I've created a JKS file with public and private RSA keys. When I load this file using external path (like c:/file.jks), the program executes like a charm. However, if I try load this same file from classpath, I got this exception:
java.io.IOException: Invalid keystore format
This is the code used to load the jks:
KeyStore keyStore = KeyStore.getInstance("JKS");
InputStream stream=this.getClass().getResourceAsStream("/lutum.jks") ;
keyStore.load(stream,passe);
the only difference is that I use FileInputStream with full path when loading externally.
What I'm doing wrong?
In general your solution should work, provisionally.
What are those provisions? Make sure that your resource folder is in your classpath. If you aren't sure, add it to the -cp flag passed to java when executing your program, or if you are using Eclipse or some other IDE, make sure it is listed as a member of the classpath for that project.
Next, check out this stackoverflow that relates to your question. While the way you are using the class's getResourceAsStream() method is valid (including the / at the start of the filename causes the class resource loader to defer to the ClassLoader's method) it is perhaps less confusing to use the ClassLoader directly. Another good example is found here.
So, first, check that your resources folder is explicitly part of the classpath. Second, prefer the following construction for finding the resource:
InputStream stream= this.class.getClassLoader().getResourceAsStream("lutum.jks");
Note the missing / from the filename. This is because the ClassLoader will automatically start searching at "project root", and the slash will likely just cause issues (if you deploy to JBoss or Tomcat, for instance, that will probably get interpreted by the classloader as an absolute file system path instead of a relative path).
I hope this helps. If not, comment me with more details on your project and I'll alter my answer accordingly.
I suspect that the two keystores are in fact not the same, and that the keystore on the classpath are somehow corrupt.
Try comparing the two keystores. Just read the files into a byte array with something like this:
public static byte[] streamToByteArray(InputStream is) throws IOException {
ByteArrayOutputStream tmp = new ByteArrayOutputStream();
int b = is.read();
while (b > -1) {
tmp.write(b);
b = is.read();
}
tmp.flush();
return tmp.toByteArray();
}
And then compare them like this:
InputStream cpStream = this.getClass().getResourceAsStream("/lutum.jks");
InputStream fileStream = new FileInputStream("c:/file.jks");
byte[] cpBytes = streamToByteArray(cpStream);
byte[] fileBytes = streamToByteArray(fileStream);
if (Arrays.equals(cpBytes, fileBytes)) {
System.out.println("They are the same.");
} else {
System.out.println("They are NOT the same.");
// print the file content ...
}
Related
Im trying to implement a configuration tool typesafehub/config
im using this code
val conf = ConfigFactory.load()
val url = conf.getString("add.prefix") + id + "/?" + conf.getString("add.token")
And the location of the property file is /src/main/resources/application.conf
But for some reason i'm receiving
com.typesafe.config.ConfigException$Missing: No configuration setting found for key 'add'
File content
add {
token = "access_token=6235uhC9kG05ulDtG8DJDA"
prefix = "https://graph.facebook.com/v2.2/"
limit = "&limit=250"
comments="?pretty=0&limit=250&access_token=69kG05ulDtG8DJDA&filter=stream"
feed="/feed?limit=200&access_token=623501EuhC9kG05ulDtG8DJDA&pretty=0"
}
Everything looks configured correctly ?? do i missed something .
thanks,
miki
The error message is telling you that whatever configuration got read, it didn't include a top level setting named add. The ConfigFactory.load function will attempt to load the configuration from a variety of places. By default it will look for a file named application with a suffix of .conf or .json. It looks for that file as a Java resource on your class path. However, various system properties will override this default behavior.
So, it is likely that what you missed is one of these:
Is it possible that src/main/resources is not on your class path?
Are the config.file, config.resource or config.url properties set?
Is your application.conf file empty?
Do you have an application.conf that would be found earlier in your class path?
Is the key: add defined in the application.conf?
Are you using an IDE or sbt?
I had a similar problem while using Eclipse. It simply did not find the application.conf file at first and later on failed to notice edits.
However, once I ran my program via sbt, all worked just fine, including Eclipse. So, I added 'main/resources' to the libraries (Project -> Properties -> Java Build Path -> Libraries", "add class folder"). That might help you as well.
Place your application.conf in the src folder and it should work
I ran into this issue inside a Specs2 test that was driven by SBT. It turned out that the issue was caused by https://github.com/etorreborre/specs2/issues/556. In that case, the Thread's contextClassLoader wasn't using the correct classloader. If you run into a similar error, there are other versions of ConfigFactory.load() that allow you to pass the current class's ClassLoader instead. If you're using Specs2 and you're seeing this issue, use a version <= 3.8.6 or >= 4.0.1.
Check you path. In my case I got the same issue, having application.conf placed in src/main/resources/configuration/common/application.conf
Incorrect:
val conf = ConfigFactory.load(s"/configuration/common/application.conf")
Correct
val conf = ConfigFactory.load(s"configuration/common/application.conf")
it turned out to be a silly mistake i made.
Following that, i does not matter if you use ":" or "=" in .conf file.
Getting the value from example:
server{
proc {
max = "600"
}
}
conf.getString("server.proc.max")
Even you can have the following conf:
proc {
max = "600"
}
proc {
main = "60000"
}
conf.getString("proc.max") //prints 600
conf.getString("proc.min") //prints 60000
I ran into this doing a getString on an integer in my configuration file.
I ran into exactly the same problem and the solution was to replace = with : in the application.conf. Try with the following content in your application.conf:
add {
token: "access_token=6235uhC9kG05ulDtG8DJDA"
prefix: "https://graph.facebook.com/v2.2/"
limit: "&limit=250"
comments: "?pretty=0&limit=250&access_token=69kG05ulDtG8DJDA&filter=stream"
feed: "/feed?limit=200&access_token=623501EuhC9kG05ulDtG8DJDA&pretty=0"
}
Strangely, IntelliJ doesn't detect any formatting or syntax error when using = for me.
in my case it was a stupid mistake,
i m change file name from "application.config" to "application.conf" and its works .
If the application.conf is not getting discovered, you could add this to build.sbt:
unmanagedSourceDirectories in Compile += baseDirectory.value / "main/resources"
Please don't use this to include any custom path. Follow the guidelines and best-practices
As mentioned by others, make sure the application.conf is place in: src/main/resources.
I placed the file there error went away.
Looking at these examples helped me as well:
https://github.com/lightbend/config/tree/main/examples/scala
Use ConfigFactory.parseFile for other locations
I need to write a program where I run a set of instructions and create a file in a directory. Once the file is created, when the same code block is run again, it should not run the same set of instructions since it has already been executed before, here the file is used as a guard.
var Directory: String = "Dir1"
var dir: File = new File("Directory");
dir.mkdir();
var FileName: String = Directory + File.separator + "samplefile" + ".log"
val FileObj: File = new File(FileName)
if(!FileObj.exists())
// blahblah
else
{
// set of instructions to create the file
}
When the programs runs initially, the file won't be present, so it should run the set of instructions in else and also create the file, and after the first run, the second run it should exit since the file exists.
The problem is that I do not understand new File, and when the file is created? Should I use file.CreateNewFile? Also, how to write this in functional style using case?
It's important to understand that a java.io.File is not a physical file on the file system, but a representation of a pathname -- per the javadoc: "An abstract representation of file and directory pathnames". So new File(...) has nothing to do with creating an actual file - you are just defining a pathname, which may or may not correspond to an existing file.
To create an empty file, you can use:
val file = new File("filepath/filename")
file.createNewFile();
If running on JRE 7 or higher, you can use the new java.nio.file API:
val path = Paths.get("filepath/filename")
Files.createFile(path)
If you're not happy with the default IO APIs, you an consider a number of alternative. Scala-specific ones that I know of are:
scala-io
rapture.io
Or you can use libraries from the Java world, such as Google Guava or Apache Commons IO.
Edit: One thing I did not consider initially: I understood "creating a file" as "creating an empty file"; but if you intend to write something immediately in the file, you generally don't need to create an empty file first.
How do I run a JMeter test case from Java code?
I have followed the example Here from Blazemeter.com
My code is as follows:
public class BasicSampler {
public static void main(String[] argv) throws Exception {
// JMeter Engine
StandardJMeterEngine jmeter = new StandardJMeterEngine();
// Initialize Properties, logging, locale, etc.
JMeterUtils.loadJMeterProperties("/home/stone/Workbench/automated-testing/apache-jmeter-2.11/bin/jmeter.properties");
JMeterUtils.setJMeterHome("/home/stone/Workbench/automated-testing/apache-jmeter-2.11");
JMeterUtils.initLogging();// you can comment this line out to see extra log messages of i.e. DEBUG level
JMeterUtils.initLocale();
// Initialize JMeter SaveService
SaveService.loadProperties();
// Load existing .jmx Test Plan
FileInputStream in = new FileInputStream("/home/stone/Workbench/automated-testing/apache-jmeter-2.11/bin/examples/CSVSample.jmx");
HashTree testPlanTree = SaveService.loadTree(in);
in.close();
// Run JMeter Test
jmeter.configure(testPlanTree);
jmeter.run();
}
}
but I keep getting the following messages in the console and my test never executes.
INFO 2014-09-23 12:04:40.492 [jmeter.e] (): Listeners will be started after enabling running version
INFO 2014-09-23 12:04:40.511 [jmeter.e] (): To revert to the earlier behaviour, define jmeterengine.startlistenerslater=false
I have also tried uncommented jmeterengine.startlistenerslater=false from jmeter.properties file
How do you know that your "test never executes"?
What is in jmeter.log file (it should be in the root of your project). Or alternatively comment JMeterUtils.initLogging() line to see the full output in STDOUT
Have you changed relative path CSVSample_user.csv in "Get user details" CSV Data Set Config as it may resolve into a different location as it recommended in Using CSV DATA SET CONFIG
Is CSVSample.jtl file generated anywhere (again it should be in the root of your project by default)? What is in it?
The code looks good and I'm pretty sure that the problem is with the path to CSVSample_user.csv file and you have something like java.io.FileNotFoundException in your log. Please double check that CSVSample.jmx file contains valid full path to CSVSample_user.csv.
UPDATE TO ANSWER QUESTIONS IN COMMENTS
jmeter.log file should be under your Eclipse workspace folder by default
Looking into CSVSample.jmx there is a View Resulst in Table listener which is configured to store results under ~/CSVSample.jtl
If you want to see summarizer messages and "classic" .jtl reporting add next few lines before jmeter.configure(testPlanTree); stanza
Summariser summer = null;
String summariserName = JMeterUtils.getPropDefault("summariser.name", "summary");
if (summariserName.length() > 0) {
summer = new Summariser(summariserName);
}
String logFile = "/path/to/jtl/results/file.jtl";
ResultCollector logger = new ResultCollector(summer);
logger.setFilename(logFile);
testPlanTree.add(testPlanTree.getArray()[0], logger);
Try using library - https://github.com/abstracta/jmeter-java-dsl.
It supports implementing JMeter test as java code.
Below example shows how to implement and execute test for REST API. Same approach could be applied to other type of tests as well.
#Test
public void testPerformance() throws IOException {
TestPlanStats stats = testPlan(
threadGroup(2, 10,
httpSampler("http://my.service")
.post("{\"name\": \"test\"}", Type.APPLICATION_JSON)
),
//this is just to log details of each request stats
jtlWriter("test" + Instant.now().toString().replace(":", "-") + ".jtl")
).run();
assertThat(stats.overall().elapsedTimePercentile99()).isLessThan(Duration.ofSeconds(5));
}
My code connects to a gmail account and reads each email received. I retrieve the content of the email message. I use javamail api for that.
When I run the code from eclipse, it works absolutely fine. But if I export everything into a jar file and then run from command prompt, then I get the following error :
java.lang.ClassCastException: com.sun.mail.imap.IMAPInputStream cannot be cast to javax.mail.Multipart
in the following line :
Multipart mp = (Multipart) msg.getContent();
I tried using this but it doesn't help :
public static void main(String[] args) throws Exception {
System.out.println("Begin");
Thread.currentThread().setContextClassLoader(getOldIds.class.getClassLoader());
//read emails
}
Properties props = System.getProperties();
props.setProperty("mail.store.protocol", "imaps");
Session session = Session.getInstance(props, null);
Store store = session.getStore("imaps");
store.connect("imap.gmail.com", -1, "username", "password");
//fetch the message from the inbox
Please suggest me what should be done.
Thanks
Add this line to your code :-
MimeMessage mimemsg = new MimeMessage(msg);
Multipart mp = (Multipart) mimemsg.getContent();
instead of :-
Multipart mp = (Multipart) msg.getContent();
Here I am safely assuming that msg if of type com.sun.mail.imap.IMAPMessage
How are you exporting everything into a jar file?
If you're combining all your application classes and all the JavaMail classes from the mail.jar file into a single new jar file, you're missing the resource files from the mail.jar file that configure the mapping from MIME type to Java class.
Your application classes should be in one jar file and that jar file should reference or use the JavaMail jar file, e.g., on the CLASSPATH when the application runs.
Thanks everyone for help...... the approach below worked for me :
BufferedReader br = new BufferedReader( new InputStreamReader(msg.getInputStream()));
content="";
String line;
while((line=br.readLine())!=null){
content = content + line;
}
System.out.println("\n\n" + content);
br.close();
I have the following code structure:
Projects/
classes/
performance/AcPerformance.class
resources/
Aircraft/
allAircraft.txt
I have the contents of the classes folder in a JAR and my AcPerformance scala code is trying to read the contents of the Aircraft folder text files. My code:
val AircraftPerf = getClass.getResource("resources/Aircraft").getFile
val dataDir = new File(AircraftPerf)
val acFile = new File(dataDir, "allAircraft.txt")
for (line <- linesFromResource(acFile)) {
// read in lines
}
When I try to run the code I get the following error:
Caused by: java.io.FileNotFoundException: C:\Projects\file:\C:\Projects\libraries\aircraft.jar!\Aircraft\allAircraft.txt (The filename, directory name, or volume label syntax is incorrect)
Is this the correct way to read the contents of a JAR? THanks!
No, URL's getFile isn't going to do what you want here—the path it gives you isn't a file system path that you could use in a File constructor. You'd be best off using getResourceAsStream and the full path to the resource:
val in = getClass.getResourceAsStream("/resources/Aircraft/allAircraft.txt")
Note that you also need to preface the path with / to make it absolute—in your current version you're looking for a resources directory under performance.