I am trying to load different file names contained in a matlab vector inside a for loop. I wrote the following:
fileNames = ['fileName1.mat', ..., 'fileName_n.mat'];
for i=1:n
load(fileNames(i))
...
end
However, it doesn't work because fileNames(i) returns the first letter of the filename only.
How can I give the full file name as argument to load (the size of the string of the filename can vary)
Use a cell instead of an array.
fileNames = {'fileName1.mat', ..., 'fileName_n.mat'};
Your code is in principle a string cat, giving you just one string (since strings are arrays of characters).
for i=1:n
load(fileNames{i})
...
end
Use { and } instead of parentheses.
Related
I am trying to write a script that will auto sort files based on the 7th and 8th digit in their name. I get the following error: "Argument must be a string scalar or character vector". Error is coming from line 16:
Argument must be a string scalar or character vector.
Error in sort_files (line 16)
movefile (filelist(i), DirOut)
Here's the code:
DirIn = 'C:\Folder\Experiment' %set incoming directory
DirOut = 'C:\Folder\Experiment\1'
eval(['filelist=dir(''' DirIn '/*.wav'')']) %get file list
for i = 1:length(filelist);
Filename = filelist(i).name
name = strsplit(Filename, '_');
newStr = extractBetween(name,7,8);
if strcmp(newStr,'01')
movefile (filelist(i), DirOut)
end
end
Also, I am trying to make the file folder conditional so that if the 10-11 digits are 02 the file goes to DirOut/02 etc.
First, try avoid using the eval function, it is pretty much dreaded as slow and hard to understand. Specially if you need to create variables. Instead do this:
filelist = dir(fullfile(DirIn,'*.wav'));
Second, the passage:
name = strsplit(Filename, '_');
Makes name a list, so you can access name{1} or possibly name{2}. Each of these are strings. But name isn't a string, it is a list. extractBetween requires a string as an input. That is why you are getting this problem. But note that you could have simply done:
newStr = name(7:8);
If name was a string, which in Matlab is a char array.
EDIT:
Since it has been now claimed that the error occurs on movefile (filelist(i), DirOut), the likely cause is because filelist(i) is a struct. Wheres a filena name (char array) should have been given at input. The solution should be replacing this line with:
movefile(fullfile(filelist(i).folder, filelist(i).name), DirOut)
Now, if you want to number the output folders too, you can do this:
movefile(fullfile(filelist(i).folder, filelist(i).name), [DirOut,filesep,name(7:8)])
This will move a file to /DirOut/01. If you wanted /DirOut/1, you could do this:
movefile(fullfile(filelist(i).folder, filelist(i).name), [DirOut,filesep,int2str(str2num(name(7:8)))])
this question about matlab:
i'm running a loop and each iteration a new set of data is produced, and I want it to be saved in a new file each time. I also overwrite old files by changing the name. Looks like this:
name_each_iter = strrep(some_source,'.string.mat','string_new.(j).mat')
and what I#m struggling here is the iteration so that I obtain files:
...string_new.1.mat
...string_new.2.mat
etc.
I was trying with various combination of () [] {} as well as 'string_new.'j'.mat' (which gave syntax error)
How can it be done?
Strings are just vectors of characters. So if you want to iteratively create filenames here's an example of how you would do it:
for j = 1:10,
filename = ['string_new.' num2str(j) '.mat'];
disp(filename)
end
The above code will create the following output:
string_new.1.mat
string_new.2.mat
string_new.3.mat
string_new.4.mat
string_new.5.mat
string_new.6.mat
string_new.7.mat
string_new.8.mat
string_new.9.mat
string_new.10.mat
You could also generate all file names in advance using NUM2STR:
>> filenames = cellstr(num2str((1:10)','string_new.%02d.mat'))
filenames =
'string_new.01.mat'
'string_new.02.mat'
'string_new.03.mat'
'string_new.04.mat'
'string_new.05.mat'
'string_new.06.mat'
'string_new.07.mat'
'string_new.08.mat'
'string_new.09.mat'
'string_new.10.mat'
Now access the cell array contents as filenames{i} in each iteration
sprintf is very useful for this:
for ii=5:12
filename = sprintf('data_%02d.mat',ii)
end
this assigns the following strings to filename:
data_05.mat
data_06.mat
data_07.mat
data_08.mat
data_09.mat
data_10.mat
data_11.mat
data_12.mat
notice the zero padding. sprintf in general is useful if you want parameterized formatted strings.
For creating a name based of an already existing file, you can use regexp to detect the '_new.(number).mat' and change the string depending on what regexp finds:
original_filename = 'data.string.mat';
im = regexp(original_filename,'_new.\d+.mat')
if isempty(im) % original file, no _new.(j) detected
newname = [original_filename(1:end-4) '_new.1.mat'];
else
num = str2double(original_filename(im(end)+5:end-4));
newname = sprintf('%s_new.%d.mat',original_filename(1:im(end)-1),num+1);
end
This does exactly that, and produces:
data.string_new.1.mat
data.string_new.2.mat
data.string_new.3.mat
...
data.string_new.9.mat
data.string_new.10.mat
data.string_new.11.mat
when iterating the above function, starting with 'data.string.mat'
I have a large text file (~3500 lines) which contains output data from an instrument. This consists of repeated entries from different measurements which are all formatted as follows:
* LogFrame Start *
variablename1: value
variablename2: value
...
variablename35: value
* LogFrame End *
Each logframe contains 35 variables. From these I would like to extract two, 'VName' and 'EMGMARKER' and put the associated values in columns in a matlab array, (i.e. the array should be (VName,EMGMARKER) which I can then associate with data from another output file which I already have in a matlab array. I have no idea where to start with this in order to extract the variables from this file, so hence my searches on the internet so far have been unsuccessful. Any advice on this would be much appreciated.
You could use textscan:
C = textscan(file_id,'%s %f');
Then you extract the variables of interest like this:
VName_indices = strcmp(C{1},'VName:');
VName = C{2}(VName_indices);
If the variable names, so 'VName' and 'EMGMARKER' , are always the same you can just read through the file and search for lines containing them and extract data from there. I don't know what values they contain so you might have to use cells instead of arrays when extracting them.
fileID = fopen([target_path fname]); % open .txt file
% read the first line of the specified .txt file
current_line = fgetl(fileID);
counter = 1;
% go through the whole file
while(ischar(current_line))
if ~isempty(strfind(current_line, VName))
% now you find the location of the white space delimiter between name and value
d_loc = strfind(current_line,char(9));% if it's tab separated - so \t
d_loc = strfind(current_line,' ');% if it's a simple white space
variable_name{counter} = strtok(current_line);% strtok returns everything up until the first white space
variable_value{counter} = str2double(strtok(current_line(d_loc(1):end)));% returns everything form first to second white space and converts it into a double
end
% same block for EMGMARKER
counter = counter+1;
current_line = fgetl(fileID);% next line
end
You do the same for EMGMARKER and you have cells containing the data you need.
I'm trying to access multiple files in a for loop, like this:
age = xlsread(strcat('Pipeline_BO_2013_',names(2),'_CDBU.xlsx'), 'Data', 'H:I')
It returns an error the filename must be string. So I did following test:
filename = strcat('Pipeline_BO_2013_',names(2),'_CDBU.xlsx')
filename =
'Pipeline_BO_2013_0107_CDBU.xlsx'
isstr(filename)
ans =
0
This is so weird. Could any one help me out? Thank you so much.
It looks like names is a cellstr and not a char array. If so, indexing in to it with parentheses like names(2) will return a 1-long cellstr array, not a char array. And when strcat is called with any of its arguments as a cellstr, it returns a cellstr. Then xlsread errors because it wants a char, not a cellstr.
Instead of just calling isstr or ischar on filename, do class(filename) and it'll tell you what it is.
Another clue is that filename is displayed with quotes. This is how cellstrs are displayed. If it were a char array, it would be displayed without quotes.
If this is the case, and names is a cellstr, you need to use {} indexing to "pop out" the cell contents.
filename = strcat('Pipeline_BO_2013_',names{2},'_CDBU.xlsx')
Or you can use sprintf, which you may find more readable, and will be more flexible once you start interpolating multiple arguments of different types.
filename = sprintf('Pipeline_BO_2013_%s_CDBU.xlsx', names{2})
% An example of more flexibility:
year = 2013;
filename = sprintf('Pipeline_BO_%04d_%s_CDBU.xlsx', year, names{2})
how I can read the following files using the for loop: (can the loop ignore the characters in filenames?)
abc-1.TXT
cde-2.TXT
ser-3.TXT
wsz-4.TXT
aqz-5.TXT
iop-6.TXT
What do I have to add at the beginning of this loop ??
for i = 1:1:6
nom_fichier = strcat(['MyFile\.......' num2str(i) '.TXT']);
You can avoid constructing the filenames by using the DIR command. For instance:
myfiles = dir('*.txt');
for i = 1:length(myfiles)
nom_fichier = myfiles(i).name;
...do processing here...
end
First of all, why would you use strcat here? This is, by itself, a SINGLE string. All concatenation has already been done by the brackets [].
['MyFile\.......' num2str(i) '.TXT']
Next, I'm not certain what is your question here. Is it how to load in the data? If the files are simply delimited numbers, with the same number of them on each line, then load will suffice to load them in, or perhaps you may need textread.
My guess is you do not know how to build the main part of of the file name. You might do it this way:
Names = {'abc' 'cde 'ser' 'wsz' 'aqz' 'iop'};
for i = 1:6
fn = ['MyFile',filesep,Names{i},'-',num2str(i),'.TXT'];
data = load(fn);
% do other stuff ...
end
If you don't want to create a variable with the names by typing them in, then use dir, perhaps like this to create a list of text file names:
Names = dir('MyFile\*.TXT');