I've looked through the posts on StackOverflow and can't seem to find the answer I am looking for. I have a large CSV file (450 MB) with hex data that looks like this:
63C000CF,6000002F,603000AF,6000C06F,617300EF,6C7C001F,6000009F,0%,63C000CF...
That is a very truncated example, but basically I have approximately 78 different hex values separated by commas, then there will be the '0%', then 78 more hex values. This will continue for a very long time. I've been using textscan like this:
data = textscan(fid, '%s', 1, 'delimiter', '%');
data = textscan(data{1}{1}, '%s', 'delimiter', ',');
data = data{1};
count = size(data);
outstring = ['%', sprintf('\n')];
for idx = 1:count(1)
string = data{idx};
stringSize = size(string);
if stringSize(2) > 1
outstring = [outstring, string, sprintf('\n')];
end
end
fprintf(output_fid, '%s', outstring)
This allowed me to format the csv file in a way to which I could use fgetl() to analyze whether or not I was looking at the data I needed. Because the data repeats itself, I can use fseek() to jump to the next occurrence before calling fgetl() again.
What I need is a way to skip to the ending. I want to just be able to use something like fgetl() but have it only return the first hex value it encounters. I will know how many bytes to shift through the file. Then I need to make sure I can read other hex values. Is what I'm asking possible? My code using textscan above takes far too long on a csv file that is 90 MB let alone 450 MB.
Answer obtained from user Cedric Wannaz on the Mathworks MATLAB Central Answers page.
NEW solution
Here is a more efficient solution; I am using a 122MB file, so you have an idea about the timing
% One line for reading the whole file. To perform once only.
tic ;
content = fileread( 'adam_1.txt' ) ;
fprintf( 'Time for reading the file : %.2fs\n', toc ) ;
% One line for defining an extraction function. To perform once only.
extract = #(label) content(bsxfun( #plus, ...
strfind( content, [label,','] ).' - 6, ...
0 : 5 )) ;
% Then it is one call per label to extract data.
tic ;
data = extract( 'CF' ) ;
fprintf( 'Time for extracting one label: %.2fs\n', toc ) ;
Running this, I obtain
Time for reading the file : 0.52s
Time for extracting one label: 0.62s
FORMER solution
Would the following work for you?
% Read file content. To do once only.
content = fileread( 'myFile.txt' ) ;
% Define regexp-based extraction function. To do once only.
getByLabel = #(label) regexp( content, sprintf( '\\w{6}(?=%s)', label ), ...
'match' ) ;
% Get all entries for e.g. label 'CF'.
entries_CF = getByLabel( 'CF' ) ;
% Get all entries for e.g. label '6F'.
entries_6F = getByLabel( '6F' ) ;
I am not completely clear on what you need to achieve ultimately; if I had to design a GUI where users can choose a label and get corresponding data, I would process the data much further during the init phase, e.g. by grouping them by label in a cell array. Regexp is not the most efficient approach in this case I guess, but the principle would be..
labels = {'CF', '6F', 'AF', ..} ;
nLabels = numel( labels ) ;
data = cell{ 1, nLabels ) ;
for lId = 1 : nLabels
data{lId} = getByLabel( labels{lId} ) ;
end
and then when a user selects 'CF' ..
lId = strcmpi( label, labels ) ;
dataForThisLabel = data{lId} ;
Related
I am generating 2500 values in Matlab in format (time,heart_rate, resp_rate) by using below code
numberOfSeconds = 2500;
time = 1:numberOfSeconds;
newTime = transpose(time);
number0 = size(newTime, 1)
% generating heart rates
heart_rate = 50 +(70-50) * rand (numberOfSeconds,1);
intHeartRate = int64(heart_rate);
number1 = size(intHeartRate, 1)
% hist(heart_rate)
% generating resp rates
resp_rate = 50 +(70-50) * rand (numberOfSeconds,1);
intRespRate = int64(resp_rate);
number2 = size(intRespRate, 1)
% hist(heart_rate)
% joining time and sensor data
joinedStream = strcat(num2str(newTime),{','},num2str(intHeartRate),{','},num2str(intRespRate))
dlmwrite('/Users/amar/Desktop/geenrated/rate.txt', joinedStream,'delimiter','');
The data shown in the console is alright, but when I save this data to a .txt file, it contains extra spaces in beginning. Hence I am not able to parse the .txt file to generate input stream. Please help
Replace the last two lines of your code with the following. No need to use strcat if you want a CSV output file.
dlmwrite('/Users/amar/Desktop/geenrated/rate.txt', [newTime intHeartRate intRespRate]);
πβπ π πππ’π‘πππ π π’ππππ π‘ππ ππ¦ ππΎπ ππ π‘βπ π ππππππ π‘ πππ π¦ππ’π πππ π. πβππ πππ π€ππ ππ₯ππππππ π€βπ¦ π¦ππ’ πππ‘ π‘βπ π’πππ₯ππππ‘ππ ππ’π‘ππ’π‘.
The data written in the file is exactly what is shown in the console.
>> joinedStream(1) %The exact output will differ since 'rand' is used
ans =
cell
' 1,60,63'
num2str basically converts a matrix into a character array. Hence number of characters in its each row must be same. So for each column of the original matrix, the row with the maximum number of characters is set as a standard for all the rows with less characters and the deficiency is filled by spaces. Columns are separated by 2 spaces. Take a look at the following smaller example to understand:
>> num2str([44, 42314; 4, 1212421])
ans =
2Γ11 char array
'44 42314'
' 4 1212421'
I want to read the data of a file with size about 60 MB into matlab in some variables, but I get errors. This is my code:
clear all ;
clc ;
% Reading Input File
Dataz = importdata('leak0.lis');
%Dataz = load('leak0.lis');
for k = 1:1370
foundPosition = 1 ;
for i=1:size(Dataz,1)
strp = sprintf('I%dz=',k);
fprintf(strp);
findValue = strfind(Dataz{i}, strp) ;
if ~isempty(findValue)
eval_param = strp + '(foundPosition) = sscanf(Dataz{i},''%*c%*c%*f%*c%*c%f'') ;';
disp(eval_param);
% str(foundPosition) = sscanf(Dataz{i},'%*c%*c%*f%*c%*c%f') ;
eval(eval_param);
foundPosition = foundPosition + 1 ;
end
end
end
When I debugged it, I found out that the dataz is empty & so it doesn't proceed to next lines. I replace it with fopen, load & etc, but it didn't work.
From the Matlab help files, import data is likely failing because it doesn't understand your file format.
From the help files
Name and extension of the file to import, specified as a string. If importdata recognizes the file extension, it calls the MATLAB helper function designed to import the associated file format (such as load for MAT-files or xlsread for spreadsheets). Otherwise, importdata interprets the file as a delimited ASCII file.
For ASCII files and spreadsheets, importdata expects to find numeric
data in a rectangular form (that is, like a matrix). Text headers can
appear above or to the left of the numeric data, as follows:
Assuming that your .lis files actually have delimited text.
You should adjust the delimiter in the importdata call so that Matlab can understand your file.
filename = 'myfile01.txt';
delimiterIn = ' ';
headerlinesIn = 1;
A = importdata(filename,delimiterIn,headerlinesIn);
I have a txt file that I want to read into Matlab. Data format is like below:
term2 2015-07-31-15_58_25_612 [0.9934343, 0.3423043, 0.2343433, 0.2342323]
term0 2015-07-31-15_58_25_620 [12]
term3 2015-07-31-15_58_25_625 [2.3333, 3.4444, 4.5555]
...
How can I read these data in the following way?
name = [term2 term0 term3] or namenum = [2 0 3]
time = [2015-07-31-15_58_25_612 2015-07-31-15_58_25_620 2015-07-31-15_58_25_625]
data = {[0.9934343, 0.3423043, 0.2343433, 0.2342323], [12], [2.3333, 3.4444, 4.5555]}
I tried to use textscan in this way 'term%d %s [%f, %f...]', but for the last data part I cannot specify the length because they are different. Then how can I read it? My Matlab version is R2012b.
Thanks a lot in advance if anyone could help!
There may be a way to do that in one single pass, but for me these kind of problems are easier to sort with a 2 pass approach.
Pass 1: Read all the columns with a constant format according to their type (string, integer, etc ...) and read the non constant part in a separate column which will be processed in second pass.
Pass 2: Process your irregular column according to its specificities.
In a case with your sample data, it looks like this:
%% // read file
fid = fopen('Test.txt','r') ;
M = textscan( fid , 'term%d %s %*c %[^]] %*[^\n]' ) ;
fclose(fid) ;
%% // dispatch data into variables
name = M{1,1} ;
time = M{1,2} ;
data = cellfun( #(s) textscan(s,'%f',Inf,'Delimiter',',') , M{1,3} ) ;
What happened:
The first textscan instruction reads the full file. In the format specifier:
term%d read the integer after the literal expression 'term'.
%s read a string representing the date.
%*c ignore one character (to ignore the character '[').
%[^]] read everything (as a string) until it finds the character ']'.
%*[^\n] ignore everything until the next newline ('\n') character. (to not capture the last ']'.
After that, the first 2 columns are easily dispatched into their own variable. The 3rd column of the result cell array M contains strings of different lengths containing different number of floating point number. We use cellfun in combination with another textscan to read the numbers in each cell and return a cell array containing double:
Bonus:
If you want your time to be a numeric value as well (instead of a string), use the following extension of the code:
%% // read file
fid = fopen('Test.txt','r') ;
M = textscan( fid , 'term%d %f-%f-%f-%f_%f_%f_%f %*c %[^]] %*[^\n]' ) ;
fclose(fid) ;
%% // dispatch data
name = M{1,1} ;
time_vec = cell2mat( M(1,2:7) ) ;
time_ms = M{1,8} ./ (24*3600*1000) ; %// take care of the millisecond separatly as they are not handled by "datenum"
time = datenum( time_vec ) + time_ms ;
data = cellfun( #(s) textscan(s,'%f',Inf,'Delimiter',',') , M{1,end} ) ;
This will give you an array time with a Matlab time serial number (often easier to use than strings). To show you the serial number still represent the right time:
>> datestr(time,'yyyy-mm-dd HH:MM:SS.FFF')
ans =
2015-07-31 15:58:25.612
2015-07-31 15:58:25.620
2015-07-31 15:58:25.625
For comlicated string parsing situations like such it is best to use regexp. In this case assuming you have the data in file data.txt the following code should do what you are looking for:
txt = fileread('data.txt')
tokens = regexp(txt,'term(\d+)\s(\S*)\s\[(.*)\]','tokens','dotexceptnewline')
% Convert namenum to numeric type
namenum = cellfun(#(x)str2double(x{1}),tokens)
% Get time stamps from the second row of all the tokens
time = cellfun(#(x)x{2},tokens,'UniformOutput',false);
% Split the numbers in the third column
data = cellfun(#(x)str2double(strsplit(x{3},',')),tokens,'UniformOutput',false)
Loading a well formatted and delimited text file in Matlab is relatively simple, but I struggle with a text file that I have to read in. Sadly I can not change the structure of the source file, so I have to deal with what I have.
The basic file structure is:
123 180 (two integers, white space delimited)
1.5674e-8
.
.
(floating point numbers in column 1, column 2 empty)
.
.
100 4501 (another two integers)
5.3456e-4 (followed by even more floating point numbers)
.
.
.
.
45 String (A integer in column 1, string in column 2)
.
.
.
A simple
[data1,data2]=textread('filename.txt','%f %s', ...
'emptyvalue', NaN)
Does not work.
How can I properly filter the input data? All examples I found online and in the Matlab help so far deal with well structured data, so I am a bit lost at where to start.
As I have to read a whole bunch of those files >100 I rather not iterate trough every single line in every file. I hope there is a much faster approach.
EDIT:
I made a sample file available here: test.txt (google drive)
I've looked at the text file you supplied and tried to draw a few general conclusions -
When there are two integers on a line, the second integer corresponds to the number of rows following.
You always have (two integers (A, B) followed by "B" floats), repeated twice.
After that you have some free-form text (or at least, I couldn't deduce anything useful about the format after that).
This is a messy format so I doubt there are going to be any nice solutions. Some useful general principles are:
Use fgetl when you need to read a single line (it reads up to the next newline character)
Use textscan when it's possible to read multiple lines at once - it is much faster than reading a line at a time. It has many options for how to parse, which it is worth getting to know (I recommend typing doc textscan and reading the entire thing).
If in doubt, just read the lines in as strings and then analyse them in MATLAB.
With that in mine, here is a simple parser for your files. It will probably need some modifications as you are able to infer more about the structure of the files, but it is reasonably fast on the ~700 line test file you gave.
I've just given the variables dummy names like "a", "b", "floats" etc. You should change them to something more specific to your needs.
function output = readTestFile(filename)
fid = fopen(filename, 'r');
% Read the first line
line = '';
while isempty(line)
line = fgetl(fid);
end
nums = textscan(line, '%d %d', 'CollectOutput', 1);
a = nums{1}(1);
b = nums{1}(2);
% Read 'b' of the next lines:
contents = textscan(fid, '%f', b);
floats1 = contents{1};
% Read the next line:
line = '';
while isempty(line)
line = fgetl(fid);
end
nums = textscan(line, '%d %d', 'CollectOutput', 1);
c = nums{1}(1);
d = nums{1}(2);
% Read 'd' of the next lines:
contents = textscan(fid, '%f', d);
floats2 = contents{1};
% Read the rest:
rest = textscan(fid, '%s', 'Delimiter', '\n');
output.a = a;
output.b = b;
output.c = c;
output.d = d;
output.floats1 = floats1;
output.floats2 = floats2;
output.rest = rest{1};
end
You can read in the file line by line using the lower-level functions, then parse each line manually.
You open the file handle like in C
fid = fopen(filename);
Then you can read a line using fgetl
line = fgetl(fid);
String tokenize it on spaces is probably the best first pass, storing each piece in a cell array (because a matrix doesn't support ragged arrays)
colnum = 1;
while ~isempty(rem)
[token, rem] = strtok(rem, ' ');
entries{linenum, colnum} = token;
colnum = colnum + 1;
end
then you can wrap all of that inside another while loop to iterate over the lines
linenum = 1;
while ~feof(fid)
% getl, strtok, index bookkeeping as above
end
It's up to you whether it's best to parse the file as you read it or read it into a cell array first and then go over it afterwards.
Your cell entries are all going to be strings (char arrays), so you will need to use str2num to convert them to numbers. It does a good job of working out the format so that might be all you need.
AIR, ID
AIR.SIT
50 1 1 1 0 0 2 1
43.57 -116.24 1. 857.7
Hi, All,
I have a text file like above. Now in Matlab, I want to create 5000 text files, changing the number "2" (the specific number in the 3rd row) from 1 to 5000 in each file, while keeping other contents the same. In every loop, the changed number is the same with the loop number. And the output in every loop is saved into a new text file, with the name like AIR_LoopNumber.SIT.
I've spent some time writing on that. But it is kind of difficult for a newby. Here is what I have:
% - Read source file.
fid = fopen ('Air.SIT');
n = 1;
textline={};
while (~feof(fid))
textline(n,1)={fgetl(fid)};
end
FileName=Air;
% - Replace characters when relevant.
for i = 1 : 5000
filename = sprintf('%s_%d.SIT','filename',i);
end
Anybody can help on finishing the program?
Thanks,
James
If your file is so short you do not have to read it line by line. Just read the full thing in one variable, modify only the necessary part of it before each write, then write the full variable back in one go.
%% // read the full file as a long sequence of 'char'
fid = fopen ('Air.SIT');
fulltext = fread(fid,Inf,'char') ;
fclose(fid) ;
%% // add a few blank placeholder (3 exactly) to hold the 4 digits when we'll be counting 5000
fulltext = [fulltext(1:49) ; 32 ; 32 ; 32 ; fulltext(50:end) ] ;
idx2replace = 50:53 ; %// save the index of the characters which will be modified each loop
%% // Go for it
baseFileName = 'AIR_%d.SIT' ;
for iFile = 1:1000:5000
%// build filename
filename = sprintf(baseFileName,iFile);
%// modify the string to write
fulltext(idx2replace) = num2str(iFile,'%04d').' ; %//'
%// write the file
fidw = fopen( filename , 'w' ) ;
fwrite(fidw,fulltext) ;
fclose(fidw) ;
end
This example works with the text in your example, you may have to adjust slightly the indices of the characters to replace if your real case is different.
Also I set a step of 1000 for the loop to let you try and see if it works without writing 1000's of file. When you are satisfied with the result, remove the 1000 step in the for loop.
Edit:
The format specifier %04d I gave in the first solution insure the output will take 4 characters, and it will pad any smaller number with zero (ex: 23 => 0023). It is sometimes desirable to keep the length constant, and in your particular example it made things easier because the output string would be exactly the same length for all the files.
However it is not mandatory at all, if you do not want the loop number to be padded with zero, you can use the simple format %d. This will only use the required number of digits.
The side effect is that the output string will be of different length for different loop number, so we cannot use one string for all the iterations, we have to recreate a string at each iteration. So the simple modifications are as follow. Keep the first paragraph of the solution above as is, and replace the last 2 paragraphs with the following:
%% // prepare the block of text before and after the character to change
textBefore = fulltext(1:49) ;
textAfter = fulltext(51:end) ;
%% // Go for it
baseFileName = 'AIR_%d.SIT' ;
for iFile = 1:500:5000
%// build filename
filename = sprintf(baseFileName,iFile);
%// rebuild the string to write
fulltext = [textBefore ; num2str(iFile,'%d').' ; textAfter ]; %//'
%// write the file
fidw = fopen( filename , 'w' ) ;
fwrite(fidw,fulltext) ;
fclose(fidw) ;
end
Note:
The constant length of character for a number may not be important in the file, but it can be very useful for your file names to be named AIR_0001 ... AIR_0023 ... AIR_849 ... AIR_4357 etc ... because in a list they will appear properly ordered in any explorer windows.
If you want your files named with constant length numbers, the just use:
baseFileName = 'AIR_%04d.SIT' ;
instead of the current line.