How to compare sas date JAN14 with other variable. I have used date1='JAN14'd but it is not working. What are the other options i can try? I have tried comparing with 'JAN14' also but again it is not working.
That's only part of a date. You need to fully specify day, month and year, e.g. '01JAN2014'd
Related
I am selecting the data from a table using a date string. I would like to select all rows that have a update time stamp greater than or equal to today.
The simplest way that I can think of is to put today's date in the string, and it works fine.
WHERE UPDATE_DTM >'29NOV2016:12:00'DT;
However, if I want to put something like today's date or system date, what should I put?
I used today(), but it returned all rows in the table. I am not sure if it's because today() in SAS refers to the date 1/1/1960? I also tried &sysdate, but it returned an error message seems like it requires a date conversion.
WHERE UPDATE_DTM > TODAY();
Any ideas? Your thoughts are greatly appreciated!
DATETIME() is the datetime equivalent of TODAY() (but includes the current time). You could also use dhms(TODAY(),0,0,0) if you want effectively midnight (or, for your example above, dhms(TODAY(),12,0,0) to get noon today).
I'm attempting to make the parameters for a Crystal Report more user-friendly for a client, who has requested that they be able to have the default values for a Start and End date parameter be the first and last day of the previous month.
I know how to use either a formula in CR or a stored procedure to produce these values, but I want to know if a variable can be used in the 'Default Value' setting for a parameter, or if it only allows for static entries. Does anyone know? Right now the user can set the date parameters to null and the stored procedure generates the data for the previous month on its own, but I thought it'd be nice if the date parameters actually displayed the dates that were being used as defaults. Thanks in advance!
You can do it, Try below process:
Create a parameter ?date with String datatype and take static and write two default strings as below:
First day of previous month
Last day of Previous month
Now go to record selection formula and write below code:
if ({?date}="First day of previous month") then
table.date=DateSerial(year(currentdate),Month(Currentdate)-1,1)
else if ({?date}="Last day of previous month")
then
table.date=Cdate(DateAdd("d",-1,DateSerial(year(currentdate),Month(Currentdate),1)))
I have a date that is stored as a number that is 201401. I would like to subtract 1 month, so that is 201312 and not 201400.
Also, if there is a more efficient way, please suggest as well. I also have the date stored as 01Jan2014, and would be fine converting the SAS date at that point, so that I can create two new columns (with 1 month subtracted) so that they have the value 01Dec2013 and 201312. Also, a function for incrementing the month forward or backward would be much appreciated.
Thanks in advance.
If you store the date as a SAS date, you can use the function intnx to increment it by whatever period you like.
newdate = intnx('Month',olddate,1,'s');
If you store it as an integer like your original, you're on your own to figure that out. My answer: don't.
The prior answer works.
I just wanted to add, storing as Date in SAS is not the same as storing as integer. It may display 01JAN2014 but it represents a number, so you can still perform computations.
If you store the date as a SAS date, you can use the function intnx to increment it by whatever period you like.
newdate = intnx('Month',olddate,1,'s');
I have imported some data into SAS from some Excel spreadsheets sent to me. When I view the output from the imported table, the date appears as "01APR2014" and maintains chronological order. When I view the column properties the type is "Date" and the length is 8. Both the format and informat are DATE9.
I need to be able to convert this date to week-year and month-year, but no matter what I try I always get Jan, 1960.
Using proc sql, I used the below to get the week-year,
"(put(datepart(a.fnlz_date),weeku3.))|| "-" ||(put(datepart(a.fnlz_date),year.)) as FNLZD_WK_YR,"
but all I got was "W00-1960". I've used the formula above successfully many times before with SAS datetime values.
For month-yr, using proc sql, I tried
"datepart(a.fnlz_date) as DT_FNLZD format=monyy.,"
but the only value returned is "JAN60".
I also tried using SUBSTR, but got an error saying it requires a character argument, so SAS must see it as a number at least.
My question; does anyone know a way to get the week-yr and/or month-yr from this format? If so, how? I'm not opposed to using a data step, but I haven't been able to get that to work either.
Thanks in advance for any help or insight provided.
datepart converts datetimes to dates. Not helpful here.
If you're just displaying this, then you have a few options, particularly for month. You can just change the format of the variable (This changes what's displayed, but not the underlying value; consider this a value label).
When you use this like this (again, it looks like you got most of the way there):
proc sql;
select datevar format=monyy5. from table;
quit;
Just don't include that datepart function call as that's not appropriate unless you have a datetime. (Date=# of days since 1/1/1960, Datetime = # of seconds since 1/1/1960:00:00:00).
That will display it with MONYY5. format, which would be MAY10 for May, 2010. You have some other format options, see the documentation on formats by category for more details.
I can't think of a Week format that matches what you want (there are week formats, like WEEKW., as you clearly found, but I don't know that they do exactly what you want. So, if you want to build one yourself, you can either build a custom picture format, or you can make a string.
Building a custom picture format isn't too hard; see the documentation on Picture formats or google SAS Date Picture Format.
proc format;
picture weekyear (default=8)
low-high = 'W%0U-%Y' (datatype=date) ;
quit;
Now you can use that as a normal format.
To get at the week/etc. to build values, you can also use functions week(), month(), etc., if that's easier.
Since the data was already in a date format, I only needed to drop the DATEPART function that only works with datetime values. So, for month-yr,
"a.fnlz_date as fnlz_mnth format=monyy.,"
gives me the results I'm looking for.
Cheers!
I want to calculate the number of days passed between past date and a current date. My past date is in the format dd/mm/yyyy format. I have used below mentioned formulas but giving the proper output.
=DAYS360(A2,TODAY())
=MINUS(D2,TODAY())
In the above formula A2 = 4/12/2012 (dd/mm/yyyy) and I am not sure whether TODAY returns in dd/mm/yyyy format or not. I have tried using 123 button on the tool bar, but no luck.
The following seemed to work well for me:
=DATEDIF(B2, Today(), "D")
DAYS360 does not calculate what you want, i.e. the number of days passed between the two dates – see the end of this post for details.
MINUS() should work fine, just not how you tried but the other way round:
=MINUS(TODAY(),D2)
You may also use simple subtraction (-):
=TODAY()-D2
I made an updated copy of #DrCord’s sample spreadsheet to illustrate this.
Are you SURE you want DAYS360? That is a specialized function used in the
financial sector to simplify calculations for bonds. It assumes a 360 day
year, with 12 months of 30 days each. If you really want actual days, you'll
lose 6 days each year.
[source]
Since this is the top Google answer for this, and it was way easier than I expected, here is the simple answer. Just subtract date1 from date2.
If this is your spreadsheet dates
A B
1 10/11/2017 12/1/2017
=(B1)-(A1)
results in 51, which is the number of days between a past date and a current date in Google spreadsheet
As long as it is a date format Google Sheets recognizes, you can directly subtract them and it will be correct.
To do it for a current date, just use the =TODAY() function.
=TODAY()-A1
While today works great, you can't use a date directly in the formula, you should referencing a cell that contains a date.
=(12/1/2017)-(10/1/2017) results in 0.0009915716411, not 61.
I used your idea, and found the difference and then just divided by 365 days. Worked a treat.
=MINUS(F2,TODAY())/365
Then I shifted my cell properties to not display decimals.
If you are using the two formulas at the same time, it will not work...
Here is a simple spreadsheet with it working:
https://docs.google.com/spreadsheet/ccc?key=0AiOy0YDBXjt4dDJSQWg1Qlp6TEw5SzNqZENGOWgwbGc
If you are still getting problems I would need to know what type of erroneous result you are getting.
Today() returns a numeric integer value: Returns the current computer system date. The value is updated when your document recalculates. TODAY is a function without arguments.
The following worked for me. Kindly note that TODAY() must NOT be the first argument in the function otherwise it will not work.
=DATEDIF( W2, TODAY(), "d")
Today() does return value in DATE format.
Select your "Days left field" and paste this formula in the field
=DAYS360(today(),C2)
Go to Format > Number > More formats >Custom number format and select the number with no decimal numbers.
I tested, it works, at least in new version of Sheets, March 2015.