value field which is string (we're not actually changing type in response docs, if needed use aggregation & it's stage $project to see int values for field value in response docs).
Since we're using aggregation operators in .find() we need to wrap everything in $expr.
Even though this is pretty common nowadays & is easy to do, but remember we're casting string to int on every Read, rather if you can take care of this on Writes or Updates it would be easy & more efficient.
To convert String into int use this
db.test.find({'year': {$type: 2}}).forEach(
function (x) {
x.value=new NumberInt(x.value);
db.test.save(x)}
)
And after that you can directly query like :
db.test.find({"value" :{$gt : 12} });
$gt wasn't set for this use case. You would have to use regex for strings. Probably easier to just create a new field with the number as a number.