So I have had an issue for a while now and thought it was worth the time to ask the more experienced regex guys if there was a way to fix this issue with a quick search and replace.
So i use a tool which generates java code(not written in java or I would manually fix the cause directly), however, it has an issue calling variables before an object is created.
This always occurs only once per object, but not for every object, the object name is unknown, and the error is always the line directly before the constructor is called. This is the format the error is always in:
this.unknownObjectName.mirror = true;
this.unknownObjectName = new Model(unknown, parameter, values);
I know there should be a trick to fix this, as a simple string replace simply will not work since 'unknownObjectName' is unknown.
Would this even be possible with regex, if so, please enlighten me :)
This is how the code SHOULD read:
this.unknownObjectName = new Model(unknown, parameter, values);
this.unknownObjectName.mirror = true;
For complex models, this error may happen hundreds of times, so this will indeed save a lot of time. That and I would rather walk on hot coals then do mindless busy work like fixing all these manually :)
Edit:
I through together a java app that does the job.
public static void main(String args[]){
File file = new File(args[0]);
File file2 = new File(file.getParentFile(), "fixed-" + file.getName());
try {
if(file2.exists()) {
file2 = new File(file.getParentFile(), "fixed-" + System.currentTimeMillis() + "-" + file.getName());
}
BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(file)));
BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(new FileOutputStream(file2)));
String line, savedline = null, lastInitVar = "";
while((line = br.readLine()) != null){
if(line.contains("= new ")){
String varname = line.substring(0, line.indexOf("=")).trim();
lastInitVar = varname;
}else if(line.contains(".mirror")){
String varname = line.substring(0, line.indexOf(".mirror")).trim();
if(!lastInitVar.equals(varname)){
savedline = line;
continue;
}
}else if(savedline != null && savedline.contains(lastInitVar)){
bw.write(savedline + "\n");
savedline = null;
}
bw.write(line + "\n");
}
bw.flush();
bw.close();
br.close();
} catch (Exception e) {
e.printStackTrace();
}
}
Over thinking it
Write a program to read line by line and when you see a object access before a constructor don't write it out, write out the next line and then write out the buffered line, rinse repeat.
Some people, when confronted with a problem, think "I know, I'll use
regular expressions." Now they have two problems. - Jamie Zawinski
Regular Expressions are for matching patterns not state based logic.
Related
Why am I getting this error? I'm trying to extract information from a bank statement PDF and tally different bills for the month. I write the data from a PDF to a text file so I can get specific data from the file (e.g. ASPEN HOME IMPRO, then iterate down to what the dollar amount is, then read that text line to a string)
When the Files.readAllLines(Path.get("bankData").get(0) code is run, I get the error. Any thoughts why? Encoding issue?
Here is the code:
public static void main(String[] args) throws IOException {
File file = new File("C:\\Users\\wmsai\\Desktop\\BankStatement.pdf");
PDFTextStripper stripper = new PDFTextStripper();
BufferedWriter bw = new BufferedWriter(new FileWriter("bankData"));
BufferedReader br = new BufferedReader(new FileReader("bankData"));
String pdfText = stripper.getText(Loader.loadPDF(file)).toUpperCase();
bw.write(pdfText);
bw.flush();
bw.close();
LineNumberReader lineNum = new LineNumberReader(new FileReader("bankData"));
String aspenHomeImpro = "PAYMENT: ACH: ASPEN HOME IMPRO";
String line;
while ((line = lineNum.readLine()) != null) {
if (line.contains(aspenHomeImpro)) {
int lineNumber = lineNum.getLineNumber();
int newLineNumber = lineNumber + 4;
String aspenData = Files.readAllLines(Paths.get("bankData")).get(0); //This is the code with the error
System.out.println(newLineNumber);
break;
} else if (!line.contains(aspenHomeImpro)) {
continue;
}
}
}
So I figured it out. I had to check the properties of the text file in question (I'm using Eclipse) to figure out what the actual encoding of the text file was.
Then, when creating the file in the program, encode the text file to UTF-8 so that Files.readAllLines could read and grab the data I wanted to get.
I'm trying to write the text from the URL to a text file in batches of 35 lines, pushing enter to continue to the next batch of 35 lines. If I don't try and write to the file in batches of 35 lines it works great and writes all of the content to the text file. But when I try and use the if statement to print in batches of 35 it won't print to the file unless I push enter around 15 times. And even then it doesn't print everything. I seems like it has something to do with the if statement but I can't figure it out.
String urlString = "https://www.gutenberg.org/files/46768/46768-0.txt";
try {
URL url = new URL(urlString);
try(Scanner input = new Scanner(System.in);
InputStream stream = url.openStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(stream));
BufferedWriter writer = new BufferedWriter(new FileWriter("C:\\Users\\mattj\\Documents\\JuliusCeasar.txt"));) {
String line;
int PAGE_LENGTH = 35;
int lineCount = 0;
while ((line = reader.readLine()) != null) {
System.out.println(line);
writer.write(line + "\n");
lineCount++;
if (lineCount == PAGE_LENGTH){
System.out.println();
System.out.println("- - - Press enter to continue - - -");
input.nextLine();
lineCount = 0;
}
}
}
} catch (MalformedURLException e) {
System.out.println("We encountered a problem regarding the following URL:\n"
+ urlString + "\nEither no legal protocol could be found or the "
+ "string could not be parsed.");
e.printStackTrace();
} catch (IOException e) {
System.out.println("Attempting to open a stream from the following URL:\n"
+ urlString + "\ncaused a problem.");
e.printStackTrace();
}
I don't know Java, but there's very similar concepts in .NET. I think there's a couple of things to consider here.
BufferWriter will not write to the file immediately, it acts - as the name suggests - as a buffer, collecting up write requests over time then doing it in batch. BufferWriter has a flush method to flush the 'queued' up writes to the file immediately - so I'd do this when you hit your 35 (never flush on every write).
Also, BufferedReader and BufferedWriter are closable, so ensure to wrap them in a try statement to make sure resources are properly unlocked/cleared.
I've created a custom Magic command with the intention of generating a spark query programatically. Here's the relevant part of my class that implements the MagicCommandFunctionality:
MagicCommandOutcomeItem execute(MagicCommandExecutionParam magicCommandExecutionParam) {
// get the string that was entered:
String input = magicCommandExecutionParam.command.substring(MAGIC.length())
// use the input to generate a query
String generatedQuery = Interpreter.interpret(input)
MIMEContainer result = Text(generatedQuery);
return new MagicCommandOutput(MagicCommandOutcomeItem.Status.OK, result.getData().toString());
}
This works splendidly. It returns the command that I generated. (As text)
My question is -- how do I coerce the notebook into evaluating that value in the cell? My guess is that a SimpleEvaluationObject and TryResult are involved, but I can't find any examples of their use
Rather than creating the MagicCommandOutput I probably want the Kernel to create one for me. I see that the KernelMagicCommand has an execute method that would do that. Anyone have any ideas?
Okay, I found one way to do it. Here's my solution:
You can ask the current kernelManager for the kernel you're interested in,
then call PythonEntryPoint.evaluate. It seems to do the job!
#Override
MagicCommandOutcomeItem execute(MagicCommandExecutionParam magicCommandExecutionParam) {
String input = magicCommandExecutionParam.command.substring(MAGIC.length() + 1)
// this is the Scala code I want to evaluate:
String codeToExecute = <your code here>
KernelFunctionality kernel = KernelManager.get()
PythonEntryPoint pep = kernel.getPythonEntryPoint(SCALA_KERNEL)
pep.evaluate(codeToExecute)
pep.getShellMsg()
List<Message> messages = new ArrayList<>()
//until there are messages on iopub channel available collect them into response
while (true) {
String iopubMsg = pep.getIopubMsg()
if (iopubMsg == "null") break
try {
Message msg = parseMessage(iopubMsg) //(I didn't show this part)
messages.add(msg)
String commId = (String) msg.getContent().get("comm_id")
if (commId != null) {
kernel.addCommIdManagerMapping(commId, SCALA_KERNEL)
}
} catch (IOException e) {
log.error("There was an error: ${e.getMessage()}")
return new MagicKernelResponse(MagicCommandOutcomeItem.Status.ERROR, messages)
}
}
return new MagicKernelResponse(MagicCommandOutcomeItem.Status.OK, messages)
}
I'm in need of storing a string in JCR that'll be used in an OSGi bundle(so that it can be modified as needed in CRXde)
I have stored my string at the location /etc/designs/shc/components/linkcheck/regex.txt/jcr:content, where regex.txt is the file that contains my regex string.
I'm using the following code to read that String in a bundle but with no luck. It is throwing NullPointerException at resourceResolver.getResource
Resource dataResource = resourceResolver.getResource("/etc/designs/shc/components/linkcheck/regex.txt/jcr:content");
Node node = dataResource.adaptTo(Node.class);
String regex = node.getProperty("jcr:data").getValue().toString();
regex.txt is of type nt:file and the data is visible in CRXde but the code fails.
Any direction will be highly appreciated!
this should work-
Resource dataResource = resourceResolver.getResource("/etc/designs/shc/components/linkcheck/regex.txt");
Node jcnode = dataResource.adaptTo(Node.class).getNode("jcr:content");
InputStream is = jcnode.getProperty("jcr:data").getBinary().getStream();
StringBuilder sb = new StringBuilder();String line;
try {
br = new BufferedReader(new InputStreamReader(is));
while ((line = br.readLine()) != null) {
sb.append(line);
}
} catch (IOException e) {
//do something
}
//do whatever with sb
Since the NullPointerException is thrown at resourceResolver.getResource(...), please check the resourceResolver is not null.
I am new in this superb place. I got help several times from this site. I have seen many answers regarding my question that was previously discussed but i am facing problem to count the number of characters using FileReader. It's working using Scanner. This is what i tried:
class CountCharacter
{
public static void main(String args[]) throws IOException
{
File f = new File("hello.txt");
int charCount=0;
String c;
//int lineCount=0;
if(!f.exists())
{
f.createNewFile();
}
BufferedReader br = new BufferedReader(new FileReader(f));
while ( (c=br.readLine()) != null) {
String s = br.readLine();
charCount = s.length()-1;
charCount++;
}
System.out.println("NO OF LINE IN THE FILE, NAMED " +f.getName()+ " IS " +charCount);
}
}`
It looks to me that each time you go through the loop, you assign the charCount to be the length of the line that iteration of the loop is concerned with. i.e. instead of
charCount = s.Length() -1;
try
charCount = charCount + s.Length();
EDIT:
If you have say the document with the contents "onlyOneLine"
Then when you first hit the while check the br.readLine() will make the BufferredReader read the first line, during the while's code block however br.readLine() is called again which advances the BufferredReader to the second line of the document, which will return null. As null is assigned to s, and you call length(), then NPE is thrown.
try this for the while block
while ( (c=br.readLine()) != null) {
charCount = charCount + c.Length(); }