Send trigger to onModule that RPC succeded - gwt

I have a Class that contain all the RPC.
One of them is :
public void authenticateUserCall(String username,String password ,DBConnectionAsync rpcService)
{
AsyncCallback<UserIdent> callback = new AsyncCallback<UserIdent>() {
public void onFailure(Throwable caught) {
Window.alert("Wrong Username or Password");
}
public void onSuccess(UserIdent result) {
Window.alert(result.getUserName());
}
};
rpcService.authenticateUser(username, password, callback);
}
If the RPC succeeds, I want to change the layout of the page to the main page for the user.
So how can I send to the onModule that the RPC succeeded ?
I don't want to build the layout in the onSuccess, and I can't clear the login layout because I don't have it on the onSuccess method.
What is the right way to do it ?

Option 1:
A couple of suggestions would be to pass in the AsyncCallback as an argument to the authenticateUserCall. This way the caller could handle on success.
Option 2: Recommended
Another option, which will give you much more flexibility is to use the EventBus to fire a custom AuthenticationEvent. I use this for handling things like roles. So for instance when the user is authenticated successfully it will return me some information about the user, like their username, password and role. I then use the EventBus to fire an AuthenticationEvent which contains this information about the user. Any of my views and activities can register for this event on the event bus and handle accordingly. So for example many of my views will disable functionality if the user is not an admin. When one of my activities handles this event it will grey out action buttons that require admin access.

Related

Handle session time out with Wicket

I'm working on a wicket legacy-project and i'm trying to fix a bug with the session time-out.
Basically I'd like to have a redirect to a customed error page after session times out.
This is what I did:
web.xml :
<session-config>
<session-timeout>1</session-timeout>
</session-config>
in the application class:
#Override
public void init() {
super.init();
getApplicationSettings().setPageExpiredErrorPage(ErrorMessagePage.class);
This is not working. I mean after session time out, nothing happens.
What am I doing wrong?
EDIT 04.05.20
Based on the feedback from Martin I tried to implement a session validaty checker:
public class SessionValidityChecker implements IRequestCycleListener {
#Override
public void onBeginRequest(RequestCycle cycle) {
HttpServletRequest request = (HttpServletRequest) cycle.getRequest().getContainerRequest();
boolean sessionValid = request.isRequestedSessionIdValid();
if (!sessionValid) {
cycle.setResponsePage(SessionExpiredPage.class);
}
}
}
and in Application.class
public void init() {
super.init();
getRequestCycleListeners().add(new SessionValidityChecker());
}
Also what I may should have specified in my first post is that I use the wicket SignInPanel for authentification. After timeout, I'd like the user to be logged out and redirected to a specific page.
This is what I've tried with the above code, but after session time out, no redirect happens. Even worst, the user is still signed in. What am I missing?
You are mistaking page expiration with session expiration.
Stateful pages are stored in a PageStore (disk) and the store may grow up to some predefined size. Once this size is reached the oldest page is removed to make room for the newest one.
If your user uses the browser Back button many times at some point Wicket will throw PageExpiredException for the deleted page.
In your case when the session expires usually the web server (e.g. Tomcat) will just create a new one. If your application has authentication enabled then it will detect that there is no authenticated user in the new http session and most probably will redirect the user to the login page.
If there is no authentication in place then Wicket will create a new instance of the requested page and render it. You can change this by changing PageSettings#recreateBookmarkablePagesAfterExpiry to false
(see https://github.com/apache/wicket/blob/79f63f66eb588a5d69e9feff7066f1244f61f387/wicket-core/src/main/java/org/apache/wicket/settings/PageSettings.java#L46)
You may use javax/servlet/http/HttpServletRequest.html#isRequestedSessionIdValid() method to find whether the the request came with an expired JSESSIONID cookie/url. If it is false then the web server just created a new HttpSession. You can do the check in Wicket's IRequestCycleListener#onBeginRequest()

Liferay : How to show a Configured Page once User Enters Valid Credentials

I am using Liferay 6.1 version .
Once a User enters http:localhost , i am displaying my Web Page called "/ravi" which consists of my Custom Portal as shown
I have configured this below properties under portal-ext.properties as shown
auth.forward.by.last.path=true
default.landing.page.path=/web/guest/ravi
Please see the screen shot of my Custom Portlet shown when the users enters http:localhost
Now my requirement is that i need to show another page ("/web/guest/test") if he enters valid crendentails .
In my processAction class , i am doing this way
public class ValidateUser extends MVCPortlet {
public void processAction(ActionRequest request, ActionResponse response) {
String userName = (String) request.getParameter("userName");
String password = (String) request.getParameter("password");
try {
// Contatcs DB and validates the credentials here
// Please let me know how can i show the Configured Page if his credentials are valid ??
}
catch (Exception e) {
}
}
}
Edited Part
Thank you very much for the answer with respect to the default login.events.post .
I am new to Liferay , so i may be doing a mistake here , so please help me if i was doing anything wrong .
I followed these steps :
Created a New Portlet named "MyLogon" Portlet and in its view.jsp created a form with two text fields (Login and Password ) and a submit button .
On click of that Submit Button , i was actually calling my processAction Method and making a DB call to validate Users from mysql db .
2.Then i created a page inside /web/guest/ravi and added this "MyLogon" Portlet to this new page /web/guest/ravi
Then configured this below properties under portal-ext.properties
auth.forward.by.last.path=true
default.landing.page.path=/web/guest/ravi
This is what i did .
And when entering http:localhost:8080 , it displayed taht page .
Please tell me if i am doing anything wrong
Edited 2nd Part
I have understood some part of your answer and i have these questions .
Could you please help
I need to validate Users based on the Data present inside my DataBase , so for this i need to do the below thins .
I need to create a Hook , to overdide this property
login.events.pre=com.LoginAction
public class LoginAction extends Action {
public void run(HttpServletRequest req, HttpServletResponse res) {
// Here i need to make a Database call to validate User Credentials and then do redirect him to the page i wanted ??
}
}
You need to create a Hook and override the default login.events.post
Below code for your reference,
public class LandingPageAction extends Action {
public LandingPageAction()
{
}
public void run(HttpServletRequest request, HttpServletResponse response) throws ActionException
{
try
{
doRun(request, response);
}
catch(Exception e)
{
throw new ActionException(e);
}
}
protected void doRun(HttpServletRequest request, HttpServletResponse response) throws Exception
{
String homeRedirect="/web/guest/test";
LastPath lastPath = new LastPath(StringPool.BLANK, homeRedirect);
session.setAttribute("LAST_PATH", lastPath);
}
}
There are few things which I don't understand here. You are hitting localhost:8080, but screen shot shows that you are already logged in (there is a SignOut link and user Ravi Kiran is already logged in), but still there is a login page shown.
default.landing.page.path comes into picture when you are loggedin user. Are you hitting localhost:8080 or localhost/web/guest/Ravi ? You are not logged in yet, so it should not redirect to /web/guest/Ravi.
You could reuse the default Authentication code in Liferay. Not sure why you are taking User credentials from request parameters and making DB call yourself.
Edited as per the update in the question
1. The default Login Page of Liferay (the one that you see when you freshly download and hit localhost:8080 comes from this path
..\default\deploy\ROOT.war\html\portlet\login.
There is a login.jsp in this path which you can edit and give your own look and feel.
You can find below entry in this login.jsp page
<portlet:param name="struts_action" value="/login/login" />
This has a corresponding entry in ../deploy/ROOT.war/WEB-INF/struts-config.xml
<action path="/login/login" type="com.liferay.portlet.login.action.LoginAction">
<forward name="portlet.login.login" path="portlet.login.login" />
</action>
You can open up the source code and look into com.liferay.portlet.login.action.LoginAction method.
This performs a basic Authentication as per your passwords.encryption.algorithm= and passwords.digest.encoding=
configuration in portal-ext.properties file. LoginAction will perform basic authentication and will redirect all
users as per path mentioned in default.landing.page.path=
If you want (some) Users to redirect to (some) other path(conditionally), you can use the code I have mentioned above by writing a Hook.
2. Once authenticated, you can login and create a Page (in your case its "ravi"). You can add your custom Portlet to this Page. You should not write a cutom portlet which will do authentication once you are already logged in

gwt-rpc delay window refresh

I have the following code in the onModuleLoad() of my application:
Window.addWindowClosingHandler(new ClosingHandler() {
#Override
public void onWindowClosing(ClosingEvent event) {
event.setMessage("If you choose to close, application will sign out");
}
});
//sign out on close
Window.addCloseHandler(new CloseHandler<Window>() {
#Override
public void onClose(CloseEvent<Window> event) {
sendLogout();
}
});
The sendLogout() function looks like this:
// Set up the callback object.
AsyncCallback<String> callback = new LogoutCallback(this);
// Make the call to the survey service.
SurveySystemService.Util.getInstance().logout(details, callback);
Where 'details' is some object.
It works just fine when the window is closed, but if I try to refresh the page, it doesn't log out. What I figured is that since the call is asynchronous, it doesn't finish getting the message off to the server before the module is restarted.
I've tried:
1. creating and calling the callback inside the onClose method.
2. using a Timer to check if the call was made.
3. Endless loos which check the same as the above (I got desperate).
In all of these solutions, the program would reach the callback creation, but the server never received anything.
any help with this?
Can you just call logout any time the page first loads. Due to the stateless nature of the web the GWT application will not know the difference between someone hitting refresh or just navigating to the page.
You can store an ID variable in session storage which should be maintained until the browser window or tab is closed. If on the application start the ID variable exists in session storage you can use it to trigger the log out.

GXT: How to bring the login page when session expires

I am developing a web application using GXT, Hibernate, mysql etc. There is a login page for the application. Actually I am getting problem to set the login page when the session expires. We can set the timeout in the web.xml file but in that case we can't redirect to login page.Can you tell me how to achieve that.
You can not do a server side redirect because the application is entirely AJAX. What you can do is use the GWT Timer class and for every one of your RPC calls check/reset the timer. If the "session" expires then you do a redirect to the login page via a History token. This was the easiest way for me
Some other reading:
http://groups.google.com/group/Google-Web-Toolkit/browse_thread/thread/b9eab8daaa993c83/d0192d356045e061?pli=1
http://gwt-ext.com/forum/viewtopic.php?f=9&t=1682
I have used the concept of throwing an exception in the server side when the session expires and then tried to catch the exception in the client side. I don't know whether there is any better way to do that.
On the server side, you can check if the session is expired and if so, throw a custom exception.
On the client side, on every async call you do a check for this known situation and react to it. You can create an abstract class for AsyncCallback that you will subclass for each GWT RPC call:
public abstract class SessionExpiredAwareAsyncCallback<T> implements AsyncCallback<T> {
#Override
public void onSuccess(T returnObject) {
doOnSuccess(returnObject);
}
#Override
public void onFailure(Throwable exception) {
if (exception instanceof SessionExpiredException) {
goToLoginPage();
} else {
doOnFailure(exception);
}
}
public abstract doOnSuccess(T returnObject);
public abstract doOnFailure(Throwable exception);
}
You can use gwteventservice to fire an event from the server to the client.

How to eliminate ReturnUrl from the browser address

Now on unauthorized attempt to access an action my ASP.NET MVC app redirects user to the login page and generates URL shown below:
http://www.mysite.com/Account/Log?ReturnUrl=%2Ftest%2Fsampleaction
So, is there a way to eliminate this string from the URL, but to save it somewhere to be able to redirect user back after login?
I wonder why you would want to do that. Maybe you are sick of misused, excessive URL parameter orgies, and you like the clean RESTful URL style and the elegant way it can be implemented using the new ASP.NET Routing feature.
However, in this case, this is exactly what URL parameters are intended for. It's not bad practice or bad style at all. And there is absolutely no reason to apply SEO witchery to your login page. So why should you make this process less reliable for the user by requiring the session state directly (or indirectly via TempData), or any other workaround?
I would consider to implement my own AuthorizationFilter and do the redirect.
public class AuthorizationFilter : IFilter
{
public bool Perform(ExecuteWhen exec, IEngineContext context,
IController controller, IControllerContext controllerContext)
{
if (context.CurrentUser.IsInRole("Administrator"))
{
return true;
}
context.Response.Redirect("home", "index");
return false;
}
}
Before redirecting to login action store url
TempData["redirect-url"] = "/requested/page/url";
on login action read that value and pass it to login view and put to a hidden field.
I would implement a AuthorizationAttribute
public class MyAuthorizeAttribute : AuthorizeAttribute
{
public override void OnAuthorization(AuthorizationContext filterContext)
{
base.OnAuthorization(filterContext);
if (filterContext.Result is HttpUnauthorizedResult)
{
filterContext.HttpContext.Session["ReturnUrl"] = filterContext.HttpContext.Request.UrlReferrer.AbsoluteUri
filterContext.Result = // Your login page controller;
}
}
}
This is not tested but might help you find the answer
Good luck to you, please provide your solution when found.