I Download the zend Framework 1.12.3 and rename with Zend and place this folder in
"C:\wamp\bin\php\"
and now i right click on 'my computer properties' and select
'Advanced->Environment Variables' and create a new
'user variable' variable name: zf and variable value: C:\wamp\bin\php\Zend\bin
and edit 'System variable->Path' where at the end of variable value i placed ';C:\wamp\bin\php\Zend\bin;'
after that i open 'php.ini' file and edit
; Windows: "\path1;\path2"
;include_path = ".;c:\php\includes;C:\wamp\bin\php\Zend\library"
and restart wamp
and go to cmd and type 'C:\wamp\bin\php\Zend\bin>zf show version'
but i always get a message
'"php.exe"' is not recognized as an internal or external command, operable program or batch file
please help to resolve.
Try to add path of your php.exe in Path variable.
select 'Advanced->Environment Variables'
In System variables:
modify Path with php-path
exemple: ";c:\php" (without comma)
Frankly speaking....you don't need to change or add any Environment Variables.
Just put zend's "library" folder in your project directory.
And it will work.It wored for me.
So your directory structure will be :
C:\wamp\YOUR-project-folder\library
Directory structure :
YOUR-project-folder
- application
- docs
- library
- public
- test
Related
https://guides.rubyonrails.org/getting_started.html
I am taking a look at 3.1.2, where it says
Verify that it is correctly installed and in your load PATH
What does it mean to check that something installed is in my load PATH?
What is a load PATH, and how might I be able to read up on all these things?
New to things. I use windows. I have a unix in my computer as well.
Load Path is simply a path defined under your environment variables - ' Path ' variable.
click here to see an image example
It usually comes up in windows 10 -> when you type 'env' or 'environment' in the search bar. -> click on ' edit the system environment variables '
Then under Environment Variables ( this is important - do not go to system variables )
click on -> path
click -> edit
after you click edit for 'path
click -> new
just add the directory location for your sqlite3.exe ( just the folder is enough , you don't have to indicate the sqlite3.exe )
click -> ok
you're good to go :)
open a new command prompt and type sqlite3 to check.
When starting Netbeans, I need to add a system property named mEnvironment and set it as a sub-directory of the user's home. Example: In the netbeans.conf, I would like to add:
netbeans_default_options="-J-XX:+UseStringDeduplication -J-Xss2m -J-DmEnvironment=${USER_HOME}/mySubDirectory ......
USER_HOME is given as example of course.
Does someone know how Netbeans get the user home directory in the netbeans.conf file?
Thank you
Paul
Does someone know how Netbeans get the user home directory in the
netbeans.conf file?
The process is convoluted, and varies by operating system, but is described in great detail within netbeans.conf itself. This is the relevant content for my Apache NetBeans 11.1 installation:
# On Windows ${DEFAULT_USERDIR_ROOT} will be replaced by the launcher
# with "<AppData>\NetBeans" where <AppData> is user's
# value of "AppData" key in Windows Registry under
# "HKCU\Software\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders"
# and ${DEFAULT_CACHEDIR_ROOT} will be replaced by the launcher
# with "<Local AppData>\NetBeans\Cache" where <Local AppData> is user's
# value of "Local AppData" key in Windows Registry under
# "HKCU\Software\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders"
#
# On Mac ${DEFAULT_USERDIR_ROOT} will be replaced by the launcher
# with "~/Library/Application Support/NetBeans" and
# ${DEFAULT_CACHEDIR_ROOT} with "~/Library/Caches/NetBeans"
#
# On other systems ${DEFAULT_USERDIR_ROOT} will be replaced by the launcher
# with "~/.netbeans" and ${DEFAULT_CACHEDIR_ROOT} with "~/.cache/netbeans"
....
netbeans_default_userdir="${DEFAULT_USERDIR_ROOT}/11.1"
However, none of that really helps you, because you cannot access the values of netbeans_default_userdir or DEFAULT_USERDIR_ROOT; they are used internally by NetBeans itself, and are not System properties. You can verify this by displaying the values returned by System.getProperties(); none of the entries in netbeans.conf are shown.
Also, you can't meaningfully add new name/value pairs in netbeans.conf; you can only modify the values of the names used by NetBeans. That file is for NetBeans configuration, not user configuration. So if you add a line containing (say) MyConfSetting="ABC" then NetBeans will simply ignore that, and it won't be accessible to you either.
However, you can use an alternative approach to set a System Property for your directory in your application:
The read-only environment variable APPDATA points to your (operating system's) user directory. On my Windows 10 machine it has the value C:\Users\johndoe\AppData\Roaming.
The default user directory for NetBeans is the value of APPDATA + a sub-directory named NetBeans + a sub-directory named the NetBeans version. On my machine it is C:\Users\johndoe\AppData\Roaming\NetBeans\11.1. See the value of User directory in the Help > About screen for confirmation.
I don't know how to dynamically determine the version of NetBeans, but if that isn't important you can programmatically create a system property specifying your directory path:
String dir = System.getenv("APPDATA") + "\\NetBeans\\mySubDirectory";
System.setProperty("myDir", dir);
System.out.println("myDir=" + System.getProperty("myDir"));
On my machine that println() call displays myDir=C:\Users\johndoe\AppData\Roaming\NetBeans\mySubDirectory. I don't know if that approach meets your requirements, but I don't know of any other simple way to dynamically set your directory name.
Notes:
I checked this on Windows 10. Details may vary on other operating systems, but the overall approach should still work.
You can also specify parameters at run time using {project} > Properties > Run > Arguments (e.g. arg1=%APPDATA%\NetBeans\MyDir) and {project} > Properties > Run > VM Options (e.g. -Dvmopt1=%APPDATA%\NetBeans\MyDir), but that approach won't work because the %APPDATA% is simply treated as the literal "%APPDATA%" rather than evaluated as an environment variable.
I got the following error while starting JBoss from a command line prompt today:
'findstr' is not recognized as an internal or external command
Please google it, you can find a lot of answers. But do as below to fix it. Add the following value to Right Click My Compuer -> Advanced -> Environment Variables -> System Variables -> Select Path variable -> append the below value.
C:\WINDOWS\system32
It should work with that change.
As others pointed, issue is in wrong settings of PATH variable in Windows.
According to article this is most probably because some stupid installer wrongly modified PATH variable in Windows registry. Registry has 2 different string value types - REG_SZ and REG_EXPAND_SZ. Only the second one allows for expansion of %SystemRoot%.
So check your path by typing set path in command prompt. If you see unexpanded %SystemRoot% and other variables in Path, you are affected (PATH should show only plain directory names, not variables).
You need to edit Path variable in registry: HKEY_CURRENT_USER\Environment and HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Control\Session Manager\Environment. As it is not possible to change the type of key, save the path value somewhere, delete the key and re-create it with type REG_EXPAND_SZ. You need to logout for changes to take effect.
for me it works when I've coped findstr(from windows/system32) to wildfly/bin
Please go throught the simplest steps:-
go to C:\Windows\system32\ and copy findstr.exe file.
paste this file into the location C:\Program Files\Java\jdk1.6.0_24\bin
Run your jboss again you will get out of this.....
Check to see if you %SystemRoot% is evaluating (type set path into a command prompt, you should not see %SystemRoot%, but instead that actual path). If your path variable's (user, or systems) first entry begins with an %(an environment variable) this can cause an issue.
To resolve this, simply swap this first entry with anything else in your path that does not lead with an environment variable.
You can also hard code the directory by replacing 'findstr' with 'C:\Windows\system32\findstr'. This is useful when using systems with restricted user permissions.
I have try to work with play framework but stuck with to run activator.bat file but solution is the same just copy file from windows/system32/findsr and past it to under stuck folder then run the respective file again.
thanks to andrewsiand Suryaprakash
Please beware that current Windows systems use a Capital "S" for the System directory, so:
C:\WINDOWS\System32
%SystemRoot%\System32
Omitting the capital S will result in a neglect of the line in the %PATH%
In my case (not JBoss related) the following helped to fixed this error.
Instead of:
SET path="%path%;C:\some\additional\path"
I used:
SET "path=%path%;C:\some\additional\path"
For IBM ACE solution for
'findstr' is not recognized as an internal or external command,
Go to the path C:\Windows\System32
Find the findstr.exe, copy it and then find the path where you bin file of your application is found. eg C:\Program Files\IBM\ACE\11.0.0.12\server\bin then past it inside the bin file
cancel the console of ace and re-open it.
Then run ACE toolkit command on ace console.
Then press enter, now it can open.
I would like to move my default "My Documents\WindowsPowerShell" folder. However, when I try this, PowerShell of course can't find $profile. Is there a file or something that I can edit to point PowerShell to a different startup folder?
What I can suggest is that you dot source the file having the content of your profile in the file $profile.AllUsersAllHosts
$profile.AllUsersAllHosts is something like C:\Windows\System32\WindowsPowerShell\v1.0\profile.ps1
Related question: Is it possible to change the default value of $profile to a new value?
You could use junction.exe from Sysinternals to make the WindowsPowershell directory a symbolic link to another location (but not a network drive).
You could do this if you wanted to store the profile scripts at C:\POSH
junction.exe "$HOME\Documents\WindowsPowerShell" 'C:\POSH'
As far as i know you can't do that. The user profile location is always under 'My Documents\WindowsPowerShell' and your only option is to relocate your documents folder (folder redirection).
By default $Profile/$Home/$PSModulePath are all within the registry... normally under
HKEY_CURRENT_USER\Volatile Environment for User environment variables
HKEY_CURRENT_USER\Environment for System environment variables
HKEY_CURRENT_USER\Software\Microsoft\Windows\Explorer\User Shell Folders
and elsewhere!
I have a folder on a server which is shared with guest access enabled. I want to be able to copy a file from that folder to a local machine with Applescript. So far I have:
property source : "server:sharedfolder:file.ext"
property destination : "Macintosh HD:Users:User:Documents:Folder"
tell application "Finder"
copy file "source" to folder "destination"
end tell
Which I think should work. But I get the error: Can't set folder source to destination number 10006. Any ideas?
Thanks.
you need to remove the quotes around your declared properties:
property source : "server:sharedfolder:file.ext"
property destination : "Macintosh HD:Users:User:Documents:Folder:"
tell application "Finder"
copy file source to folder destination
end tell
It is also good practice to terminate your folder paths with a ":".
HTH
Your current script reads: "Copy the variable source to the variable destination." I'm assuming you don't want to just change the variables around; you're using the wrong command. See my answer to this question to learn more.