Rich enumeration with iteration in Scala - scala

I am trying to implement a Rich enumeration in Scala, where my enumeration would also have to implement for example a trait.
This work fine, however when I tried to iterate the enumerations, the Enumeration.values returns a ValueSet, which is a collection of Enumeration.Value
Is there a simple way to implement this feature, without going to macros and sealed traits are suggested from Travis Brown Iteration over a sealed trait in Scala? ?

Enumeration in scala can be done relatively easy with an Enumeration class. Below is an example of it.
trait Num {
def echo
}
object Status extends Enumeration {
case class StatusVal(code: Int, name: String) extends Val with Num {
override def echo {
println("Number: " + name)
}
}
val ONE = StatusVal(1, "One")
val TWO = StatusVal(2, "Two")
val THREE = StatusVal(2, "Three")
}
Status.values foreach (s => s.asInstanceOf[Num].echo)

You may have to convert first:
Enumeration and mapping with Scala 2.10
I guess both answers there are relevant, but I'd totally forgotten mine.
This thread
https://groups.google.com/d/msg/scala-internals/8RWkccSRBxQ/snNuzjJakhkJ
might mark the start of the long road to the enum replacement. It contains a few divergent (pun alert) opinions on usage.
Early stop on the road:
https://stackoverflow.com/a/4346618/1296806

Have you tried implicit conversions? Remember to keep the scope tight:
// I have deliberated stolen #cyrillk example :).
// Just add this line to the body os Status (Enumeration Object)
implicit def valueToNum(v: Value): Num = v.asInstanceOf[Num]
Value will be implicit cast to Num, so:
Status.values foreach (s => s.echo) // works!
Working Example
Chek out a Better example by Sean Ross.

Related

How to normalise a Union Type (T | Option[T])?

I have the following case class:
case class Example[T](
obj: Option[T] | T = None,
)
This allows me to construct it like Example(myObject) instead of Example(Some(myObject)).
To work with obj I need to normalise it to Option[T]:
lazy val maybeIn = obj match
case o: Option[T] => o
case o: T => Some(o)
the type test for Option[T] cannot be checked at runtime
I tried with TypeTest but I got also warnings - or the solutions I found look really complicated - see https://stackoverflow.com/a/69608091/2750966
Is there a better way to achieve this pattern in Scala 3?
I don't know about Scala3. But you could simply do this:
case class Example[T](v: Option[T] = None)
object Example {
def apply[T](t: T): Example[T] = Example(Some(t))
}
One could also go for implicit conversion, regarding the specific use case of the OP:
import scala.language.implicitConversions
case class Optable[Out](value: Option[Out])
object Optable {
implicit def fromOpt[T](o: Option[T]): Optable[T] = Optable(o)
implicit def fromValue[T](v: T): Optable[T] = Optable(Some(v))
}
case class SomeOpts(i: Option[Int], s: Option[String])
object SomeOpts {
def apply(i: Optable[Int], s: Optable[String]): SomeOpts = SomeOpts(i.value, s.value)
}
println(SomeOpts(15, Some("foo")))
We have a specialized Option-like type for this purpose: OptArg (in Scala 2 but should be easily portable to 3)
import com.avsystem.commons._
def gimmeLotsOfParams(
intParam: OptArg[Int] = OptArg.Empty,
strParam: OptArg[String] = OptArg.Empty
): Unit = ???
gimmeLotsOfParams(42)
gimmeLotsOfParams(strParam = "foo")
It relies on an implicit conversion so you have to be a little careful with it, i.e. don't use it as a drop-in replacement for Option.
The implementation of OptArg is simple enough that if you don't want external dependencies then you can probably just copy it into your project or some kind of "commons" library.
EDIT: the following answer is incorrect. As of Scala 3.1, flow analysis is only able to check for nullability. More information is available on the Scala book.
I think that the already given answer is probably better suited for the use case you proposed (exposing an API can can take a simple value and normalize it to an Option).
However, the question in the title is still interesting and I think it makes sense to address it.
What you are observing is a consequence of type parameters being erased at runtime, i.e. they only exist during compilation, while matching happens at runtime, once those have been erased.
However, the Scala compiler is able to perform flow analysis for union types. Intuitively I'd say there's probably a way to make it work in pattern matching (as you did), but you can make it work for sure using an if and isInstanceOf (not as clean, I agree):
case class Example[T](
obj: Option[T] | T = None
) {
lazy val maybeIn =
if (obj.isInstanceOf[Option[_]]) {
obj
} else {
Some(obj)
}
}
You can play around with this code here on Scastie.
Here is the announcement from 2019 when flow analysis was added to the compiler.

Map an instance using function in Scala

Say I have a local method/function
def withExclamation(string: String) = string + "!"
Is there a way in Scala to transform an instance by supplying this method? Say I want to append an exclamation mark to a string. Something like:
val greeting = "Hello"
val loudGreeting = greeting.applyFunction(withExclamation) //result: "Hello!"
I would like to be able to invoke (local) functions when writing a chain transformation on an instance.
EDIT: Multiple answers show how to program this possibility, so it seems that this feature is not present on an arbitraty class. To me this feature seems incredibly powerful. Consider where in Java I want to execute a number of operations on a String:
appendExclamationMark(" Hello! ".trim().toUpperCase()); //"HELLO!"
The order of operations is not the same as how they read. The last operation, appendExclamationMark is the first word that appears. Currently in Java I would sometimes do:
Function.<String>identity()
.andThen(String::trim)
.andThen(String::toUpperCase)
.andThen(this::appendExclamationMark)
.apply(" Hello "); //"HELLO!"
Which reads better in terms of expressing a chain of operations on an instance, but also contains a lot of noise, and it is not intuitive to have the String instance at the last line. I would want to write:
" Hello "
.applyFunction(String::trim)
.applyFunction(String::toUpperCase)
.applyFunction(this::withExclamation); //"HELLO!"
Obviously the name of the applyFunction function can be anything (shorter please). I thought backwards compatibility was the sole reason Java's Object does not have this.
Is there any technical reason why this was not added on, say, the Any or AnyRef classes?
You can do this with an implicit class which provides a way to extend an existing type with your own methods:
object StringOps {
implicit class RichString(val s: String) extends AnyVal {
def withExclamation: String = s"$s!"
}
def main(args: Array[String]): Unit = {
val m = "hello"
println(m.withExclamation)
}
}
Yields:
hello!
If you want to apply any functions (anonymous, converted from methods, etc.) in this way, you can use a variation on Yuval Itzchakov's answer:
object Combinators {
implicit class Combinators[A](val x: A) {
def applyFunction[B](f: A => B) = f(x)
}
}
A while after asking this question, I noticed that Kotlin has this built in:
inline fun <T, R> T.let(block: (T) -> R): R
Calls the specified function block with this value as its argument and returns
its result.
A lot more, quite useful variations of the above function are provided on all types, like with, also, apply, etc.

Trouble with constructors in Scala

It's been a while since I've used constructors at all- so naturally when I have to use one in Scala I'm having trouble.
I want to do the following: When I create a new class without passing through anything- it creates an empty vector.
Otherwise if it passes through a vector- we use that vector and define it to be used with the class.
How do I do this? I previously had
Class example{
val a: Vector[int] = Vector();
Then I'm lost. I was thinking of doing something like
Class example{
val a: Vector[Int] = Vector()
def this(vector: Vector[Int]){
this{
a = vector
}
}
But I'm getting tons of errors. Can anyone help? I'm trying to find my scala book but I can't find it- I know it had a good section on constructors.
Sounds like you want a constructor with a default argument:
class example(val a : Vector[Int] = Vector())
If you really want to do this by constructor overloading, it looks like this:
class Example(val a: Vector[Int]) {
def this() = this(Vector())
}
Personal-opinion addendum: Overloading and default arguments are often good to avoid. I'd recommend just making a different function that calls the constructor:
class Example(val a: Vector[Int])
object Example {
def empty = new Example(Vector())
}
case class Example(a: Vector[Int] = Vector())
No need to put the val keyword.
Also, using the case keywork you get:
a compact initialisation syntax: Example(Vector(1,2)), instead of new Example(Vector(1,2))
pattern matching for you class
equality comparisons implicitly defined and pretty toString
Reference

Generic synchronisation design

We are building some sync functionality using two-way json requests and this algorithm. All good and we have it running in prototype mode. Now I am trying to genericise the code, as we will be synching for several tables in the app. It would be cool to be able to define a class as "extends Synchable" and get the additional attributes and sync processing methods with a few specialisations/overrides. I have got this far:
abstract class Synchable [T<:Synchable[T]] (val ruid: String, val lastSyncTime: String, val isDeleted:Int) {
def contentEquals(Target: T): Boolean
def updateWith(target: T)
def insert
def selectSince(clientLastSyncTime: String): List[T]
def findByRuid(ruid: String): Option[T]
implicit val validator: Reads[T]
def process(clientLastSyncTime: String, updateRowList: List[JsObject]) = {
for (syncRow <- updateRowList) {
val validatedSyncRow = syncRow.validate[Synchable]
validatedSyncRow.fold(
valid = { result => // valid row
findByRuid(result.ruid) match { //- do we know about it?
case Some(knownRow) => knownRow.updateWith(result)
case None => result.insert
}
}... invalid, etc
I am new to Scala and know I am probably missing things - WIP!
Any pointers or suggestions on this approach would be much appreciated.
Some quick ones:
Those _ parameters you pass in and then immediately assign to vals: why not do it in one hit? e.g.
abstract class Synchable( val ruid: String = "", val lastSyncTime: String = "", val isDeleted: Int = 0) {
which saves you a line and is clearer in intent as well I think.
I'm not sure about your defaulting of Strings to "" - unless there's a good reason (and there often is), I think using something like ruid:Option[String] = None is more explicit and lets you do all sorts of nice monad-y things like fold, map, flatMap etc.
Looking pretty cool otherwise - the only other thing you might want to do is strengthen the typing with a bit of this.type magic so you'll prevent incorrect usage at compile-time. With your current abstract class, nothing prevents me from doing:
class SynchableCat extends Synchable { ... }
class SynchableDog extends Synchable { ... }
val cat = new SynchableCat
val dog = new SynchableDog
cat.updateWith(dog) // This won't end well
But if you just change your abstract method signatures to things like this:
def updateWith(target: this.type)
Then the change ripples down through the subclasses, narrowing down the types, and the compiler will omit a (relatively clear) error if I try the above update operation.

Chaining logging with a simple expression in Scala

I usually use Scala with SLF4J through the Loggable wrapper in LiftWeb. This works decently well with the exception of the quite common method made up only from 1 chain of expressions.
So if you want to add logging to such a method, the simply beautiful, no curly brackets
def method1():Z = a.doX(x).doY(y).doZ()
must become:
def method1():Z = {
val v = a.doX(x).doY(y).doZ()
logger.info("the value is %s".format(v))
v
}
Not quite the same, is it? I gave it a try to solve it with this:
class ChainableLoggable[T](val v:T){
def logInfo(logger:Logger, msg:String, other:Any*):T = {
logger.info(msg.format(v, other))
v
}
}
implicit def anyToChainableLogger[T](v:T):ChainableLoggable[T] = new ChainableLoggable(v)
Now I can use a simpler form
def method1():Z = a.doX(x).doY(y).doZ() logInfo(logger, "the value is %s")
However 1 extra object instantiation and an implicit from Any starts to look like a code stink.
Does anyone know of any better solution? Or maybe I shouldn't even bother with this?
Scala 2.10 has just a solution for you - that's a new feature Value Class which allows you to gain the same effect as the implicit wrappers provide but with no overhead coming from instantiation of those wrapper classes. To apply it you'll have to rewrite your code like so:
implicit class ChainableLoggable[T](val v : T) extends AnyVal {
def logInfo(logger:Logger, msg:String, other:Any*) : T = {
logger.info(msg.format(v, other))
v
}
}
Under the hood the compiler will transform the logInfo into an analogue of Java's common "util" static method by prepending your v : T to it's argument list and updating its usages accordingly - see, nothing gets instantiated.
That looks like the right way to do it, especially if you don't have the tap implicit around (not in the standard library, but something like this is fairly widely used--and tap is standard in Ruby):
class TapAnything[A](a: A) {
def tap(f: A => Any): A = { f(a); a }
}
implicit def anything_can_be_tapped[A](a: A) = new TapAnything(a)
With this, it's less essential to have the info implicit on its own, but if you use it it's an improvement over
.tap(v => logger.info("the value is %s".format(v)))
If you want to avoid using implicits, you can define functions like this one in your own logging trait. Maybe not as pretty as the solution with implicits though.
def info[A](a:A)(message:A=>String) = {
logger.info(message(a))
a
}
info(a.doX(x).doY(y).doZ())("the value is " + _)