I'm have problems using zenity.
Here's the script:
CHECKED=`cat /tmp/1 | \
zenity --width=500 --height=450 --list --radiolist --separator=' ' \
--title="Select Results." \
--text="show lines" --column="" --column="Files"`
The file /tmp/1:
1
2
3
4
5
6
7
8
9
When I run this script it only displays lines 1,3,5,7,9
What am I doing wrong?
1 line in the input file equals 1 column in the dialogue. Because you are adding radio buttons, your dialogue has 2 columns (hence your two --column arguments) so your input doesn't match what is to be displayed. In other words, Zenity expects something like this:
FALSE
1
FALSE
2
FALSE
3
TRUE
4
...where TRUE/FALSE signifies whether the radio button is pre-selected when the dialogue opens.
To fix your script without modification of the input file, you can simply prefix each line with an extra line:
CHECKED=`cat /tmp/1 | \
sed 's/^/FALSE\n/g' | \
zenity --width=500 --height=450 --list --radiolist --separator=' ' \
--title="Select Results." \
--text="show lines" --column="" --column="Files"`
Related
Zenity is used in many of my bash projects, but looking at the advanced features of YAD there are many reasons to switch. After some testing unfortunately I discovered there is no --imagelist option for the list type dialog. This is a major problem as most of my projects use imagelists.
The below example runs on zenity version 3.28.1
#!/bin/bash
table=(~/image.png " " "Title1" " " "description1" "output1" ~/image.png " " "Title2" " " "description2" "output2" ~/image.png " " "Title3" " " "description3" "output3")
zenity --list --title="page title" --text="some random text" --imagelist --ok-label=Open --cancel-label=Home --print-column=6 --hide-column=6 --separator=' ' --width=600 --height=400 \
--column="Cover image" \
--column=" " \
--column="Name" \
--column=" " \
--column="details" \
--column="Folder" \
"${table[#]}"
the dialog should look like this:
In this example ${table[#]} is an array that contains all the data for each row including the file-path to the image in column 1. Is there a way to do this in YAD?
I installed YAD and looked at all the help pages provided in terminal, also tried to run similar imagelist examples, but it seems to be not supported (syntax is mostly the same as YAD is a fork of zenity)
With yad the columns can have a type associated with them. In your case you want to use the :IMG type for the first column, and the other two can remain as plain text.
table=(
~/image.png "" "Title1" "" "description1" "output1"
~/image.png "" "Title2" "" "description2" "output2"
~/image.png "" "Title3" "" "description3" "output3"
)
yad \
--list \
--title="page title" \
--text="some random text" \
--imagelist \
--print-column=6 \
--hide-column=6 \
--separator=' ' \
--width=600 \
--height=400 \
--column="Cover image:IMG" \
--column=" " \
--column="Name" \
--column=" " \
--column="details" \
--column="Folder" \
--button="Home":1 \
--button="Open":20 \
--response=20 \
"${table[#]}"
The output, missing your images
That will set the exit code to 20 if you press Enter or click Open on a list item, as well as outputting "output1" or "output2" etc.
That said, I have been experiencing issues with the exit codes or output text not appearing correctly. The above example works fine for me, but if I change the the Open exit code to "25" instead of "20" it stops working. No idea why it behaves inconsistently.
I have two rules on my Snakefile: one generates several sets of files using wildcards, the other one merges everything into a single file. This is how I wrote it:
chr = range(1,23)
rule generate:
input:
og_files = config["tmp"] + '/chr{chr}.bgen',
output:
out = multiext(config["tmp"] + '/plink/chr{{chr}}',
'.bed', '.bim', '.fam')
shell:
"""
plink \
--bgen {input.og_files} \
--make-bed \
--oxford-single-chr \
--out {config[tmp]}/plink/chr{chr}
"""
rule merge:
input:
plink_chr = expand(config["tmp"] + '/plink/chr{chr}.{ext}',
chr = chr,
ext = ['bed', 'bim', 'fam'])
output:
out = multiext(config["tmp"] + '/all',
'.bed', '.bim', '.fam')
shell:
"""
plink \
--pmerge-list-dir {config[tmp]}/plink \
--make-bed \
--out {config[tmp]}/all
"""
Unfortunately, this does not allow me to track the file coming from the first rule to the 2nd rule:
$ snakemake -s myfile.smk -c1 -np
Building DAG of jobs...
MissingInputException in line 17 of myfile.smk:
Missing input files for rule merge:
[list of all the files made by expand()]
What can I use to be able to generate the 22 sets of files with the wildcard chr in generate, but be able to track them in the input of merge? Thank you in advance for your help
In rule generate I think you don't want to escape the {chr} wildcard, otherwise it doesn't get replaced. I.e.:
out = multiext(config["tmp"] + '/plink/chr{{chr}}',
'.bed', '.bim', '.fam')
should be:
out = multiext(config["tmp"] + '/plink/chr{chr}',
'.bed', '.bim', '.fam')
I would like to extract all lines between INFO:root:id is and one line after the INFO:root:newId.
Can anyone advise how I can achieve this?
Currently I'm using
sed -n '/INFO:root:id is/,/INFO:root:newId/p' 1/python.log
and I'm trying to figure out how to print one line after the second pattern match.
INFO:root:id is
INFO:root:16836211
DEBUG:urllib3.connectionpool:Starting new HTTPS connection (1): abc.hh.com
DEBUG:urllib3.connectionpool:https://abc.hh.com:443 "POST /api/v2/import/row.json HTTP/1.1" 201 4310
INFO:root:newId
INFO:root:35047536
INFO:root:id is
INFO:root:46836211
DEBUG:urllib3.connectionpool:Starting new HTTPS connection (1): abc.hh.com
DEBUG:urllib3.connectionpool:https://abc.hh.com:443 "POST /api/v2/import/row.json HTTP/1.1" 201 4310
INFO:root:newId
INFO:root:55547536
If I am understanding question correctly
$ seq 10 | sed -n '/3/,/5/{/5/N;p;}'
3
4
5
6
/3/ is starting regex and /5/ is ending regex
/5/N get additional line for ending regex
tested on GNU sed, syntax might differ for other versions
With awk
$ seq 10 | awk '/3/{f=1} f; /5/{f=0; if((getline a)>0) print a}'
3
4
5
6
Unclear whether you want only the first set of lines after a match or all matches.
If you want the first set between the matching patterns, it is easy if you use /INFO:root:id/ for your end match as well and then use head -n -1 to print everything but the last line.
$ sed -n '/INFO:root:id is/,/INFO:root:id/p' test.txt | head -n -1
INFO:root:id is
INFO:root:16836211
DEBUG:urllib3.connectionpool:Starting new HTTPS connection (1): abc.hh.com
DEBUG:urllib3.connectionpool:https://abc.hh.com:443 "POST /api/v2/import/row.json HTTP/1.1" 201 4310
INFO:root:newId
INFO:root:35047536
Just use flags to indicate when you've found the beginning and ending regexps and print accordingly:
$ seq 10 | awk 'e{print buf $0; buf=""; b=e=0} /3/{b=1} b{buf = buf $0 ORS; if (/5/) e=1}'
3
4
5
6
Note that this does not have the potential issue of printing lines when there's only the beginning or ending regexp present but not both. The other answers, including your currently accepted answer, have that problem:
$ seq 10 | sed -n '/3/,/27/{/27/N;p;}'
3
4
5
6
7
8
9
10
$ seq 10 | awk '/3/{f=1} f; /27/{f=0; if((getline a)>0) print a}'
3
4
5
6
7
8
9
10
$ seq 10 | awk 'e{print buf $0; buf=""; b=e=0} /3/{b=1} b{buf = buf $0 ORS; if (/27/) e=1}'
$
Note that the script I posted correctly didn't print anything because a block of text beginning with 3 and ending with 27 was not present in the input.
I've been trying to pull a field from a row in a file although each row may have plus or minus 2 or 3 fields per row. They aren't always equal in the number of fields per row.
Here is a snippet:
A orarpp 45286124 1 1 0 20 60 Nov 25 9-16:42:32 01:04:58 11176 117056 0 - oracleXXX (LOCAL=NO)
A orarpp 45351560 1 1 3 20 61 Nov 30 5-03:54:42 02:24:48 4804 110684 0 - ora_w002_XXX
A orarpp 45548236 1 1 22 20 71 Nov 26 8-19:36:28 00:56:18 10628 116508 0 - oracleXXX (LOCAL=NO)
A orarpp 45679190 1 1 0 20 60 Nov 28 6-23:42:20 00:37:59 10232 116112 0 - oracleXXX (LOCAL=NO)
A orarpp 45744808 1 1 0 20 60 10:52:19 23:08:12 00:04:58 11740 117620 0 - oracleXXX (LOCAL=NO)
A root 45810380 1 1 0 -- 39 Nov 25 9-19:54:34 00:00:00 448 448 0 - garbage
In the case of the first line, I'm interested in 9-16:42:32 and the similar fields for each row.
I've tried to pull it by using ':' as the field separator and then filter from there however, what I am trying to accomplish is to do something if the number before the dash (in the example it's 9) is greater than one.
cat file.txt | grep oracle | awk -F: '{print substr($1, length($1)-5)}'
This is because the number of fields on either side of the actual field I need can be different from line to line.
Definitely not the most efficient but I've been trying to do this with an awk one liner.
Hints or a direction would be appreciated to get me moving again. I am not opposed to doing in a better way than awk.
Thanks.
Maybe cut is the right tool for this job? For example, with your snippet:
$ cut -c 62-71 file.txt
9-16:42:32
5-03:54:42
8-19:36:28
6-23:42:20
23:08:12
9-19:54:34
The arguments tell cut to snip columns (-c) 62 through 71.
For additional processing, you can pipe it to awk.
You can also accomplish the whole thing in awk by accepting entire lines and then using substr to extract the columns you want. For example, this awk command produces the same output as the cut command above:
awk '{ print substr($0, 62, 10) }' file.txt
Whether you create a pipeline or do the processing entirely in awk is at least in part a matter of personal taste / style.
Would this do?
awk -F: '/oracle/ {print substr($0,62,10)}' file.txt
9-16:42:32
8-19:36:28
6-23:42:20
23:08:12
This search for oracle and then print 10 characters starting from position 62
You can grab those identifiers with one of
grep -o '[[:digit:]]\+-[[:digit:]]\{2\}:[[:digit:]]\{2\}:[[:digit:]]\{2\}'
grep -oP '\d+-\d\d:\d\d:\d\d' # GNU grep
It sounds like you want to do something with the lines, not just find the ids. Please elaborate.
Using GNU awk:
gawk --re-interval '
/oracle/ && \
match($0, /([[:digit:]]+)-([[:digit:]]{2}:){2}[[:digit:]]{2}/, a) && \
a[1]>1 {
# do something with the matching line
print
}
' file
Q1: Sed specify the whole line and if the line is nothing but the string then delete
I have a file that contains several of the following numbers:
1 1
3 1
12 1
1 12
25 24
23 24
I want to delete numbers that are the same in each line. For that I have either been using:
sed '/1 1/d' < old.file > new.file
OR
sed -n '/1 1/!p' < old.file > new.file
Here is the main problem. If I search for pattern '1 1' that means I get rid of '1 12' as well. So for I want the pattern to specify the whole line and if it does, to delete it.
Q2: Automation of question 1
I am also trying to automate this problem. The range of numbers in the first column and the second column could be from 1 to 25.
So far this is what I got:
for ((i=1;i<26;i++)); do
sed "/'$i' '$i'/d" < oldfile > newfile; mv newfile oldfile;
done
This does nothing to the oldfile in the end. :(
This would be more readable with awk:
awk '$1 == $2 {next} {print}' oldfile > newfile
Update based on comment:
If the requirement is to remove lines where the two values are within 1 of each other:
awk '{d = $1-$2; if (-1 <= d && d <= 1) next; else print}' oldfile
Unfortunately, awk does not have abs() (at least nawk and gawk don't)
Just put the first number in a group (\([0-9]*\)) and then look for it with a backreference (\1). Since the line to delete should contain only the group, repeated, use the ^ to mark the beginning of line and the $ to mark the end of line. For example, for the following file:
$ cat input
1 1
3 1
12 1
1 12
12 12
12 13
13 13
25 24
23 24
...the result is:
$ sed '/^\([0-9]*\) \1$/d' input
3 1
12 1
1 12
12 13
25 24
23 24
You can also do it with grep:
grep -E -v "([0-9])*\s\1" testfile
Look for multiple digits in a row and remember them, followed by a single whitespace, followed by whatever digits you remembered.