powershell script delete first character in output - powershell

How would I delete the first line in the output from this command? If the output is A123456, I just want it to show me 123456 with the A.
Get-User $_ | Select sAMAccountName


Just get the substring starting at the second letter(index 1).
Get-User $_ | Select #{n="AccountName";e={$_.sAMAccountName.Substring(1)}}
If you just need the value, you could do it like this:
Get-User $_ | % { $_.sAMAccountName.Substring(1) }


Substring(1) returns a substring containing all chars after the first one.
Get-User $_ | Select #{N="myAccountName";E={$_.sAMAccountName).substring(1)}}


You can remove the first character with the -replace operator:
(Get-User $_ | select -Expand sAMAccountName) -replace '^.'
Or
Get-User $_ | select #{n='sAMAccountName';e={$_.sAMAccountName -replace '^.'}}
if you want to keep objects rather than strings.


$str = "#123456";
$str = $str.Substring(1,($str.Length-1));
$str;

Related

How to make netstat output's headings show properly in out-gridview?

when I use:
netstat -f | out-gridview
in PowerShell 7.3, I get the window but it has only one column which is a string. I don't know why it's not properly creating a column for each of the headings like Proto, Local Address etc.
how can I fix this?

While commenter Toni makes a good point to use Get-NetTCPConnection | Out-GridView instead, this answer addresses the question as asked.
To be able to show output of netstat in grid view, we have to parse its textual output into objects.
Fortunately, all fields are separated by at least two space characters, so after replacing these with comma, we can simply use ConvertFrom-CSV (thanks to an idea of commenter Doug Maurer).
netstat -f |
# Skip unwanted lines at the beginning
Select-Object -skip 3 |
# Replace two or more white space characters by comma, except at start of line
ForEach-Object { $_ -replace '(?<!^)\s{2,}', ',' } |
# Convert into an object and add it to grid view
ConvertFrom-Csv | Out-GridView
For a detailed explanation of the RegEx pattern used with the -replace operator, see this RegEx101 demo page.
This is the code of my original answer, which is functionally equivalent. I'll keep it as an example of how choosing the right tool for the job can greatly simplify code.
$headers = #()
# Skip first 3 lines of output which we don't need
netstat -f | Select-Object -skip 3 | ForEach-Object {
# Split each line into columns
$columns = $_.Trim() -split '\s{2,}'
if( -not $headers ) {
# First line is the header row
$headers = $columns
}
else {
# Create an ordered hashtable
$objectProperties = [ordered] #{}
$i = 0
# Loop over the columns and use the header columns as property names
foreach( $key in $headers ) {
$objectProperties[ $key ] = $columns[ $i++ ]
}
# Convert the hashtable into an object that can be shown by Out-GridView
[PSCustomObject] $objectProperties
}
} | Out-GridView

Remove the last character of an array

i'm trying to remove the last character of an array.
I have an array with:
name1;
name2;
Now i want to remove the last ";".
I'v though on something like:
$array = $array | Select -last 1 | foreach{$_.replace(";", "")}
But thats just an idea. Also not working, because it will leave only the last entry.

To change just the last object, process every object of the array and check if it's the last. replace only on the last one:
$array = $array | ForEach-Object {
if( $array.IndexOf($_) -eq ($array.count -1) ){
$_.replace(";","")
}else{$_}
}

Try this to remove/replace last semi colon ';' from each element.
$array | foreach{ $_ -replace ';$', '' }
and if you want to remove the same from any where in the string, just remove the $

How to add quotes and commas in PowerShell?

I have a CSV file where I only need 1 Column Called "SerialNumber" I need to combine the text lines, remove any blank space, add each line in quotes and separate by comma.
So far I have multiple miles of code that work, but it adds quotes at the end and doesn't add quotes in the beginning.
$SerialList = import-csv .\log.csv | select -ExpandProperty Serialnumber | Out-File -FilePath .\Process.txt
(gc process.txt) | ? {$_.trim() -ne "" } | set-content process.txt
gc .\process.txt | %{$_ -replace '$','","'} | out-file process1.csv
Get-Content .\process1.csv| foreach {
$out = $out + $_
}
$out| Out-File .\file2.txt
Output:
SerialNumber
1234
1234
4567
4567
Expected Output:
"1234","1234","4567","4567"

Try the following (PSv3+):
(Import-Csv .\log.csv).SerialNumber -replace '^.*$', '"$&"' -join "," > .\file2.txt
(Import-Csv .\log.csv).SerialNumber imports the CSV file and .SerialNumber uses member-access enumeration to extract the SerialNumber column values as an array.
-replace '^.*$', '"$&"' encloses each array element in "...".
Regex ^.*$ matches each array element in full.
Replacement expression "$&" replaces the element with what was matched ($&) enclosed in " chars. - for background, see this answer
-join "," joins the resulting array elements with , as the separator.

How to join array in pipe

I wish to join the result from a pipe.
I tried using -join
PS> type .\bleh.log | where { $_ -match "foo"} | select -uniq | $_ -join ','
But that give me this error :/
Expressions are only allowed as the first element of a pipeline.

You could try this :
#(type .\bleh.log | where { $_ -match "foo"} | select -uniq) -join ","
You would need a Foreach-Object (alias %) after the last pipe to have the $_ variable available but it wouldn't help since it holds a single cell value (for each loop iteration).

How to change column position in powershell?

Is there any easy way how to change column position? I'm looking for a way how to move column 1 from the beginning to the and of each row and also I would like to add zero column as a second last column. Please see txt file example below.
Thank you for any suggestions.
File sample
TEXT1,02/10/2015,55.930,57.005,55.600,56.890,1890
TEXT2,02/10/2015,51.060,52.620,50.850,52.510,4935
TEXT3,02/10/2015,50.014,50.74,55.55,52.55,5551
Output:
02/10/2015,55.930,57.005,55.600,56.890,1890,0,TEXT1
02/10/2015,51.060,52.620,50.850,52.510,4935,0,TEXT2
02/10/2015,50.014,50.74,55.55,52.55,5551,0,TEXT3

Another option:
#Prepare test file
(#'
TEXT1,02/10/2015,55.930,57.005,55.600,56.890,1890
TEXT2,02/10/2015,51.060,52.620,50.850,52.510,4935
TEXT3,02/10/2015,50.014,50.74,55.55,52.55,5551
'#).split("`n") |
foreach {$_.trim()} |
sc testfile.txt
#Script starts here
$file = 'testfile.txt'
(get-content $file -ReadCount 0) |
foreach {
'{1},{2},{3},{4},{5},{6},0,{0}' -f $_.split(',')
} | Set-Content $file
#End of script
#show results
get-content $file
02/10/2015,55.930,57.005,55.600,56.890,1890,0,TEXT1
02/10/2015,51.060,52.620,50.850,52.510,4935,0,TEXT2
02/10/2015,50.014,50.74,55.55,52.55,5551,0,TEXT3

Sure, split on commas, spit the results back minus the first result joined by commas, add a 0, and then add the first result to the end and join the whole thing with commas. Something like:
$Input = #"
TEXT1,02/10/2015,55.930,57.005,55.600,56.890,1890
TEXT2,02/10/2015,51.060,52.620,50.850,52.510,4935
TEXT3,02/10/2015,50.014,50.74,55.55,52.55,5551
"# -split "`n"|ForEach{$_.trim()}
$Input|ForEach{
$split = $_.split(',')
($Split[1..($split.count-1)]-join ','),0,$split[0] -join ','
}

I created file test.txt to contain your sample data. I Assigned each field a name, "one","two","three" etc so that i could select them by name, then just selected and exported back to csv in the order you wanted.
First, add the zero to the end, it will end up as second last.
gc .\test.txt | %{ "$_,0" } | Out-File test1.txt
Then, rearrange order.
Import-Csv .\test.txt -Header "one","two","three","four","five","six","seven","eight" | Select-Object -Property two,three,four,five,six,seven,eight,one | Export-Csv test2.txt -NoTypeInformation
This will take the output file and get rid of quotes and header line if you would rather not have them.
gc .\test2.txt | %{ $_.replace('"','')} | Select-Object -Skip 1 | out-file test3.txt