Comparison of two rows in TSQL - tsql

Question

Good Day
I have the following result set returned:
financeYearEnd FromDate ToDate ClientPortfolioCode
2013-12-31 00:00:00.000 2014-01-01 2014-01-31 C1
2013-12-31 00:00:00.000 2014-01-01 2014-01-31 C2
2012-12-31 00:00:00.000 2013-12-01 2013-12-31 C1
2012-12-31 00:00:00.000 2013-12-01 2013-12-31 C2
What I need to do is the following:
I need to compare the financeYearEnd of all the C1 Fields (there will always only be two), and see if they are different to each other
2013-12-31 00:00:00.000 2014-01-01 2014-01-31 C1
2012-12-31 00:00:00.000 2013-12-01 2013-12-31 C1
As seen, the financeYearEnd does differ, so I need to store that result as a row in a temporary Table.
This needs to be done for all distinct ClientPortfolioCodes(Which will always appear in groups of two)
How can this be achieved?
I have tried select distinct .. - didn't work. It returned all my rows
EDIT -
WITH cteCompareTopTwoYears
AS (
SELECT TOP (
SELECT COUNT(*) * 2
FROM #ClientPortFolios
) FinancialYearEnd AS financeYearEnd
,FromDate
,ToDate
,CA.ClientPortfolioCode
FROM rpt.F3_fn_ClientPortfolios_CapitalAccount_IncludingYTD CA
WHERE (
(
CA.FromDate = (DATEADD(m, - 1, #FromDate))
AND CA.ToDate = (DATEADD(m, - 1, #ToDate))
)
OR (
CA.FromDate = #FromDate
AND CA.ToDate = #ToDate
)
)
AND (
CA.ClientPortFolioCode IN (
SELECT ClientPortfolioCode
FROM #ClientPortfolios
)
)
ORDER BY FromDate DESC
)
SELECT *
FROM cteCompareTopTwoYears c

Answer 1

Perhaps with the help of ROW_NUMBER, e.g.:
WITH CTE AS
(
SELECT financeYearEnd, FromDate, ToDate, ClientPortfolioCode,
rn = row_Number () OVER (Partition By ClientPortfolioCode
Order By financeYearEnd ASC)
FROM dbo.TableName
)
SELECT financeYearEnd, FromDate, ToDate, ClientPortfolioCode
FROM CTE
WHERE rn > 1
Demo