Having trouble using the export-csv - powershell

Question

I have 3 csv files and they are all only 1 column long. I have tried lots of thing to put it all in one csv file but i cant get it to work. When i output it, it all ends up in one column here is what i did so far
#Putting Csv files to Array
$CSV1 = #(gc $EmailPathCsv)
$CSV2 = #(gc $UserLPathCsv)
$CSV3 = #(gc $EmailPathCsv)
#
for ($i=0; $i -lt $CSV1.Count; $i++)
{
$CSV4 += $CSV1[$i] + "," + $CSV2[$i] + "," + $CSV3[$i] + " "
}
$csv4 | out-file -append $MergedCsvExport

Answer 1

Your loop is adding everything into $CSV4, each time through the loop $CSV4 gets longer and longer.
Then you print it once. That's why you get one really long line. Try printing it once every time through the loop, and overwriting $CSV4 every time:
#Putting Csv files to Array
$CSV1 = #(gc $EmailPathCsv)
$CSV2 = #(gc $UserLPathCsv)
$CSV3 = #(gc $EmailPathCsv)
#
for ($i=0; $i -lt $CSV1.Count; $i++)
{
$CSV4 = $CSV1[$i] + "," + $CSV2[$i] + "," + $CSV3[$i] + " "
out-file -InputObject $csv4 -Append -FilePath $MergedCsvExport
}

Answer 2

I'd use a foromat string for that.
$CSV1 = #(gc $EmailPathCsv)
$CSV2 = #(gc $UserLPathCsv)
$CSV3 = #(gc $EmailPathCsv)
for ($i=0; $i -lt $CSV1.Count; $i++)
{
'"{0}","{1}","{2}"' -f $CSV1[$i],$CSV2[$i],$CSV3[$i] |
add-content $MergedCsvExport
}

Answer 3

As a more fun answer:
$CSV1 = 1,2,3,4
$CSV2 = 10,11,12,13
$CSV3 = 'a','b','c','d'
$c = gv -Name CSV* | select -expand name | sort
(gv -Va $c[0])|%{$r=0}{#($c|%{(gv -Va $_)[$r]}) -join ',';$r++}
Sample output:
1, 10, a
2, 11, b
3, 12, c
4, 13, d
You could put |Out-File "merged-data.csv" on the end to save to a file.
It works for more columns too, just add more arrays called $CSV{something}.
Edit: I wonder if Get-Variable's output is in a predictable order, or unspecified? If you don't mind if the column order might change, it collapses to:
$CSV1 = 1,2,3,4
$CSV2 = 10,11,12,13
$CSV3 = 'a','b','c','d'
(gv CSV*)[0].Value|%{$r=0}{#((gv CSV*)|%{(gv -Va $_.Name)[$r]}) -join ',';$r++}
Edit again: Well, in case anyone notices and is curious, and has time on their hands, I've expanded it all out with an explanation of what it's doing:
# Search the local variable scope for variables named CSV*
# This will find $CSV1, $CSV2, etc.
# This means the number of columns
# isn't fixed, you can easily add more.
# Take their names, sort them.
# Result: an array of strings "CSV1", "CSV2", ...
# for however many variables there are
$columnVariables = Get-Variable -Name "CSV*" | Select-Object -Expand Name | Sort-Object
# NB. if you remove $CSV3= from your code, it is
# still in memory from previous run. To remove
# it, use `Remove-Variable "CSV3"
# In pseudo-code, what the next part does is
# for row in range(data):
# #(CSV1[row], CSV2[row], ... CSVn[row]) -join ','
# The outer loop over the number of columns
# is done by piping something of the right length
# into a foreach loop, but ignoring the content.
# So get the first column array content:
$firstColumn = (Get-Variable $columnVariables[0]).Value
# and pipe it into a loop.
# The loop uses ForEach {setup} {loop} pattern
# to setup a row-counter before the loop body
$firstColumn | ForEach { $row=0 } {
# Now we know the row we are on, we can get
# $CSV1[row], $CSV2[row], ...
# Take the column variable array "CSV1", "CSV2", ..
# Loop over them
$rowContent = $columnVariables | ForEach {
# $_ a string of the name, e.g. "CSV1"
# Use Get-Variable to convert it
# into the variable $CSV1
# with -ValueOnly to get the array itself
# rather than details about the variable
$columnVar = Get-Variable -ValueOnly $_
# $columVar is now one of the $CSVn variables
# so it contains, e.g. 1,2,3,4
# Index into that for the current row
# to get one item, e.g. 3
# Output it into the pipeline
($columnVar)[$row]
} # This is the end of the inner loop
# The pipeline now contains the column
# values/content making up a single row
# 1
# 10
# 'a'
# Back in the outer row loop, Take the row
# content and make it a comma separated string
# e.g. "1,10,a"
# Output this into the pipeline
#($rowContent) -join ','
# Increment the row counter
$row++
}