read data from chart, ms as x value - charts

i have some trouble with adding pinots to a chart and read them back to an array.
with tis code iam adding a new piont to my chart, y_value is a normal double var
time_stamp is a string with the current daytime (15:56:45:799) with millisecounds
string time_stamp = DateTime.Now.ToLongTimeString() + ":" + DateTime.Now.Millisecond.ToString();
chart_logger.Series[0].Points.AddXY(time_stamp, y_value);
after plotting the chart i want to save alle datapionts in an txt file, so i want the read all points form the chart
i tried it with
DataPoint[] asd = chart_logger.Series[0].Points.ToArray();
it read all the y values from the chart but i the x values are always zero
does someone have any idea
thanks for the help
Ralf

You need to use `ToOADate()' and 'FromOADate(double d)'.
chart_logger.Series[0].XValueType = ChartValueType.DateTime;
chart_logger.ChartAreas[0].AxisX.LabelStyle.Format = "MM/dd/yyyy HH:mm:ss.fff";
chart_logger.Series[0].Points.AddXY(DateTime.Now.ToOADate(), y_value);
DataPoint[] asd = chart_logger.Series[0].Points.ToArray();
var x = DateTime.FromOADate(asd[0].XValue);
Or
chart_logger.Series[0].YValuesPerPoint = 2;
var time = DateTime.Now;
string time_stamp = time.ToLongTimeString() + ":" + time.Now.Millisecond.ToString();
chart_logger.Series[0].Points.AddXY(time_stamp, y_value, time.ToOADate());
DataPoint[] asd = chart_logger.Series[0].Points.ToArray();
var x = DateTime.FromOADate(asd[0].YValues[1]);

Related

Alluvial plot - reorder lodes

I have created an alluvial plot but, for visibility purposes I would like to move one lode in one of the axes: more specifically I would like the "NA" of the "Type of surgery" to be at the top so the last 4 axes are aligned.
This is the code I used on R:
aes(y = ID, axis1 = Reason, axis2 = Response, axis3=Type_of_surgery, axis4=Margins, axis5=RT_post_op, axis6=Chemo_post_op)) +
geom_alluvium(aes(fill = Type_of_surgery), width = 1/12,aes.bind = TRUE) +
geom_flow(aes.bind = TRUE) +
geom_stratum(width = 1/3, fill = "grey", color = "white") +
geom_label(stat = "stratum", aes(label = after_stat(stratum))) +
scale_x_discrete(limits = c("Reason", "Response","Type of surgery", "Margins","RT post op", "Chemo post-op"), expand = c(0.1,0.1)) +
scale_fill_brewer(type = "qual", palette = "Pastel1") +
ggtitle("TBC") ```
This is the plot I obtained:
[Alluvial plot][1]
[1]: https://i.stack.imgur.com/nDCIZ.png
I am beginning on the world of coding so any help would be most welcome,
Thank you all for your help,
JB

How to get value at a point of line extended - TradingView Pine script

Im using the code below to draw a line:
//#version=4
simplesma = sma(close, 14)
var line3 = line.new(bar_index[0], high[0], bar_index, low, extend = extend.right)
line.set_xy1(line3, bar_index[5], simplesma[5])
line.set_xy2(line3, bar_index[3], simplesma[3])
That line has been drawn using 2 points in the history.
And then I use this code to draw a plot
price_point = line.get_price(line3,bar_index)
plot(price_point, title='Price', color=#ffcc00, transp=30)
Im trying to display the value on a label but the following code does not work:
var label3 = label.new(bar_index, high, text = "Value: "+ tostring(price_point, "#.########"), style = label.style_label_lower_left, color=#ffcc00, textcolor=#ff0000)
label.set_xy(label3,bar_index, price_point)
Can you please help me to show it on label ?
The variable price_point is the value at the current bar (bar_index). You don't need to use the function tostring().
Oh I found it.
var label3 = label.new(bar_index, high, text = "", style = label.style_label_lower_left, color=#ffcc00, textcolor=#ff0000)
label.set_xy(label3,bar_index, price_point)
label.set_text(label3, "Value: "+ tostring(price_point, "#.########"))

MATLAB filename separation

In filename "name" like '10_m1_m2_const_m1_waves_20_90_m2_waves_90_20_20200312_213048' I need to separate
'10_m1_m2_const_m1_waves_20_90_m2_waves_90_20' from '20200312_213048'
name_sep = split(name,"_");
sep = '_';
name_join=[name_sep{1,1} sep name_sep{2,1} sep .....];
is not working, because a number of "_" are variable.
So I need to move a file:
movefile([confpath,name(without 20200312_213048),'.config'],[name(without 20200312_213048), filesep, name, '.config']);
Do you have any idea? Thank you!
Maybe you can try regexp to find the starting position for the separation:
ind = regexp(name,'_\d+_\d+$');
name1 = name(1:ind-1);
name2 = name(ind+1:end);
such that
name1 = 10_m1_m2_const_m1_waves_20_90_m2_waves_90_20
name2 = 20200312_213048
Or the code below with option tokens:
name_sep = cell2mat(regexp(name,'(.*)_(\d+_\d+$)','tokens','match'));
which gives
name_sep =
{
[1,1] = 10_m1_m2_const_m1_waves_20_90_m2_waves_90_20
[1,2] = 20200312_213048
}
You can use strfind. Either if you have a key that is always present before or after the point where you want to split the name:
nm = '10_m1_m2_const_m1_waves_20_90_m2_waves_90_20_20200312_213048';
key = 'waves_90_20_';
idx = strfind(nm,key) + length(key);
nm(idx:end)
Or if you know how may _ are in the part that you want to have:
idx = strfind(nm,'_');
nm(idx(end-2)+1:end)
In both cases, the result is:
'20_20200312_213048'
As long as the timestamp is always at the end of the string, you can use strfind and count backwards from the end of the string:
name = '10_m1_m2_const_m1_waves_20_90_m2_waves_90_20_20200312_213048';
udscr = strfind(name,'_');
name_date = name(udscr(end-1)+1:end)
name_meta = name(1:udscr(end-1)-1)
name_date =
'20200312_213048'
name_meta =
'10_m1_m2_const_m1_waves_20_90_m2_waves_90_20'

Convert geographical coordinates using measurements package

I am trying to convert some data with the indicated measurements package, but I'm not succeeding on it.
My data:
Long Lat
62ᵒ36.080 58ᵒ52.940
61ᵒ28.020 54ᵒ59.940
62ᵒ07.571 56ᵒ48.873
62ᵒ04.929 57ᵒ33.605
63ᵒ01.419 60ᵒ30.349
63ᵒ09.555 61ᵒ29.199
63ᵒ43.499 61ᵒ23.590
64ᵒ34.175 62ᵒ30.304
63ᵒ16.342 59ᵒ16.437
60ᵒ55.090 54ᵒ49.269
61ᵒ28.013 54ᵒ59.928
62ᵒ07.868 56ᵒ48.040
62ᵒ04.719 57ᵒ32.120
62ᵒ36.083 58ᵒ51.766
63ᵒ01.644 60ᵒ30.714
64ᵒ33.897 62ᵒ30.772
63ᵒ43.604 61ᵒ23.426
63ᵒ09.288 61ᵒ29.888
63ᵒ16.722 59ᵒ16.204
What I'm trying:
library(measurements)
library(readxl)
coord = read.table('coord_converter.txt', header = T, stringsAsFactors = F)
# change the degree symbol to a space
lat = gsub('°','', coord$Lat)
long = gsub('°','', coord$Long)
# convert from decimal minutes to decimal degrees
lat = measurements::conv_unit(lat, from = 'deg_dec_min', to = 'dec_deg')
long = measurements::conv_unit(long, from = 'deg_dec_min', to = 'dec_deg')
What I'm getting with this penultimate line:
Warning messages:
In split(as.numeric(unlist(strsplit(x, " "))) * c(3600, 60), f = rep(1:length(x), : NAs introduced by coercion
In as.numeric(unlist(strsplit(x, " "))) * c(3600, 60) : longer object length is not a multiple of shorter object length
In split.default(as.numeric(unlist(strsplit(x, " "))) * c(3600, : data length is not a multiple of split variable
Can someone point my mistake or make a suggestion of how to proceed?
Thank you!
I think the issue here was that after gsub call, degrees and minutes were not space delimited, as required by measurements::conv_unit.
For example, this works fine (for this reproducible example I also changed "ᵒ" to "°"):
library(measurements)
#read your data
txt <-
"Long Lat
62°36.080 58°52.940
61°28.020 54°59.940
62°07.571 56°48.873
62°04.929 57°33.605
63°01.419 60°30.349
63°09.555 61°29.199
63°43.499 61°23.590
64°34.175 62°30.304
63°16.342 59°16.437
60°55.090 54°49.269
61°28.013 54°59.928
62°07.868 56°48.040
62°04.719 57°32.120
62°36.083 58°51.766
63°01.644 60°30.714
64°33.897 62°30.772
63°43.604 61°23.426
63°09.288 61°29.888
63°16.722 59°16.204"
coord <- read.table(text = foo, header = TRUE, stringsAsFactors = F)
# change the degree symbol to a space
lat = gsub('°',' ', coord$Lat)
long = gsub('°',' ', coord$Long)
# convert from decimal minutes to decimal degrees
lat = measurements::conv_unit(lat, from = 'deg_dec_min', to = 'dec_deg')
long = measurements::conv_unit(long, from = 'deg_dec_min', to = 'dec_deg')
yields...
> cbind(long, lat)
long lat
[1,] "62.6013333333333" "58.8823333333333"
[2,] "61.467" "54.999"
[3,] "62.1261833333333" "56.81455"
[4,] "62.08215" "57.5600833333333"
[5,] "63.02365" "60.5058166666667"
[6,] "63.15925" "61.48665"
[7,] "63.7249833333333" "61.3931666666667"
[8,] "64.5695833333333" "62.5050666666667"
[9,] "63.2723666666667" "59.27395"
[10,] "60.9181666666667" "54.82115"
[11,] "61.4668833333333" "54.9988"
[12,] "62.1311333333333" "56.8006666666667"
[13,] "62.07865" "57.5353333333333"
[14,] "62.6013833333333" "58.8627666666667"
[15,] "63.0274" "60.5119"
[16,] "64.56495" "62.5128666666667"
[17,] "63.7267333333333" "61.3904333333333"
[18,] "63.1548" "61.4981333333333"
[19,] "63.2787" "59.2700666666667"

Swift 3 - To the power of (pow) function not working as expected

Please could somebody help me. I am trying to run a simple compounding calculation in Swift.
Formula I am trying to recreate:
T = P(1+r/n)^(n*t), where
T = Total, P = Starting amount, r = interest rate, n = number of times compounded and t = number of years
My code as follows:
import Darwin
var total: Double
var startingAmount: Double = 5000.00
var interestRate: Double = 0.05
var numberOfTimesCompounded: Double = 4.0
var numberOfYears: Double = 2.0
var totalYear1: Double
var toThePowerOf: Double
totalYear1 = startingAmount * (1 + interestRate / numberOfTimesCompounded)
toThePowerOf = numberOfTimesCompounded * number of years
total = pow(totalYear1,toThePowerOf)
The answer to the formula should be 5,522.43
In my code above, TotalYear1 = 5062.50 (which is correct) and toThePowerOf = 8.0 (which is correct) However, total shows = 4314398832739892000000.00 which clearly isn't right. Could anyone tell me what I am doing wrong with my calculation of total?
Many thanks
You've actually implemented T = (P(1+r/n))^(n*t), which doesn't even make dimensional sense.
startingAmount needs to be multiplied at the end, it can't be part of the pow:
totalYear1 = (1 + interestRate / numberOfTimesCompounded)
toThePowerOf = numberOfTimesCompounded * number of years // [sic]
total = startingAmount * pow(totalYear1,toThePowerOf)