Processing mulitiple files line by line in Perl - perl

I'm trying to look for multiple files using glob() and then process each file line by line. When I run this:
my #dir = glob($ARGV[0]);
foreach my $file (#dir){
local $/ = undef;
open (input, "<$file");
while (my $line = <input>){
$line =~ ...
}
close(input);
}
it does open the files, but only works for the first line of every file. It exits the while-loop after just one iteration. Where is the flaw here?

The line local $/ = undef; is your problem. $/ stores the sequence of characters that define the end of a line. By setting it to undef you basically tell perl to read the complete file at once. See perlvar for details.

Related

Perl File Read: multiple lines combined while reading in list context

I am reading a file using the following code:
open ($myfile, "<file.txt") or die "Could not open the file";
#lines = <$myfile>;
foreach $line (#lines){
print $line;
}
close myfile;
The contents of the file are:
Crossroads Blues
Terraplane Blues
Come on in My Kitchen
Walking Blues
Mister Jelly Roll Maker
Last Fair Deal Gone Down
32-20 Blues
Kindhearted Woman Blues
If I Had Possession Over Judgement Day
Preaching Blues
Blind Willie's Blues
When You Got a Good Friend
Rambling on My Mind
Stones in My Passway
Wild Jelly Roll Blues
Traveling Riverside Blues
Roll My Jellyroll
Milkcow's Calf Blues
Me and the Devil Blues
Hellhound on My Trail
But the output of the program is:
Hellhound on My Trailsuesdudgement Day
It looks like the code reads only one line, and replaces the first characters with the new line that is read. I have tried different files. Only one line is printed, which is basically aggregated over all the lines.
Your original file has just a carriage-return (CR) at the end of each line when it should have a linefeed (LF) or possibly both CR and LF if it originated from a Windows system and you are reading it on Linux
Without any newlines to split up the data, #lines has only a single element which contains the entire file contents
Printing that text to the terminal results in all of the lines being displayed on top of one another as you have seen
You need to fix the creation of your file, but in the mean time you can read it correctly by changing Perl's record separator $/ like this
use strict;
use warnings 'all';
open my $fh, '<', 'file.txt' or die "Could not open the file: $!";
my #lines = do {
local $/ = "\r";
<$fh>;
};
chomp #lines;
print "$_\n" for #lines;
Please check your original script and posted script are same.
You did mention the last line is only printing by your example program. It won't. It will print the whole lines.
Always put use warnings; and use strict; in top of the program.
Then storing the whole file into an array then read from an array is a very poor method. Use while loop instead.
open ($myfile, "<","file.txt") or die "Could not open the file";
while(<$myfile>)
{
print ; # Data are store into the default variable $_. So no need to mention the $_ in print statement.
}
The below script will produce the your mentioned output.
foreach (#lines)
{
$line = $_; # this or
#new = $_; # this
}
print $line; #last line
print #new; #last line
If you want to store the particular data into another variable, look at concatenation for string($) and push or unshift for an array(#)

Change line in textfile using perl

I read other places on how to do this but they were confusing for me.
I want to read lines from a text file and when I come across a certain line I want to append something to it.
My code is:
open my $p, "$username_filename" or die "can not open $username_filename: $!";
foreach $line (<$p>){
if ($line =~ /^listen/){
`echo "whatever" >> $username_file`;
}
}
However when I run this I get this error
sh: -c: line 0: syntax error near unexpected token `newline' sh: -c: line 0: `echo "current_user" >> '
Is this way correct to edit the file and why am I getting this error?
Working with files is not like editing in a word processor. Lines are an illusion, a file is just a big string of characters. You can't change a line in the middle of a file for the same reason you can't change a line in the middle of a book, the words can't be moved around to make room.
Instead, like a book, if you want to change something you need to rewrite the whole thing.
The basic algorithm is to...
Open the file for reading.
Open a temporary file for writing.
Read a line, alter the line, write the line.
Repeat 3 until done reading.
Overwrite the file with the temp file.
Some other notes...
print writes to STDOUT by default, but you can give it a filehandle to write to instead.
foreach my $line (<$fh>) is unfortunately not optimized to read files. It will read the possibly enormous file into memory. while(my $line = <$fh>) reads one line at a time.
I've turned on strict. This forces you to declare your variables. It protects you from typos like the one you made of $username_file vs $username_filename.
You could use something like "$filename.tmp" but File::Temp provides temp files that are guaranteed to be temporary, unique and cleaned up when the program exits.
use strict;
use warnings;
use autodie; # because writing 'or die' gets old fast
use File::Temp; # provides safe temp files
my $filename = ...; # set it somehow
open my $read, "<", $filename;
my $temp = File::Temp->new;
while(my $line = <$read>) {
if( $line =~ /^listen/ ) {
chomp $line; # remove the newline
$line .= " whatever\n"; # add our content and put a newline back
}
# Write the line to the temp file
print $temp $line;
}
# Overwrite our file with the rewritten temp file
rename $temp->filename, $filename;
That's inside a program. If you just want to do it quickly, you can do it on the command line with -i and -p.
perl -i.bak -pe 'if( /^listen/ ) { chomp; $_ .= "whatever" }' filename
-p says to run the code on each line of the file. The line will be put into $_ and whatever is in $_ will be printed. -i says to edit the file in place. -i.bak makes a backup of the original file just in case you make a mistake.
There are a few problems with your attempt. The big one is that using echo >> file will append to the file, not insert at some arbitrary place inside the file.
Another problem is that you're trying to append to a file called $username_file, and you haven't declared or defined that variable.
I don't think perl lets you insert into the middle of a file. I think your best bet would be to read the file a line at a time, and on the correct line(s), append the text you want. Write each line to a new file, then swap the files around at the end.
For example:
#!/usr/bin/perl
my $in_filename = "in.txt";
my $out_filename = "out.txt";
open (my $in, "<", $in_filename) or die;
open (my $out, ">", $out_filename) or die;
while (my $lline = <$in>)
{
chomp $lline;
if ( $lline =~ /listen/ )
{
print "$lline whatever\n";
}
else
{
print "$lline\n";
}
}
close $in;
close $out;
rename $in_filename, "$in_filename.original";
rename $out_filename, $in_filename;
I use chomp to remove line endings, because <$in> gives us a line including its line endings, wish otherwise messes up the append.
As always there are many ways to achieve this. I think using sed is probably a better option for this, but you specifically asked how to do it in perl, so perl it is.

Is there an issue with opening filenames provided on the command line through $_?

I'm having trouble modifying a script that processes files passed as command line arguments, merely for copying those files, to additionally modifying those files. The following perl script worked just fine for copying files:
use strict;
use warnings;
use File::Copy;
foreach $_ (#ARGV) {
my $orig = $_;
(my $copy = $orig) =~ s/\.js$/_extjs4\.js/;
copy($orig, $copy) or die(qq{failed to copy $orig -> $copy});
}
Now that I have files named "*_extjs4.js", I would like to pass those into a script that similarly takes file names from the command line, and further processes the lines within those files. So far I am able get a file handle successfully as the following script and it's output shows:
use strict;
use warnings;
foreach $_ (#ARGV) {
print "$_\n";
open(my $fh, "+>", $_) or die $!;
print $fh;
#while (my $line = <$fh>) {
# print $line;
#}
close $fh;
}
Which outputs (in part):
./filetree_extjs4.js
GLOB(0x1a457de8)
./async_submit_extjs4.js
GLOB(0x1a457de8)
What I really want to do though rather than printing a representation of the file handle, is to work with the contents of the files themselves. A start would be to print the files lines, which I've tried to do with the commented out code above.
But that code has no effect, the files' lines do not get printed. What am I doing wrong? Is there a conflict between the $_ used to process command line arguments, and the one used to process file contents?
It looks like there are a couple of questions here.
What I really want to do though rather than printing a representation of the file handle, is to work with the contents of the files themselves.
The reason why print $fh is returning GLOB(0x1a457de8) is because the scalar $fh is a filehandle and not the contents of the file itself. To access the contents of the file itself, use <$fh>. For example:
while (my $line = <$fh>) {
print $line;
}
# or simply print while <$fh>;
will print the contents of the entire file.
This is documented in pelrdoc perlop:
If what the angle brackets contain is a simple scalar variable (e.g.,
<$foo>), then that variable contains the name of the filehandle to
input from, or its typeglob, or a reference to the same.
But it has already been tried!
I can see that. Try it after changing the open mode to +<.
According to perldoc perlfaq5:
How come when I open a file read-write it wipes it out?
Because you're using something like this, which truncates the file
then gives you read-write access:
open my $fh, '+>', '/path/name'; # WRONG (almost always)
Whoops. You should instead use this, which will fail if the file
doesn't exist:
open my $fh, '+<', '/path/name'; # open for update
Using ">" always clobbers or creates. Using "<" never does either. The
"+" doesn't change this.
It goes without saying that the or die $! after the open is highly recommended.
But take a step back.
There is a more Perlish way to back up the original file and subsequently manipulate it. In fact, it is doable via the command line itself (!) using the -i flag:
$ perl -p -i._extjs4 -e 's/foo/bar/g' *.js
See perldoc perlrun for more details.
I can't fit my needs into the command-line.
If the manipulation is too much for the command-line to handle, the Tie::File module is worth a try.
To read the contents of a filehandle you have to call readline read or place the filehandle in angle brackets <>.
my $line = readline $fh;
my $actually_read = read $fh, $text, $bytes;
my $line = <$fh>; # similar to readline
To print to a filehandle other than STDIN you have to have it as the first argument to print, followed by what you want to print, without a comma between them.
print $fh 'something';
To prevent someone from accidentally adding a comma, I prefer to put the filehandle in a block.
print {$fh} 'something';
You could also select your new handle.
{
my $oldfh = select $fh;
print 'something';
select $oldfh; # reset it back to the previous handle
}
Also your mode argument to open, causes it to clobber the contents of the file. At which point there is nothing left to read.
Try this instead:
open my $fh, '+<', $_ or die;
I'd like to add something to Zaid's excellent suggestion of using a one-liner.
When you are new to perl, and trying some tricky regexes, it can be nice to use a source file for them, as the command line may get rather crowded. I.e.:
The file:
#!/usr/bin/perl
use warnings;
use strict;
s/complicated/regex/g;
While tweaking the regex, use the source file like so:
perl -p script.pl input.js
perl -p script.pl input.js > testfile
perl -p script.pl input.js | less
Note that you don't use the -i flag here while testing. These commands will not change the input files, only print the changes to stdout.
When you're ready to execute the (permanent!) changes, just add the in-place edit -i flag, and if you wish (recommended), supply an extension for backups, e.g. ".bak".
perl -pi.bak script.pl *.js

How to open/join more than one file (depending on user input) and then use 2 files simultaneously

EDIT: Sorry for the misunderstanding, I have edited a few things, to hopefully actually request what I want.
I was wondering if there was a way to open/join two or more files to run the rest of the program on.
For example, my directory has these files:
taggedchpt1_1.txt, parsedchpt1_1.txt, taggedchpt1_2.txt, parsedchpt1_2.txt etc...
The program must call a tagged and parsed simultaneously. I want to run the program on both of chpt1_1 and chpt1_2, preferably joined together in one .txt file, unless it would be very slow to do so. For instance run what would be accomplished having two files:
taggedchpt1_1_and_chpt1_2 and parsedchpt1_1_and_chpt1_2
Can this be done through Perl? Or should I just combine the text files myself(or automate that process, making chpt1.txt which would include chpt1_1, chpt1_2, chpt1_3 etc...)
#!/usr/bin/perl
use strict;
use warnings FATAL => "all";
print "Please type in the chapter and section NUMBERS in the form chp#_sec#:\n"; ##So the user inputs 31_3, for example
chomp (my $chapter_and_section = "chpt".<>);
print "Please type in the search word:\n";
chomp (my $search_key = <>);
open(my $tag_corpus, '<', "tagged${chapter_and_section}.txt") or die $!;
open(my $parse_corpus, '<', "parsed${chapter_and_section}.txt") or die $!;
For the rest of the program to work, I need to be able to have:
my #sentences = <$tag_corpus>; ##right now this is one file, I want to make it more
my #typeddependencies = <$parse_corpus>; ##same as above
EDIT2: Really sorry about the misunderstanding. In the program, after the steps shown, I do 2 for loops. Reading through the lines of the tagged and parsed.
What I want is to accomplish this with more files from the same directory, without having to re-input the next files. (ie. I can run taggedchpt31_1.txt and parsedchpt31_1.txt...... I want to run taggedchpt31 and parsedchpt31 - which includes ~chpt31_1, ~chpt31_2, etc...)
Ultimately, it would be best if I joined all the tagged files and all the parsed files that have a common chapter (in the end still requiring only two files I want to run) but not have to save the joined file to the directory... Now that I put it into words, I think I should just save files that include all the sections.
Sorry and Thanks for all your time! Look at FMc's breakdown of my question for more help.
You could iterate over the file names, opening and reading each one in turn. Or you could produce an iterator that knows how to read lines from sequence of files.
sub files_reader {
# Takes a list of file names and returns a closure that
# will yield lines from those files.
my #handles = map { open(my $h, '<', $_) or die $!; $h } #_;
return sub {
shift #handles while #handles and eof $handles[0];
return unless #handles;
return readline $handles[0];
}
}
my $reader = files_reader('foo.txt', 'bar.txt', 'quux.txt');
while (my $line = $reader->()) {
print $line;
}
Or you could use Perl's built-in iterator that can do the same thing:
local #ARGV = ('foo.txt', 'bar.txt', 'quux.txt');
while (my $line = <>) {
print $line;
}
Edit in response to follow-up questions:
Perhaps it would help to break your problem down into smaller sub-tasks. As I understand it, you have three steps.
Step 1 is to get some input from the user -- perhaps a directory name, or maybe a couple of file name patterns (taggedchpt and parsedchpt).
Step 2 is for the program to find all of the relevant file names. For this task, glob() or readdir()might be useful. There are many questions on StackOverflow related to such issues. You'll end up with two lists of file names, one for the tagged files and one for the parsed files.
Step 3 is to process the lines across all of the files in each of the two sets. Most of the answers you have received, including mine, will help you with this step.
No one has mentioned the #ARGV hack yet? Ok, here it is.
{
local #ARGV = ('taggedchpt1_1.txt', 'parsedchpt1_1.txt', 'taggedchpt1_2.txt',
'parsedchpt1_2.txt');
while (<ARGV>) {
s/THIS/THAT/;
print FH $_;
}
}
ARGV is a special filehandle that iterates through all the filenames in #ARGV, closing a file and opening the next one as necessary. Normally #ARGV contains the command-line arguments that you passed to perl, but you can set it to anything you want.
You're almost there... this is a bit more efficient than discrete opens on each file...
#!/usr/bin/perl
use strict;
use warnings FATAL => "all";
print "Please type in the chapter and section NUMBERS in the for chp#_sec#:\n";
chomp (my $chapter_and_section = "chpt".<>);
print "Please type in the search word:\n";
chomp (my $search_key = <>);
open(FH, '>output.txt') or die $!; # Open an output file for writing
foreach ("tagged${chapter_and_section}.txt", "parsed${chapter_and_section}.txt") {
open FILE, "<$_" or die $!; # Read a filename (from the array)
foreach (<FILE>) {
$_ =~ s/THIS/THAT/g; # Regex replace each line in the open file (use
# whatever you like instead of "THIS" &
# "THAT"
print FH $_; # Write to the output file
}
}

perl + how to declares array

the following script (test.pl) append $insert[1] text between $first_line[1] and $second_line[1] on myfile.txt file and send output to output.txt
but if I declare the array as
my $first_line[1]=")";
my $second_line[1]="NIC Hr_Nic (";
my $insert[1]="hello world
line 2
line3 "
I get
syntax error at ./test.pl line 10, near "$first_line["
syntax error at ./test.pl line 11, near "$second_line["
syntax error at ./test.pl line 12, near "$insert["
Execution of ./test.pl aborted due to compilation errors.
how to declare the follwoing arrays?
remark: (without the my on the array the script work fine)
lidia
#!/usr/bin/perl
# Slurp file myfile.txt into a single string
open(FILE,"myfile.txt") || die "Can't open file: $!";
undef $/;
my $file = <FILE>;
# Set strings to find and insert
my $count=1;
my $first_line[1]=")";
my $second_line[1]="NIC Hr_Nic (";
my $insert[1]="hello world
line 2
line 3 " ;
For composite types like arrays and hashes, you only need to declare the composite as a lexical variable:
my #first_line = ...;
From there, you don't need to declare composite elements, like you are doing.
You might start with a book such as Learning Perl to pick up the basics of the language. A little study up front will save you a lot of pain and suffering later.
It looks like you are trying to affect the first couple of lines of a file. In that case, see the answer to How do I change, delete, or insert a line in a file, or append to the beginning of a file?:
How do I change, delete, or insert a line in a file, or append to the beginning of a file?
(contributed by brian d foy)
The basic idea of inserting, changing, or deleting a line from a text file involves reading and printing the file to the point you want to make the change, making the change, then reading and printing the rest of the file. Perl doesn't provide random access to lines (especially since the record input separator, $/, is mutable), although modules such as Tie::File can fake it.
A Perl program to do these tasks takes the basic form of opening a file, printing its lines, then closing the file:
open my $in, '<', $file or die "Can't read old file: $!";
open my $out, '>', "$file.new" or die "Can't write new file: $!";
while( <$in> )
{
print $out $_;
}
close $out;
Within that basic form, add the parts that you need to insert, change, or delete lines.
To prepend lines to the beginning, print those lines before you enter the loop that prints the existing lines.
open my $in, '<', $file or die "Can't read old file: $!";
open my $out, '>', "$file.new" or die "Can't write new file: $!";
print $out "# Add this line to the top\n"; # <--- HERE'S THE MAGIC
while( <$in> )
{
print $out $_;
}
close $out;
To change existing lines, insert the code to modify the lines inside the while loop. In this case, the code finds all lowercased versions of "perl" and uppercases them. The happens for every line, so be sure that you're supposed to do that on every line!
open my $in, '<', $file or die "Can't read old file: $!";
open my $out, '>', "$file.new" or die "Can't write new file: $!";
print $out "# Add this line to the top\n";
while( <$in> )
{
s/\b(perl)\b/Perl/g;
print $out $_;
}
close $out;
To change only a particular line, the input line number, $., is useful. First read and print the lines up to the one you want to change. Next, read the single line you want to change, change it, and print it. After that, read the rest of the lines and print those:
while( <$in> ) # print the lines before the change
{
print $out $_;
last if $. == 4; # line number before change
}
my $line = <$in>;
$line =~ s/\b(perl)\b/Perl/g;
print $out $line;
while( <$in> ) # print the rest of the lines
{
print $out $_;
}
To skip lines, use the looping controls. The next in this example skips comment lines, and the last stops all processing once it encounters either END or DATA.
while( <$in> )
{
next if /^\s+#/; # skip comment lines
last if /^__(END|DATA)__$/; # stop at end of code marker
print $out $_;
}
Do the same sort of thing to delete a particular line by using next to skip the lines you don't want to show up in the output. This example skips every fifth line:
while( <$in> )
{
next unless $. % 5;
print $out $_;
}
If, for some odd reason, you really want to see the whole file at once rather than processing line-by-line, you can slurp it in (as long as you can fit the whole thing in memory!):
open my $in, '<', $file or die "Can't read old file: $!"
open my $out, '>', "$file.new" or die "Can't write new file: $!";
my #lines = do { local $/; <$in> }; # slurp!
# do your magic here
print $out #lines;
Modules such as File::Slurp and Tie::File can help with that too. If you can, however, avoid reading the entire file at once. Perl won't give that memory back to the operating system until the process finishes.
You can also use Perl one-liners to modify a file in-place. The following changes all 'Fred' to 'Barney' in inFile.txt, overwriting the file with the new contents. With the -p switch, Perl wraps a while loop around the code you specify with -e, and -i turns on in-place editing. The current line is in $. With -p, Perl automatically prints the value of $ at the end of the loop. See perlrun for more details.
perl -pi -e 's/Fred/Barney/' inFile.txt
To make a backup of inFile.txt, give -i a file extension to add:
perl -pi.bak -e 's/Fred/Barney/' inFile.txt
To change only the fifth line, you can add a test checking $., the input line number, then only perform the operation when the test passes:
perl -pi -e 's/Fred/Barney/ if $. == 5' inFile.txt
To add lines before a certain line, you can add a line (or lines!) before Perl prints $_:
perl -pi -e 'print "Put before third line\n" if $. == 3' inFile.txt
You can even add a line to the beginning of a file, since the current line prints at the end of the loop:
perl -pi -e 'print "Put before first line\n" if $. == 1' inFile.txt
To insert a line after one already in the file, use the -n switch. It's just like -p except that it doesn't print $_ at the end of the loop, so you have to do that yourself. In this case, print $_ first, then print the line that you want to add.
perl -ni -e 'print; print "Put after fifth line\n" if $. == 5' inFile.txt
To delete lines, only print the ones that you want.
perl -ni -e 'print unless /d/' inFile.txt
... or ...
perl -pi -e 'next unless /d/' inFile.txt
You should use my #first_line = (); to declare a new empty array. You don't have to give a size.
But there are many, many things wrong with the code you posted. For instance, if you only ever have one element, why use an array at all?