I have question about the other options... i have form like this...
<form action="edit.php" method="post">
.
.
.
.
<button class="btn btn-success" name="submit_mult" type="submit">Edit</button>
</form>
I have another button called (delete) inside of above form in same page that will take action to delete.php page.
But the delete button is need to action to delete.php, but is already used up with action="edit.php" see above codes
How can i solve that to make both works!
AM
You can use the formaction attribute on the button:
<button type="submit" formaction="delete.php">Delete</button>
This overrides the action attribute of the form when you click on that button.
Related
If I create a form using form tag helper the submit button triggers the OnPost event
<form method="post" asp-page="login">
However if I use
<form method="post" action="/auth/login">
The OnPost event is not fired.
And yes, asp-page="login" translates tp "/auth/login".
Even if I use asp-page="login" and copy the url from the console inspector and paste onto my cshtml page, a blank page is returned.
Any thoughts?
You can try to add #Html.AntiForgeryToken() into the second form.When you use the second form,it will lose a hidden input which contains the antiforgery token.
<form method="post" action="/auth/login">
#Html.AntiForgeryToken()
<input type="submit" value="submit" />
</form>
Seems like a common question but could not find on this site. Must be due to my lack of experience in jquery or ajax.
I have a form like this:
<form id="form1">
+Add Item
</form>
when the person clicks "+Add Item" it pops up a new page which allows him to navigate and click the desired checkbox. Then it should insert in the above form something like:
<input type="hidden" name="item1_id" value="4">Item 1<br>
where value="4" would be the id of the checkbox checked.
any help would be greatly appreciated.
Don't use an anchor tag. Instead, create a div container for your pop up, which you can load dynamically:
$('#container').load('add-item.php');
Then add a listener to your item buttons append the result in your form:
$("#item_1").click(function() {
var $newinput = $("<input type='hidden' />");
$newinput.val(4);
$newinput.attr("name","item1_id")
$("#form1").append($newinput,"Item 1<br>");
});
Good Day
I am using an ASP.NET webform where I have wrapped the following button inside the form tags:
<form runat="server">
<button class="btn btn-primary" onclick="window.location='http://google.co.za';">Login</button>
</form>
ISSUE: The problem is that when clicking on the button, it just directs to the current page...does not redirect. However, when I remove the form tags, the button works. If I leave the form tags and I use an anchor tag to relocate, it works as well...It is just the button that is giving me issues.
Why is that?
I am using Twitter bootstrap as well(extra info..)
Thank you
Add type="button" attribute to your button tag. Without it button works as submit.
I need to get the value from outside the form. My gsp looks like this
<g:textField name="email" value="${someInstance?.email}"/>
<input type="button" id="checkEmail" class="button" value="Validate" onclick="checkEmail()"/>
<span id="responseDiv"></span>
<g:form action="save">
someCode
<g:submitButton disabled="true" style="color:#999999;" class="save" name="save" action="save" id="saveButton" value="${message(code: 'default.button.save.label', default: 'Submit')}"/>
</g:form>
First, to check if an email is in use, click button (id="checkEmail") and onclick goes to js code checkEmail() which has remoteFunction that updates responseDiv. After that, user enters information to the form, and user clicks submitButton. When that submit button is clicked, I would like my gsp to send email value along with other information to the controller. Any suggestion?
Thanks in advance.
Easy, put the input inside the form.
If that isn't an option for some reason, use the callback to update a hidden field inside the form with something like $("#hiddenEmail").val(emailAddress);
PS. I like how you gave a span an id of responseDiv :)
I have set up a bootstrap modal with a form inside it, I just noticed that when I press the Enter key, the modal gets dismissed.
Is there a way not to dismiss it when pressing Enter?
I tried activating the modal with keyboard:false, but that only prevents dismissal with the ESC key.
I just had this problem too.
My problem was that i had a close button in my modal
<button class="close" data-dismiss="modal">×</button>
Pressing enter in the input field caused this button to be fired. I changed it to an anchor instead and it works as expected now (enter submits the form and does not close the modal).
<a class="close" data-dismiss="modal">×</a>
Without seeing your source, I can't confirm that your cause is the same though.
Just add the type="button" attribute to the button element, some browsers interpret the type as submit by default.
https://developer.mozilla.org/en-US/docs/Web/HTML/Element/button#Attributes
This applies for all the buttons you have in the modal.
<button type="button" class="close" data-dismiss="modal">×</button>
I had this problem even after removing ALL buttons from my Bootstrap Modal, so none of the solutions here helped me.
I found that a form with a single text field would cause the browser to do a form submit (and result in dismiss), if you hit Enter while keyboard focus is on the text field. This seems to be more of a browser/form issue than anything with Bootstrap.
My solution was to set the form's onsubmit attribute to onsubmit="return false"
This may be a problem if you are actually using the submit event, but I'm using JS frameworks that generate AJAX requests rather than doing a browser submit, so I prefer disabling submit entirely. (It also means I don't have to manually tweak every form element that might trigger a submit).
More info here: Bootstrap modal dialogs with a single text input field always dismiss on Enter key
I had same problem, and i solved it with
<form onsubmit="return false;">
but there is one more solution, you can add dummy invisible input, so your form would look like this:
<form role="form" method="post" action="submitform.php">
<input type="text" id="name" name="name" >
<input type="text" style="display: none;">
</form>
You can put the login button before the cancel button and this would solve the issue you are having as well.
<div class="modal-footer">
<button type="submit" class="btn primary">Login</button>
<button type="submit" class="btn" data-dismiss="modal">Cancel</button>
</div>
I had a similar experience just now and the way I solved it was instead of using a tag, I changed the tag to an tag with type="button". This seemed to solve the problem of pressing the "enter" key and dismissing the bootstrap modal.
I had this problem too and I solved it this way. I added onsubmit to form. I also wanted to be able to use enter key as a saving key so I added save_stuff() javascript to onsubmit. return false; is used to prevent the form submit.
<form onsubmit="save_stuff(); return false;">
...
</form>
<script>
function save_stuff(){
//Saving stuff
}
</script>