Mysqli second query doesn't work - mysqli

Question

I want to use de result from my first query to insert in a second query, there's not error in the sintaxis.
I've been reading a lot but anything seems to work.
HELP!!!!
$sql = "CALL sp_producto(1);";
$rs = $mysqli->query($sql);
$idNuevo;
if ($fila = $rs->fetch_assoc()) {
$idNuevo = $fila['idNew']; //recupera el id del insertado
$talleres = explode(",", $_POST["proceso_prod"]);
foreach ($talleres as $t) {
//THIS DOESN'T WORK BUT IDONT KNOW WHY
$sql = "INSERT INTO proceso_produccion () VALUES (" . $idNuevo . ", ".$t.")";
echo $sql;
$mysqli->query($sql);
}
}

Answer 1

INSERT INTO proceso_produccion () VALUES (" . $idNuevo . ", ".$t.")
This line is the issue, if you are inserting values in all of your table columns no need to have this ()
,change your code to this :
INSERT INTO proceso_produccion VALUES (" . $idNuevo . ", ".$t.")
but if you are inserting to only certain column, you have to specify the column names,
like this :
INSERT INTO proceso_produccion ('firstColumn','anotherColumn') VALUES (" . $idNuevo . ", ".$t.")

Answer 2

Niang answered right, but also check if both values you are entering are integers. Otherwise, the should be in quotes like so:
INSERT INTO proceso_produccion ('firstColumn','anotherColumn') VALUES ('" . $idNuevo . "', '".$t."')
Also, this condition is not a real condition:
if ($fila = $rs->fetch_assoc()) {
You are only assigning value to $fila this way. It should be:
if ($fila == $rs->fetch_assoc()) {
Finally, if query still doesn't work can you please post echoed query, the result of echo $sql.