Mule and JDBC Query Result - postgresql

Question

I am using mule to connect to a Postgres database server.
I can't use the datamapper since I am using the community edition.
The object to xml transformer is not giving a good formatted result.
Any ideas of how I can transform the jdbc response into a good format for parsing.
Here is my configuration file.
This is the datasource with the connector.
<jdbc:postgresql-data-source name="PostgreSQL_Data_Source"
user="USERNAME" password="PASSWORD"
url="jdbc:postgresql://*******:***/*****"
transactionIsolation="UNSPECIFIED" doc:name="PostgreSQL Data Source" />
<jdbc:connector name="organizations" dataSource-ref="PostgreSQL_Data_Source"
validateConnections="true" queryTimeout="-1" pollingFrequency="0"
doc:name="JDBC">
<jdbc:query key="getOrganizations" value="SELECT * FROM organization" />
<jdbc:query key="getOrganizationApplications"
value="SELECT * FROM organization o,application a,organization_apps oa WHERE o.id=oa.org_id AND a.id=oa.app_id AND o.id=#[flowVars['org_id']]" />
<jdbc:query key="insertOrganization"
value="INSERT INTO organization(name, phone, email, address, website) VALUES (?, ?, ?, ?, ?)" />
<jdbc:query key="getOrganizationUsers"
value="SELECT * FROM &quot;public&quot;.user WHERE org_id=#[flowVars['org_id']]" />
</jdbc:connector>
and this is the flow:
<flow name="logixy-platform-organizations-workflow" doc:name="logixy-platform-organizations-workflow">
<http:inbound-endpoint exchange-pattern="request-response"
host="localhost" port="8082" doc:name="HTTP" path="organization" />
<set-variable variableName="choice"
value="#[message.inboundProperties['choice']]" doc:name="Set Choice" />
<choice doc:name="Choice">
<when expression="#[flowVars['choice'] == '0']">
<jdbc:outbound-endpoint exchange-pattern="request-response"
queryTimeout="-1" doc:name="getAllOrganizations" connector-ref="organizations"
queryKey="getOrganizations" />
</when>
<when expression="#[flowVars['choice'] == '2']">
<set-variable variableName="org_id"
value="#[(int)(message.inboundProperties['org_id'])]" doc:name="Set Organization ID" />
<jdbc:outbound-endpoint exchange-pattern="request-response"
queryKey="getOrganizationUsers" queryTimeout="-1" connector-ref="organizations"
doc:name="getOrganizationUsers" />
</when>
<when expression="#[flowVars['choice'] == '1']">
<set-variable variableName="#['org_id']"
value="#[(int)(message.inboundProperties['org_id'])]" doc:name="Set Organization ID" />
<jdbc:outbound-endpoint exchange-pattern="request-response"
queryKey="getOrganizationApplications" queryTimeout="-1"
connector-ref="organizations" doc:name="getOrganizationApplications" />
</when>
</choice>
<mulexml:object-to-xml-transformer
doc:name="Object to XML" />
</flow>

Answer 1

You should really define "a good format for parsing", but I guess you don't like the "entry", "string", etc field names.
You have plenty of options to format the XML, for example:
use XSLT to transform the generated XML to your preferred format
define a class in Java or Groovy that corresponds to your return data and then either
use object-to-json and then json-to-object with your class as return class
assign the return data to objects of your class in Java or Groovy
Once you have your data as custom objects, object-to-xml-transformer will print produce a much cleaner output.