I have removed some documents in my last query by mistake, Is there any way to rollback my last query mongo collection.
Here it is my last query :
db.foo.remove({ "name" : "some_x_name"})
Is there any rollback/undo option? Can I get my data back?
There is no rollback option (rollback has a different meaning in a MongoDB context), and strictly speaking there is no supported way to get these documents back - the precautions you can/should take are covered in the comments. With that said however, if you are running a replica set, even a single node replica set, then you have an oplog. With an oplog that covers when the documents were inserted, you may be able to recover them.
The easiest way to illustrate this is with an example. I will use a simplified example with just 100 deleted documents that need to be restored. To go beyond this (huge number of documents, or perhaps you wish to only selectively restore etc.) you will either want to change the code to iterate over a cursor or write this using your language of choice outside the MongoDB shell. The basic logic remains the same.
First, let's create our example collection foo in the database dropTest. We will insert 100 documents without a name field and 100 documents with an identical name field so that they can be mistakenly removed later:
use dropTest;
for(i=0; i < 100; i++){db.foo.insert({_id : i})};
for(i=100; i < 200; i++){db.foo.insert({_id : i, name : "some_x_name"})};
Now, let's simulate the accidental removal of our 100 name documents:
> db.foo.remove({ "name" : "some_x_name"})
WriteResult({ "nRemoved" : 100 })
Because we are running in a replica set, we still have a record of these documents in the oplog (being inserted) and thankfully those inserts have not (yet) fallen off the end of the oplog (the oplog is a capped collection remember) . Let's see if we can find them:
use local;
db.oplog.rs.find({op : "i", ns : "dropTest.foo", "o.name" : "some_x_name"}).count();
100
The count looks correct, we seem to have our documents still. I know from experience that the only piece of the oplog entry we will need here is the o field, so let's add a projection to only return that (output snipped for brevity, but you get the idea):
db.oplog.rs.find({op : "i", ns : "dropTest.foo", "o.name" : "some_x_name"}, {"o" : 1});
{ "o" : { "_id" : 100, "name" : "some_x_name" } }
{ "o" : { "_id" : 101, "name" : "some_x_name" } }
{ "o" : { "_id" : 102, "name" : "some_x_name" } }
{ "o" : { "_id" : 103, "name" : "some_x_name" } }
{ "o" : { "_id" : 104, "name" : "some_x_name" } }
To re-insert those documents, we can just store them in an array, then iterate over the array and insert the relevant pieces. First, let's create our array:
var deletedDocs = db.oplog.rs.find({op : "i", ns : "dropTest.foo", "o.name" : "some_x_name"}, {"o" : 1}).toArray();
> deletedDocs.length
100
Next we remind ourselves that we only have 100 docs in the collection now, then loop over the 100 inserts, and finally revalidate our counts:
use dropTest;
db.foo.count();
100
// simple for loop to re-insert the relevant elements
for (var i = 0; i < deletedDocs.length; i++) {
db.foo.insert({_id : deletedDocs[i].o._id, name : deletedDocs[i].o.name});
}
// check total and name counts again
db.foo.count();
200
db.foo.count({name : "some_x_name"})
100
And there you have it, with some caveats:
This is not meant to be a true restoration strategy, look at backups (MMS, other), delayed secondaries for that, as mentioned in the comments
It's not going to be particularly quick to query the documents out of the oplog (any oplog query is a table scan) on a large busy system.
The documents may age out of the oplog at any time (you can, of course, make a copy of the oplog for later use to give you more time)
Depending on your workload you might have to de-dupe the results before re-inserting them
Larger sets of documents will be too large for an array as demonstrated, so you will need to iterate over a cursor instead
The format of the oplog is considered internal and may change at any time (without notice), so use at your own risk
While I understand this is a bit old but I wanted to share something that I researched in this area that may be useful to others with a similar problem.
The fact is that MongoDB does not Physically delete data immediately - it only marks it for deletion. This is however version specific and there is currently no documentation or standardization - which could enable a third party tool developer (or someone in desperate need) to build a tool or write a simple script reliably that works across versions. I opened a ticket for this - https://jira.mongodb.org/browse/DOCS-5151.
I did explore one option which is at a much lower level and may need fine tuning based on the version of MongoDB used. Understandably too low level for most people's linking, however it works and can be handy when all else fails.
My approach involves directly working with the binary in the file and using a Python script (or commands) to identify, read and unpack (BSON) the deleted data.
My approach is inspired by this GitHub project (I am NOT the developer of this project). Here on my blog I have tried to simplify the script and extract a specific deleted record from a Raw MongoDB file.
Currently a record is marked for deletion as "\xee" at the start of the record. This is what a deleted record looks like in the raw db file,
‘\xee\xee\xee\xee\x07_id\x00U\x19\xa6g\x9f\xdf\x19\xc1\xads\xdb\xa8\x02name\x00\x04\x00\x00\x00AAA\x00\x01marks\x00\x00\x00\x00\x00\x00#\x9f#\x00′
I replaced the first block with the size of the record which I identified earlier based on other records.
y=”3\x00\x00\x00″+x[20804:20800+51]
Finally using the BSON package (that comes with pymongo), I decoded the binary to a Readable object.
bson.decode_all(y)
[{u’_id': ObjectId(‘5519a6679fdf19c1ad73dba8′), u’name': u’AAA’, u’marks': 2000.0}]
This BSON is a python object now and can be dumped into a recover collection or simply logged somewhere.
Needless to say this or any other recovery technique should be ideally done in a staging area on a backup copy of the database file.
Related
I am writing a method that updates a single document in a very large MongoCollection,
and I have an index that I want the MongoCollection.Update() call to use to drastically reduce lookup time, but I can't seem to find anything like MongoCursor.SetHint(string indexName).
Is using an index on an update operation possible? If so, how?
You can create index according to your query section of update command.
For example if you have this collection, named data:
> db.data.find()
{ "_id" : ObjectId("5334908bd7f87918dae92eaf"), "name" : "omid" }
{ "_id" : ObjectId("5334943fd7f87918dae92eb0"), "name" : "ali" }
{ "_id" : ObjectId("53349478d7f87918dae92eb1"), "name" : "reza" }
and if you do this update query:
> db.data.update(query={name:'ali'}, update={name: 'Ali'})
without any defined index, the number of scanned document is 2:
"nscanned" : 2,
But if you define an index, according to your query, here for name field:
db.data.ensureIndex({name:1})
Now if you update it again:
> db.data.update(query={name:'Ali'}, update={name: 'ALI'})
Mongodb use your index for doing update, and number of scanned document is 1:
"nscanned" : 1,
But if you want to hint for update, you can hint it for your query:
# Assume that the index and field of it exists.
> var cursor = db.data.find({name:'ALI'}).hint({family:1})
Then use it in your update query:
> db.data.update(query=cursor, update={name: 'ALI'})
If you already have indexed your collection, update will be using the CORRECT index right away. There is no point to provide hint (in fact you can't hint with update).
Hint is only for debugging and testing purposes. Mongo is in most cases smart enough to automatically decide which index (if you have many of them) should be used in a particular query and it reviews its strategy from time to time.
So short answer - do nothing. If you have an index and it is useful, it will be automatically used on find, update, delete, findOne.
If you want to see if it is used - take the part of the query which searches for something and run it through find with explain.
Example for hellboy. This is just an example and in real life it can be more complex.
So you have a collection with docs like this {a : int, b : timestamp}. You have 2 indexes: one is on a, another is on b. So right now you need to do a query like a > 5 and b is after 2014. For some reason it uses index a, which does not give you the faster time (may be because you have 1000 elements and most of them are bigger than 5 and only 10 are > 2004 ). SO you decided to hint it to use b index. Cool it works much faster now. But your collection changes and right now you are in 2020 year and most of your documents have b bigger than 2014. So right now your index b is not doing so much work. But mongo still uses it, because you told so.
I have a distributed application that uses mongoDB as a backend. The application has two collections (C1 and C2) with a M:1 relationship, so that if I delete a document in C1, I need to search C1 for any other documents that point to the same doc in C2, and if there are no matches, then delete the related doc in C2.
This obviously has the problem of race conditions that could insert new documents into C1 while the search is going on that point to the soon-to-be-deleted document in C2, resulting in DB inconsistency. Deletes can be delayed such that they could be batched up and performed once a week, say, during low load, so I'm considering writing a distributed locking system for mongo to solve the RC problem.
Questions:
Is there a better approach than distributed locking?
Does software like this already exist for Mongo? I've seen single document examples of locks, but not database level distributed locks.
UPDATE
I left this out to avoid confusing the issue, but I need to include it now. There's actually another resource (R) (essentially a file on a remote disk) that needs to be deleted along with with C2 document and C2:R is M:1. R is completely outside the mongodb ecosystem, which is why my mind jumped to locking the application so I can safely delete all this stuff. Hence the reversing links idea mentioned below won't work for this case. Yes, the system is complicated, and no, it can't be changed.
UPDATE2
My attempts to abstract away implementation details to keep the question succinct keeps biting me. Another detail: R is manipulated via REST calls to another server.
1.
This type of problem is usually solved by embedding. So essentially C1 and C2 could be a single collection and C2 doc would embed itself into C1. Obviously this is not always possible or desirable and one of the downsides of this is data duplication. Another downside is that you would not be able to find all C2s without going through all C1s and given M:1 relationship it's not always good thing to do. So it depends if these cons are a real problem in your application.
2.
Another way to handle it would be to just remove links from C1 to C2 thus leaving C2 documents to exist with no links. This could have low cost in some cases.
3.
Use Two Phase Commit similar to as described here: http://docs.mongodb.org/manual/tutorial/perform-two-phase-commits/.
4.
Yet another option could be to reverse your links. C2 would have an array of links that point to C1s. Each time you delete C1 you $pull from that array a link to deleted C1. Immediately after you delete from C2 with a condition that array of links is empty and its _id is what you got back from update. If race condition happens when you insert a new document into C1 and trying to update C2 and you got back result that you didn't update anything then you can either fail your insert or try to insert a new C2. Here is an example:
// Insert first doc
db.many.insert({"name": "A"});
// Find it to get an ID to show.
db.many.find();
{ "_id" : ObjectId("52eaf9e05a07ef0270a9eccc"), "name" : "A" }
// lets add a tag to it right after
db.one.update({"tag": "favorite"}, {$addToSet: {"links": ObjectId("52eaf9e05a07ef0270a9eccc")}}, {upsert: true, multi: false});
// show that tag was created and a link was added
db.one.find();
{ "_id" : ObjectId("52eafaa77365653791085540"), "links" : [ ObjectId("52eaf9e05a07ef0270a9eccc") ], "tag" : "favorite" }
// Insert one more doc which will not be tagged just for illustration
db.many.insert({"name": "B"});
// Insert last document, show IDs of all docs and tag the last document inserted:
db.many.insert({"name": "C"});
db.many.find();
{ "_id" : ObjectId("52eaf9e05a07ef0270a9eccc"), "name" : "A" }
{ "_id" : ObjectId("52eafab95a07ef0270a9eccd"), "name" : "B" }
{ "_id" : ObjectId("52eafac85a07ef0270a9ecce"), "name" : "C" }
db.one.update({"tag": "favorite"}, {$addToSet: {"links": ObjectId("52eafac85a07ef0270a9ecce")}}, {upsert: true, multi: false});
// Now we have 2 documents tagged out of 3
db.one.find();
{ "_id" : ObjectId("52eafaa77365653791085540"), "links" : [ ObjectId("52eaf9e05a07ef0270a9eccc"), ObjectId("52eafac85a07ef0270a9ecce") ], "tag" : "favorite" }
// START DELETE PROCEDURE
// Let's delete first tagged document
db.many.remove({"_id" : ObjectId("52eaf9e05a07ef0270a9eccc")});
// remove the "dead" link
db.one.update({"tag": "favorite"}, {$pull: {"links": ObjectId("52eaf9e05a07ef0270a9eccc")}});
// just to show how it looks now (link removed)
db.one.find();
{ "_id" : ObjectId("52eafaa77365653791085540"), "links" : [ ObjectId("52eafac85a07ef0270a9ecce") ], "tag" : "favorite" }
// try to delete a document that has no links - it's not the case here yet, so the doc is not deleted.
db.one.remove({"tag" : "favorite", "links": {$size: 0}});
db.one.find();
{ "_id" : ObjectId("52eafaa77365653791085540"), "links" : [ ObjectId("52eafac85a07ef0270a9ecce") ], "tag" : "favorite" }
// DELETE OF THE FIRST DOC IS COMPLETE, if any docs got added with
// links then the tag will just have more links
// DELETE LAST DOC AND DELETE UNREFERENCED LINK
db.many.remove({"_id" : ObjectId("52eafac85a07ef0270a9ecce")});
db.one.update({"tag": "favorite"}, {$pull: {"links": ObjectId("52eafac85a07ef0270a9ecce")}});
// no links are left
db.one.find();
{ "_id" : ObjectId("52eafaa77365653791085540"), "links" : [ ], "tag" : "favorite" }
db.one.remove({"tag" : "favorite", "links": {$size: 0}});
// LAST DOC WAS DELETED AND A REFERENCING DOC WAS DELETED AS WELL
// final look at remaining data
db.one.find();
// empty
db.many.find();
{ "_id" : ObjectId("52eafab95a07ef0270a9eccd"), "name" : "B" }
If upsert happens after you delete from one then it will just create a new doc and add a link. If it happens before then old one doc will stay and links will be updated properly.
UPDATE
Here is one way to deal with "delete file" requirements. It assumes you have POSIX compliant filesystem like ext3/ext4, many other FSs would have same properties too. For each C2 you create you should create a randomly named hard link which points to the R file. Store the path to that link in C2 doc for example. You'll end up with multiple hard links pointing to a single file. Whenever you delete a C2 you delete this hard link. Eventually when link count goes to 0 OS will delete the file. Thus there is no way you can delete the file unless you delete all hard links.
Another alternative to reversing C1<->C2 links and using FS hard links is to use multiphase commit which you can implement in any way you want.
Disclaimer: whatever mechanisms I described should work, but might contain some cases that I missed. I didn't try exactly this approach myself, but I used similar "transactional" file deletion scheme in the past successfully. So such solution I think will work but requires good testing and thinking it through will all possible scenarios.
UPDATE 2
Given all the constraints you will have to implement either multi stage commit or a some sort of locking/transaction mechanism. You can also order all your operations through a task queue which will naturally be free of race conditions (synchronous). All of these mechanisms will slow the system down a bit but you can pick granularity level of a C2 document id which is not so bad I suppose. Thus you'll still be able to run stuff in parallel with isolation on C2 id level.
One of the simple practical approaches is to use a message bus/queue.
If you are not using sharding, you can use TokuMX instead of MongoDB, which has support for multi-document, multi-statement transactions with atomic commit and rollback, among other nice things. These transactions work across collections and databases, so they seem like they would work for your application without many changes.
There is a full tutorial here.
Disclaimer: I am an engineer at Tokutek
Alek,
Have you considered moving the relationships to a different collection. You can have a collection that maps all the relationships from C1 to C2. Each document can also store a boolean indicating it is marked for collection. You can write a background task that will periodically scan this table and look for collections that have been deleted. The advantage of this model is that it is easy to detect when the collections are out of sync.
E.g.
{
C1_ID,
[C2_ID_1, C2_ID_2....],
true/false
}
I'm storing timeseries in MongoDB and the strucuture is as follows:
{
"_id" : ObjectId("5128e567df6232180e00fa7d"),
"values" : [563.424, 520.231, 529.658, 540.459, 544.271, 512.641, 579.591, 613.878, 627.708, 636.239, 672.883, 658.895, 646.44, 619.644, 623.543, 600.527, 619.431, 596.184, 604.073, 596.556, 590.898, 559.334, 568.09, 568.563],
"day" : 20110628,
}
The values-array is representing a value for each hour. So the position is important since position 0 = first hour, 1 = second hour and so on.
To update the value of a specific hour is quite easy. For example, to update the 7th hour of the day I do this:
db.timeseries.update({day:20130203},{$set : {values.6 : 482.65}}, {upsert : true})
My problem is that I would like to use upsert, like this
db.timeseries.update({day:20130203},{$set : {values.6 : 482.65}})
But if the document does not exist, MongoDB will craete an embedded document intead of an embedded array. Like this:
{
"_id" : ObjectId("5128e567df6232180e00fa7d"),
"values" : {"6" : 482.65},
"day" : 20130203,
}
There is a ticket to add a feature to solve this issue here, but meanwhile I have come up with a work-around to solve this in my case.
What I do, is that I first created a uniqe-index on the day-field. And whenever I want to upsert a hourly volume I do these two commands.
db.timeseries.insert({day:20130203, values : []}); // Will be rejected if it exists
db.timeseries.update({day:20130203},{$set : {values.6 : 482.65}});
The first statement tried to create a new document - and thanks to the uniqe-index the insert will be rejected if it already exists. If not, a document with an embedded array for value-field will be created. This ensures that the update will work.
Result:
{
"_id" : ObjectId("5128e567df6232180e00fa7d"),
"values" : [null,null,null,null,null,null,482.65],
"day" : 20130203,
}
And here's is my question
In production, when several commands like this will be run simultaneously can I be sure that my update-command will be executed after my insert-command? Note that I want to run both commands in unsafe-mode, that is I will not wait for any response from the server.
(It would also be interesting to here comments about my work-around from a performance perspective.)
Generally yes, there is a way to ensure that two requests from a client use the same connection. By using the same connection you force a strict order of execution on the server.
The way to accomplish this are different for different drivers.
For the Asynchronous Java Driver you can create a "Serialized" MongoClient from the initial MongoClient instance and it will ensure that all requests use a single connection.
For the 10gen java driver it will automatically (via a ThreadLocal) try to use the same connection. You can also give a hint to the driver via the DB.requestStart()/DB.requestEnd() methods that a group of commands need to be pipe-lined.
The startRequest/endRequest applies to most of the 10gen drivers. As another example the PyMongo driver mongo_client has a start_request()/end_request() pair.
From a performance point of view, it is better using only one access to the database than two. Cannot you use $push instead of $set for updating the values field?
Given a large (millions+) collection of documents similar to:
{ _id : ObjectId, "a" : 3, "b" : 5 }
What is the most efficient way to process these documents directly on the server, with the results added to each document within the same collection? For example, add a key c whose value equals a+b.
{ _id : ObjectId, "a" : 3, "b" : 5, "c" : 8 }
I'd prefer to do this in the shell.
Seems that find().forEach() would waste time in transit between the db and the shell, and mapReduce() seems intended to process groups of objects down into aggregated data (though I may be misunderstanding).
EDIT: I'd prefer a solution that doesn't block, if there is one (other than using a cursor on the client)...
From the MongoDB Docs on db.eval():
"db.eval() is used to evaluate a function (written in JavaScript) at the database server.
This is useful if you need to touch a lot of data lightly. In that scenario, network transfer of the data could be a bottleneck."
The documentation has an example of how to use it that is very similar to what you are trying to do.
forEach is your best option. I would run it on the server (from the shell) to reduce latency.
I have some scripts which update, mongoDb records which look like this :
{ "_id" : "c12345", "arr" : [
{
"i" : 270099850,
"a" : 772,
},
{
"i" : 286855630,
"a" : 622,
}
] }
The scripts append elements in the "arr" array of the object,using "pushAll" which
works fine and is very fast.
My requirement:
1. Keep modifying these objects, but process them once the size of arr exceeds 1000.
When arr exceeds 1000,I choose some important records, discard some less important ones,
and discard some old ones, and reduce the size of arr to 500 .
Current implementation:
1. Script A takes some data from somewhere and finds the object in another collection
using "_id" field, and appends that data into "arr" array.
The same script when finds the element,checks for size of "arr", if less than 1000, it does a normal append to arr, else proceeds to processing of PHP object retreived through find,modifies it, and updates the mongo record using "SET".
Current bottlenecks:
1. I want the updating script to run very fast. Upserts are fast, however the find and modifying operations are slower for each record.
Ideas in mind:
1. Instead of processing EXCEEDED items within the scripts, set a bool flag in the object, and process it using a seperate Data Cleaner script. ( but this also requires me to FIND the object before doing UPSERT ).
always maintain a COUNT variable in the object,which stores current length of "arr", and use it in Data cleaner script which cleans all the objects fetched through a mongodb
query "count" > 1000. ( As mongodb does not allow $size operator to have Ranges, and only equal condition currently, I need to have my own COUNT counter)
Any other clean and efficient ideas you can suggest ?
Thanks .
In version 2.3.2 of mongo a new feature has been added. There is now a $slice that can be used to keep an array to a fixed size.
E.g.:
t.update( {_id:7}, { $push: { x: { $each: [ {a:{b:3}} ], $slice:-2, $sort: {'a.b':1} } } } )
There's no easy way to do this, however, this is a good idea:
Instead of processing EXCEEDED items within the scripts, set a bool flag in the object, and process it using a seperate Data Cleaner script.
Running a separate script definitely makes sense for this.
MongoDB does not have a method for "fixed-length" arrays. But it definitely does not have a method for doing something like this:
choose some important records, discard some less important ones, and discard some old ones
The only exception I would make is the "bool" flag. You probably want just a straight counter. If you can index on this counter then it should be fast to find those arrays that are "too big".