I fail to think how should I proceed for plotting x=y plane withing a 2x2x2 space.
I create a 2x2 meshgrid
[X,Y]=meshgrid(-1:0.1:1,-1:0.1:1);
then I come to define Z - I get stuck
My thoughts go like this
I need to create a 21x21 array for Z ( I use surf function.. and the dimensions of X, Y, Z must match. Right?).
I need to populate only those values of Z that follow x==y
Now for each such point i.e. x==y Z will vary -1:0.1:1 .. Does This require that I iterate again and again on the x==y and keep drawing Z with values from -1:0.1:1?
Am I going the right way about plotting this plane? Kindly help.
You simply need to define X and Z, Y is equal to X by definition:
[X Z] = meshgrid(-1:.1:1,-1:.1:1);
figure;
surf(X,X,Z);xlabel('x');ylabel('y');zlabel('z');
Results with
You are actually trying to do something two dimensional in a 3 dimensional setting.
A bit unintuitive, but that does not mean it can't be done, for example:
[X,Y]=meshgrid(-1:0.1:1,-1:0.1:1);
Z = zeros(size(X)); % Perhaps you want NaN rather than zeros
idx = X==Y;
Z(idx)=X(idx).^2+Y(idx) % Of course identical to X(idx).^2+X(idx)
surf(Z)
Related
>> x=0:0.001:720;
>> y=sind(x);
>> z=cosd(x);
>> surf(x,y,z);
I want to plot a surface using the above code i.e. x in X-axis, y is Y-axis, and z in Z-axis.
I also programmed a FORTRAN code for the following purpose, created a csv file, and plotted it in origin. I am getting a result as this:
However, in MATLAB, I am getting a similar idea when using:-
>> plot3(x,y,z)
as in this image:
but it's not a surface (for obvious reasons).
When using the surf command, I am also getting an error saying:
Z must be a matrix, not a scalar or vector.
What could be the possible problem with my code?
Using surf requires Z to be a matrix. This is fixed easily with functions like meshgrid (also useful is griddata).
Using meshgrid makes using surf very accessible.
But both Z and Y are just functions of X so I'm unable to explain why your plot Z-value would change with both X and Y. From the analytical (mathematical) equations you've listed, the Z-value should be constant in the Y-dimension.
stepsize = 1; % use 10 for cleaner look
x = 0:stepsize:720;
y = sind(x);
[X,Y] = meshgrid(x,y);
Z = cosd(X);
surf(X,Y,Z)
Notice that the contour lines are straight & parallel in the Y dimension (using surfc(X,Y,Z)).
Another method is to loop through elements of x (indexed by i) and y (indexed by j) where both x and y (vectors) to calculate Z(i,j) where Z is a matrix. Due to default assignment for rows & columns, this method requires transposing the Z matrix such as surf(X,Y,Z.').
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I have coordinate vectors X and Y and corresponding vector of function values Z. I need to plot a surface Z(X,Y), and I need to put Z values on a regular mesh, right now X and Y define points distributed irregularly. What is the best way to do it in matlab?
Thanks!
If you have a function such as z=f(x,y) then you could use fsurf().
fsurf(#(x,y) x^2+y^2);
Or else, if you have data points then you could use surf()
[x, y]=meshgrid(-5:0.1:5);
z = x.^2 + y.^2;
mesh(x,y,z);
You could specify the axis as per your need.
The following worked for me:
Zinter = scatteredInterpolant(Xs,Ys,Z) %defines interpolant for scattered data and allows to calculate values of z for any point
I am trying to do a figure similar to the one attached.
I have exactly a (224x1) vector with dates (x-axis), a (10x1) vector with maturities (y-axis) and a (224x10) matrix with the values (z-axis).
I tried surf(X, Y, Z) but I got an error ("data dimensions must agree").
How can I combine this to make a plot like the one attached?
Thanks, V!
Edit: The second plot is the one I am getting using Luis Mendo's suggestion:
Use
surf(Y,X,Z)
From the documentation (emphasis added):
surf(x,y,Z) and surf(x,y,Z,C), with two vector arguments replacing
the first two matrix arguments, must have length(x) = nand
length(y) = m where [m,n] = size(Z). In this case, the vertices
of the surface patches are the triples (x(j), y(i), Z(i,j)).
Note that x corresponds to the columns of Z and y corresponds to
the rows.
Do
[X,Y]=meshgrid(x,y);
surf(X,Y,Z);
You need to create a meshgrid to be able to plot a surf. X ,Y and Z need to be the same size!
x=linspace(0, 2*pi, 100);
y=sin(x);
z=exp(-x);
Given that x, y, and z are already initialized, how do I write a function that plots exp(-x)sin(x) across the interval [0, 4pi] without additional calls to sin or exp? Just need some help getting started.
Thanks to #Rayryeng for getting me started. I believe the following command more closely satisfies the question's specifications.
plot(x+x, z.*z.*y)
Well, you've already created arrays for sin and exp stored in y and z respectively. These arrays were created on the same domain as x. You just need to multiply both arrays together element-wise and plot the graph. It's as simple as doing:
plot(x, z.*y);
Here, .* stands for element-wise multiplication. If you were to do z*y, MATLAB interprets this as matrix multiplication where z and y are interpreted to be matrices. This is obviously not what you want.
However, your array of x only contains points from 0 to 2*pi. If you want to plot this from 0 to 4*pi, you have to modify your call to linspace:
x=linspace(0, 4*pi, 100); %// Change
y=sin(x);
z=exp(-x);
plot(x, z.*y);
Now, x will contain 100 points between 0 to 4*pi. For more information on basic MATLAB operations, check out this link: http://www.mathworks.com/help/matlab/matlab_prog/array-vs-matrix-operations.html. What you have asked falls into the basic realms of array and matrix operations.
Edit
In the spirit of your question, we can't modify linspace. You did something clever where we can simply scale our values of x by 2 or adding with x so that we have points going from 0 to 2*pi to 0 to 4*pi. Also, if we scale our points by 2, this means that our input argument into the function must also be scaled by 2. So, the final function we need to plot is:
y = exp(-2x)*sin(2x)
Noting your hint, exp(-2x) = exp(-x-x) = exp(-x)exp(-x). Further, note that sin(2x) performs a compression by a factor of 2 (tip of the hat goes to knedlsepp for noticing my blunder). Due to the periodic nature of sin(x), we know that elements will repeat after 2*pi, and so if you want to go to 4*pi, simply subsample y by a factor of 2 and then append these same elements to a new vector. Therefore, our expression for the function simplifies to:
y = exp(-x)exp(-x)sin(2x)
This leads to the answer alluded to knedlsepp:
plot(x+x, z.*z.*[y(1:2:end) y(1:2:end)]);
As such, you should consider changing your edits to match this answer instead. It isn't quite right with respect to the sin(x) part in your code.
Given 3 vector-pair, X, Y and Z, how to generate the contour? I understand that we need to make use of the contour plot. But the thing is that we need to pass in a 2x2 matrix for this argument, which presumably, is a matrix of Z corresponding to each X,Y pair. But this would mean that I have to go extra miles to create such a matrix by using griddata interpolation first before talking about contour generation.
Is there any other more succinct method?
Yes. Use the Tricontour tool. It is found on the file exchange (on Matlab Central.) This does the contouring as you desire directly, without forcing you to use meshgrid and griddata.
MATLAB addresses this need of yours fairly succinctly.
What you need to do is use meshgrid to two-dimensionalize your X and Y vectors. Here is a simple example to demonstrate how to generate a contour plot of z = sin (x^2 + x*y^2):
x = -10:0.1:10;
y = -10:0.1:10;
[x,y] = meshgrid(x,y);
z = sin(x.^2+x.*y.^2);
contour(x,y,z)
Note the use of the .^ and .* notations, which forces MATLAB to conduct an element-by-element evaluation of the z matrix, making it 2D in the process.