How can I find all emails in php files and replace with an email?
find . -iname '*.php' -exec grep -E -o "\b[a-zA-Z0-9.-_]+#[a-zA-Z0-9.-]+\.[a-zA-Z]+\b" -exec sed -i 's//email#domain.com/g' {} \;
Find emails in php files command is:
find . -iname '*.php' -exec grep -E -o "\b[a-zA-Z0-9.-_]+#[a-zA-Z0-9.-]+\.[a-zA-Z]+\b" {} \;
and replace command is:
find . -iname '*.php' -type f -exec sed -i 's/old-email#domain.com/new-email#domain.com/g' {} \;
But I don't know exactly how to join them in one command.
Any ideas?
Related
Kind of new to Perl, still navigating my way through.
Is there another way to write the bash command below in "Perl"?
find $INPUT_DIR -ctime -$DAYS_NUM -type f -exec grep -hs EDI_DC {} \; |
grep -i -v xml >> $OUTPUT_DIR/$OUTPUT_FILENAME
where INPUT_DIR, DAYS_NUM, OUTPUT_DIR and OUTPUT_FILENAME are arguments passed during runtime.
When you try to convert find command to perl, consider using find2perl script.
It generate the perl code.
find2perl 'INPUT_DIR' -ctime -'DAYS_NUM' -type f -exec grep -hs EDI_DC {} \;
Hopefully this is a simple one, but I can't figure it out. I'm trying to work out why this command isn't finding any results:
find . -iname '*.cgi' -o -iname '*.txt' -o -iname '*.htm' -o -iname '*.html' -o -iname '*.php' -exec grep -l 'community.cgi' {} +
If I simplify it and just do:
find . -iname '*.cgi' -o -iname '*.txt' -o -iname '*.htm' -o -iname '*.html' -o -iname '*.php'
Then I get the list of files I'm expecting. For some reason the -exec part doesn't seem to be what I'm expecting. If I just run a basic grep on ALL files, I get the list of files as well:
grep -l 'community.cgi' .
Logical-and binds tighter than logical-or. Try:
find . \( -iname '*.cgi' -o -iname '*.txt' -o -iname '*.htm' -o -iname '*.html' -o -iname '*.php' \) -exec grep -l 'community.cgi' {} +
Here, parens (which have to be escaped to pass through the shell) are used to bind the -iname tests together so that -exec runs if any one of those tests is true.
This works for me:
$> find . -name "*.log" -exec basename '{}' \;
20160114.log
20160115.log
20160116.log
20160117.log
20160118.log
Is the {}, \ and ';' mandatory when using -exec as any other syntax simply doesn't work?
The following, more complex example doesn't work:
$> find . -name "*.log" -exec echo $(basename '{}') \;
./log/20160114.log
./log/20160115.log
./log/20160116.log
./log/20160117.log
./log/20160118.log
echo here is just to demonstrate. I eventually plan to use something like rm $TARGET_DIR/$(basename '{}') in its place… It just doesn't work that way (nesting). Any ideas?
I am writing a script that will saech for php files that contain a phrase and I would like that phrase replaced with a new one below is my little script but it is not working it searches ok but does not work with the search and replace section
find . -type f -name "*.php" -exec grep -H "define('DB_HOST', 'localhost');" {} \; | xargs sed -i "define('DB_HOST', 'localhost');/define('DB_HOST', '10.0.0.1');/g"
can someone explain to me what i am doing wrong
many thanks
Joe
did you forget the 's/' at the beggining of the sed expression? As in
sed 's/expression1/expression2/g'
You seem to have
sed 'espression1/expression2/g'
Edit
Another thing: You don't need to use xarg here. You can use multiple -exec flags - and it will to each only if all the previous succeeded:
find . -name '*.php' -exec grep 'whatever' {} \; -exec sed -i 's/whatever/you want/g' {} \;
This will work:
find . -type f -name "*.php" -exec grep -l "define('DB_HOST', 'localhost');" {} \; | xargs sed -i "s/define('DB_HOST', 'localhost');/define('DB_HOST', '10.0.0.1');/g"
Corrections
Missing s/ in sed search and replace command
use grep -l instead of grep -H
On my FTP server, I look for files delivered in the past day and remove in-place header & trailer records.
find . -type f -name "CDC*" -ctime -1 -exec sed -i'' -e '1d' -e '$d' '{}' \;
This works well.
I want to automate this in a script. But how can I send myself an email notification is no files are found? I am thinking of doing something like:
find . -type f -name "CDC*" -ctime -1 -exec sed -i'' -e '1d' -e '$d' '{}' \;
EXIT=`echo $?`
case $EXIT in
0) ...do stuff...
*) mail....exit
esac;;
There has to a better way, right?
I'm pretty sure that you could take whatever command you need to do the search, and pipe a wc -l on to the end of it. Then use an if statement to check for zero. So using your example above.
NUMLINES=`find . -type f -name "CDC*" -ctime -1 -exec sed -i'' -e '1d' -e '$d' '{}' \ | wc -l`
if [ "$NUMLINES" -eq 0 ] ; then
foo
fi
Or something like that. I didn't check if that syntax is correct though. But i'm sure you get my drift