I'v got the following query:
SELECT
nr
, txt = info.result
FROM
dbo.anlagen AS a
CROSS APPLY
ocAuxiliary.splitString(
ISNULL(
ocAuxiliary.parseRTF(a.notiz)
,'')
,80)
AS info
which works fine on on database, but not on another. The functions / SPROCS are created by code and therefore deterministic.
Error on B is:
Meldung 102, Ebene 15, Status 1, Zeile 9
Falsche Syntax in der Nähe von '.'.
( Wrong Syntax near '.'.)
Just calling the used functions/SPROCS works fine also:
On DB A
SELECT * from ocAuxiliary.splitString('1234567890', 3)
returns
iteration result
1 123
2 456
3 789
4 0
as it does on DB B.
On DB A
select ocAuxiliary.parseRTF('{\rtf1\ansi\ansicpg1252\deff0{\fonttbl{\f0\fnil\fcharset0 Arial;}}\viewkind4\uc1\pard\lang1031\fs20 12 ')
returns 12
as it does on DB B.
I simply don't see the mistake.
Related
I am new to PL/SQL and I can't figure out what is the problem in the following function, as I get the error ORA-00904: par_cantitate invalid identifier. Please, please could you help me. Thank you!
CREATE OR REPLACE FUNCTION vanzari_med(par_cantitate
ProduseVandute.Cantitate%TYPE)
RETURN NUMBER IS
c ProduseVandute.Cantitate%TYPE;
s Medicament.Stoc%TYPE;
NO_SALES EXCEPTION;
BEGIN
SELECT Stoc INTO s
FROM ProduseVandute pv, Medicament m
WHERE pv.Cantitate=m.Stoc and Cantitate=par_cantitate;
IF s<>15
THEN RAISE NO_SALES;
ELSE
SELECT Cantitate INTO c
FROM ProduseVandute pv, Medicament m,(SELECT * FROM Vanzari GROUP
BY ID_Vanzari)v
WHERE Cantitate=par_cantitate and pv.Cantitate=m.Stoc and
pv.ID_Vanzari=v.ID_Vanzari;
END IF;
RETURN c;
END vanzari_med
Are you sure? If tables you used contain at least columns from this function, then it compiles. Though, as you didn't handle exception you raised, it might not work properly, but - it compiles.
Sample tables:
SQL> CREATE TABLE ProduseVandute
2 (
3 cantitate NUMBER,
4 id_vanzari NUMBER
5 );
Table created.
SQL> CREATE TABLE medicament
2 (
3 stoc NUMBER
4 );
Table created.
SQL> CREATE TABLE vanzari
2 (
3 id_vanzari NUMBER
4 );
Table created.
Your function, unmodified (just added terminators at the end):
SQL> CREATE OR REPLACE FUNCTION vanzari_med(par_cantitate
2 ProduseVandute.Cantitate%TYPE)
3 RETURN NUMBER IS
4 c ProduseVandute.Cantitate%TYPE;
5 s Medicament.Stoc%TYPE;
6 NO_SALES EXCEPTION;
7 BEGIN
8 SELECT Stoc INTO s
9 FROM ProduseVandute pv, Medicament m
10 WHERE pv.Cantitate=m.Stoc and Cantitate=par_cantitate;
11 IF s<>15
12 THEN RAISE NO_SALES;
13 ELSE
14 SELECT Cantitate INTO c
15 FROM ProduseVandute pv, Medicament m,(SELECT * FROM Vanzari GROUP
16 BY ID_Vanzari)v
17 WHERE Cantitate=par_cantitate and pv.Cantitate=m.Stoc and
18 pv.ID_Vanzari=v.ID_Vanzari;
19 END IF;
20 RETURN c;
21 END vanzari_med;
22 /
Function created.
SQL>
I have a file,
ID,DNS,R_D,R_A
1,123456,2014/11/17,10
2,987654,2016/05/20,30
3,434343,2017/08/01,20
that I'm trying to load to oracle using External Tables. I have to skip the header row and also load the date column.
This is my query:
DECLARE
FILENAME VARCHAR2(400);
BEGIN
FILENAME := 'actual_data.txt';
EXECUTE IMMEDIATE 'CREATE TABLE EXT_TMP (
ID NUMBER(25),
DNS VARCHAR2(20),
R_D DATE,
R_A NUMBER(25)
)
ORGANIZATION EXTERNAL (
TYPE ORACLE_LOADER
DEFAULT DIRECTORY USER_DIR
ACCESS PARAMETERS (
RECORDS DELIMITED BY NEWLINE
FIELDS TERMINATED BY '',''
MISSING FIELD VALUES ARE NULL
SKIP 1
(
"ID",
"DNS",
"R_D" date "dd-mon-yy",
"RECHARGE_AMOUNT"
)
)
LOCATION (''' || FILENAME || ''')
)
PARALLEL 5
REJECT LIMIT UNLIMITED';
END;
I get following exception:
ERROR at line 1:
ORA-29913: error in executing ODCIEXTTABLEOPEN callout
ORA-29400: data cartridge error
KUP-00554: error encountered while parsing access parameters
KUP-01005: syntax error: found "skip": expecting one of: "column, exit, (,
reject"
KUP-01007: at line 4 column 5
ORA-06512: at "SYS.ORACLE_LOADER", line 19
I'm using sqlplus.
Could some oracle veterans please help me out and tell me what I'm doing wrong here? I'm very new to oracle.
You don't want to create any kind of tables (including external ones) in PL/SQL; not that it is impossible, but it is opposite of the best practices.
Have a look at my attempt, based on information you provided - works OK.
SQL> alter session set nls_date_format = 'dd.mm.yyyy';
Session altered.
SQL> create table ext_tmp
2 (
3 id number,
4 dns varchar2(20),
5 r_d date,
6 r_a number
7 )
8 organization external
9 (
10 type oracle_loader
11 default directory kcdba_dpdir
12 access parameters
13 (
14 records delimited by newline
15 skip 1
16 fields terminated by ',' lrtrim
17 missing field values are null
18 (
19 id,
20 dns,
21 r_d date 'yyyy/mm/dd',
22 r_a
23 )
24 )
25 location ('actual_data.txt')
26 )
27 parallel 5
28 reject limit unlimited;
Table created.
SQL> select * from ext_tmp;
ID DNS R_D R_A
---------- -------------------- ---------- ----------
1 123456 17.11.2014 10
2 987654 20.05.2016 30
3 434343 01.08.2017 20
SQL>
In my case skip 1 didn't work even with placing it between records delimited by newline and fields terminated by ',' lrtrim until I used load when. Now skip 1 works with the following access parameters:
access parameters (
records delimited by newline
load when (someField != BLANK)
skip 1
fields terminated by '','' lrtrim
missing field values are null
reject rows with all null fields
)
I have been having fun with an issue where I need to break apart a string in SQL Server 2012 and test for values it may or may not contain. The values, when present, will be separated by up to two different ; symbols.
When there is nothing, it will be blank.
When there is a single value, it will show up without the delimiter.
When there are two or more, up to 3, they will be separated by the delimiter.
As I said, if there is nothing in the record, it will be blank. Below are some example of how the data may come across:
' ',
'1',
'24',
'15;1;24',
'10;1;22',
'5;1;7',
'12;1',
'10;12',
'1;5',
'1;1;1',
'15;20;22'
I have searched the forums and found many clues, but I have not been able to come up with a total solution given all potential data values. Essentially, I would like to break it into 3 separate values.
text before the first delimiter or in the absence of the delimiter, just the text.
Text after the first delimiter and before the second in situation where there are two delimiters.
The following has worked consistently:
substring(SUBSTRING(Food_Desc, charindex(';', Food_Desc) + 1, 4), 0,
charindex(';', SUBSTRING(Food_Desc, charindex(';', Food_Desc) + 1, 4))) as [Middle]
Text after the second delimiter in the even there are two delimiters and there is a third value
The main challenge is the fact that the delimiter, when present, moves depending on the value in the table. values 1-9 make it show up as the second character in the string, values 10-24 make it show up as the 3rd, etc.
Any help would be greatly appreciated.
This is simple if you have a well written t-sql splitter function. For this solution I'm using Jeff Moden's delimitedsplit8k.
sample data and solution
DECLARE #table table (someid int identity, sometext varchar(100));
INSERT #table VALUES (' '),('1'),('24'),('15;1;24'),('10;1;22'),
('5;1;7'),('12;1'),('10;12'),('1;5'),('1;1;1'),('15;20;22');
SELECT
someid,
sometext,
ItemNumber,
Item
FROM #table
CROSS APPLY dbo.DelimitedSplit8K_LEAD(sometext, ';');
results
someid sometext ItemNumber Item
----------- ----------------- ----------- --------
1 1
2 1 1 1
3 24 1 24
4 15;1;24 1 15
4 15;1;24 2 1
4 15;1;24 3 24
5 10;1;22 1 10
5 10;1;22 2 1
5 10;1;22 3 22
6 5;1;7 1 5
6 5;1;7 2 1
6 5;1;7 3 7
7 12;1 1 12
7 12;1 2 1
8 10;12 1 10
8 10;12 2 12
9 1;5 1 1
9 1;5 2 5
10 1;1;1 1 1
10 1;1;1 2 1
10 1;1;1 3 1
11 15;20;22 1 15
11 15;20;22 2 20
11 15;20;22 3 22
Below is a modified version of a similar question How do I split a string so I can access item x?. Changing the text value for #sample to each of your possibilities listed seemed to work for me.
DECLARE #sample VARCHAR(200) = '15;20;22';
DECLARE #individual VARCHAR(20) = NULL;
WHILE LEN(#sample) > 0
BEGIN
IF PATINDEX('%;%', #sample) > 0
BEGIN
SET #individual = SUBSTRING(#sample, 0, PATINDEX('%;%', #sample));
SELECT #individual;
SET #sample = SUBSTRING(#sample, LEN(#individual + ';') + 1, LEN(#sample));
END;
ELSE
BEGIN
SET #individual = #sample;
SET #sample = NULL;
SELECT #individual;
END;
END;
I have a multi-table join and want to update a table based on the result of that join. The join table produces both the scope of the update (only those rows whose effort.id appears in the result should be updated) and the data for the update (a new column should be set to the value of a calculated column).
I've made progress but can't quite make it work. Here's my statement:
UPDATE
efforts
SET
dropped_int = jt.split
FROM
(
SELECT
ef.id,
s.id split,
s.kind,
s.distance_from_start,
s.sub_order,
max(s.distance_from_start + s.sub_order)
OVER (PARTITION BY ef.id) AS max_dist
FROM
split_times st
LEFT JOIN splits s ON s.id = st.split_id
LEFT JOIN efforts ef ON ef.id = st.effort_id
) jt
WHERE
((jt.distance_from_start + jt.sub_order) = max_dist)
AND
kind <> 1;
The SELECT produces the correct join table:
id split kind dfs sub max_dist dropped dropped_int
403 33 2 152404 1 152405 TRUE 33
404 33 2 152404 1 152405 TRUE 33
405 31 2 143392 1 143393 TRUE 33
406 31 2 143392 1 143393 TRUE 33
407 29 2 132127 1 132128 TRUE 33
408 29 2 132127 1 132128 TRUE 33
409 29 2 132127 1 132128 TRUE 33
and does indeed update the efforts.id column, but there are two problems: First, it updates all efforts, not just those that are produced from the query, and second, it sets effort.id to the split value of the first row in the query result, but I need it to set each effort to the associated split value.
If this were non-SQL, it might look something like:
jt_rows.each do |jt_row|
efforts[jt_row].dropped_int = jt[jt_row].split
end
But I don't know how to do that in SQL. It seems like this should be a fairly common problem, but after a couple of hours of searching I'm coming up short.
How should I modify my statement to produce the described result? If it matters, this is Postgres 9.5. Thanks in advance for any suggestions.
EDIT:
I did not get a workable answer but ended up solving this with a mixture of SQL and native code (Ruby/Rails):
dropped_splits = SplitTime.joins(:split).joins(:effort)
.select('DISTINCT ON (efforts.id) split_times.effort_id, split_times.split_id')
.where(efforts: {dropped: true})
.order('efforts.id, splits.distance_from_start DESC, splits.sub_order DESC')
update_hash = Hash[dropped_splits.map { |x| [x.effort_id, {dropped_split_id: x.split_id, updated_at: Time.now}] }]
Effort.update(update_hash.keys, update_hash.values)
Use a condition in the WHERE clause that relates efforts table with a subquery:
efforts.id = jt.id
that is:
WHERE
((jt.distance_from_start + jt.sub_order) = max_dist)
AND
kind <> 1
AND
efforts.id = jt.id
I am getting a tad frustrated and was wondering if you can help:
I have a Pitch Values Table with the following Columns PitchValues_Skey, PitchType_Skey (this is a foreign key), Start Date, End Date and finally value:
For Example:
1 7 01/01/2010 31/12/2010 £15
2 7 01/01/2011 31/12/2011 £20
And all I want to do is update my Bookings table with how much each booking is going to be, so I put together the code below which worked fine when I only had 2010 data, but I know have 2011 and 2012 and want to update it but it will only update with the 2010 prices.
SELECT Bookings.Booking_Skey, DATEDIFF(day, Bookings.ArrivalDate, Bookings.DepartureDate) * PitchValues.Value AS BookingValue,
PitchValues.PitchType_Skey
FROM Bookings INNER JOIN
PitchValues ON Bookings.PitchType_Skey = PitchValues.PitchType_Skey
WHERE (Bookings.Booking_Skey = 1)
So when I run the query above I would expect to see one line of data but instead I see 4 (See Below)
I would expect this:
Booking_Skey BookingValue PitchType_Skey
1 420 4
But I get this
Booking_Skey BookingValue PitchType_Skey
1 420 4
1 453.6 4
1 476.7 4
1 476.7 4
All sorted now, thanks for your help.
SELECT Bookings.Booking_Skey, DATEDIFF(DAY, Bookings.ArrivalDate, Bookings.DepartureDate) * PitchValues.Value AS BookingValue, PitchValues.PitchType_Skey
FROM Bookings
INNER JOIN PitchValues ON Bookings.PitchType_Skey = PitchValues.PitchType_Skey
AND Bookings.ArrivalDate BETWEEN PitchValues.StartDate AND PitchValues.EndDate
WHERE (Bookings.Booking_Skey = 1)