I like to find some thing with sed in file that have many occurrence
File As below
"xyz": "somename_dsa", some other text, "xyz": "zcbr53", some other text, "xyz": "zms53",
Item needed
I need text after "xyz" :
Using gnu awk
awk -v RS='"xyz"' 'NR>1 {print $2}' file
"somename_dsa",
"zcbr53",
"zms53",
Or just the data
awk -v RS='"xyz"' -F\" 'NR>1 {print $2}' file
somename_dsa
zcbr53
zms53
This might work for you (GNU sed):
sed '/"xyz":\s*/!d;s//\n/g;s/^[^\n]*\n//' file
Delete any lines that don't have the required string. Replace the required string with a newline and chop off the first entry.
You may try this,
$ cat rr.txt
"xyz": "somename_dsa", some other text, "xyz": "zcbr53", some other text, "xyz": "zms53"
$ sed -r '/[^"]*"xyz": ([^,]*)/ s//\1 /g' rr.txt
"somename_dsa" "zcbr53" "zms53"
$ sed -r '/[^"]*"xyz": "([^"]*)"/ s//\1 /g' rr.txt
somename_dsa zcbr53 zms53
All the captured texts are separated by spaces.
Related
I have lines that start like this: 2141058222 11/22/2017 and I want to append a ; at the end of the ten digit number like this: 2141058222; 11/22/2017.
I've tried sed with sed -i 's/^[0-9]\{10\}\\$/;&/g' which does nothing.
What am I missing?
Try this:
echo "2141058222 11/22/2017" | sed -r 's/^([0-9]{10})/&;/'
echo "2141058222 11/22/2017" | sed 's/ /; /'
Output:
2141058222; 11/22/2017
If the input is always in the format specified, GNU cut works, and might even be more efficient than sed:
cut -c -10,11- --output-delimiter ';' <<< "2141058222 11/22/2017"
Output:
2141058222; 11/22/2017
For an input file that'd be:
cut -c -10,11- --output-delimiter ';' file
I am trying to use sed script to remove the content of an array in a file. I have tried to delete the content to only leave the brackets (). However I can't get the sed script to work over multiple lines.
I am trying to change the current state of the file:
LIST = ( "content"
"content1"
"content3")
to this:
LIST = ()
However the sed script I am using only changes the file to this:
LIST = ()
"content"
"content1"
"content2"
sed -e 's/LIST=\([^)]*\)/LIST=() /g' filename
I should also mention there are other sets of brackets in the file which I don't want affected.
e.g
LISTNUMBER2("CONTENT")
should not be emptied.
this sed one-liner works for your example:
sed -n '1!H;1h;${x;s/(.*)/()/;p}'
test:
kent$ echo 'LIST = ( "content"
"content1"
"content3")'|sed -n '1!H;1h;${x;s/(.*)/()/;p}'
LIST = ()
if you could use awk, this one-liner works for your example too:
awk -v RS="" '{sub(/\(.*\)/,"()")}1'
test:
kent$ echo 'LIST = ( "content"
"content1"
"content3")'|awk -v RS="" '{sub(/\(.*\)/,"()")}1'
LIST = ()
EDIT for OP's comment
multi brackets situation:
awk
awk -v RS="\0" -v ORS="" '{gsub(/LIST\s*=\s*\([^)]*\)/,"LIST = ()")}1' file
test:
kent$ cat file
LISTKEEP2("CONTENT")
LIST = ( "content"
"content1"
"content3")
LISTNUMBER2("CONTENT")
kent$ awk -v RS="\0" -v ORS="" '{gsub(/LIST\s*=\s*\([^)]*\)/,"LIST = ()")}1' file
LISTKEEP2("CONTENT")
LIST = ()
LISTNUMBER2("CONTENT")
sed:
sed -nr '1!H;1h;${x;s/(LIST\s*=\s*\()[^)]*\)/\1)/;p}' file
kent$ sed -nr '1!H;1h;${x;s/(LIST\s*=\s*\()[^)]*\)/\1)/;p}' file
LISTKEEP2("CONTENT")
LIST = ()
LISTNUMBER2("CONTENT")
Another sed solution:
sed '/LIST = (/{:next;/)/{s/(.*)/()/;b;};N;b next;}'
Here's a version that would not change any block containing a certain string ("keepme" in this example, but could be anything):
sed '/LIST = (/{:next;/)/{/keepme/b;s/(.*)/()/;b;};N;b next;}'
Since this does the keepme test after it finds the closing parenthesis that tag can be anywhere in the block.
My text looks like this:
cat
catch
cat_mouse
catty
I want to replace "cat" with "dog".
When I do
sed "s/cat/dog/"
my result is:
dog
catch
cat_mouse
catty
How do I replace with sed if only part of the word matches?
There's a mistake :
You lack the g modifier
sed 's/cat/dog/g'
g
Apply the replacement to all matches to the regexp, not just the first.
See
http://www.gnu.org/software/sed/manual/html_node/The-_0022s_0022-Command.html
http://sed.sourceforge.net/sedfaq3.html#s3.1.3
If you want to replace only cat by dog only if part of the word matches :
$ perl -pe 's/cat(?=.)/dog/' file.txt
cat
dogch
dog_mouse
dogty
I use Positive Look Around, see http://www.perlmonks.org/?node_id=518444
If you really want sed :
sed '/^cat$/!s/cat/dog/' file.txt
bash-3.00$ cat t
cat
catch
cat_mouse
catty
To replace cat only if it is part of a string
bash-3.00$ sed 's/cat\([^$]\)/dog\1/' t
cat
dogch
dog_mouse
dogty
To replace all occurrences of cat:
bash-3.00$ sed 's/cat/dog/' t
dog
dogch
dog_mouse
dogty
awk solution for this
awk '{gsub("cat","dog",$0); print}' temp.txt
I have a file which looks like below:
memory=500G
brand=HP
color=black
battery=5 hours
For every line, I want to remove everything after = and also the =.
Eventually, I want to get something like:
memory:brand:color:battery:
(All on one line with colons after every word)
Is there a one-line sed command that I can use?
sed -e ':a;N;$!ba;s/=.\+\n\?/:/mg' /my/file
Adapted from this fine answer.
To be frank, however, I'd find something like this more readable:
cut -d = -f 1 /my/file | tr \\n :
Here's one way using GNU awk:
awk -F= '{ printf "%s:", $1 } END { printf "\n" }' file.txt
Result:
memory:brand:color:battery:
If you don't want a colon after the last word, you can use GNU sed like this:
sed -n 's/=.*//; H; $ { g; s/\n//; s/\n/:/g; p }' file.txt
Result:
memory:brand:color:battery
This might work for you (GNU sed):
sed -i ':a;$!N;s/=[^\n]*\n\?/:/;ta' file
perl -F= -ane '{print $F[0].":"}' your_file
tested below:
> cat temp
abc=def,100,200,dasdas
dasd=dsfsf,2312,123,
adasa=sdffs,1312,1231212,adsdasdasd
qeweqw=das,13123,13,asdadasds
dsadsaa=asdd,12312,123
> perl -F= -ane '{print $F[0].":"}' temp
abc:dasd:adasa:qeweqw:dsadsaa:
My command is
First step:
sed 's/([a-z]+)(\=.*)/\1:/g' Filename |cat >a
cat a
memory:
brand:
color:
battery:
Second step:
sed -e 'N;s/\n//' a | sed -e 'N;s/\n//'
My output is
memory:brand:color:battery:
I have a file called data.txt.
I want to add the current date, or time, or both to the beginning or end of each line.
I have tried this:
awk -v v1=$var ' { printf("%s,%s\n", $0, v1) } ' data.txt > data.txt
I have tried this:
sed "s/$/,$var/" data.txt
Nothing works.
Can someone help me out here?
How about :
cat filename | sed "s/$/ `date`/"
The problem with this
awk -v v1=$var ' { printf("%s,%s\n", $0, v1) } ' data.txt > data.txt
is that the > redirection happens first, and the shell truncates the file. Only then does the shell exec awk, which then reads an empty file.
Choose one of these:
sed -i "s/\$/ $var/" data.txt
awk -v "date=$var" '{print $0, date}' data.txt > tmpfile && mv tmpfile data.txt
However, does your $var contain slashes (such as "10/04/2011 12:34") ? If yes, then choose a different delimiter for sed's s/// command: sed -i "s#\$# $var#" data.txt