Taking Integration Error - matlab

Question

I'm new at MATLAB. I want to write code of this equations.
I tried with below code which is written by me.
k=-6:6;
n=-6:6
x= double(k>=0);
h=10*exp(-10*(n-k)).*double((n<=0));
fonk=double(k>=0).*(10*exp(-10*(n-k)).*double(k-n>=0));
for n=1:5
y=integral(#(k)fonk(k,n),6,6);
stem((-6:-6),y);
But It gives
Subscript indices must either be real positive integers or logicals.
Error in untitled2>#(k)fonk(k,n) (line 10)
y=integral(#(k)fonk(k,n),1,6);
Error in integralCalc/iterateScalarValued (line 315)
fx = FUN(t);
Error in integralCalc/vadapt (line 133)
[q,errbnd] = iterateScalarValued(u,tinterval,pathlen);
Error in integralCalc (line 76)
[q,errbnd] = vadapt(#AtoBInvTransform,interval);
Error in integral (line 88)
Q = integralCalc(fun,a,b,opstruct);
Error in untitled2 (line 10)
y=integral(#(k)fonk(k,n),1,6);
errors. I have been googling for this error but I cant find solution. Thanks for Helping.

Answer 1

Modifying your 5th line should be sufficient. You don't need 1~4th lines.
fonk=#(kv,nv) double(kv>=0).*(10*exp(-10*(nv-kv)).*double(kv-nv>=0));
for n=1:5
y(n)=integral(#(z) fonk(z,n),-6,6);
end
stem(y)
You need to define fonk as a function that takes two arguments otherwise integral does not understand it. Also you need to use a vector form of y to store results.