Ordering query Crosstab Postgres - postgresql

Question

I'm trying to pivot a table in Postgres. My table 'sample' has many columns (code, sector, item, year, period, value, preorder), instead of having 1 concept, 1 year, 1 value per row, i want the concept with values by year. From this;
Item Value Year PreOrder
Sales 50 2011 1
Costs -20 2011 2
GrossProfit 30 2011 3
Expenses -5 2011 4
Tax -3 2011 5
Profit 22 2011 6
Sales 45 2012 3
Costs -20 2012 4
GrossProfit 25 2012 5
Expenses -5 2012 6
Tax -3 2012 7
Profit 17 2012 8
To this:
Item 2011 2012
Sales 50 45
Costs -20 -20
GrossProfit 30 25
Expenses -5 -5
Tax -3 -3
Profit 22 17
Using crosstab in Postgres:
Select * from crosstab($$Select item, year, value from sec_sample
Where cik=320193
AND period='Annual'
AND Sector='Agro'
Order by year, preorder
$$,
$$VALUES ('2011'::int), ('2012')$$)
AS value("item" varchar(255), "2011" numeric(20,2), "2012" numeric(20,2));
However this results in:
Item 2011 2012
Sales 50
Costs -20
GrossProfit 30
Expenses -5
Tax -3
Profit 22
Sales 45
Costs -20
GrossProfit 25
Expenses -5
Tax -3
Profit 17
Any idea how i can modify my query? Thx

Answer 1

AFAIK, to group by item you have to order by item:
Select * from crosstab($$Select item, year, value from sec_sample
Where cik=320193
AND period='Annual'
AND Sector='Agro'
Order by item, year, preorder
$$,
$$VALUES ('2011'::int), ('2012')$$)
AS value("item" varchar(255), "2011" numeric(20,2), "2012" numeric(20,2));
But you can pivot without using crosstab, like this:
select
s.item,
sum(case when s.year = 2011 then s.value else 0 end) as "2011",
sum(case when s.year = 2012 then s.value else 0 end) as "2012"
from sec_sample as s
group by s.item
order by min(s.preorder)
I think it's easier to modify this type of query
sql fiddle demo