I have a class hierarchy for JPA entities with the base class being a MappedSuperclass which has one ID defined. I am trying to use a composite key in a subclass however that does not seem to work
My code looks like this
#MappedSuperclass
public class BaseEntity implements Serializable {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Basic(optional = false)
#Column(name = "id")
protected Long id;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
}
#Entity
#EntityListeners(EntityBaseListener.class)
#Inheritance(strategy=InheritanceType.JOINED)
#Table(name = "catalog_entity")
public class BaseCatalogEntity extends BaseEntity {
#Column(name = "created_at", nullable = false)
#Temporal(TemporalType.TIMESTAMP)
private Date createdAt;
#Column(name = "updated_at", nullable = false)
#Temporal(TemporalType.TIMESTAMP)
private Date updatedAt;
public void setCreatedAt(Date date)
{
createdAt = date;
}
public void setUpdatedAt(Date date)
{
updatedAt = date;
}
public Date getCreatedAt() {
return createdAt;
}
public Date getUpdatedAt() {
return updatedAt;
}
}
#Entity
#Table(schema = "student_catalog")
#IdClass(value = StudentCatalog.StudentCatalogPK.class)
public class StudentCatalog extends BaseCatalogEntity {
#Id
#Column(name = "name", nullable = false, length = 100)
private String name;
#Id
#Column(name = "version", nullable = false)
private Integer version;
#Column(name = "description" , length = 255)
private String description;
#Column(name = "vendor" , length = 50)
private String vendor;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getVersion() {
return version;
}
public void setVersion(Integer version) {
this.version = version;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
public String getVendor() {
return vendor;
}
public void setVendor(String vendor) {
this.vendor = vendor;
}
public static class StudentCatalogPK implements Serializable {
private Long id;
private String name;
private Integer version;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getVersion() {
return version;
}
public void setVersion(Integer version) {
this.version = version;
}
#Override
public boolean equals(Object obj) {
boolean result = false;
if(obj != null && (obj instanceof StudentCatalogPK)) {
StudentCatalogPK other = (StudentCatalogPK)obj;
result = (Objects.equals(this.id, other.id) && Objects.equals(this.name, other.name) &&
Objects.equals(this.version, other.version));
}
return result;
}
#Override
public int hashCode() {
return (27780 + (this.id != null ? this.id.hashCode() : 0) +
(this.version != null ? this.version.hashCode() : 0) +
(this.name != null ? this.name.hashCode() : 0));
}
}
}
I get the following exception:
Exception Description: Invalid composite primary key specification. The names of the primary key fields or properties in the primary key class [com.example.jpa.StudentCatalog$StudentCatalogPK] and those of the entity bean class [class com.example.jpa.StudentCatalog] must correspond and their types must be the same. Also, ensure that you have specified ID elements for the corresponding attributes in XML and/or an #Id on the corresponding fields or properties of the entity class.
I am using Eclipselink 2.5.1. Is there a way I can get this to work without changing the BaseEntity and BaseCatalogEntity classes?
It is not legal in JPA to redefine the id in subclasses. This would lead to ambiguities in the table mappings as well as in polymorphic queries.
The desire to extend the key defined in a superclass is a common issue when business keys are used for DB identity. I would advise to use only surrogate keys (like UUID) for DB identity and business keys for instance identity.
Under following conditions:
your base entity should use TABLE_PER_CLASS inheritance (and as I can see it is)
your base entity (composite key) key is of the same type as that one you want to have in your derived class (so there should be also composite key of String and Integer).
You can use #AttributeOverride annotation under class declaration, removing #Id fields from it:
#AttributeOverride(name = "id", column = #Column(name = "NAME"))
This - in result, can change column name in derived entity's table and that's the most you can acheive.
When using #MappedSuperClass, it would be advisable to make the BaseEntity Class as abstract and then extending the Base class from other Entity classes.
Cleaner approach keeping inheritance in mind and designing your application.
Related
To find an object from entity with primary key we use em.find(Person.class, <Id>).
I'm using JPA EclipseLink and I have a Person entity which has a composite primary key(#classId),
the Person entity:
#Entity
#IdClass(PersonId.class)
public class Person {
#Id
private int id;
#Id
private String name;
public String getName() {
return name;
}
// getters & setters
}
and the PersonID:
public class PersonId implements Serializable {
private static final long idVersionUID = 343L;
private int id;
private String name;
// must have a default construcot
public PersonId() {
}
public PersonId(int id, String name) {
this.id = id;
this.name = name;
}
//getters & setters
//hachCode & equals
}
How to use em.find to get a Person object?
I found the solution :
PersonId personeId = new PersonId(33, "Jhon");
Person persistedPerson = em.find(Person.class, personeId);
System.out.println(persistedPerson.getID() + " - " + persistedPerson.getName());
I have one exception, which yold what I have no mapping on table. But I have this
Exeption is : \
AnnotationException: mappedBy reference an unknown target entity property: Relative.people in Person.relations
Relative entity is here:
#Entity
#Table(name = "relation")
public class Relative extends AbstractModel<UUID> implements Model<UUID> {
private UUID id;
private Person person;
private RelationTypeEnum relation;
public Relative() {
}
#Override
public void assignId() {
id = UUID.randomUUID();
}
#Override
#Id
#Column(name = "id")
public UUID getId() {
return id;
}
#ManyToOne
#JoinColumn(name="person_id", nullable=false)
public Person getPerson() {
return person;
}
#Column(name = "relation")
public RelationTypeEnum getRelation() {
return relation;
}
public void setId(UUID id) {
this.id = id;
}
public void setPerson(Person person) {
this.person = person;
}
public void setRelation(RelationTypeEnum relation) {
this.relation = relation;
}
}
And Person entity is here:
#Entity
#Table(name = "people")
public class Person extends AbstractModel<UUID> implements Model<UUID> {
private UUID id;
private String name;
private List<Relative> relations;
#Override
public void assignId() {
id = UUID.randomUUID();
}
#Override
#Id
#Column(name = "id")
public UUID getId() {
return id;
}
#Column(name = "name")
public String getName() {
return name;
}
#OneToMany(targetEntity=Relative.class, cascade=CascadeType.ALL,
mappedBy="people")
public List<Relative> getRelations() {
return relations;
}
public void setId(UUID id) {
this.id = id;
}
public void setName(String username) {
this.name = username;
}
public void setRelations(List<Relative> relations) {
this.relations = relations;
}
}
Solved.
Just changed
#Table(name = "people")
to
#Table(name = "person")
In my case there was a project which included a copy of the jar causing this issue. It was a web project which is including the jar inside its lib i.e. 2 copies of the same jar one with a different class version. Only discovered this when I physically opened the main ear and found the 2nd jar inside a web project.
I'm trying to do a database lookup using JPA with EclipseLink. My database is Oracle 11.2.0. I have the following entity classes defined:
#Entity
#Table(name = "BS_PROVIDERS")
public class BsProvider {
#Id
#Column(name = "GUID")
private String guid;
public String getGuid() { return guid; }
public void setGuid(String guid) { this.guid = guid; }
#Column(name = "NAME")
private String name;
public String getName() { return name; }
public void setName(String name) { this.name = name; }
}
#Entity
#Table(name = "CP_PROVIDERS")
public class CpProvider{
#Id
#Column(name = "GUID")
private String guid;
public String getGuid() { return guid; }
public void setGuid(String guid) { this.guid = guid; }
#Column(name = "NAME")
private String name;
public String getName() { return name; }
public void setName(String name) { this.name = name; }
}
#NamedQueries({
#NamedQuery(
name = Catalog.FIND_BY_CPP_AND_BSP,
query = "select c from Catalog c where (c.cpProvider = :cpProvider) and ( (:bsProvider IS NULL) or (c.bsProvider = :bsProvider))"
)
})
#Entity
#Table(name = "CATALOGS")
public class Catalog {
public static final String FIND_BY_CPP_AND_BSP = "Catalog.findByCppAndBsp";
public static final String CP_PROVIDER_PARAM = "cpProvider";
public static final String BS_PROVIDER_PARAM = "bsProvider";
#Id
#Column(name = "GUID")
private String guid;
public String getGuid() { return guid; }
public void setGuid(String guid) { this.guid = guid; }
#Column(name = "NAME")
private String name;
public String getName() { return name; }
public void setName() { this.name = name; }
#ManyToOne
#JoinColumn(name = "CPP_GUID")
private CpProvider cpProvider;
public CpProvider getCpProvider() { return cpProvider; }
public void setCpProvider(CpProvider cpProvider) { this.cpProvider = cpProvider; }
#ManyToOne()
#JoinColumn(name = "BSP_GUIG")
private BsProvider bsProvider;
public BsProvider getBsProvider() { return bsProvider; }
public void setBsProvider(BsProvider bsProvider) { this.bsProvider = bsProvider; }
}
Code that creates the query and sets the parameters:
TypedQuery<Catalog> catalogQuery = em.createNamedQuery(Catalog.FIND_BY_CPP_AND_BSP, Catalog.class);
catalogQuery.setParameter(Catalog.CP_PROVIDER_PARAM, cpProvider);
catalogQuery.setParameter(Catalog.BS_PROVIDER_PARAM, bsProvider);
List<Catalog> catalogList = catalogQuery.getResultList();
When the variable bsProvider is NULL, all parameters are registerd are registerd correctly according to the EclipseLink log:
SELECT GUID, NAME, BSP_GUIG, CPP_GUID FROM CATALOGS WHERE ((CPP_GUID = ?) AND ((? IS NULL) OR (BSP_GUIG = ?)))
bind => [18EC0EDB-21A4-4845-960A-D5D2BDAC7B87, null, null]
Otherwise when the variable bsProvider refers to an existing entity I get the following exception:
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.3.2.v20111125-r10461): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: java.sql.SQLException: Invalid column type
Error Code: 17004
Call: SELECT GUID, NAME, BSP_GUIG, CPP_GUID FROM CATALOGS WHERE ((CPP_GUID = ?) AND ((? IS NULL) OR (BSP_GUIG = ?)))
bind => [18EC0EDB-21A4-4845-960A-D5D2BDAC7B87, com.bssys.ebpp.dbaccess.model.BsProvider#5dbbe8df, 44E8F4BF-CFDC-49DB-AB0B-718C72D6B4EF]
As you can see the first and the third parameters are bound correctly (they are replaced by the primary key values), but the second is not. What's the reason of such a strange behavior?
I have an existing JPA entity ("Reference") with an ID column as its primary key that it inherits from a base class "BaseEntity" (using the #MappedSuperclass annotation on the superclass).
I also have a 1-M relationship between a Reference and another entity called Violation. Violation was previously defined with a foreign key "REFERENCE_ID" to the "ID" column of the Reference entity.
Recently, I tried to add an unrelated composite key to the Reference entity. This should not have affected the 1-M relationship between Reference and Violation. However, when I run the code in my tomcat server, I see the following stack trace:
Caused by: org.hibernate.AnnotationException: referencedColumnNames(ID) of org.qcri.copydetection.sdk.metastore.entity.Violation.reference referencing org.qcri.copydetection.sdk.metastore.entity.Reference not mapped to a single property
at org.hibernate.cfg.BinderHelper.createSyntheticPropertyReference(BinderHelper.java:205) ~[hibernate-annotations-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:110) ~[hibernate-annotations-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.cfg.AnnotationConfiguration.processEndOfQueue(AnnotationConfiguration.java:541) ~[hibernate-annotations-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.cfg.AnnotationConfiguration.processFkSecondPassInOrder(AnnotationConfiguration.java:523) ~[hibernate-annotations-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.cfg.AnnotationConfiguration.secondPassCompile(AnnotationConfiguration.java:380) ~[hibernate-annotations-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.cfg.Configuration.buildMappings(Configuration.java:1206) ~[hibernate-core-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.ejb.Ejb3Configuration.buildMappings(Ejb3Configuration.java:1459) ~[hibernate-entitymanager-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.ejb.EventListenerConfigurator.configure(EventListenerConfigurator.java:193) ~[hibernate-entitymanager-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:1086) ~[hibernate-entitymanager-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.ejb.Ejb3Configuration.configure(Ejb3Configuration.java:685) ~[hibernate-entitymanager-3.5.6-Final.jar:3.5.6-Final]
at org.hibernate.ejb.HibernatePersistence.createContainerEntityManagerFactory(HibernatePersistence.java:73) ~[hibernate-entitymanager-3.5.6-Final.jar:3.5.6-Final]
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:268) ~[spring-orm-3.1.2.RELEASE.jar:3.1.2.RELEASE]
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:310) ~[spring-orm-3.1.2.RELEASE.jar:3.1.2.RELEASE]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1514) ~[spring-beans-3.1.2.RELEASE.jar:3.1.2.RELEASE]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1452) ~[spring-beans-3.1.2.RELEASE.jar:3.1.2.RELEASE]
... 39 common frames omitted
Here is the code for the 3 classes involved:
#Entity
#Table(name = "REFERENCE")
#XmlRootElement
#XmlAccessorType(XmlAccessType.PROPERTY)
#IdClass(Reference.ContextualName.class)
public class Reference extends BaseEntity {
#Column(name= "LOCATION", unique=true)
#XmlElement
private String location;
#Id
#AttributeOverrides({
#AttributeOverride(name = "name", column = #Column(name = "NAME")),
#AttributeOverride(name = "account", column = #Column(name = "ACCOUNT_ID"))
})
#Column(name = "NAME")
#XmlElement
private String name;
#ManyToOne(optional=false)
#XmlTransient
#JoinColumn(name = "ACCOUNT_ID", referencedColumnName = "ID")
private Account account;
public String getLocation() {
return location;
}
public void setLocation(String location) {
this.location = location;
}
public Reference() {}
public Reference(String name) {
setName(name);
}
public void setName(String name) {
this.name = name;
}
public String getName() {
return this.name;
}
public Account getAccount() {
return this.account;
}
public void setAccount(Account account) {
this.account = account;
}
#Embeddable
private class ContextualName implements Serializable {
private static final long serialVersionUID = -3687389984589209378L;
#Basic(optional = false)
#Column(name = "NAME")
#XmlElement
private String name;
#ManyToOne(optional=false)
#XmlTransient
#JoinColumn(name = "ACCOUNT_ID", referencedColumnName = "ID")
private Account account;
ContextualName() {}
}
}
#MappedSuperclass
#XmlAccessorType(XmlAccessType.FIELD)
public abstract class BaseEntity {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID")
#XmlElement
private Long id;
#Basic(optional = true)
#Column(name = "CREATED", insertable = false, updatable = false, columnDefinition="TIMESTAMP DEFAULT CURRENT_TIMESTAMP")
#Temporal(TemporalType.TIMESTAMP)
#XmlElement
private Date creationDate;
protected BaseEntity() {}
public Long getId() {
return id;
}
public void setId(Long id) {
if(this.id==null) {
this.id = id;
} else if (this.id!=id) {
throw new IllegalArgumentException("Cannot change the id after it has been set, as it is a generated field.");
}
}
public Date getCreationDate() {
return creationDate;
}
public void setCreationDate(Date creationDate) {
if(this.creationDate==null) {
this.creationDate = creationDate;
} else if (this.creationDate!=creationDate) {
throw new IllegalArgumentException("Cannot change the creation-date after it has been set, as it is a generated field.");
}
}
}
#Entity
#Table(name = "VIOLATION")
#XmlRootElement
#XmlAccessorType(XmlAccessType.FIELD)
public class Violation extends BaseEntity {
#ManyToOne (optional=false, fetch= FetchType.EAGER)
#JoinColumn(name = "REFERENCE_ID", referencedColumnName = "ID")
private Reference reference;
#ManyToOne (optional=false, fetch= FetchType.EAGER)
#JoinColumn(name = "SUSPECT_ID", referencedColumnName = "ID")
private Suspect suspect;
#ManyToOne (optional=false, fetch= FetchType.EAGER)
#XmlTransient
#JoinColumn(name = "SEARCH_ID", referencedColumnName = "ID")
private Search search;
#Basic(optional = false)
#Column(name = "SCORE")
#XmlElement
private double score;
public Violation() {}
public Violation(Search search, Reference ref, Suspect sus, double score) {
this.search = search;
this.reference = ref;
this.suspect = sus;
this.score = score;
}
public double getScore() {
return score;
}
public void setScore(double score) {
this.score = score;
}
public Reference getReference() {
return reference;
}
public void setReference(Reference reference) {
this.reference = reference;
}
public Suspect getSuspect() {
return suspect;
}
public void setSuspect(Suspect suspect) {
this.suspect = suspect;
}
public Search getSearch() {
return search;
}
public void setSearch(Search search) {
if(this.search!=null && this.search!=search) {
this.search.removeViolation(this);
}
this.search = search;
if(search!=null) {
if(!search.getViolations().contains(this)) {
search.addViolation(this);
}
}
}
}
To cut a long story short, I'm totally confused how to go about adding a composite key to an existing (legacy) entity that already has an ID column. I can't remove the ID column, nor can I change the 1-M relationship between Reference and Violation. I can't for the life of me understand the error message because the "REFERENCE_ID" foreign key column of the Violation entity is being mapped to a single "ID" column of the Reference entity.
Many thanks in advance!
I want to copy the entity's UUID, generated at run time to another field.
The entity id is generated via the code described bellow:
package eclipselink.example;
public class UUIDSequence extends Sequence implements SessionCustomizer {
public UUIDSequence() {
super();
}
public UUIDSequence(String name) {
super(name);
}
#Override
public Object getGeneratedValue(Accessor accessor,
AbstractSession writeSession, String seqName) {
return UUID.randomUUID().toString().toUpperCase();
}
...
public void customize(Session session) throws Exception {
UUIDSequence sequence = new UUIDSequence("system-uuid");
session.getLogin().addSequence(sequence);
}
}
Persitence.xml:
property name="eclipselink.session.customizer" value="eclipselink.example.UUIDSequence"
The entity:
public abstract class MyEntity{
private String id;
private String idCopy;
#Id
#Basic(optional = false)
#GeneratedValue(generator="system-uuid")
#XmlElement(name = "ID")
public String getId() {
return id;
}
}
How can I instruct JPA (Eclipse-link) to copy the UUID generated at runtime to idCopy field as well?
I'm not 100% sure this will work (I don't know if EclipseLink calls the setter or assigns the field directly), but give this a try:
public abstract class MyEntity{
private String id;
private String idCopy;
#Id
#Basic(optional = false)
#GeneratedValue(generator="system-uuid")
#XmlElement(name = "ID")
public String getId() {
return id;
}
public void setId(String id) {
this.id = id;
this.idCopy = id;
// or
// this.setIdCopy(id);
}
}