I have a question about the wrappers/accordeons. I now have multiple wrappers and in each wrapper there is a form. Now, I want one sendbutton on the end of the page. The sendbutton which will send all the forms that have been filled in at once.
How can I do that?
I don't know why you want to break input into different forms and then submit them again at once. Would it not make sense to use one form and submit the data and process it the way you want using the processFormData hook? may be because you want the accordion to group you form fields. Let me help you this way:
Create your form in the format shown below. Make sure the form has a tabless layout to be able to use fieldsets.
Create a fieldset without a label. You may add the class ce_accordion just in case you have some styling attached to it.
Create a field of type html and add the following markup.
<div class="toggler">Form 1 headline here</div>
Create another field with the following markup
<div class="toggler">
Now create your input fields from here. for example a text field,textares.
Create a field of type html to close html markup created in step 3
</div>
Create a fieldset wrapper end here.
The above steps can be repeated as many as how many groups of fields you want to create in an accordion.
Now create you submit button here and it will send all your data the way you want.
Just a by the way:
If some one submits a form in a wrapper that is closed, how will he know which wrapper has error fields?
$(document).ready(function() {
$(".ce_accordion").each(function(index,el) {
if($(this).find("p.error")){
$(this).addClass("hasErrors");
$(this).find("div.toggler").addClass("active").attr("aria-expanded","true");
}
});
});
You can now add a style for .hasErrors rule
Related
I want to create a validator for an angular2 form that involves several controls. So far, all I have found is how to create validators for controls inside a form, in an isolated way, like this:
this.myControl = new FormControl('',Validators.Required);
but I didn't find any example of a validator that involves the state of several controls at the same time.
To explain my case, here is a simple example.
In this example, what I want is:
IF the checkbox is selected, I want the two input boxes to be NOT REQUIRED.
IF the checbox is NOT selected, I want the two input boxes to be REQUIRED.
I could to this programmatically, but I wanted to know if there is an elegant solution that involves validators at a form level, not only at FormControl level.
I am building a multi-step application form with React. Having first built it with pure internal state I am now in the process of refactoring to Redux using redux-form.
Having used the example here as a basis: http://redux-form.com/5.2.5/#/examples/wizard?_k=oftw7a we have come a good way.
However the problem appears when i have two forms which are supposed to have the same value. During one of the pages i have a name field, that is supposed to be duplicated on the name field of the next page. The opposite should happen if you go back from the last page. Any tips to how this could be achieved?
Using the wizard, you are basically working with the exact same form that's split into multiple pieces. Ultimately it's the same form, because redux-form tracks them by name. It is how the library identifies the pieces of the same form - using the name.
form: 'wizard',
Here you can see that the exact same instance of the form will be shared throughout the pieces. fields work in a similar manner. Each field is defined as part of a form.
As long as you use the same field constants inside the fields object that you pass into the reduxForm function and as long as the value for form is the same, so that they use the same underlying form object, it should work for you just fine.
On one page you should pass in
export default reduxForm({
form: 'wizard',
fields : {
'fieldIWantOnBothPartsOfTheForm',
'someOtherFieldThatShouldOnlyBeHere',
},
...
And then on the other page:
export default reduxForm({
form: 'wizard',
fields : {
'fieldIWantOnBothPartsOfTheForm',
'thirdFieldHere',
},
...
Also, make sure you keep destroyOnUnmount equal to false if you want to navigate back-and-forth.
Hope that helps.
I'm looking for a way to have a button toggeling the field of my form. When "locking" the form with the toggle button no data can be typed. When "unlocking" data should be allowed to be typed. What I want to achieve with this is simple avoiding users to accidentally type.
I found the code below and it works. Only problem is that it only applies to one input field. I want it to work on more that one.
<input type="checkbox" id="yourBox">
<input type="text" id="yourText">
<script>
document.getElementById('yourBox').onchange = function() {
document.getElementById('yourText').disabled = this.checked;
};
</script>
Mark the fields you want to disable with a CSS class, and then use jQuery to disable them.
jQuery - Disable Form Fields
If you want a pure Javascript solution, just repeat this line
document.getElementById('yourText').disabled = this.checked;
for each field.
Or, you can do something like this this: How to Get Element By Class in JavaScript?. Note that you can assign multiple CSS classes to the same field, so assign another class to identify those fields that need to be disabled.
I want to be able to format a field in Joomla. I'm creating a form that has a number of inputs and I want to format the inputs to have a yellow background and be of various lengths. Currently my form is produced in the standard Joomla way:
<div class="tablecol1">
<?php echo $this->form->getLabel('dob'); ?>:
</div>
<div class="tablecol2">
<?php echo $this->form->getInput('dob'); ?>
</div>
I've looked through the JForm stuff but I can't figure out how to control the format of the generated input box?
help would be great thanks
Setting a class for the inputs would be the quickest and easiest way as mentioned by MasterAM. You can then style it however you wish using CSS.
If you need to change the HTML or particular attributes that are not possible to set through the default parameters, then the next option is to create your own field type.
You can either override the existing ones or create ones with new names. For example you could copy the checkbox field (/library/joomla/form/fields/checkbox.php) into your own folder (/components/com_mycomponent/form/fields).
If you leave it as JFormFieldCheckbox it will override the default one. If you rename it - e.g. JFormFieldCustomCheckbox then you can have your own one.
The primary function you will want to look at is getInput(). This generates the HTML and will let you create your own input html with whatever attributes you wish.
To use custom attributes/settings from your form xml file, in your getInput() function you will use something like:
$fieldsize = $this->element['field_size'];
I have divided form in to two sections: sec1 and sec2. Each section is part of a div named as sec1Div and sec2Div. Based upon some selection one of div is hidden. But the problem is that still fields in hidden section are submitted. Please suggest a way so that all of fields in a div are not submitted on submit.
There are several ways to do that. You can hook a function to the form submit's event, or you can remove the name attributes of the fields inside the hidden div. You can also disable the fields, by setting disabled="disabled".
If you are using jQuery, you can do those examples.
To disable all fields in the hidden div, you can do something like:
function hideDiv(el) {
$('input', el).each(function(){
$(this).attr('disabled', 'disabled');
});
$(el).hide();
}
And, the appropriate show div function:
function showDiv(el) {
$('input', el).each(function(){
$(this).removeAttr('disabled');
});
$(el).show();
}
Please remind that this is just a code example. But you can take the idea from that.
The reason this is happening is because the elements are still within the form element. Hiding a div using CSS won't change this - they're still present in the DOM.
It would likely be easiest to add a hidden input field to each div that can be used to identify server side which one you should be processing. You can then simply ignore the data from the hidden form.
If you really must stop the data from being posted, it's a little messy but you could move the hidden div's contents outside of the form element so that the fields won't be submitted. If you wanted to display the div again, you'd then need to move the fields back in. Depending on how complex your CSS is, this could cause problems in some browsers, so I'd advise using my first suggestion.