Form display after submission - forms

I am trying to build a simple CMS and have run into a problem I hope you can help me with.
I have a public display page that fetches data from a MySQL database. This works fine.
I also have an admin page where the data is loaded into a form field so that a maintainer can change it.
My problem is that after hitting the submit button, the data is successfully sent to the DB but I cannot find a way to get the form to show the latest data. It is always one submit step behind.
Sample code:
<?php
//retrieve data from MySQL
mysql_connect('localhost:3306','dundryor_show','show1');
mysql_select_db('dundryor_stofl_test');
$query = mysql_query("SELECT * FROM form_test where id = '0'");
$output = mysql_fetch_array($query);
$user_text = $output['user_text'];
mysql_close();
//display form and populate
echo '<form method="post">';
echo 'This text is stored in the database and can be changed by the user:<p>';
echo '<input type="Text" name="user_text" size="50" value="';
echo $user_text;
echo '"><br><input type="Submit" name="update" value="Update Database">';
echo '</form>';
//process submit event, write new data to DB
if ($_POST['update'])
{
$user_text = $_POST['user_text'];
mysql_connect('localhost:3306','dundryor_show','show1');
mysql_select_db('dundryor_stofl_test');
mysql_query("UPDATE form_test set user_text = '$user_text' where id = '0'");
mysql_close();
}
?>
As an added complication, the file name needs to be dynamic, i.e. not just "myform.php" but "myform.php?option=this_can_be_anything". So a reference to a static URL would not work.
Any suggestions much appreciated.

Related

Open FPDF in new tab

I have a pdf generated (fpdf) from a post form. I would like the pdf to open in a new tab and/or window prompting the user to save the pdf. I'm guessing I need to save the output to a string
$data=$pdf->Output("OfficeForm.pdf", "S");
but what exactly can I do with this string to get it to open in a new window. I've attempted something like this but it's not working. Am I on the right track or is window.open not what I need?
echo "<script type=\"text/javascript\">
window.open('$data', '_blank')
</script>";
If you use a form you can do it by specifying target='_blank' in the -tag (next to where you should have submit='something')
Example:
This will open a new Tab (showing whatever "makepdf.php" produces) on submit.
Hope it answers the question correctly
I simply added target="_blank" to my form opening tag and used $_SESSION[]; to pass my form to the FPDF code:
<?php session_start(); ?>
<form id ="buildPDFform" name="buildPDFform" target="_blank" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
...some code for my form
<input type="submit" name="buildPDf" id="buildPDf" class="buildPDFbutton" value="Build the PDF">
</form>
Then when the form is submitted I gather my form items, put them in an array, create a session the array goes into and use a header("Location: testcode.php") to redirect to where my FPDF code is.
if (isset($_POST['buildPDf'])) {
$pdfArray = array();
foreach ($_POST as $key => $value) {
...gather your form items into your array
}
$_SESSION['pdfArray'] = $pdfArray;
header("Location: testcode.php");
}
And don't forget in your FPDF code file (testcode.php in my case) to grab your session that has the array.
<?php
session_start();
$pdfArray = $_SESSION['pdfArray'];
... your FPDF code
$pdf->Output('I');
?>
source: https://www.thesitewizard.com/html-tutorial/open-links-in-new-window-or-tab.shtml
use target="_blank" in your a tag to open it to new tab
Try $pdf->Output("OfficeForm.pdf", "I");

CodeIgniter form_open() action not working correctly

I have have a view in which there's a form that manages products (either add new product or -if an id passed- editing an existing one). If an id is passed then the form action should be eg 'admin/product/manage/5', if no id passed then it should be like this 'admin/product/manage'.
<?php echo form_open('admin/product/manage/{optional product id}', array('class' => 'ajax-form')); ?>
I have also created and this route:
$route['admin/product/manage'] = "admin/product/manage";
$route['admin/product/manage/(:num)'] = "admin/product/manage/$1";
How can I make my form action work correctly? is it possible to put inside the action the route somehow??
This is my Controller:
public function manage($id = NULL){
//fetch a single product to edit or create a new one
if (isset($id) === true) {
$data['prod'] = $this->product_model->get($id);
$data['vers'] = $this->product_version_model->get_by('product_id',$id);
} else {
$data['prod'] = $this->product_model->make_new();// this returns $product->product_name = ''; in order to be empty the input field and not throughing errors
}
$this->product_model->save_product();
$this->product_version_model->save_version();
// load the view
$this->layout->view('admin/products/manage', $data);
}
This is my view:
<?php echo form_open('admin/product/manage', array('class' => 'ajax-form')); ?>
<p>
<label for="product_name">Product *</label>
<input type="text" name="product_name" value="<?php echo set_value('product_name', $prod->product_name); ?>" />
<?php echo form_error('product_name'); ?>
</p>
<?php echo form_close() . PHP_EOL; ?>
You need to declare both possible routes in order of importance, so:
$route['admin/product'] = "admin/product/manage";
$route['admin/product/(:num)'] = "admin/product/manage/$1";
From the Codeigniter Docs:
Routes will run in the order they are defined. Higher routes will always take precedence over lower ones.
Edit:
According to the changes you have made to your question I can say the following:
First of all isset() returns boolean only, so you don't need the type check "=== true". isset($id) is sufficient.
In order to have your form action set to the id you need to include it either in a hidden field or in the action itself.
So for example:
$action_id = (isset($id) ? '/'.$id : ''); // Using ternary operators here
echo form_open('admin/product/manage'.$action_id, array('class' => 'ajax-form'));
and add the id to the view data in your controller:
$data['id'] = $id;
As a side note: In order to comply with SoC (Separation of Concerns) you'd prepare all data in your controller (with e.g. models all having their own task) and pass the processed data to the view instead of partially generating data in the view itself.

Why is CakePHP 2.3.0 adding a '1' to my Form Post Values?

I'm using cakephp 2.3.0. I searched in the manual for quite awhile, but I haven't found the answer. Also, I've searched the Internet, but still haven't found what I'm looking for. SO, I'm posting my question here. Note, I'm fairly new to cakephp.
Scenario:
I have a simple form with two fields: activity and zip code.
I'm using POST on the form.
When I type in some value in those fields and submit, I echo those 'post' values/parameters and display in the browser screen. What I typed in, I can see on the screen, but the number '1' is added to the end of what I typed in the form.
Here is an example. I type in these values in the form, 'walk' and '44555'. Then I click 'Submit'. The post goes to my controller's action, which then calls my view. My view is displayed on the browser screen and I echo out those 'post' values. The results on screen are 'walk1' and '445551'.
Example #2: If I follow the steps above and don't enter any values in my form (I'll add error checking later), what I see on the browser screen is '1' and '1'.
I am unable to figure out why I am getting the value of '1' added to my form's POST values?
I'll be glad to include any other additional php code to this posting, if requested by someone trying to help.
Here is my FORM code (from my view)...I know there are DIV helpers, but I'll get to that later:
echo $this->Form->create(null, array('url' => array('controller'=>'activities', 'action'=>'results'))); ?>
<div class="box1" style="position:relative; top:10px; left:10px; float: left;">
Search here.... <br>
<hr>
<?php echo $this->Form->input('activityName', array('size'=>'30',
'label'=>'Activity Name:', 'value'=>'i.e. walking, etc.'));?>
<br>
<?php echo $this->Form->input('zip', array('size'=>'7', 'label'=>'Postal Code:')); ?>
<br>
</div>
<div class="box1" align="right">
<?php echo $this->Form->end('Go Search');?>
</div>
Here is my controller code:
<?php
class ActivitiesController extends AppController {
public $helpers = array('Html', 'Form');
public function index() {
//other code....
}
public function results() {
$this->layout = 'second';
$name = $this->request->data['Activity']['activityName'];
$pCode = $this->request->data['Activity']['zip'];
$this->set('theName', $name);
$this->set('theZip', $pCode);
$this->set('results', $this->Activity->
find('all', array('conditions' => array('name' => $name, 'postal_code' => $pCode))));
$this->set('title_for_layout', 'Results');
$this->render();
}
}
?>
My final view code. I left off some of the code...just showing the part that matters:
<div style="position:relative; top:10px; left:5px; ">
<?php echo print_r($theName); ?>
<br>
<?php echo print_r($theZip); ?>
Thanks
The 1 comes from printing the return value of print_r() which is true (i.e. 1).
In other words: you shouldn't do echo print_r(), just do print_r(). The function handles the printing by itself, you don't have to print the results manually.
(Also, print_r() is almost never the best choice to print out values except when debugging and even then CakePHP's debug() is much more suitable.)

Joomla 2.5 - component development - using form

I am trying to add some form to my component, but I am not shure what naming conventions must be applied to work it correctly.
Currently I have a working form - it displays fields stored in XML file and loads data from database to it. However, when i try to submit this form (edit or add new records), it doesn't work. After pressing submit (save() method) it just redirects me and displays that record was edited successfuly but it wasn't. When I try to edit existing record, after pressing submit nothing happens and when I try to add new record, it just adds empty/blank record.
So I was doing a little debug and discovered, that problem is in the JController::checkEditId() method. It always returns false which means that JControllerForm::save() returns false as well and that's why it doesn't save it correctly. HTML code of form is correct and I can access the data by using global array $_POST.
I suspect that this problem is because of naming conventions in methods loadFormData, getForm of JModelAdmin class. I am not sure how to name that form.
So here is my code related to this problem:
Subcontroller for displaying the form - controllers/slideshowform.php
class SlideshowModelSlideshowForm extends JModelAdmin{
public function getForm($data = array(), $loadData = true){
return $this->loadForm('com_slideshow.slideshowform', 'editform', array('load_data' => $loadData, 'control' => 'jform'));
}
protected function loadFormData(){
$data = JFactory::getApplication()->getUserState('com_slideshow.edit.slideshowform.data', array());
if (empty($data))
{
$data = $this->getItem();
}
return $data;
}
public function getTable($table = "biometricslideshow"){
return parent::getTable($table);
}
}
views/slideshowform/view.html.php
class SlideshowViewSlideshowForm extends JView{
public function display($tmpl = null){
if (count($errors = $this->get('Errors')))
{
JError::raiseError(500, implode('<br />', $errors));
return false;
}
$this->form = $this->get('form');
$this->item = $this->get('item');
JToolBarHelper::save('slideshowform.save');
parent::display();
}
}
views/slideshowform/tmpl/default.php
<?php
defined('_JEXEC') or die('Restricted access');
JHtml::_('behavior.tooltip');
?>
<form method="post" action="<?php echo JRoute::_("index.php?option=com_slideshow&id=".(int) $this->item->id)?>" name="adminForm" id="slideshow-form">
<fieldset class="adminform">
<legend>Edit slide</legend>
<table>
<input type="hidden" name="task" value="">
<?php echo JHtml::_('form.token'); ?>
<?php
foreach($this->form->getFieldset() as $field){
?>
<tr><td><?php echo $field->label ?></td><td><?php echo $field->input ?></td></tr>
<?php
}
?>
</table>
</fieldset>
</form>
Can someone take o look, please?
you have to add controller SlideshowControllerSlideshowForm and code save method. In there you have to validate the form data and call SlideshowModelSlideshowForm->save event, then redirect with success/failure message.

Facebook App FBML, fb:friend-selector get friend userid

i am trying to get the current logged in user's friends, they should select one friend using the form below and then submit it to the same page.
The script is suppose to get the friend's userid (only one) and add it to the database.
The script is working fine but its not posting the right ID (Wrong ID $_POST['friend_selector_id']), it posts an id that looks like this: 2147483647 and i am not sure if this is the profile id or what but i need the id that you use with this code <fb:profile-pic uid=. i need the userid. Could somebody help me out ?
Thank You :D
<form action="<?php echo $appCanvasUrl.'challenge.php?gameid='.$_GET[gameid].'&userid='.$user.'&userid2='.$friend_selector_id; ?>" id="challenge" method="post">
<fb:friend-selector uid="<?PHP echo $user; ?>" name="userid2" idname="friend_selector_id"/>
<INPUT type="submit" value="Challenge"> </form>
<?php
if(isset($_GET['gameid']) && is_numeric($_GET['userid']) && isset($_GET['userid2'])) {
$gameid = am_injection($_GET[gameid]);
$userid2 = am_injection($_POST['friend_selector_id']);
$userid1 = am_injection($user);
am_queries($db, "INSERT INTO `AMCMS_challenges` (`primkey` ,`userkey1` ,`userkey2` ,`gameid` ,`winner`, `score1`, `score2`) VALUES (NULL, $userid1, $userid2, $gameid, 0, 0, 0);");
echo 'Challenge recorded.';
} else {
echo 'Please select a friend to challenge!';
exit;
}
My bad, it wasn't the script, it was my database. I had to set the fields to BIGINT otherwise the number recorded in the database was completely different :)