I am writing some perl script and I want to include module. Everything is okay when I am in the same directory that my script.pl is. But when I try to start my script from other directory it says it cant locate my module. My includes looks like this:
use Functions qw(translateWord sendHelp);
and the file with module is called Functions.. I tried something like this:
use lib '..';
but it failed too.. I also tried:
use Cwd 'abs_path';
BEGIN {
my $dir = abs_path($0);
use lib "$dir";
}
but again it failed.. I also tried this:
use Cwd 'abs_path';
my $dir = abs_path($0);
use lib $dir;
and still fail.. I am new to Perl.
Thanks in advance!
The canonical way of accomplishing this is with 'use lib'. Using a lib of .. is not ideal though, because it's relative to the current working directory when you invoke the script.
The way to accomplish this is with FindBin.
E.g.
use FindBin;
use lib $FindBin::Bin."/../";
To traverse up a directory level from the 'base location' of your script.
Try this :
BEGIN{
unshift #INC, '/FULL/PATH/TO/DIR/OF/YOUR/MODULE';
}
Related
So, i've got a problem with loading a module via require.
We have a working directory. The program loads a PACKAGE (bolded not to make you confused) (which is ok - thanks to correct and local namespaces), but it has to load another module from very different directory. So, as i've heard, it should be unshifted into #INC in BEGIN block. But....This begin should take a param (currently from initial programm), containing some path to configuration file, which containing parameter i need (path to module, which i need to unshift).
BEGIN inited, i check #INC - unshift seems to be succeed. Then, in PACKAGE methods we need to load this module, but when i try to do something like:
eval{
print STDERR "Trying...\n";
my $path = "path/to/module"; # contains "DIR" dir and "Module.pm",
# also tried to write this path as "path/to/module/DIR/Module.pm"
require $path;
DIR::Module->import();
print STDERR "Success\n";
1;
} or {print STDERR "Failed\n";}
my $module = DIR::Module->new();
And I got "Trying.." and "Failed". Tried use lib with fullpath - got nothing. What am i doing wrong?
You say $path is the path to the module, but you also say it's the path to the directory containing DIR/Module.pm. I'm assuming it's the latter because it needs to be the former.
my $path = "/path/to/lib";
require "$path/DIR/Module.pm";
Remember to use $RealBin if the path is relative to your script.
use FindBin qw( $RealBin );
my $path = "$RealBin/../lib";
require "$path/DIR/Module.pm";
Note that it rarely makes sense to import from a dynamically loaded module.
If there's no reason to avoid loading this module at compile-time, I'd go with
use lib qw( /path/to/lib );
use DIR::Module;
Again, remember to use $RealBin if the path is relative to your script.
use FindBin qw( $RealBin );
use lib "$RealBin/../lib";
use DIR::Module;
I am building up a website using Perl. I organized my files as follow:
/index.cgi
/perl/modules/databaseFunctions.pm
/perl/indexCheck.cgi
/database/database.xml
Inside databaseFunctions.pm I have a function X() that reads and writes on database.xml. In X() I have specified relative path of the database as follow:
sub X{
my $db_path='../../database/database.xml';
my $parser=XML::LibXML->new();
my $doc=$parser->parse_file($db_path);
....
....
}
Here is the problem:
I have to call X() from index.cgi and indexCheck.cgi but I get an error the following error:
Could not create file parser context for file "../../database/database.xml": No such file or directory at perl/modules/databaseFunctions.pm line 21.
I think the problem is that when I call X() inside index.cgi or inside /perl/indexCheck.cgi the relative path of the database is different but I don't know how to set a path that works for index.cgi and /perl/indexCheck.cgi.
I think the problem boils down to "How to find out the path of the current script (*.pl)?" and
"How to find out the path of the current module (*.pm)?".
Scripts
For scripts, there is a very convenient module, FindBin, that offers 4 variables for the current script's name and path with
either symlinks resolved or not. Usually $FindBin::Bin is what you are looking for. It's the path of the current script.
I often use it to enhance the #INC path so that my scripts find additional (own) modules like so:
use FindBin;
use lib "$FindBin::Bin/my_mod_path";
use MyModule;
In this case MyModule.pm is searched for in the directory my_mod_path below the current script's path. Very convenient.
The module is part of the core distribution, i.e. no further installation is neccessary.
Modules
FindBin may not safely be used from inside modules because then it depends who (script or module) makes the first use FindBin;.
So if you don't want to care about the order, don't use FindBin; in modules, only in scripts.
For modules, there is some trick. Use the perl function caller().
Depending on the context called in, it returns the $filename of the file where it actually was called.
Thus, in modules you can safely use the following to get the module's path:
use File::Basename;
my $path_of_this_module = File::Basename::dirname( eval { ( caller() )[1] } );
Given that path you can navigate relative to it in order to find the other files you need, e.g. "$path_of_this_module/../.." and so on.
EDIT
index.cgi:
#!/usr/bin/env perl
use strict;
use warnings;
use FindBin;
use lib "$FindBin::Bin/perl/modules";
use databaseFunctions;
databaseFunctions::X( "called from index.cgi\n" );
perl/indexCheck.cgi:
#!/usr/bin/env perl
use strict;
use warnings;
use FindBin;
use lib "$FindBin::Bin/modules";
use databaseFunctions;
databaseFunctions::X( "called from indexCheck.cgi\n" );
perl/modules/databaseFunctions.pm:
package databaseFunctions;
use File::Basename;
my $path_of_this_module = File::Basename::dirname( eval { ( caller() )[1] } );
sub X {
my $arg = shift;
my $db_path="$path_of_this_module/../../database/database.xml";
open(my $fh, '>>', $db_path) or die "cannot open $db_path: $!\n";
print $fh $arg;
close($fh);
}
1;
When I now call ./index.cgi and then ./perl/indexCheck.cgi, then I get the following:
database/database.xml:
called from index.cgi
called from indexCheck.cgi
Exactly, what I thought you were looking for.
I have a perl module /x/y/z/test.pm. Inside this module, I want to read a config file /x/y/z/test.config. Yet, I am including my module from /a/b/c/mymain.pl. How can I get /x/y/z/ to build the path for /x/y/z/test.config in /x/y/z/test.pm?
Thanks,
AFAIK FindBin will show mymain.pl (and it might have been used in other modules, then the first invocation will win). Try __FILE__:
my $path = __FILE__;
$path =~ s/pm$/config/;
I made myself a custom PERL module and it works when called by a script in the same directory, but not from outside the directory for somewhat obvious reasons. How do I use the module without installing it? eg:
use 5.012;
use warnings;
use Y:/my/dir/to/module.pm;
use lib 'Y:/my/dir/to';
use module; # BAD name for module, lowercase is reserved for pragmas...
If you only have one module, instead of using lib, you can do this :
BEGIN {
unshift #INC,"dir";
##INC is the directory list, where perl searches for .pm files
}
use Foo::Bar; #dir/Foo/Bar.pm
#or
do "dir/Foo/Bar.pm"; #perldoc -f do
How can you get current script directory in Perl?
This has to work even if the script is imported from another script (require).
This is not the current directory
Example:
#/aaa/foo.pl
require "../bbb/foo.pl"
#/bbb/bar.pl
# I want to obtain my directory (`/bbb/`)
print($mydir)
The script foo.pl could be executed in any ways and from any directory, like perl /aaa/foo.pl, or ./foo.pl.
What people usually do is
use FindBin '$Bin';
and then use $Bin as the base-directory of the running script. However, this won't work if you do things like
do '/some/other/file.pl';
and then expect $Bin to contain /some/other/ within that. I'm sure someone thought of something incredibly clever to work this around and you'll find it on CPAN somewhere, but a better approach might be to not include a program within a program, but to use Perl's wonderful ways of code-reuse that are much nicer than do and similar constructs. Modules, for example.
Those generally shouldn't care about what directory they were loaded from. If they really need to operate on some path, you can just pass that path to them.
See Dir::Self CPAN module. This adds pseudo-constant __DIR__ to compliment __FILE__ & __LINE__.
use Dir::Self;
use lib __DIR__ . '/lib';
I use this snippet very often:
use Cwd qw(realpath);
use File::Basename;
my $cwd = dirname(realpath($0));
This will give you the real path to the directory containing the currently running script. "real path" means all symlinks, "." and ".." resolved.
Sorry for the other 4 responses but none of them worked, here is a solution that really works.
In below example that adds the lib directory to include path the $dirname will contain the path to the current script. This will work even if this script is included using require from another directory.
BEGIN {
use File::Spec;
use File::Basename;
$dirname = dirname(File::Spec->rel2abs( __FILE__ )) . "/lib/";
}
use lib $dirname;
From perlfaq8's answer to How do I add the directory my program lives in to the module/library search path?
(contributed by brian d foy)
If you know the directory already, you can add it to #INC as you would for any other directory. You might if you know the directory at compile time:
use lib $directory;
The trick in this task is to find the directory. Before your script does anything else (such as a chdir), you can get the current working directory with the Cwd module, which comes with Perl:
BEGIN {
use Cwd;
our $directory = cwd;
}
use lib $directory;
You can do a similar thing with the value of $0, which holds the script name. That might hold a relative path, but rel2abs can turn it into an absolute path. Once you have the
BEGIN {
use File::Spec::Functions qw(rel2abs);
use File::Basename qw(dirname);
my $path = rel2abs( $0 );
our $directory = dirname( $path );
}
use lib $directory;
The FindBin module, which comes with Perl, might work. It finds the directory of the currently running script and puts it in $Bin, which you can then use to construct the right library path:
use FindBin qw($Bin);
You can also use local::lib to do much of the same thing. Install modules using local::lib's settings then use the module in your program:
use local::lib; # sets up a local lib at ~/perl5
See the local::lib documentation for more details.
Let's say you're looking for script.pl. You may be running it, or you may have included it. You don't know. So it either lies in the %INC table in the first case or as $PROGRAM_NAME (aka $0) in the second.
use strict;
use warnings;
use English qw<$PROGRAM_NAME>;
use File::Basename qw<dirname>;
use File::Spec;
use List::Util qw<first>;
# Here we get the first entry that ends with 'script.pl'
my $key = first { defined && m/\bscript\.pl$/ } keys %INC, $PROGRAM_NAME;
die "Could not find script.pl!" unless $key;
# Here we get the absolute path of the indicated path.
print File::Spec->rel2abs( dirname( $INC{ $key } || $key )), "\n";
Link to File::Basename, File::Spec, and List::Util