I try to generate a list of days with their week number (defined by ISO 8601) accordingly :
mydate='2012-12-25 02:26:55.983'
for (i=1;i<365;i++)
{
mydateAsDate=new Date().parse('yyyy-MM-dd H:mm:ss.S',mydate)+i;
println 'Week ' + mydateAsDate.format('w') + ' => ' + mydateAsDate.format('dd.MM.yyyy');
}
This works but I would like to get the year also like this:
Week 1-2013
I can't figure out which year information I should take.
Any idea?
As Jon Skeet said, I'd recommend using Joda-Time.
If you do, the following should fix your issues:
mydate= new DateTime(2012,12,25)
yearLater = myDate.plusYears(1)
while(myDate < yearLater){
println "Week ${myDate.weekOfWeekyear} - ${myDate.year}"
myDate = myDate.plusDays(1)
}
Not sure I understand, but you mean like:
String startDateString = '2012-12-25 02:26:55.983'
Date startDate = Date.parse( 'yyyy-MM-dd H:mm:ss.S', startDateString )
(1..364).each { i ->
println( (startDate++).format( "dd.MM.yyyy : 'Week' w'-'yyyy" ) )
}
I got it : SimpleDateFormat delivers the right week year information when using the YYYY format
thus this is only available in java 1.7
thanks for your responses though !
cheers
Related
Sorry if similar questions have been asked too many times, but it seems that there's one or more issues with every answer I find.
I have a date in the form of a String: Ex.: "04112005"
This is a date. 4th of November, 2005.
I want to get the difference, in years and days, between the current date and this date.
The code I have so far gets the year and just substracts them:
fun getAlderFraFodselsdato(bDate: String): String {
val bYr: Int = getBirthYearFromBirthDate(bDate)
var cYr: Int = Integer.parseInt(SimpleDateFormat("yyyy").format(Date()))
return (cYr-bYr).toString()
}
However, naturally, this is quite innacurate, since the month and days aren't included.
I've tried several approaches to create Date, LocalDate, SimpleDate etc. objects and using these to calcualate the difference. But for some reason I haven't gotten any of them to work.
I need to create a Date (or similar) object of the current year, month and day. Then I need to create the same object from a string containing say, month and year (""04112005""). Then I need to get the difference between these, in years, months and days.
All hints are appreciated.
I would use java.time.LocalDate for parsing and today along with a java.time.Period that calculates the period between two LocalDates for you.
See this example:
fun main(args: Array<String>) {
// parse the date with a suitable formatter
val from = LocalDate.parse("04112005", DateTimeFormatter.ofPattern("ddMMyyyy"))
// get today's date
val today = LocalDate.now()
// calculate the period between those two
var period = Period.between(from, today)
// and print it in a human-readable way
println("The difference between " + from.format(DateTimeFormatter.ISO_LOCAL_DATE)
+ " and " + today.format(DateTimeFormatter.ISO_LOCAL_DATE) + " is "
+ period.getYears() + " years, " + period.getMonths() + " months and "
+ period.getDays() + " days")
}
The output for a today of 2020-02-21 is
The difference between 2005-11-04 and 2020-02-21 is 14 years, 3 months and 17 days
It Works Below 26 API level
There are too many formates of dates you just enter the format of date and required start date and end date. It will show you result. You just see different date formate hare and here if you need.
tvDifferenceDateResult.text = getDateDifference(
"12 November, 2008",
"31 August, 2021",
"dd MMMM, yyyy")
General method to calculate date difference
fun getDateDifference(fromDate: String, toDate: String, formater: String):String{
val fmt: DateTimeFormatter = DateTimeFormat.forPattern(formater)
val mDate1: DateTime = fmt.parseDateTime(fromDate)
val mDate2: DateTime = fmt.parseDateTime(toDate)
val period = Period(mDate1, mDate2)
// period give us Year, Month, Week and Days
// days are between 0 to 6
// if you want to calculate days not weeks
//you just add 1 and multiply weeks by 7
val mDays:Int = period.days + (period.weeks*7) + 1
return "Year: ${period.years}\nMonth: ${period.months}\nDay: $mDays"
}
For legacy Date functions below api 26 without running desugaring with Gradle plugin 4.0, java.time.* use:
fun getLegacyDateDifference(fromDate: String, toDate: String, formatter: String= "yyyy-MM-dd HH:mm:ss" , locale: Locale = Locale.getDefault()): Map<String, Long> {
val fmt = SimpleDateFormat(formatter, locale)
val bgn = fmt.parse(fromDate)
val end = fmt.parse(toDate)
val milliseconds = end.time - bgn.time
val days = milliseconds / 1000 / 3600 / 24
val hours = milliseconds / 1000 / 3600
val minutes = milliseconds / 1000 / 3600
val seconds = milliseconds / 1000
val weeks = days.div(7)
return mapOf("days" to days, "hours" to hours, "minutes" to minutes, "seconds" to seconds, "weeks" to weeks)
}
The above answers using java.time.* api is much cleaner and accurate though.
I am using a datepicker in a modal window in my Bootstrap application. I am using the original Datepicker from Stefan Petre. I built it where it works in a desktop and mobile using a mouse and it works fine.
Recently I had a user request to allow it to also work with a keyboard. I removed the readonly property to allow the user to enter a date in the input field. The date-format is set to 'mm/dd/yyyy'.
When I enter a date like today for example like this "12/11/13" then it will default to 1913. This isn't a huge deal as I could just train the users to use 4 digits, but I would rather just have it default to this century.
Note: This only seems to happen for the date-format with a 4 digit year. This also seems to happen in the same manner in the newer forks of Stefan's code.
Note: I am using Bootstrap 2.0.4. I am testing with Firefox.
Here is what it looks like:
In JavaScript, set the datepicker's assumeNearbyYear attribute to true, like this:
$("#dp").datepicker({
assumeNearbyYear: true
});
This happens because the Bootstrap datepicker is using JavaScript Date objects. When you create a new Date object and pass in a two digit year it will output 1900+year (see Why does Javascript evaluate a 2-digit year of 00 as 1900 instead of 2000?)
You could try to tweak the datepicker source code, but that might be too complicated.
From what I can see on http://www.eyecon.ro/bootstrap-datepicker/ there is no option to set a range for the selectable dates, but you could change the format to use two digit years.
On your screenshot I can see, that you are using the datepicker for "Arrival Date" which I assume is in the future. On the website there is an example on how to disable dates in the past.
I hope that helps.
UPDATE
I have written an event handler for your problem which should do the trick.
Javascript on http://jsfiddle.net/pCYbd/1/
$("#dp").datepicker();
$("#dp").on("keyup", function(e) {
var date, day, month, newYear, value, year;
value = e.target.value;
if (value.search(/(.*)\/(.*)\/(.*)/) !== -1) {
date = e.target.value.split("/");
month = date[0];
day = date[1];
year = date[2];
if (year === "") {
year = "0";
}
if (year.length < 4) {
newYear = String(2000 + parseInt(year));
$(this).datepicker("setValue", "" + month + "/" + day + "/" + newYear);
if (year === "0") {
year = "";
}
return $(this).val("" + month + "/" + day + "/" + year);
}
}
});
CoffeeScript on http://jsfiddle.net/pCYbd/2/
$("#dp").datepicker()
$("#dp").on "keyup", (e) ->
value = e.target.value
if value.search(/(.*)\/(.*)\/(.*)/) != -1
date = value.split("/")
month = date[0]
day = date[1]
year = date[2]
year = "0" if year == ""
if year.length < 4
newYear = String(2000 + parseInt(year))
$(#).datepicker("setValue", "#{month}/#{day}/#{newYear}")
year = "" if year == "0"
$(#).val("#{month}/#{day}/#{year}")
My JavaScript skills are not the best, but this should work.
Updating bootstrap-datepicker.js as shown in this post solved it for me https://github.com/eternicode/bootstrap-datepicker/pull/1461/commits/2ea16adad27cbc4d4dfa20b924addfb480e5b036
yyyy: function(d,v){
if (format.parts.indexOf('yyyy') > -1 && v < 1000) v = 2000+v; // this line ***
return d.setUTCFullYear(v);
},
I'm using bootstrap-datepicker v1.5.1 and if you look around line 1741 where it does the year mapping, you will notice this:
yyyy: function (d, v) {
return d.setUTCFullYear(v);
},
yy: function (d, v) {
return d.setUTCFullYear(2000 + v);
},
When you specify that the control uses a four year date "yyyy", it will only do the return d.setUTCFullYear(v);, which will get you the previous century that JavaScript gives you. When you specify that it use the two year date "yy", it will do the correct 2000+ that you need for the current century.
So if you want the correct two year date to be 2016, 2017, etc., you need to set your datepicker to use the "yy" like so:
$('#tbPurchaseDate').datepicker({
format: 'mm/dd/yy',
autoclose: true,
todayBtn: 'linked',
todayHighlight: true,
orientation: 'bottom auto'
});
Or you can change the "yyyy" setting in the bootstrap-datepicker.js to match the "yy" version, but then you'd have to remember to do that every time you update the datepicker js file via nuget. It's much easier to just change your format setting.
Of course, if you want the full 4 digit year to display in the control, then you might want to try one of the elaborate fixes listed here or just set the "yyyy" to what the "yy" is in the js file.
Or just update your code to the latest version (1.6.4 right now) and "yyyy" and "yy" are the same and you use assumeNearbyYear: true as noted in another answer here.
For me, the best solution was to customize parseDate function in bootstrap-datepicker.js file directly. Inside a function, there is variable setters_map with yyyy property which I modified a bit. Here is my solution:
yyyy: function(d,v) {
if (v.toString().length == 2 && v <= 30) {
v = 2000 + parseInt(v);
}
return d.setUTCFullYear(v);
},
In my case it was needed to convert only years that are less or equals 30.
In the update function of bootstrap-datepicker.js I added this block of code:
var str = this.element.prop('value');
var defaulted = false;
if (str.lastIndexOf("/") >= 0 && (str.match(/\//g) || []).length == 2)
{
var yr = str.substring(str.lastIndexOf("/") + 1);
if (yr.length <= 2)
defaulted = true;
}
if (this.date.getFullYear() < 2000 && defaulted) {
this.date.setFullYear(this.date.getFullYear() + 100);
}
right before the viewdate is set on this line:
this.viewDate = new Date(this.date.getFullYear(), this.date.getMonth(), 1, 0, 0, 0, 0);
It will work 100% if you update below two line in UTCDate() of bootstrap-datepicker.js core file:
function UTCDate(){
/* Date defaulted date from 2000 if entered date year less than 4 degit*/
if(arguments!=null && arguments[0].toString().length<4)
arguments[0] = 2000 + arguments[0];
return new Date(Date.UTC.apply(Date, arguments));
}
What I am trying to do here is this - I want to give index to only the workdays in each week.
So, if in a week, Monday and Wednesday are holidays, then Tuesday should get 1, Thursday should get 2, Friday should get the index 3. Otherwise, in a normal week without any holidays, Monday should get 1, Tuesday 2, Wednesday 3, and so on ...
Here is the code I have written (I haven't coded in years now, so please pardon the crude approach)
Sheet 'Holidays' contains a list of holidays in the column B starting from row 2
Variable date is the date for which I want to find out the index for
Variable dayOfTheWeek is the number of day of 'date' counted from last Sunday, so if date is a Monday, dayOfTheWeek is 1; if date is Tuesday, dayOfTheWeek is 2, and so on ...
function indexOfWorkdayOfTheWeek (date, dayOfTheWeek, lastSundayDate)
{
var activeSheet = SpreadsheetApp.getActiveSpreadsheet();
var activeCell = activeSheet.getActiveRange();
var activeRow = activeCell.getRowIndex();
var activeColumn = activeCell.getColumn();
var count = 1;
for (var j = 1; j < dayOfTheWeek; j++)
{
var date2 = lastSundayDate.valueOf() + j*86400;
Logger.log('Date ' + j + ' is:' + date2);
Logger.log('Last Sunday is:' + lastSundayDate);
if (holidayOrNot(date2) == true)
{
}
else
{
count = count + 1;
}
}
return count;
}
function holidayOrNot(date2)
{
var holidaysSheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName('Holidays');
var listOfHolidays = holidaysSheet.getSheetValues(2, 2, 95, 1);
var isDateMatch = false;
for (var k = 0; k < 90; k++)
{
if (date2 == listOfHolidays[k].valueOf())
{
isDateMatch = true;
break;
}
else
{
continue;
}
}
return isDateMatch;
}
I think the problem is two-fold here:
The date2 calculation isn't working for some reason (var date2 = lastSundayDate.valueOf() + j*86400;)
The function holidayOrNot is returning false, no matter what, even if it encounters a holiday ... the condition date2 == listOfHolidays[k] isn't working for some reason...
Help would be appreciated!
maybe this method below could help you in your calculations, it returns an integer corresponding to the day of the year so if you apply this to your holidays days and compare to the days of interest it could be a good way to find matches.
here it is, just add these lines outside of any function in your script (so you can use it anywhere) then use it like this :
var d = new Date().getDOY();
Logger.log(d)
Here the method :
Date.prototype.getDOY = function() {
var onejan = new Date(this.getFullYear(),0,1);
return Math.ceil((this - onejan) / 86400000);
}
Assuming that lastSundayDate is being passed around correctly, I see a glaring problem:
lastSundayDate.valueOf().
valueOf() on Date objects returns the primitive value... it looks like you're going for adding a day to the date (86400 seconds * j)? I can't tell what the logic is supposed to be here. But the valueOf() date2 is definitely giving you an integer something like: 1384628769399 (see here).
What you really want to accomplish is something like Date.getDay(), or something similar so that you can add hours, days, etc. to the original Date. This is likely the source of all your problems.
What you can do is read the Mozilla Developer Network documentation on Date objects to see all of the functions on Dates and their uses. You can greatly simplify what you're trying to do by using these functions, instead of doing abstract operations like j * 86400.
It should also be noted that you can do simple operations such as the following, to add 4 hours to the current Date (time):
var myDate = new Date();
Logger.log(myDate); // ~ console.write
var laterDate = new Date(myDate.setHours(myDate.getHours() + 4));
Logger.log(laterDate); // ~ console.write
which gives the following:
[13-11-16 14:13:38:947 EST] Sat Nov 16 14:13:38 GMT-05:00 2013
[13-11-16 14:13:38:954 EST] Sat Nov 16 18:13:38 GMT-05:00 2013
Working with dates can be tricky - but it's always best to use the simplest methods that are available, which are built into the Date objects themselves. There are also numerous other libraries that provide extended functionality for Dates such as Date js.
If you're still running into your problem after attempting to try using methods I displayed above, please run your script and post both the Execution Transcript and the content of the Logger so that I can help you narrow down the issue :)
What is counter part of this code in GWT ?
public int returnAllDaysOf(2012,6){
Calendar calendar = Calendar.getInstance();
calendar.set(2012, Calendar.FEBRUARY, 1);
int daysOfFeb = calendar.getActualMaximum(Calendar.DAY_OF_MONTH);
return daysOfFeb;
}
Thanks in advance for your help.
I want to get the number of days of a month in the client side. I searched Google and StackOverFlow but didn't get anything.
for example Feb has 29 days, Match has 31 days and so on ...
I don't know a direct way, but you can calculate this value by adding one month to your date, and then calcualting the difference in days:
final Date myDate = ...;
final Date copyOfDate = CalendarUtil.copyDate(myDate);
CalendarUtil.addMonthsToDate(copyOfDate, 1);
final int daysBetween = CalendarUtil.getDaysBetween(myDate, copyOfDate);
Note: This even works if myDate is something like 2012-01-31. copyOfDate is then 2012-03-02 (because february doesn't have 31 days), and the result is correct again.
"Cheating" way to do it:
int daysInCurrentMonth = new Date(year-1900, month+1, 0).getDate();
I.E.
int daysInJanuary2014 = new Date(114, 1, 0).getDate();
basically set the Date object to the 0th day of the NEXT month, then get the day of the month.
NOTE: Date(int year, int month, int date) expects year=calendarYear-1900 (i.e. 2014=114) and month is 0-based (i.e. January would be month 0)
and yes, I know this constructor is deprecated, but I still use it.
DateField dfMois = new DateField();
Calendar calendar = Calendar.getInstance();
calendar.setTime(dfMois.getValue());
Date date = dfMois.getValue();
Date dateCopy = dateFin;
dateCopy.setDate(calendar.getActualMaximum(Calendar.DAY_OF_MONTH));
if(date.getMonth() == Calendar.FEBRUARY + 1){
date.setDate(31 - dateCopy.getDate());
date.setMonth(date.getMonth()-1);
}
else{
date.setDate(dateCopy.getDate());
}
dfMois.setValue(date);
In your code... it work.
I need to get the end date of the given month for some calculation purpose,
how can I do that in PHP, I tried using date() function, but It didn't work.
I used this:
date($year.'-'.$month.'-t');
But this gives the current month's end date.
I think I'm wrong somewhere, I couldn't find where I'm going wrong here.
If I give year as 2012 & month as 03, then it must show me as 2012-03-31.
This code will give you last day for a specific month.
$datetocheck = "2012-03-01";
$lastday = date('t',strtotime($datetocheck));
You want to replace your date() call with:
date('Y-m-t', strtotime($year.'-'.$month.'-01'));
The first parameter to date() is the format you want to be returned, and the second parameter has to be a unix timestamp (or not passed to use the current timestamp). In your case, you can generate a timestamp with the function strtotime(), passing it a date string with the year, the month, and 01 for the day. It will return that same year and month, but the -t in the format will be replaced by the last day of the month.
If you want to return only the last day of the month without year and month:
date('t', strtotime($year.'-'.$month.'-01'));
Just use 't' as your format string.
Current month:
echo date('Y-m-t');
Any month:
echo date('Y-m-t', strtotime("$year-$month-1"));
Try below code.
$m = '03';//
$y = '2012'; //
$first_date = date('Y-m-d',mktime(0, 0, 0, $m , 1, $y));
$last_day = date('t',strtotime($first_date));
$last_date = date('Y-m-d',mktime(0, 0, 0, $m ,$last_day, $y));
function lastday($month = '', $year = '') {
if (empty($month)) {
$month = date('m');
}
if (empty($year)) {
$year = date('Y');
}
$result = strtotime("{$year}-{$month}-01");
$result = strtotime('-1 second', strtotime('+1 month', $result));
return date('Y-m-d', $result);
}
function firstOfMonth() {
return date("Y-m-d", strtotime(date('m').'/01/'.date('Y').' 00:00:00')). 'T00:00:00';}
function lastOfMonth() {
return date("Y-m-d", strtotime('-1 second',strtotime('+1 month',strtotime(date('m').'/01/'.date('Y').' 00:00:00')))). 'T23:59:59';}
$date1 = firstOfMonth();
$date2 = lastOfMonth();
try this ,this give you a current month's starting and ending date.
date("Y-m-d",strtotime("-1 day" ,strtotime("+1 month",strtotime(date("m")."-01-".date("Y")))));
function getEndDate($year, $month)
{
$day = array(1=>31,2=>28,3=>31,4=>30,5=>31,6=>30,7=>31,8=>31,9=>30,10=>31,11=>30,12=>31);
if($year%100 == 0)
{
if($year%400 == 0)
$day[$month] = 29;
}
else if($year%4 == 0)
$day[$month] = 29;
return "{$year}-{$month}-{$day[$month]}";
}
If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:
$a_date = "2012-03-23";
$date = new DateTime($a_date);
$date->modify('last day of this month');
echo $date->format('Y-m-d');