I have data similar to one given below:
ID UserID PlayerID Name
1 56 21 A
2 57 34 B
3 77 77 C
4 65 23 D
5 77 77 E
I want the rows with same value in UserID and PlayerID column to be at the top.
I have currently done this:
select * from tblTest
order by abs(UserID - PlayerID ) asc
Any better way to achieve this result?
Try this
SELECT * From tblTest
Order By Case When UserID = PlayerID Then 0 Else 1 End
Related
I have a following question:
create table memorization_word_translation
(
id serial not null
from_word_id integer not null
to_word_id integer not null
);
This table stores pairs of integers, that are often in reverse order, for example:
35 36
35 37
36 35
37 35
37 39
39 37
Question is - if I make a query, for example:
select * from memorization_word_translation
where from_word_id = 35 or to_word_id = 35
I would get
35 36
35 37
36 35 - duplicate of 35 36
37 35 - duplicate of 35 37
How is to use DISTINCT in this example to filter out all duplicates even if they are reversed?
I want to keep it only like this:
35 36
35 37
You can do it with ROW_NUMBER() window function:
select from_word_id, to_word_id
from (
select *,
row_number() over (
partition by least(from_word_id, to_word_id),
greatest(from_word_id, to_word_id)
order by (from_word_id > to_word_id)::int
) rn
from memorization_word_translation
where 35 in (from_word_id, to_word_id)
) t
where rn = 1
See the demo.
demo:db<>fiddle
You could try a it with a small sorting algorithm (here a comparison) in combination with DISTINCT ON.
The DISTINCT ON clause works an arbitrary columns or terms, e.g. on a tuple. This CASE clause sorts the two columns into tuples and removes tied (ordered) ones. The source columns can be returned in your SELECT statement:
select distinct on (
CASE
WHEN (from_word_id >= to_word_id) THEN (from_word_id, to_word_id)
ELSE (to_word_id, from_word_id)
END
)
*
from memorization_word_translation
where from_word_id = 35 or to_word_id = 35
I'm trying to write a query that will include a count for the primary and secondary activity only when Group ID = 260 and Item id in(1302,1303,1305,1306) for each individual RecordID. So far I have been able to single out the rows with those conditions, but I only want to count the primary and secondary activities once(because the Primary and Secondary activities are the same for their corresponding RecordID regardless of how many rows there are), if they aren't null, regardless of how many RecordID's match those conditions.
RecordID: GroupID: ItemID: PrimActivity: SecActivity:
320 260 1302 36 0
320 260 6456 36 0
320 312 1303 36 0
560 400 1302 46 48
560 312 1305 46 48
460 260 1305 45 56
460 260 1302 45 56
Result I'm getting:
RecordID: Count:
320 2
460 4
Expected result:
RecordID: Count:
320 1
460 2
SELECT dfr.RecordID,
COUNT(CASE WHEN dfr.PrimActivity <> 0 and a.GroupID =260 then 1
ELSE NULL END) +
COUNT(CASE WHEN dfr.SecActivity <> 0 and a.GroupID =260 then 1 ELSE
NULL END) AS Count
From ActivityItem ai
Join DailyRecord dfr on ai.PrimActivity = dfr.PrimActivity
Join AreaInfo af on af.AreaInfoID = dfr.AreaInfoID
Join Information a on dfr.RecordID = a.RecordID
Join Lookup lp on lp.ItemID = a.ItemID
WHERE a.GroupID like '260' and EXISTS(
SELECT b.RecordID, b.GroupID, b.ItemID
FROM Areainfo b
where a.RecordID=b.RecordID and b.ItemID IN(1302,1303,1305,1306)
GROUP BY dfr.RecordID
You should be more clear when you explain the structure of tables you are using. However, I reach the expected result starting from your sample table doing this:
SELECT RecordID,COUNT(*) as Count
FROM (SELECT DISTINCT RecordID,ItemID,PrimActivity,SecActivity
FROM [TABLE YOU POSTED]
WHERE GroupID = 260 and ItemID in (1302,1303,1305,1306) ) A
GROUP BY RecordID
I have a table that contains 3 columns of ids, clothes, shoes, customers and relates them.
I have a query that works fine :
select clothes, shoes from table where customers = 101 (all clothes and shoes of customer 101). This returns
clothes - shoes (SET A)
1 6
1 2
33 12
24 null
Another query that works fine :
select clothes ,shoes from table
where customers in
(select customers from table where clothes = 1 and customers <> 101 ) (all clothes and shoes of any other customer than 101, with specified clothes). This returns
shoes - clothes(SET B)
6 null
null 24
1 1
2 1
12 null
null 26
14 null
Now I want to get all clothes and shoes from SET A that are not in SET B.
So (example) select from SET A where NOT IN SET B. This should return just clothes 33, right?
I try to convert this to a working query :
select clothes, shoes from table where customers = 101
and
(clothes,shoes) not in
(
select clothes,shoes from
table where customers in
(select customers from table where clothes = 1 and customers <> 101 )
) ;
I tried different syntaxes, but the above looks more logic.
Problem is I never get clothes 33, just an empty set.
How do I fix this? What goes wrong?
Thanks
Edit , here is the contents of the table
id shoes customers clothes
1 1 1 1
2 1 4 1
3 1 5 1
4 2 2 2
5 2 3 1
6 1 3 1
44 2 101 1
46 6 101 1
49 12 101 33
51 13 102
52 101 24
59 107 51
60 107 24
62 23 108 51
63 23 108 2
93 124 25
95 6 125
98 127 25
100 3 128
103 24 131
104 25 132
105 102 28
106 10 102
107 23 133
108 4 26
109 6 4
110 4 24
111 12 4
112 14 4
116 102 48
117 102 24
118 102 25
119 102 26
120 102 29
122 134 31
The except clause in PostgreSQL works the way the minus operator does in Oracle. I think that will give you what you want.
I think notionally your query looks right, but I suspect those pesky nulls are impacting your results. Just like a null is not-NOT equal to 5 (it's nothing, therefore it's neither equal to nor not equal to anything), a null is also not-NOT "in" anything...
select clothes, shoes
from table1
where customers = 101
except
select clothes, shoes
from table1
where customers in (
select customers
from table1
where clothes = 1 and customers != 101
)
For PostgreSQL null is undefined value, so You must get rid of potential nulls in your result:
select id,clothes,shoes from t1 where customers = 101 -- or select id...
and (
clothes not in
(
select COALESCE(clothes,-1) from
t1 where customers in
(select customers from t1 where clothes = 1 and customers <> 101 )
)
OR
shoes not in
(
select COALESCE(shoes,-1) from
t1 where customers in
(select customers from t1 where clothes = 1 and customers <> 101 )
)
)
if You wanted unique pairs you would use:
select clothes, shoes from t1 where customers = 101
and
(clothes,shoes) not in
(
select coalesce(clothes,-1),coalesce(shoes,-1) from
t1 where customers in
(select customers from t1 where clothes = 1 and customers <> 101 )
) ;
You can't get "clothes 33" if You are selecting both clothes and shoes columns...
Also if u need to know exactly which column, clothes or shoes was unique to this customer, You might use this little "hack":
select id,clothes,-1 AS shoes from t1 where customers = 101
and
clothes not in
(
select COALESCE(clothes,-1) from
t1 where customers in
(select customers from t1 where clothes = 1 and customers <> 101)
)
UNION
select id,-1,shoes from t1 where customers = 101
and
shoes not in
(
select COALESCE(shoes,-1) from
t1 where customers in
(select customers from t1 where clothes = 1 and customers <> 101)
)
And Your result would be:
id=49, clothes=33, shoes=-1
(I assume that there aren't any clothes or shoes with id -1, You may put any exotic value here)
Cheers
Hi if I have the following table:
Person------Score-------Score_type
1 30 A
1 35 A
1 15 B
1 16 B
2 74 A
2 68 A
2 40 B
2 39 B
Where for each person and score type I want to pick out the maximum score to obtain a table like:
Person------Score-------Score_type
1 35 A
1 16 B
2 74 A
2 40 B
I can do this using multiple select statements, but this will be cumbersome, especially later on. so I was wondering if there is a function which can help me do this. I have used the parititon function before but only to label sequences in a table....
select person,
score_type,
max(score) as score
from scores
group by person, score_type
order by person, score_type;
With "partition function" I guess you mean window functions. They can indeed be used for this as well:
select person
score_type,
score
from (
select person,
score_type,
score,
row_number() over (partition by person, score_type order by score desc) as rn
from scores
) t
where rn = 1
order by person, score_type;
Using the max() aggregate function along with the grouping by person and score_type should do the trick.
I use Oracle 10g and I have a table that stores a snapshot of data on a person for a given day. Every night an outside process adds new rows to the table for any person whose had any changes to their core data (stored elsewhere). This allows a query to be written using a date to find out what a person 'looked' like on some past day. A new row is added to the table even if only a single aspect of the person has changed--the implication being that many columns have duplicate values from slice to slice since not every detail changed in each snapshot.
Below is a data sample:
SliceID PersonID StartDt Detail1 Detail2 Detail3 Detail4 ...
1 101 08/20/09 Red Vanilla N 23
2 101 08/31/09 Orange Chocolate N 23
3 101 09/15/09 Yellow Chocolate Y 24
4 101 09/16/09 Green Chocolate N 24
5 102 01/10/09 Blue Lemon N 36
6 102 01/11/09 Indigo Lemon N 36
7 102 02/02/09 Violet Lemon Y 36
8 103 07/07/09 Red Orange N 12
9 104 01/31/09 Orange Orange N 12
10 104 10/20/09 Yellow Orange N 13
I need to write a query that pulls out time slices records where some pertinent bits, not the whole record, have changed. So, referring to the above, if I only want to know the slices in which Detail3 has changed from its previous value, then I would expect to only get rows having SliceID 1, 3 and 4 for PersonID 101 and SliceID 5 and 7 for PersonID 102 and SliceID 8 for PersonID 103 and SliceID 9 for PersonID 104.
I'm thinking I should be able to use some sort of Oracle Hierarchical Query (using CONNECT BY [PRIOR]) to get what I want, but I have not figured out how to write it yet. Perhaps YOU can help.
Thanks you for your time and consideration.
Here is my take on the LAG() solution, which is basically the same as that of egorius, but I show my workings ;)
SQL> select * from
2 (
3 select sliceid
4 , personid
5 , startdt
6 , detail3 as new_detail3
7 , lag(detail3) over (partition by personid
8 order by startdt) prev_detail3
9 from some_table
10 )
11 where prev_detail3 is null
12 or ( prev_detail3 != new_detail3 )
13 /
SLICEID PERSONID STARTDT N P
---------- ---------- --------- - -
1 101 20-AUG-09 N
3 101 15-SEP-09 Y N
4 101 16-SEP-09 N Y
5 102 10-JAN-09 N
7 102 02-FEB-09 Y N
8 103 07-JUL-09 N
9 104 31-JAN-09 N
7 rows selected.
SQL>
The point about this solution is that it hauls in results for 103 and 104, who don't have slice records where detail3 has changed. If that is a problem we can apply an additional filtration, to return only rows with changes:
SQL> with subq as (
2 select t.*
3 , row_number () over (partition by personid
4 order by sliceid ) rn
5 from
6 (
7 select sliceid
8 , personid
9 , startdt
10 , detail3 as new_detail3
11 , lag(detail3) over (partition by personid
12 order by startdt) prev_detail3
13 from some_table
14 ) t
15 where t.prev_detail3 is null
16 or ( t.prev_detail3 != t.new_detail3 )
17 )
18 select sliceid
19 , personid
20 , startdt
21 , new_detail3
22 , prev_detail3
23 from subq sq
24 where exists ( select null from subq x
25 where x.personid = sq.personid
26 and x.rn > 1 )
27 order by sliceid
28 /
SLICEID PERSONID STARTDT N P
---------- ---------- --------- - -
1 101 20-AUG-09 N
3 101 15-SEP-09 Y N
4 101 16-SEP-09 N Y
5 102 10-JAN-09 N
7 102 02-FEB-09 Y N
SQL>
edit
As egorius points out in the comments, the OP does want hits for all users, even if they haven't changed, so the first version of the query is the correct solution.
In addition to OMG Ponies' answer: if you need to query slices for all persons, you'll need partition by:
SELECT s.sliceid
, s.personid
FROM (SELECT t.sliceid,
t.personid,
t.detail3,
LAG(t.detail3) OVER (
PARTITION BY t.personid ORDER BY t.startdt
) prev_val
FROM t) s
WHERE (s.prev_val IS NULL OR s.prev_val != s.detail3)
I think you'll have better luck with the LAG function:
SELECT s.sliceid
FROM (SELECT t.sliceid,
t.personid,
t.detail3,
LAG(t.detail3) OVER (PARTITION BY t.personid ORDER BY t.startdt) 'prev_val'
FROM TABLE t) s
WHERE s.personid = 101
AND (s.prev_val IS NULL OR s.prev_val != s.detail3)
Subquery Factoring alternative:
WITH slices AS (
SELECT t.sliceid,
t.personid,
t.detail3,
LAG(t.detail3) OVER (PARTITION BY t.personid ORDER BY t.startdt) 'prev_val'
FROM TABLE t)
SELECT s.sliceid
FROM slices s
WHERE s.personid = 101
AND (s.prev_val IS NULL OR s.prev_val != s.detail3)