How do I use a UNC path in a powershell script? - powershell

I have some powershell code that calls WinZip and makes an archive.
$program = "c:\program files (x86)\WinZip\WZZIP.EXE"
& $program -a -P -r c:\temp\test.zip ("\\server.domain.com\FirstName LastName\ProjectId\*.*")
The two backslashes are part of a UNC path. I must use UNC and a fully qualified domain name.
The above code attempts to run but hangs until I kill it (press the stop button in ISE).
When I wrap the UNC path in parenthesis, again the code attempts to run but hangs.
How do I fix this? I'm stuck with UNC paths and using WinZip.

UNC paths are not supported in WinZip from the command line. You will need to map a drive letter to the UNC path before preforming the zip. You can easily script this:
net use s: "\\server.domain.com\FirstName LastName\ProjectId\"
Alternatively, you can copy the files locally, zip them, then delete them from the local copy leaving only your zip file.
I believe 7zip does not have this limitation and is generally capable of doing everything WinZip is and more.

While not a direct answer to your question, perhaps you could use the PowerShell module PowerShellZIP at CodePlex (http://powershellzip.codeplex.com/) to create the ZIP files for you.
Then you can use the full powershell pipeline to create the ZIP files rather than calling out to WinZip.
I haven't tested to see if this module can zip files from an UNC path tho..

Related

Creating files at PSModulePath in batch

I am currently trying to write a batch program that installs a module named SetConsolePath.psm1 at the correct location. I am a beginner with Batch and I have absolutely no powershell experience.
Through the internet, I have learned how to display PSModulePath with powershell -command "echo $env:PSModulePath.
How can I, via .bat file, move SetConsolePath.psm1 from the desktop to the location displayed by powershell -command "echo $env:PSModulePath?
Thank you in advance, and I apologize for my lack of experience.
Before I answer, I must out that you do not want to copy PowerShell module files directly to the path pointed by PsModulePath. You really want to create a folder inside PSModulePath and copy the files there instead.
The prefix env in a Powershell variable indicates an environment variable. $env:PSModulePath is actually referring to the PSMODULEPATH environment variable. On the command line, and in batch files, environment variables can be displayed by placing the name between percent symbols. (In fact, you could have displayed this value by typing echo %PSMODULEPATH% instead.)
To reference the desktop folder, have a look at this answer, which shows you how to use another environment variable, USERPROFILE.
Therefore, to copy the file from the desktop directory to the path specified in PSModulePath, you would do this:
COPY "%USERPROFILE%\Desktop\SetConsolePath.psm1" "%PSMODULEPATH%"
And, as I warned earlier, you really should copy the file to a folder underneath PsModulePath. So what you really want is:
IF NOT EXIST "%PSMODULEPATH%\MyNewFolder" MKDIR "%PSMODULEPATH%\MyNewFolder"
COPY "%USERPROFILE%\Desktop\SetConsolePath.psm1" "%PSMODULEPATH%\MyNewFolder"

How do I silently install a 7-zip self-extracting archive to a specific directory?

The Ruby Devkit is a 7-zip based self-extracting archive.
I would like to invoke it silently without having to install 7-Zip to extract the files to a folder of my choosing, so that I can script the installation. I imagine it to be something like:
cmd> DevKit-tdm-32-4.5.2-20111229-1559-sfx.exe /silent /dir="C:\DevKit"
But that, of course, doesn't work. What command line flags must I use to silently extract this archive into a folder of my choice?
try this:
C:\> DevKit-tdm-32-4.5.2-20111229-1559-sfx.exe -o"C:\DevKit" -y
Update 2017: The tool from 7zsfx.info is now dead and gone.
Original, old post from 08-2015:
If you are trying to extract an 7zip SFX (http://7zsfx.info/) archive:
sfx.exe -y -gm2 -InstallPath="C:\\your\\target\\path"
Switches Docu
-y hide some prompts
-gm2 hides the extraction dialog completely (silent mode)
-InstallPath sets the target path (you need double backslashes)
7z SFX Guide
The official way to create a SFX package is to use -sfx[{name}] : Create SFX archive.
And that means the created SFX packages uses two kinds of CLI options:
official CLI options from 7zSFX, and
the passed through options you configured in your config, before creating the package.
You can think of it as parameter forwarding to the packaged executable. This parameter forwarding depends on the SetEnvironment and RunProgramm configuration!
The full process:
Create archive Package.7z:
containing Installer.msi and additional crap.cab file.
Create config file config.txt:
;!#Install#!UTF-8!
Title="Installation"
SetEnvironment="strInstall=hidcon:Installer.msi /qn"
RunProgram="%strInstall%"
;!#InstallEnd#!
Now we generate Test.exe by combining sfx+config+archive into an executable.
copy /b 7zS.sfx + config.txt + Package.7z SfxInstaller.exe
Note: 7zS.sfx is from the official 7zip extra package.
Now, when you run SfxInstaller.exe you can pass for instance /lv InstallerLog.txt to create a install log, e.g.
SfxInstaller.exe /lv InstallerLog.txt
Since 7-zip is used, simply create a self-extracting archive in .exe. and run it with switches -o and -y.
I use it to save space on USB drive. For instance, I run VDiskAir application infrequently. I create a self-extracting archive of the VDiskAir program folder (about 15MB):
7z a -SFX -mx9 VDiskAir.exe [VDiskAir folder path]
NB: -mx9 is used here to maximise compression.
I create a DOS BAT to run the self-extracting VDiskAir.exe (about 5MB) created, save it as VDiskAir.bat containing:
VDiskAir.exe -o%TMP% -y
%TMP%\VDiskAir\VDisk_Air.exe
I'm not worried that the VDiskAir folder (in %TMP% extracted with VDiskAir program files) is undeleted after running VDiskAir this way, since I have a BAT script to clear %TMP% on shutting down/starting up.
Below is what I use for Autodesk product:
Start /W %~dp0AutoCAD_2018_French_LP_Win_64bit_dlm.sfx.exe -suppresslaunch -d C:\Autodesk

How to partially extract a folder from a 7z file using powershell

I'm trying to automate the install of my platform. I've made a script for compressing the build of the deployables to a 7zip file.
Now i need to uncompress partially some folders to a specific destination.
Package
-app1
--folder11
---folder111
--folder12
-app2
--folder21
--folder22
...
I need to create a powershell script to extract the content of 'app1' to a destination folder.
I've been trying to use the following command but the result is not the as i expected.
I've been receiving the full path and not the content from folder11 recursivelly.
Set-Alias zip $ZipCommand
zip x $FilePath app1\folder11 -oc:DeployableFolder -r
Any ideas? Suggestions?
Thanks.
I tried and had no issue.
set-alias zip "c:\Program Files\outils\7-Zip\7z.exe"
zip x program.7z python-core-2.6.1\lib -oc:\data
I eventually got a c:\data\python-core-2.6.1 which only contains the lib folder with all its subfolders & files.
The only difference I see is the backslash \ in the output path.
HTH

Compressing only files using 7z without preserving the path

I am using 7z command line executable to zip files, but I see that while adding to an archive the path of the files is preserved in the archive.
So if I do
7z a -tzip myzip.zip dir1\dir2\*
the archive myzip.zip will contain the path dir1\dir2. I do not want this, rather I want only the files to be added to the zip file without the paths being preserved.
I searched quite a bit but do not seem to find any way of doing this, maybe I am missing something obvious?
Thanks
Just add a dot before the path, i.e.
7z a -tzip -r myzip.zip .\Relative\Dir\*
Give the full path. That should work. Not the relative path from the current location.
For example, I give the below, where I want the files in the man5 folder to be archived.
$ 7z a -tzip myzip.zip /home/pradeeban/Desktop/man4/man5/*
The zip contained only the files, without the directories.
Then I gave only the relative path. It had the directories, inside the zip.
$ 7z a -tzip myzip.zip Desktop/man4/man5/*
Tried with Linux (Ubuntu 12.04). Not sure whether that differs from Windows.
I discovered a way to do this by using a relative path:
7z a -tzip myzip.zip %CD%\dir1\dir2\*
%CD% is how you get the current path in a Windows batch file, but it also works from the command line. More info about Capturing the current directory from a batch file.
As explained in related question in 7-zip user FAQ, 7z stores paths relative to working directory, so you will need to first cd to desired top-level directory for archive and run 7-zip from here.
cd dir1\dir2\
7z a -tzip myzip.zip *
If you run it from script and don't want to affect it with changed directory, use directory push/pop facilities available in your shell of choice or run cd+7-zip in spawned process to avoid affecting your entire script with changed directory. For example, using Windows' start that would be:
start /D dir1\dir2\ /wait 7z a -tzip myzip.zip *
This worked for me
Consider folder structure like C:\Parent\SubFolders..... And you want to create parent.zip which will contain all files and folders C:\Parent without parent folder [i.e it will start from SubFolders.....]
cd /D "C:\Parent"
"7z.exe" a Parent.zip "*.*" -r
This will create Parent.zip in C:\Parent

finding a files path in the command line

I am doing a batch scripting assignment where I have to call one script from inside another. I need the script to run the second script no matter where my lecturer saves these scripts. How would I do this. Is there some way to find the path of script inside the script and use that to execute the file. Any help would be great. I think I need to use %'s but i'm not sure.
The name of the script is Hello World.bat.
How would I copy Hello World.bat to the C:\ if I don't know which directory the lecturer has placed it in. what command/s would I use so that the copy would work regardless of the scripts location.
I don't see the "DOS" tag, but I'll assume that it is for now. If you want the entire path, you can get it by doing this:
echo %cd%
If you want just the last folder, this works (inside a .bat file):
for %%* in (.) do #echo %%~n*
Note that from the command line, the above command will work with single %'s:
for %* in (.) do #echo %~n*
If the script you are executing is calling other scripts in the SAME folder location, you can prefix the path statement with "%~dp0" or "%~dps0" but do not put a backslash between that and the name of the script you are calling. In other words, if script1.bat is calling script2.bat in the same folder, the statement in script1.bat would refer to "%~dp0script2.bat"
sorry about batch files, am not familiar, but in nix shell, there is the locate command which can return the path of the file , if you know the filename exactly and the name is unique.
like
name=$(locate filname)