I have two text files that I need to compare by date/time modified (not by its contents).
Source text file is at N:\folder1\source.log and the other is at C:\folder1\dest.log. If two text files are the same exit, if there not the same run N:\folder1\copy.bat
Basically, I have various files contained inside "folder1" in both locations in which i want the vbscript to only check the log file if the same. The batch file will simply copy and overwrite all files, making everything updated.
You need a FileSystemObject for file access, the .DateLastModified property of the files to compare, and the = (equal) operator:
>> t1 = goFS.GetFile("calibre.log").DateLastModified
>> t2 = goFS.GetFile("tmp\calibre.log").DateLastModified
>> WScript.Echo t1, t2, CStr(t1 = t2)
>>
05.09.2009 20:14:39 05.09.2009 20:14:39 True
Related
I have a bunch of zip folders that I have to extract and read the data (stored in a unique file). The problem is some of these folders have two files by any kind of error (instead of 1) with the same name. When I use the Matlab command "unzip", one of the files is overwrited by the other. The problem is these two files are not the same: one of them has the information I need, and the other one is almost empty. So I would like to rename these two files to file_a and file_b, extract them, and once both are extracted, keep only the larger one.
Do you know if there is any way to rename files inside a zip?
I made a function which will modify the filenames inside the zip file so they can be uncompressed seemlessly.
The function locate the file names in the zip file and change the first letter of each file it encounter with a sequence "A, B, C, D, etc ...".
function differentiateFileNames(zipFilename)
%% get the filenames contained in the zip file
filenames = getZipFileNames(zipFilename) ;
nFiles = numel(filenames) ;
%% Find the positions of the file name fields
% read the full file as a string
str = fileread(zipFilename) ;
% if all filenames are identical, we only need to search for the first name
% in our list
idx = strfind( str , filenames{1} ) ;
%% group indices by physical file
% Each filename appears twice in the zip file:
% ex for 2 files: file1 ... file2 ... file1 ...file2
idx = reshape(idx,nFiles,2)-1 ;
%% Now modify each filename
% (replace the first character of each filename)
fid = fopen(zipFilename,'r+') ;
for k=1:nFiles
char2write = uint8('A'+(k-1)) ; % will be: A, B, C, D, ect ...
fseek(fid,idx(k,1),'bof') ;
fwrite(fid,char2write,'uint8') ;
fseek(fid,idx(k,2),'bof') ;
fwrite(fid,char2write,'uint8') ;
end
fclose(fid) ;
end
function filenames = getZipFileNames(zipFilename)
try
% Create a Java file of the ZIP filename.
zipJavaFile = java.io.File(zipFilename);
% Create a Java ZipFile and validate it.
zipFile = org.apache.tools.zip.ZipFile(zipJavaFile);
% Extract the entries from the ZipFile.
entries = zipFile.getEntries;
catch exception
if ~isempty(zipFile)
zipFile.close;
end
delete(cleanUpUrl);
error(message('MATLAB:unzip:invalidZipFile', zipFilename));
end
cleanUpObject = onCleanup(#()zipFile.close);
k = 0 ;
filenames = cell('') ;
while entries.hasMoreElements
k=k+1;
filenames{k,1} = char(entries.nextElement.getName) ;
end
zipFile.close
end
Be aware that this script assumes that all the files have a similar name in the zip file. When it locate the file names position it only check versus the first file name found.
The sub function getZipFileNames is just a rip off of parts of the unzip.m, with only the necessary content to be able to read the file names contained in the zip file.
For testing:
I made a zip file containing 2 files:
New Text Document1.txt
New Text Document2.txt
I modified the file names inside the zip file with a hex editor, in order to have:
New Text Document1.txt
New Text Document1.txt
so both files have the same name in the archive. If I try to unzip that file, as you described I only get one file in output (the last file overwrite the other).
If I run differentiateFileNames(zipFilename), then unzip the file, I get 2 files in the output directory:
Aew Text Document1.txt
Bew Text Document1.txt
I know it can look a bit cryptic, but it insures the files are diferentiated. If you want, as an exercise, it wouldn't take much to extend the script to directly unzip the files, find out the largest one, delete the other, then rename the file left with the proper original name.
I want to read multiple files from a folder but this code does not work properly:
direction=dir('data');
for i=3:length(direction)
Fold_name=strcat('data\',direction(i).name);
filename = fullfile(Fold_name);
fileid= fopen(filename);
data = fread (fileid)';
end
I modified your algorithm to make it easier
Just use this form :
folder='address\datafolder\' ( provide your folder address where data is located)
then:
filenames=dir([folder,'*.txt']); ( whatever your data format is, you can specify it in case you have other files you do not want to import, in this example, i used .txt format files)
for k = 1 : numel(filenames)
Do your code
end
It should work. It's a much more efficient method, as it can apply to any folder without you worrying about names, number order etc... Unless you want to specify certain files with the same format within the folder. I would recommend you to use a separate folder to put your files in.
In case of getting access to all the files after reading:
direction=dir('data');
for i=3:length(direction)
Fold_name=strcat('data\',direction(i).name);
filename = fullfile(Fold_name);
fileid(i)= fopen(filename);
data{i-2} = fread (fileid(i))';
end
I apologize in advance that this question is not specific. But my goal is to take a bunch of image files, which are currently named as: 0.tif, 1.tif, 2.tif, etc... and rename them just as numbers to 000.tif, 001.tif, 002.tif, ... , 010.tif, etc...
The reason I want to do this is because I am trying to load the images into matlab and for batch processing but matlab does not order them correctly. I use the dir command as dir(*.tif) to get all the images and load them into an array of files that I can iterate over and process, but in this array element 1 is 0.tif, element 2 is 1.tif, element 3 is 10.tif, element 4 is 100.tif, and so on.
I want to keep the ordering of the elements as I process them. However, I do not care if I have to change the order of the elements BEFORE processing them (i.e. I can make it work to rename, for example, 2.tif to 10.tif if I had to) but I am looking for a way to convert the file names the way I initially described.
If there is a better way to get matlab to properly order the files when it loads them into the array using dir please let me know because that would be much easier.
Thanks!!
You can do this without having to rename the files, if you want. When you grab the files using dir, you'll have a list of files like so:
files =
'0.tif'
'1.tif'
'10.tif'
...
You can grab just the numeric part using regexp:
nums = regexp(files,'\d+','match');
nums = str2double([nums{:}]);
nums =
0 1 10 11 12 ...
regexp returns its matches as a cell-array, the second line converts it back to actual numbers.
We can now get an actual numeric order by sorting the resulting array:
[~,order] = sort(nums);
and then put the files in the correct order:
files = files(order);
This should (I haven't tested it, I don't have a folder full of numerically labelled files handy) produce a list of files like so:
files=
'0.tif'
'1.tif'
'2.tif'
'3.tif'
...
this is partially dependent on the version of matlab you have. If you have a version with findstr this should work well
num_files_to_rename = numel(name_array);
for ii=1:num_files_to_rename
%in my test i used cells to store my strings you may need to
%change the bracket type for your application
curr_file = name_array{ii};
%locates the period in the file name (assume there is only one)
period_idx = findstr(curr_file ,'.');
%takes everything to the left of the period (excluding the period)
file_name = str2num(curr_file(1:period_idx-1));
%zeropads the file name to 3 spaces using a 0
new_file_name = sprintf('%03d.tiff',file_name)
%you can uncomment this after you are sure it works as you planned
%movefile(curr_file, new_file_name);
end
the actual rename operation movefile is commented out for now. make sure the output names are as you expect before uncommenting it and renaming all the files.
EDIT there is no real error checking in this code, it just assumes every file name has one and only one period, and an actual number as the name
The Batch file below do the rename of the files you want:
#echo off
setlocal EnableDelayedExpansion
for /F "delims=" %%f in ('dir /B *.tif') do (
set "name=00%%~Nf"
ren "%%f" "!name:~-3!.tif"
)
Note that this solution preserve the same order of your original files, even if there are missing numbers in the sequence..
I have a number of text files with no Sequential Order :
010010.txt 010030.txt 010070.txt
How could I change the file names to:
text01.txt text02.txt ....
Is it possible not to re writte over the old directory but create a new directory
I have used the following script but the result is that it is working fine but it goes from text001.txt to text021.txt to then text041.txt
any idea?
directory = 'C:\test\'; %//' Directory with txt files
filePattern = fullfile(directory, '*.txt'); %//' files pattern with absolute paths
old_filename = cellstr(ls(filePattern)) %// Get the filenames
file_ID = strrep(strrep(old_filename,'file',''),'.txt','') %// Get numbers associated with each file
file_ID_doublearr = str2double(file_ID)
file_ID_doublearr = file_ID_doublearr - min(file_ID_doublearr)+1
file_ID = strtrim(cellstr(num2str(file_ID_doublearr)))
str_zeros = arrayfun(#(t) repmat('0',1,t), 4-cellfun(#numel,file_ID),'uni',0) %// Get zeros string to be pre-appended to each filename
new_filename = strcat('file',str_zeros,file_ID,'.txt') %// Generate new filenames
cellfun(#(m1,m2) movefile(m1,m2),fullfile(directory,old_filename),fullfile(directory,new_filename)) %// Finally rename files with the absolute paths
That looks pretty complicated. I would simply make a system call to move all of the files to a new directory, then sequentially rename each file one at a time with additional system calls. It also looks like you're using Windows, so I'll provide a solution for that platform. You have the beginning right where you are reading in the files from a source directory.
directory = 'C:\test\'; %// Directory with txt files
directoryToCopyOver = 'C:\out\'; %// Directory where you want to copy the files over
%// Copy source directory to target directory
system(['xcopy ' directory ' ' directoryToCopyOver]);
filePattern = fullfile(directoryToCopyOver, '*.txt'); %//' files pattern with absolute paths
names = dir(filePattern); %// Find all files with above pattern
%// For each file we have...
for idx = 1 : numel(names)
name = names(idx).name; %// Get a name of a file
%// Rename this file to textxx.txt
outName = sprintf('text%2.2d.txt', idx);
%// Call system and rename the file
system(['ren ' directoryToCopyOver name ' ' directoryToCopyOver outName]);
end
Some important things to note is that I use system to make system calls to your Windows command prompt. I use xcopy to copy a whole directory from one point to another. In this case, this would be your source directory over to a new target directory. After I do this, I invoke MATLAB's dir to determine all of the file names that match the particular pattern you have laid out, which is all of the text files.
Then, for each text file name we have, we read in this name, then create an output name of type textxx.txt, where xx is a number starting from 1 to as many text files as we have, and then I invoke the Windows command prompt command ren to rename the file from the original name to the new name. Also, take a look at sprintf from MATLAB. It is designed to create strings using formatting delimiters. If you see how I called it, %2.2d means that I am expecting the number to be two digits long, and should the number be less than two digits, fill the spaces with a zero. If you want to increase the amount of digits, simply add more to each place. For example, if you want to have 4 digits, do %4.4d, and so on. This will properly create the right string so that we can rename the right file in this new directory.
Hope this helps!
i have thousand files in a folder, however, i only need to extract out hundred files from the folder according to the filename listed in a text file into new folder. The filenames in text file is listed as a column..is that possible to be run by using matlab?what is the code shall i need to write? Thanks.
example:
filenames.txt is in the C:\matlab
folder include thousand files is named as BigFiles also in C:\matlab
files to be extracted from BigFiles folder is listed in column as below:
filenames.txt
a1sndh
sd3rfe
rgd4de
sd5erw
please advise...thanks...
Enumerate all files in a folder of a specific type (if needed) using:
%main directory to process
directory = 'to_process';
%enumerate all files (.m in this case)
files = dir(fullfile(directory,'*.m'));
numfiles = length(files);
fprintf('Found %i files\n',numfiles)
Then you could load the single column using one of the many file I/O functions in Matlab.
Then just loop through all the input names and check it's name against all the read in files (files{i}.name), and if so, move it.
EDIT:
From what I understood, you are looking for a solution along the lines:
filenames.txt
a.txt
b.txt
c.txt
.
.
.
moveMyFiles.m
%# read filenames listed in a text file
fid = fopen('C:\matlab\filenames.txt');
fList = textscan(fid, '%s');
fList = fList{1};
fclose(fid);
%# source/destination folder names
sourceDir = 'C:\matlab\BigFiles';
destDir = 'C:\matlab\out';
if ~exist(destDir,'dir')
mkdir(destDir);
end
%# move files one by one
for i=1:numel(fList)
movefile(fullfile(sourceDir,fList{i}), fullfile(destDir,fList{i}));
end
You can replace the MOVEFILE function by COPYFILE if you simply want to copy the files instead of moving them...