I'm trying to get grades of each question, I have a query but it only return final grade of whole exam, but i want grade of each question, how to get it?
Here is query that i have:
SELECT mdl_grade_items.id AS ItemID,
mdl_course.shortname AS CourseShortname,
mdl_grade_items.itemname AS ItemName,
mdl_grade_items.grademax AS ItemGradeMax,
mdl_grade_items.aggregationcoef AS ItemAggregation,
mdl_grade_grades.finalgrade AS FinalGrade,
mdl_user.username AS StudentID,
mdl_user.id
FROM mdl_grade_items
INNER JOIN mdl_grade_grades
ON mdl_grade_items.id = mdl_grade_grades.itemid
INNER JOIN mdl_role_assignments
ON mdl_grade_grades.userid = mdl_role_assignments.userid
AND mdl_grade_items.courseid = mdl_role_assignments.mdlcourseid
INNER JOIN mdl_course
ON mdl_course.id = mdl_grade_items.courseid
INNER JOIN mdl_user
ON mdl_user.id = mdl_role_assignments.userid
Ok, i found it
SELECT mqa.id,meqi.grade * (select fraction from mdl_question_attempt_steps where
questionattemptid = mqas.questionattemptid and state like 'mangr%' order by id desc limit
1 ) finalgrade,me.course , mqas.userid,u.firstname, u.lastname, mqa.questionsummary,
mqa.responsesummary , meqi.grade
FROM mdl_question_attempts mqa
left JOIN mdl_question_attempt_steps mqas ON mqa.id = mqas.questionattemptid
left JOIN mdl_user u ON mqas.userid = u.id
left JOIN mdl_examm_question_instances meqi ON meqi.question = mqa.questionid
left JOIN mdl_examm me ON meqi.examm = me.id
WHERE me.course= $courseID and userid = $userID
Related
I have the following query:
SELECT array_agg(DISTINCT p.id) AS price_ids,
array_agg(p.name) AS price_names
FROM items
LEFT JOIN prices p on p.item_id = id
LEFT JOIN third_table t3 on third_table.item_id = id
WHERE id = 1;
When I LEFT JOIN the third_table all my prices are duplicated.
I'm using DISTINCT inside ARRAY_AGG() to get the ids without dups, but I want the names without dups aswell.
If I use array_agg(DISTINCT p.name) AS price_names, it will return distinct values based on the name, not the id.
I want to do something similar to array_agg(DISTINCT ON (p.id) p.name) AS price_names, but it is invalid.
How can I use DISTINCT ON inside ARRAY_AGG()?
Aggregate first, then join:
SELECT p.price_ids,
p.price_names,
t3.*
FROM items
LEFT JOIN (
SELECT pr.item_id,
array_agg(pr.id) AS price_ids,
array_agg(pr.name) AS price_names
FROM prices pr
GROUP BY pr.item_id
) p on p.item_id = items.id
LEFT JOIN third_table t3 on third_table.item_id = id
WHERE items.id = 1;
Using a lateral join might be faster if you only pick a single item:
SELECT p.price_ids,
p.price_names,
t3.*
FROM items
LEFT JOIN LATERAL (
SELECT array_agg(pr.id) AS price_ids,
array_agg(pr.name) AS price_names
FROM prices pr
WHERE pr.item_id = items.id
) p on true
LEFT JOIN third_table t3 on third_table.item_id = id
WHERE items.id = 1;
the values returned in column a.user_id are id numbers. I would like to return them as a name or initials e.g. 1 = Chris O or C.ONeill
I have tried CASE function but did not know where to put it
SELECT DISTINCT
sb.start_time::date AS shift_date,
i.title AS industry,
wl.name AS venue_name,
w.first_name,
w.last_name,
MIN(cs.start_time::date) AS first_completed_shift,
i.title AS industry,
w.interviewed_on AS induction_date,
d.issue_date AS edbs_issue_date,
d.created_at AS date_dbs_added,
a.user_id --IS IT POSSIBLE TO GET THESE AS VALUES,e.g. a.user_id '1' = 'Chris O or C.ONeill' USING USER NAMES INSTEAD OF USER ID?
FROM shift_bookings sb
JOIN jobs j ON sb.job_id = j.id
JOIN listings l ON j.listing_id = l.id
JOIN work_locations wl ON l.venue_id = wl.id
JOIN workers w ON sb.worker_id = w.id
JOIN completed_shifts cs ON w.id = cs.worker_id
JOIN documents d ON w.id = d.documentable_id
JOIN audits a ON d.id = a.auditable_id
JOIN industries i ON j.industry_id = i.id
WHERE sb.shift_id IN (253106)
AND d.document_type_id = 33
AND a.auditable_type = 'Document'
GROUP BY
sb.start_time::date,
wl.name,
w.first_name,
w.last_name,
i.title,
w.interviewed_on,
d.issue_date,
d.created_at,
a.user_id
a.user_id output will be something else I can set
I have a query like this:
select c.id, c.name, c.website, c.longdescription, c.description, c.email,
(SELECT jsonb_agg(ev) FROM
(SELECT ev.title, ev.description, ev.longdescription,
(SELECT jsonb_agg(ed) FROM
(SELECT ed.startdate, ed.enddate, ed.id WHERE ed.id notnull)ed) as dates, ev.id WHERE ev.id notnull) ev) as events,
(SELECT jsonb_agg(ca) FROM (SELECT ct.zip, ca.id, ca.street1, ca.street2, ca.addresstype_id, ST_Y(ca.geopoint::geometry) as latitude, ST_X(ca.geopoint::geometry) as longitude
WHERE ca.id notnull)ca) as addresses
FROM companies c
LEFT JOIN events ev ON ev.company_id = c.id
LEFT JOIN companyaddresses ca ON ca.company_id = c.id
LEFT JOIN cities ct ON ct.id = ca.city_id
LEFT JOIN eventdates ed ON ed.event_id = ev.id
GROUP by c.id
I am getting the error "ERROR: subquery uses ungrouped column "ev.title" from
outer query Position: 125".
Can't figure out how to group it correctly for the subqueries. Any suggestions?
Give this a try:
SELECT c.id, c.name, c.website, c.longdescription, c.description, c.email,
(SELECT jsonb_agg(ev) FROM
(SELECT even.title, even.description, even.longdescription,
(SELECT jsonb_agg(ed) FROM
(SELECT eventdates.startdate, eventdates.enddate, eventdates.id FROM eventdates WHERE eventdates.event_id = even.id)ed) as dates,
even.id FROM events even WHERE even.company_id = c.id) ev) as events,
jsonb_agg((SELECT ca FROM (SELECT ct.zip, ca.id, ca.street1, ca.street2, ca.addresstype_id, ST_Y(ca.geopoint::geometry) as latitude, ST_X(ca.geopoint::geometry) as longitude WHERE ca.id notnull)ca)) as addresses
FROM companies c
LEFT JOIN companyaddresses ca ON ca.company_id = c.id
LEFT JOIN cities ct ON ct.id = ca.city_id
Group by c.id
this query is not returning correct latest_enrolment date. whenever i enrol a user in course, it doesnot updates enrolment date in database.. can anyone help?
SELECT TRIM(c.id) course_id,TRIM(c.fullname) course_fullname,FROM_UNIXTIME(u.timecreated) as registration ,FROM_UNIXTIME( ra.timemodified ) latest_enrolment_date,COUNT( * ) AS enrol_count
FROM mdl_user u
INNER JOIN mdl_role_assignments ra ON ra.userid = u.id
INNER JOIN mdl_context ct ON ct.id = ra.contextid
INNER JOIN mdl_course c ON c.id = ct.instanceid
INNER JOIN mdl_role r ON r.id = ra.roleid
INNER JOIN mdl_course_categories cc ON cc.id = c.category
WHERE r.id =5 GROUP BY c.id
Something like this
SELECT MAX(ue.timecreated) AS latest_enrolment_date
FROM mdl_enrol e
JOIN mdl_user_enrolments ue ON ue.enrolid = e.id
WHERE e.courseid = xx
This question already has an answer here:
Closed 10 years ago.
Possible Duplicate:
How to eliminate NULL fields in TSQL
I am using SSMS 2008 R2 and am developing a TSQL query. I want just 1 record / profile_name. Because some of these values are NULL, I am currently doing LEFT JOINS on most of the tables. But the problem with the LEFT JOINs is that now I get > 1 record for some profile_names!
But if I change this to INNER JOINs then some profile_names are excluded entirely because they have NULL values for these columns. How do I limit the query result to just one record / profile_name regardless of NULL values? And if there are non-NULL values then I want it to choose the record with non-NULL values. Here is initial query:
select distinct
gp.group_profile_id,
gp.profile_name,
gp.license_number,
gp.is_accepting,
case when gp.is_accepting = 1 then 'Yes'
when gp.is_accepting = 0 then 'No '
end as is_accepting_placement,
mo.profile_name as managing_office,
regions.[region_description] as region,
pv.vendor_name,
pv.id as vendor_id,
at.description as applicant_type,
dbo.GetGroupAddress(gp.group_profile_id, null, 0) as [Office Address],
gsv.status_description
from group_profile gp With (NoLock)
inner join group_profile_type gpt With (NoLock) on gp.group_profile_type_id = gpt.group_profile_type_id and gpt.type_code = 'FOSTERHOME' and gp.agency_id = #agency_id and gp.is_deleted = 0
inner join group_profile mo With (NoLock) on gp.managing_office_id = mo.group_profile_id
left outer join payor_vendor pv With (NoLock) on gp.payor_vendor_id = pv.payor_vendor_id
left outer join applicant_type at With (NoLock) on gp.applicant_type_id = at.applicant_type_id and at.is_foster_home = 1
inner join group_status_view gsv With (NoLock) on gp.group_profile_id = gsv.group_profile_id and gsv.status_value = 'OPEN' and gsv.effective_date =
(Select max(b.effective_date) from group_status_view b With (NoLock)
where gp.group_profile_id = b.group_profile_id)
left outer join regions With (NoLock) on isnull(mo.regions_id, gp.regions_id) = regions.regions_id
left join enrollment en on en.group_profile_id = gp.group_profile_id
join event_log el on el.event_log_id = en.event_log_id
left join people client on client.people_id = el.people_id
As you can see, the results of the above query is 1 row / profile_name:
group_profile_id profile_name license_number is_accepting is_accepting_placement managing_office region vendor_name vendor_id applicant_type Office Address status_description Cert Date2
But now watch what happens when I add in 2 LEFT JOINs and 1 additional column:
select distinct
gp.group_profile_id,
gp.profile_name,
gp.license_number,
gp.is_accepting,
case when gp.is_accepting = 1 then 'Yes'
when gp.is_accepting = 0 then 'No '
end as is_accepting_placement,
mo.profile_name as managing_office,
regions.[region_description] as region,
pv.vendor_name,
pv.id as vendor_id,
at.description as applicant_type,
dbo.GetGroupAddress(gp.group_profile_id, null, 0) as [Office Address],
gsv.status_description,
ri.[description] as race
from group_profile gp With (NoLock)
inner join group_profile_type gpt With (NoLock) on gp.group_profile_type_id = gpt.group_profile_type_id and gpt.type_code = 'FOSTERHOME' and gp.agency_id = #agency_id and gp.is_deleted = 0
inner join group_profile mo With (NoLock) on gp.managing_office_id = mo.group_profile_id
left outer join payor_vendor pv With (NoLock) on gp.payor_vendor_id = pv.payor_vendor_id
left outer join applicant_type at With (NoLock) on gp.applicant_type_id = at.applicant_type_id and at.is_foster_home = 1
inner join group_status_view gsv With (NoLock) on gp.group_profile_id = gsv.group_profile_id and gsv.status_value = 'OPEN' and gsv.effective_date =
(Select max(b.effective_date) from group_status_view b With (NoLock)
where gp.group_profile_id = b.group_profile_id)
left outer join regions With (NoLock) on isnull(mo.regions_id, gp.regions_id) = regions.regions_id
left join enrollment en on en.group_profile_id = gp.group_profile_id
join event_log el on el.event_log_id = en.event_log_id
left join people client on client.people_id = el.people_id
left join race With (NoLock) on el.people_id = race.people_id
left join race_info ri with (nolock) on ri.race_info_id = race.race_info_id
The above query results in all of the same profile_names, but some with NULL race values:
group_profile_id profile_name license_number is_accepting is_accepting_placement managing_office region vendor_name vendor_id applicant_type Office Address status_description Cert Date2 race
Unfortunately it complicates matters that I need to join in 2 additional tables for this one additional field value (race). If I simply change the last two LEFT JOINs above to INNER JOINs then I eliminate the NULL rows above. But I also eliminate some of the profile_names:
group_profile_id profile_name license_number is_accepting is_accepting_placement managing_office region vendor_name vendor_id applicant_type Office Address status_description Cert Date2 race
Hopefully I have provided all of the details that you need for this question.
Not the most elegant solution, but one that will work:
select [stuff]
from group_profile gp With (NoLock)
inner join group_profile_type gpt With (NoLock) on gp.group_profile_type_id = gpt.group_profile_type_id and gpt.type_code = 'FOSTERHOME' and gp.agency_id = #agency_id and gp.is_deleted = 0
inner join group_profile mo With (NoLock) on gp.managing_office_id = mo.group_profile_id
join payor_vendor pv on ISNULL(gp.payor_vendor_id, 'THISVALUEWILLNEVEROCCUR') = ISNULL(pv.payor_vendor_id, 'THISVALUEWILLNEVEROCCUR')
...etc...
Biggest issue with what I posted is that you'll be doing a whole lot of table scans.