i am writing a plugin for openfire. in this plugin i want to create node and subscribe clients to this node. i am successful in creating the nodes but i am unable to subscribe client to it. i am using this code to subscibe client but no use.
Node retreived = pubsub.getNode(nodeId);
NodeSubscription subscription = new NodeSubscription(retreived,
new JID("dinga#exalanche"), new JID("dinga#exalanche"),
State.subscribed, "sdfsdfdsds");
retreived.addSubscription(subscription);
retreived.approveSubscription(subscription, true);
retreived.saveToDB();
atlast i have found it. it was simple
just one line
retreived.createSubscription(null, new JID("dinga#exalanche"), new JID("dinga#exalanche"), false, null);
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Please take a look at the images. The response that I am getting on IBM UI side is not showing in the Java console. It is empty or null, but the intent is hit correctly.
I am developing a chatbot using the java watson conversation api, but I am facing an error while hitting the child node. Is it a context issue or something else? I am not able to figure it out. I attached the code.
Please help.
input_gui is user input
MessageRequest newMessage = new
MessageRequest.Builder().inputText(input_gui).context(context).build();
MessageResponse response = conversationService.message(workspaceId, newMessage).execute();
newMessage = new MessageRequest.Builder()
.inputText(input_gui)
.context(response.getContext()) // output context from the first message
.build();
System.out.println("watson response"+response);
Please look at image i am attaching. This image is .......
Here is working code I got my error I called service credential every time so context get initialize on every input message that why I am not able to get single conversation id in conversation now it's working
MessageRequest newMessage = new MessageRequest.Builder().inputText(input).context(context).build();
MessageResponse response = service.message(WORKSPACE_ID,newMessage).execute();
context = response.getContext();
System.out.println(response);
I'm not one expert in Java but, trying to help you, check the Java SDK examples for Watson Conversation. You can check out this project from IBM Developers, they are using Conversation Service with Java.
See the code that I did a few months ago for one test:
MessageRequest.Builder messageRequestBuilder = new MessageRequest.Builder();
messageRequestBuilder.inputText(input_gui);
messageRequestBuilder.context(question.context); //this context comes from a previous step
ServiceCall<MessageResponse> response = conversationService.message(workspaceId, messageRequestBuilder.build());
MessageResponse mAnswer = response.execute();
Object textObject = mAnswer.getOutput().get("text");
I am currently using the ServicePartitionResolver to get the http endpoint of another application within my cluster.
var resolver = ServicePartitionResolver.GetDefault();
var partition = await resolver.ResolveAsync(serviceUri, partitionKey ?? ServicePartitionKey.Singleton, CancellationToken.None);
var endpoints = JObject.Parse(partition.GetEndpoint().Address)["Endpoints"];
return endpoints[endpointName].ToString().TrimEnd('/');
This works as expected, however if I redeploy my target application and its port changes on my local dev box, the source application still returns the old endpoint (which is now invalid). Is there a cache somewhere that I can clear? Or is this a bug?
Yes, they are cached. If you know that the partition is no longer valid, or if you receive an error, you can call the resolver.ResolveAsync() that has an overload that takes the earlier ResolvedServicePartition previousRsp, which triggers a refresh.
This api-overload is used in cases where the client knows that the
resolved service partition that it has is no longer valid.
See this article too.
Yes. They are cached. There are 2 solutions to overcome this.
The simplest code change that you need to do is replace var resolver = ServicePartitionResolver.GetDefault(); with var resolver = new ServicePartitionResolver();. This forces the service to create a new ServicePartitionResolver object to every time. Whereas, GetDefault() gets the cached object.
[Recommended] The right way of handling this is to implement a custom CommunicationClientFactory that implements CommunicationClientFactoryBase. And then initialize a ServicePartitionClient and call InvokeWithRetryAsync. It is documented clearly in Service Communication in the Communication clients and factories section.
Recently, I was tasked to do a simple chat app for iOS, using Swift.. So, I have a parse server ready and running! All I want to know, is how to use triggers..
Let's say I have opened a conversation and I just received a new message. How can I get it, without constantly checking for new messages? I saw that cloud code is probably the way to go, but if it is so, is it practical? I mean, if I have 5000 users and they are constantly chatting, will it perform well?
Thanks in advance!
You want to use Parse LiveQuery component.
Add Live Query to your server's config:
let api = new ParseServer({
...,
liveQuery: {
classNames: ['Test', 'TestAgain']
}
});
// Initialize a LiveQuery server instance, app is the express app of your Parse Server
let httpServer = require('http').createServer(app);
httpServer.listen(port);
var parseLiveQueryServer = ParseServer.createLiveQueryServer(httpServer);
Install Parse LiveQuery library as a pod to your project (pod 'ParseLiveQuery').
Subscribe for events:
let myQuery = Message.query()!.where("user", equalTo: PFUser.currentUser()!)
let subscription: Subscription<Message> = myQuery.subscribe()
Handle events:
subscription.handleEvent { query, event in
// Handle event
// This callback gets called every time an object is created, updated, deleted etc.
}
I am trying to implement a proof of concept service bus using MassTransit. I have three applications which need to communicate changes of a common entity type between each other. So when the user updates the entity in one application, the other two are notified.
Each application is configured as follows with their own queue:
bus = ServiceBusFactory.New(sbc =>
{
sbc.UseMsmq();
sbc.VerifyMsmqConfiguration();
sbc.ReceiveFrom("msmq://localhost/app1_queue");
sbc.UseSubscriptionService("msmq://localhost/subscription");
sbc.UseControlBus();
sbc.Subscribe(subs =>
{
subs.Handler<IMessage1>(IMessage1_Received);
});
});
There is also a subscription service application configured as follows:
subscriptionBus = ServiceBusFactory.New(sbc =>
{
sbc.UseMsmq();
sbc.VerifyMsmqConfiguration();
sbc.ReceiveFrom("msmq://localhost/subscription");
});
var subscriptionSagas = new InMemorySagaRepository<SubscriptionSaga>();
var subscriptionClientSagas = new InMemorySagaRepository<SubscriptionClientSaga>();
subscriptionService = new SubscriptionService(subscriptionBus, subscriptionSagas, subscriptionClientSagas);
subscriptionService.Start();
The problem is that when one of the applications publishes a message, all three applications receive it (including the original sender).
Is there any way to avoid this (without resorting to adding the application name to the message)?
Thanks,
G
So MassTransit is a pub/sub system. If you publish a message, everyone registered to receive it will. If you need only some endpoints to receive it, then you really need to directly send. It's just how this works.
You could include the source in your message and discard messages that aren't of interest to you. If you implement the Consumes.Accept interface, I think the Accept method would allow you to do so easily without mixing that into the normal consumption code.
I am trying to discover items that a pubsub service provides. When I log into the target server, I can get the response successfully. But when I connect bu do not login, it gives a bad request error.
This is the code:
ConnectionConfiguration config = new ConnectionConfiguration(serverAddress, 5222);
config.setServiceName(serviceName);
connection = new XMPPConnection(config);
connection.connect();
connection.login(userName, password); //!!!when I remove this line, bad request error is received
ServiceDiscoveryManager discoManager = ServiceDiscoveryManager.getInstanceFor(connection);
DiscoverItems items;
try {
items = discoManager.discoverItems("pubsubservice." + serverName);
} catch (XMPPException e) {
e.printStackTrace();
}
Is there a way to discover items when the user is not logged in, but the connection is established?
No, you must authenticate to send stanzas to any JID in XMPP (otherwise they would not be able to reply to you, since they wouldn't know your address).
Perhaps one option for you is anonymous authentication. Most servers support it, and it creates a temporary account on the server for you, with a temporary JID. You don't need a password, and login time is quick.
#MattJ is correct and you could try using anon login. That will get you part way there.
Your current request will only get you the nodes though, after which you will have to get the items for each node. It would be simpler to use PubsubManager to get the information you want since it provides convenience methods for accessing/using all things pubsub.
Try the documentation here, the getAffiliations() method is what you are looking for.
BTW, I believe the typical default service name for pubsub is pubsub not pubsubservice. At least this is the case for Openfire.