I have a query as below.
Post.native(function(err, collection) {
collection.find({
$or: [ { id :id }, { parentid : id} ]
}, function(err, result) {
if (err)
console.log({error: err});
console.log(result);
});
});
But this returns zero results , even though i have one result satisfying {id : id} and two results satisfying {parentid : id}. I need three results to be printed.
Please correct me if my query is wrong. Any help would be appreciated.
Please help. Thanks a lot
Here are some of the most common things I would do to debug this problem.
If you use the native driver and the fields you are querying are MongoIds, you need to ensure that ids are instances of ObjectId, i.e.
id = new mongo.ObjectID(id)
Also, mongodb natively stores its id as _id. Did you specifically create an id field?
Related
I wish to return just the document id's from mongo that match a find() query.
I know I can pass an object to exclude or include in the result set, however I cannot find a way to just return the _id field.
My thought process is returning just this bit of information is going to be way more efficient (my use case requires no other document data just the ObjectId).
An example query that I expected to work was:
collection.find({}, { _id: 1 }).toArray(function(err, docs) {
...
}
However this returns the entire document and not just the _id field.
You just need to use a projection to find what ya want.
collection.find({filter criteria here}, {foo: 0, bar: 0, _id: 1});
Since I don't know what your document collection looks like this is all I can do for you. foo: 0 for example is exclude this property.
I found that using the cursor object directly I can specify the required projection. The mongodb package on npm when calling toArray() is returning the entire document regardless of the projection specified in the initial find(). Fixed working example below that satisfies my requirements of just getting the _id field.
Example document:
{
_id: new ObjectId(...),
test1: "hello",
test2: "world!"
}
Working Projection
var cursor = collection.find({});
cursor.project({
test1: 0,
test2: 0
});
cursor.toArray(function(err, docs) {
// Importantly the docs objects here only
// have the field _id
});
Because _id is by definition unique, you can use distinct to get an array of the _id values of all documents as:
collection.distinct('_id', function(err, ids) {
...
}
you can do like this
collection.find({},'_id').toArray(function(err, docs) {
...
}
I want to query for a document with a given condition and have it return the _id for that document. Here is what I tried, but it doesn't work:
User.find(
{phone: phone},
null,
{},
function (err, data) {
user_id = data._id;
}
);
Basically, I'm trying to query the Users collection for a user/document with a certain phone number, and then have it return the _id for that user. What am I doing wrong?
If you're trying to find only one document you need to use findOne:
User.findOne({phone : phone}, function(err, data) {
if (err) return console.error(err);
user_id = data._id;
});
If multiple documents satisfy the query, this method returns the first document according to the natural order which reflects the order of documents on the disk.
If you want to get multiple documents you need to use find and your data parameter will then contain all users that matches your criteria.
How can I get an array of all the doc ids in MongoDB? I only need a set of ids but not the doc contents.
You can do this in the Mongo shell by calling map on the cursor like this:
var a = db.c.find({}, {_id:1}).map(function(item){ return item._id; })
The result is that a is an array of just the _id values.
The way it works in Node is similar.
(This is MongoDB Node driver v2.2, and Node v6.7.0)
db.collection('...')
.find(...)
.project( {_id: 1} )
.map(x => x._id)
.toArray();
Remember to put map before toArray as this map is NOT the JavaScript map function, but it is the one provided by MongoDB and it runs within the database before the cursor is returned.
One way is to simply use the runCommand API.
db.runCommand ( { distinct: "distinct", key: "_id" } )
which gives you something like this:
{
"values" : [
ObjectId("54cfcf93e2b8994c25077924"),
ObjectId("54d672d819f899c704b21ef4"),
ObjectId("54d6732319f899c704b21ef5"),
ObjectId("54d6732319f899c704b21ef6"),
ObjectId("54d6732319f899c704b21ef7"),
ObjectId("54d6732319f899c704b21ef8"),
ObjectId("54d6732319f899c704b21ef9")
],
"stats" : {
"n" : 7,
"nscanned" : 7,
"nscannedObjects" : 0,
"timems" : 2,
"cursor" : "DistinctCursor"
},
"ok" : 1
}
However, there's an even nicer way using the actual distinct API:
var ids = db.distinct.distinct('_id', {}, {});
which just gives you an array of ids:
[
ObjectId("54cfcf93e2b8994c25077924"),
ObjectId("54d672d819f899c704b21ef4"),
ObjectId("54d6732319f899c704b21ef5"),
ObjectId("54d6732319f899c704b21ef6"),
ObjectId("54d6732319f899c704b21ef7"),
ObjectId("54d6732319f899c704b21ef8"),
ObjectId("54d6732319f899c704b21ef9")
]
Not sure about the first version, but the latter is definitely supported in the Node.js driver (which I saw you mention you wanted to use). That would look something like this:
db.collection('c').distinct('_id', {}, {}, function (err, result) {
// result is your array of ids
})
I also was wondering how to do this with the MongoDB Node.JS driver, like #user2793120. Someone else said he should iterate through the results with .each which seemed highly inefficient to me. I used MongoDB's aggregation instead:
myCollection.aggregate([
{$match: {ANY SEARCHING CRITERIA FOLLOWING $match'S RULES} },
{$sort: {ANY SORTING CRITERIA, FOLLOWING $sort'S RULES}},
{$group: {_id:null, ids: {$addToSet: "$_id"}}}
]).exec()
The sorting phase is optional. The match one as well if you want all the collection's _ids. If you console.log the result, you'd see something like:
[ { _id: null, ids: [ '56e05a832f3caaf218b57a90', '56e05a832f3caaf218b57a91', '56e05a832f3caaf218b57a92' ] } ]
Then just use the contents of result[0].ids somewhere else.
The key part here is the $group section. You must define a value of null for _id (otherwise, the aggregation will crash), and create a new array field with all the _ids. If you don't mind having duplicated ids (according to your search criteria used in the $match phase, and assuming you are grouping a field other than _id which also has another document _id), you can use $push instead of $addToSet.
Another way to do this on mongo console could be:
var arr=[]
db.c.find({},{_id:1}).forEach(function(doc){arr.push(doc._id)})
printjson(arr)
Hope that helps!!!
Thanks!!!
I struggled with this for a long time, and I'm answering this because I've got an important hint. It seemed obvious that:
db.c.find({},{_id:1});
would be the answer.
It worked, sort of. It would find the first 101 documents and then the application would pause. I didn't let it keep going. This was both in Java using MongoOperations and also on the Mongo command line.
I looked at the mongo logs and saw it's doing a colscan, on a big collection of big documents. I thought, crazy, I'm projecting the _id which is always indexed so why would it attempt a colscan?
I have no idea why it would do that, but the solution is simple:
db.c.find({},{_id:1}).hint({_id:1});
or in Java:
query.withHint("{_id:1}");
Then it was able to proceed along as normal, using stream style:
createStreamFromIterator(mongoOperations.stream(query, MortgageDocument.class)).
map(MortgageDocument::getId).forEach(transformer);
Mongo can do some good things and it can also get stuck in really confusing ways. At least that's my experience so far.
Try with an agregation pipeline, like this:
db.collection.aggregate([
{ $match: { deletedAt: null }},
{ $group: { _id: "$_id"}}
])
this gona return a documents array with this structure
_id: ObjectId("5fc98977fda32e3458c97edd")
i had a similar requirement to get ids for a collection with 50+ million rows. I tried many ways. Fastest way to get the ids turned out to be to do mongoexport with just the ids.
One of the above examples worked for me, with a minor tweak. I left out the second object, as I tried using with my Mongoose schema.
const idArray = await Model.distinct('_id', {}, function (err, result) {
// result is your array of ids
return result;
});
I need to select users for corresponding data from query.
I have this collection in my DB (two or more rows are output of my query as well)
> db.Friends.find()
{ "userId" : "k3XCWdN5M2pbzBiFD", "followeeId" : "3MTmHcJNEzaaS8hrd","_id" : "aiRD.." }
{ "userId" : "k3XCWdN5M2pbzBiFD", "followeeId" : "SoTozuZ4nWooRBeFz","_id" : "QingX.." }
When it would be just one result as findOne(...) the second query would looks like this:
users.findOne({ _id: firstQueryResult.followeeId })
But now the problem is... how can i select the users from users collection when i dont have only one followeeId but more of them?
Please someone show me an example of code.
My research:
Is this a good solution?
friendsData.forEach(function(relationShip) {
followeeIds.push(relationShip.followeeId);
});
console.log(followeeIds);
Ok i finalllly figure out the problem.For next readers:
Check if autopublish is enabled or disabled.
If is disabled you need to publish the collection from the DB
Meteor.publish("userData", function () {
return Meteor.users.find({},
{fields: {'username': 1}});
});
PS: i want to publish only username field and thats all!
You need to subscribe the data as well!
Meteor.subscribe("userData");
Now you can access other users data this way:
users= Meteor.users.findOne({username: "Nolifer"});
To my original problem ... i will probably use this function for iterate over more then one row result(its more a SQL term but i am not sure what term use in mongoDb maybe a document? whatever):
users.forEach(function(user) {
console.log(user);
});
Thats it!
P.S.: I think there is nothing wrong on this but what i know right? :) So if someone know a better way please leave a comment. If not give me know if it was useful for you :)
According to the mongo manual, use the $in operand: http://docs.mongodb.org/manual/reference/operator/in/#op._S_in
db.inventory.find( { qty: { $in: [ 5, 15 ] } } )
I'm trying to 'stream' data from a node.js/MongoDB instance to the client using websockets. It is all working well.
But how to I identify the last document in the result? I'm using node-mongodb-native to connect to MongoDB from node.js.
A simplified example:
collection.find({}, {}, function(err, cursor) {
if (err) sys.puts(err.message);
cursor.each(function(err, doc) {
client.send(doc);
});
});
Since mongodb objectId contatins creation date you can sort by id, descending and then use limit(1):
db.collection.find().sort( { _id : -1 } ).limit(1);
Note: i am not familiar with node.js at all, above command is mongo shell command and i suppose you can easy rewrite it to node.js.
Say I have companies collection. Below snippet gives me last document in the collection.
db.companies.find({},{"_id":1}).skip(db.companies.find().count()-1);
Code cannot rely on _id as it may not be on a specific pattern always if it's a user defined value.
Use sort and limit, if you want to use cursor :
var last = null;
var findCursor = collection.find({}).cursor();
findCursor.on("data", function(data) {
last = data;
...
});
findCursor.on("end", function(data) {
// last result in last
....
});