I am trying to send the HTML response form the Ajax Call. Exactly I want to render a JSP and return the resulted HTML String as the response.
I tried to follow the steps given in the following post. https://www.liferay.com/community/forums/-/message_boards/message/4940181
But I could not found the methods in PortalUtil class.
I am using LR6.2.
This can be done by including a jsp in the response.
getPortletContext().getRequestDispatcher("/WEB-INF/jsp/html.jsp").include(p_request, p_response);
Once the control is passed to the JSP, it will act like the normal JSPs, you can get the vales from request and go ahead with the manipulations.
Related
I got this problem, I have built a rest api and I don't know how to deal with this:
When the javascript client (Marionette.js) is in charge of making the views, I don't have problems, because as it is known, it just requests an url (e.g. example.com/user/37), the server retrieves a json with {id:'37', name:'Peter', age:'24'} (there is one controller class named User) and Marionette shows that data in the view. But if the user enter to example.com/user/37 by the browser it will show just {id:'37', name:'Peter', age:'24'} without any view. What can I do if I want to see the same view in both cases?
If you're trying to serve up HTML or JSON from the same endpoint then your server should be making that decision based on the request's Accept header. If the request's Accept header is application/json then your server should return just the JSON ortherwise return the HTML.
You can see that SoundCloud uses the same technique for returning XML or JSON from their API:
Resources are returned as XML by default, or JSON if a .json extension is appended to the resource URI. We encourage you to use JSON. You can also send an appropriate Accept header specifying the format you would like. For example, a request with the header Accept: application/json will return resources represented as a JSON document.
What you are trying to do is pratically impossible.
why ?
When your first enter the url example.com it's the server that responds with all the artifacts that compose your application (html, js, css ...) and the browser display it.
Now, when you enter ther url example.com/user/37 the server only sends the JSON data without any html, js or css, so the browser display the raw data he received.
What you are trying to do is to force the server to give two responses (JSON or html/js/css) depending on the user request.
You can do it, but it would be so complicated that's not worth the efforts.
Given a one page app that uses push state and RESTful backend, we can imagine accessing the listing of a resource at /resourceName (i.e. /users). So /users would create a formated list of users
Now the problem is that this resource JSON or XML feed should also be mapped to /resourceName, so if boot form my application entry point at / then all is good, when navigating to /users the JS router can trigger a Ajax call that get the JSON data. Now the problem is if the URL is pointing directly at /users then i will land on a JSON feed instead of the actual listing. I could route all call to a main entry point and then let the JS router do the work though if i do so the AJAX call to fetch JSON wil brake.
I remember a while ago people adding .json to their json request, or even a GET parameter ?format=json and then having the controller taking different actions. I find that somewhat hacky.. Are there any other ways to go about this?
For that matter i am using laravel4 backend and backboneJS
I think the .json on the end of the request is the best approach. the other approach could be to create a separate endpoint endpoint for api request api.mydomain.com vs www.mydomain.com
What method you use to get a different response depends on how you'd like to go about it. Since you're asking about an opinionated topic (There is no one right answer), here's some options you can explore.
First, here's a good read from Apigee on API design, which covers what I'll write about here. See page 20 on "Support multiple formats"
The Rails way: Append a .json, .xml or other extension at the end of your request and handle that code within Laravel (You may want to use the "before" filter to check the request or Laravel's excellent route parameters, which allow the use of regex to define the route).
You can check the "accept" header in the request and set that header in your ajax calls to "application/json" instead of the default "application/html" to inform your application which format to use in its response. Again, the before or after filters may come in handy to check the request and define the response as appropriate
Create a query string `?format=json" or similar. Same comments as in point 1.
Laravel doesn't have built-in methods to change the response for you. You can, however, fairly easily detect what's being asked and choose which format to return in. It does take some thinking about how you want to accomplish that, however.
Some options off the top of my head:
Use the "before" or "after" filter to check what the request "wants" for a format, and do some transformations on the response to make that work
Extend the request and response class to "automate" this (request class to detect format, response class to transform the response to the correct format)
Hope that helps
It's valid to say which representation do you want. E.g. JSON, XML or binary, depends on what you want and which serializers have you developed.
You framework should support either setting of default representation or if you provide some mapping URL -> method you should be able to say which representation you are going to return - also either by default or taken within some object which represents your request.
I ended up using different endpoints as suggested by #Aaron Saunders. In laravel 4 this is dumb easy to implement using group routes:
app.php:
'domain' => 'whatever.dev',
routes.php:
define('APP_DOMAIN', 'app.' . Config::get('app.domain'));
define('API_DOMAIN', 'api.' . Config::get('app.domain'));
Route::group(array('domain' => API_DOMAIN), function()
{
// API ROUTES
});
Route::group(array('domain' => APP_DOMAIN), function()
{
// VIEW ROUTES
});
Beautiful!
I'm working on a REST API using the FOSRestBundle and I'd like to be able to use the same URL for returning HTML and JSON depending on the request Accept header; i.e. if you call the URL directly from a browser (Accept : text/html etc) HTML is returned from a twig file, if you are making an AJAX request (Accept : application/JSON etc), JSON is returned using the FOSRestBundle.
Currently I can get this to work by throwing a small if statement at the top of each function to check the request accept header, if it's asking for HTML it returns the twig file, if it's asking for JSON it hits the service.
You should rather send "Accept" header with your requests. Read content negotiation (“Accept” HTTP header) based routing in symfony2.0 and Format listener.
The request scope does not exist when run in command line mode, I had to remove request from each constructor and the problem disappeared.
I'm using GWT to develop a web app. I'm currently using AJAX calls to retrieve values from the server. I have following queries regarding to AJAX calls:
Assume: I have an app, name of which is: "Application" and the entry point class is: "entry.java"
I know: the application could be invoked as: http://localhost:8080/Application/entry.html
1. I would like to know what what is the output URL given by gwt.getmodulebaseURL()?
Assume: In the same application I have a service called "ServerValuesService" and its corresponding Async. I have corresponding serviceImpl, which has a method called List < String >search(String) at the server side.
I could retrieve the values from the server as well. However,
2. I would like to know what would be the direct URL to access this service? For Instance, I need to obtain the list of values, by just giving a URL (passing value for the String). i.e. I need to access the method search(String) and retrieve the list just by typing a url such as:
http://localhost:8080/Application/entry/serverValuesService?string="hello"
I'm sure the above URL is wrong. I need to know exact conversion between URL and the corresponding service. Is this possible at all?
Thanks in advance!
1) In your case it will give you http://localhost:8080/Application . Application is your modulename.
2) These services are actually HttpServlets and their URL's are defined in the web.xml file. But Google uses POST method to send your variables and takes care of serialization for you, what you are trying to do is send it via GET method which is as far as I know not implemented by Google RemoteServiceServlet.So I would say no its not possible unless you extend these services to work with GET methods yourself but I don't know if that is possible.
Assume: I have an app, name of which is: "Application" and the entry point class is: "entry.java"
I know: the application could be invoked as: http://localhost:8080/Application/entry.html
The url http://localhost:8080/Application/entry.html is called host page url. In this html page you load your GWT module using a script tag:
<!-- This script tag is what actually loads the GWT module. The -->
<!-- 'nocache.js' file (also called a "selection script") is -->
<!-- produced by the GWT compiler in the module output directory -->
<!-- or generated automatically in hosted mode. -->
<script language="javascript" src="calendar/calendar.nocache.js"></script>
So if you put above example in your entry.html, the module will be loaded from http://localhost:8080/Application/calendar/calendar.nocache.js making http://localhost:8080/Application/calendar/ your module base url.
I would like to know what would be the direct URL to access this
service? For Instance, I need to obtain the list of values, by just
giving a URL (passing value for the String). i.e. I need to access the
method search(String) and retrieve the list just by typing a url
GWT RPC use a custom serialization format to encode requests to the RPC Service on server. The RPC service is implemented as a subclass of RemoteServiceServlet on the server. The RemoteServiceServlet handles the http POST requests, de-serializing the request from client and invvoking appropriate service method of sub-class.
So for directly accessing the service you'll need:
1. The service URL
2. Request payload encoded in GWT's custom serialization format
3. Ability to HTTP POST the payload to the Service URL
1 and 3 are easy to acquire. You already know the URL at which your service is mapped in web.xml. And you can do post from any http client or browser plugins like this. The hard-part would be to generate request payload in GWT's custom serialization format. For simple cases, you can generate a request from your application and capture the raw payload from Firebug, Fiddler or similar tool and simply replay it using your http client.
i've got a wicket form, which when submitted should give users a file to download. the file is generated by an external servlet (based on the form), which writes generated content to response's output stream.
normally this can be done using getRequestCycle().setRequestTarget(new RedirectRequestTarget(redirectUrl); on form submit, where redirectUrl will be the external servlet's url with parameters.
however, redirectUrl shows up in browser's address bar, which is not good as users see parameter values, which they shouldn't.
in order to overcome that, i've implemented a custom DynamicWebResource, which fetches the servlet output as byte[] and is bound to a virtual url through usual wicket shared resource mechanism.
on form submit i do the following:
RequestParameters rps = new RequestParameters();
rps.setResourceKey(new ResourceReference("myResource").getSharedResourceKey());
getRequestCycle().setRequestTarget(new SharedResourceRequestTarget(rps));
and then rely on wicket's internal ways of handling.
when debugging i can clearly see that my shared resource is correctly invoked, the external servlet's response is correctly generated, fetched and then written to current response with all the headers and stuff, but nothing happens after that, no errors, just nothing.
when i call my shared resource directly specifying the url wicket has bound it to (like http://localhost:8080/webAppRoot/wicket/myResource?param1=value) - everything works, file is well-formed and downloadable.
is there something additional i have to do? it's most probably something stupid, but i've been banging my head agains the wall for a day already...
problem solved. the reason for the response not to be processed by the browser was the fact that the form was submitted using AJAX. changing submit type to plain solved the issue.