I'm working on a query that will eventually be used as the record source for a report.
I have a customers and orders table. I want to show customer_id, order_id, and order_date in a query, but I only want to show data associated with the earliest order date for each customer. Basically, I need to show the order_id field without including it in the group by clause. If I include it in the group by clause, I get a lot more records than I want. Based on my research, the code below will work in mysql, but not ms access.
Select customer.customer_id, order.order_id, min(order.order_dt)
From customer inner join order on customer.customer_id = order.customer_id
Group by customer.customer_id
I've tried grouping by order_id in a sub query and ordering by customer then date, then using the first function in the outer query. Unfortunately, the first function doesn't work as advertised.
Any help is greatly appreciated!
Does this work for you? It should bring up the earliest orders by order date for each customer. If there is more than one order on the earliest order date for a customer, all of those orders will be shown, though, so keep it in mind.
SELECT c.customer_id, o.order_id, o.order_dt
FROM customers AS c INNER JOIN (orders AS o INNER JOIN (SELECT customer_ID, MIN([order_dt]) AS MinOrder_dt FROM Orders GROUP BY customer_id) AS d ON (o.Customer_ID = d.customer_id) AND (o.[order_dt] = d.MinOrder_dt)) ON c.customer_id = o.customer_id;
I am deriving a table with just the customer_id and the min order_dt and joining customers and orders to that to only bring up the oldest orders.
Related
I have a user table and another order table. A user can have many orders. How do I get the last 1000 users and those users use my last 1000 orders for each one?
Query - Get users
select distinct users.id, users.first_name, users.last_name
from users
limit 2;
Query - Get orders
select distinct orders.id, orders.user_id
from orders
limit 2;
First you need to know.. When it comes to query data don't do separate operation.. If you put out All Users and Orders Your data will be unordered and not consistency.. So you need to make Join to see All User with Order they have.. And as stated by #Sharon you need to add column date_ordered to see that order make.. I am assume you already have that column but i will call that column with date_ordered..
And your query will be :
select
users.id,
users.first_name,
users.last_name,
orders.id
from
users
inner join orders on users.id = orders.user_id
order by
orders.date_ordered desc
limit 1000
By order date_ordered use desc you will get the latest all the user with their order.. And i assume user_id column in table orders have constraint foreign key references to table users with column id..
Postgres allows you to create a table using inheritance. We have a design where we have 1400 tables that inherit from one main table. These tables are for each of our vendor's inventory.
When I want to query stock for a vendor, I just query the main table. When running Explain, the explanation says that it is going through all 1400 indexes and quite a few of the inherited tables. This causes the query to run very slowly. If I query only the vendor's stock table, I cut the query time to less than 50% of the time by querying the main table.
We have a join on another table that pulls identifiers for the vendor's partner vendors and we also want to query their stock. Example:
SELECT
(select m2.company from sup.members m2 where m2.id = u.id) as company,
u.id,
u.item,
DATE_PART('day', CURRENT_TIMESTAMP - u.datein::timestamp) AS daysinstock,
u.grade as condition,
u.stockno AS stocknumber,
u.ic,
CASE WHEN u.rprice > 0 THEN
u.rprice
ELSE
NULL
END AS price,
u.qty
FROM pub.net u
LEFT JOIN sup.members m1
ON m1.id = u.id OR u.id = any(regexp_split_to_array(m1.partnerslist,','))
WHERE u.ic in ('01036') -- part to query
AND m1.id = 'N40' -- vendor to query
The n40_stock table has stock for the vendor with id = N40 and N40's partner vendors (partnerslist) are G01, G06, G21, K17, N49, V02, M16 so I would also want
to query the g01_stock, g06_stock, g21_stock, k17_stock, n49_stock, v02_stock, and m16_stock tables.
I know about the ONLY clause but is there away to modify this query to get the data from ONLY the specific inherited tables?
Edit
This decreases the time to under 800ms, but I'd like it less:
WITH cte as (
SELECT partnerslist as a FROM sup.members WHERE id = 'N40'
)
SELECT
(select m2.company from sup.members m2 where m2.id = u.id) as company,
u.id,
u.item,
DATE_PART('day', CURRENT_TIMESTAMP - u.datein::timestamp) AS daysinstock,
u.grade as condition,
u.stockno AS stocknumber,
u.ic,
CASE WHEN u.rprice > 0 THEN
u.rprice
ELSE
NULL
END AS price,
u.qty
FROM pub.net u
WHERE u.ic in ('01036') -- part to query
AND u.id = any(regexp_split_to_array('N40,'||(select a from cte), ','))
I cannot retrieve the company from sup.members in the cte because I need the one from the u.id, which is different when the partner changes in the where clause.
Inherited table lookups are based on the actual WHERE clause, which maps to the CHECK table constraint. Simply inheriting tables is not good enough.
https://www.postgresql.org/docs/9.6/static/ddl-partitioning.html
Caveat, you can not use a dynamically created variables where the actual value is not implemented in the raw query. This results in a check of all inherited tables.
I have 3 tables users, orders and comments every tables has 10087250,24949600 and 26532000 much records, I made this query to counts comments on every order but it is taking more than half an hour to execute, how to speed up this query.
Note: there is already index on foreig_key columns.
select users.user_name, orders.id, count(comments.order_id)
from orders
inner join users on users.id=orders.user_id
inner join comments on orders.id=comments.order_id
group by comments.order_id, users.user_name, orders.id
limit 2;
For the first - probably yuo need ORDER BY clause to use it with LIMIT
If you need most commented pair you can ORDER BY count DESC
The second things comments.order_id = orders.id. Why do you use both for GROUP?
group by comments.order_id, users.user_name, orders.id
May be you can help something like this:
WITH grouped AS (
SELECT order_id AS id, count(*)
FROM comments
GROUP BY 1
ORDER BY 2 DESC
LIMIT 2
)
SELECT u.user_name, g.id, g.count
FROM grouped AS g
JOIN orders AS o ON
o.id = g.id
JOIN users AS u ON
u.id = o.user_id
This allows to avoid join all tables before filtering and grouping
You can try to use temporary tables before aggregating the records. This might help to reduce the query time. Something like this...
CREATE TEMPORARY TABLE temp_table(
...
);
INSERT INTO temp_table
SELECT users.user_name, orders.id, comments.order_id
FROM orders INNER JOIN users ON users.id = orders.user_id INNER JOIN comments ON orders.id = comments.order_id;
SELECT user_name, id, count(order_id) FROM temp_table group by order_id, user_name, id;
I think you need to reduce a unneccessary join between orders and comments tables. All you want to get from table comments is how many comments of an order, so you need to do denormalization.
It means you need to add a comments_count column into orders table, and when every a comment is added to an order, just increase it or decrease it if a comment of order is deleted.
After you add new comments_count column, you need to update comments_count for each order.
Then you can just load orders table and you already have comments count for each order.
I have a list of Matter data in Table1 that I need to query, as well as get the most recent Invoice Number in Table2 that is tied to the original Matter. I'm having extreme difficulty in joining these tables together and only getting one result for each Matter as I only want the most recent Invoice #.
Any and all help would be greatly appreciated.
Table1
Table2
RESULT
The following assigns numbers to each invoice row in order of date, and selects only the most recent. Note that this assumes InvoiceDate is stored as a date,datetime, or something else that will sort chronologically, and that in the event of two invoices for the same date, returning either will be fine. If you need to return both invoices in the event of ties, replace row_number with rank.
Select * from Table1 a
inner join
(Select *
, row_number() over (partition by MatterID order by InvoiceDate desc) as RN
from Table2) b
on a.MatterID = b.MatterID and b.RN = 1
I got 2 tables like Customers and Orders, in table Customers I got columns id, name, in table Orders I got columns id, customer_id, order_date.
Now I need to make one select that will return me each Customer's id, name and the last order_date.
I tried to make like this:
select
Customers.id,
Customers.name,
(select Orders.order_date from Orders where Orders.customer_id = Customer.id order by order_date desc) as last_order_date
from
Customers
But it get the wrong index and takes forever to execute.
Whats the best way to make this select in PostgreSQL?
Thanks in advanced.
If not restricting by customer_id, then the query will end up having to scan the entire orders table.
SELECT c.id
,c.name
,MAX(o.order_date) AS last_order_date
FROM Customers c
LEFT OUTER JOIN Orders o ON (o.customer_id = c.id)
GROUP BY c.id, c.name