resolve all given the Type - autofac

Question

From the Autofac documentation I can see how to get all registrations for a class T:
public T[] ResolveAll<T>()
{
return _container.Resolve<IEnumerable<T>>().ToArray();
}
But when I only have the Type available, how can I get the equivalent results?
public Array ResolveAll(Type service)
{
return _container.Resolve( ???
}
I am trying to implement a wrapper class which has a pre-defined interface.
EDIT
For quick reference, the answer from Matthew Watson (with relevant ideas from David L) is:
public Array ResolveAll(Type service)
{
var typeToResolve = typeof(IEnumerable<>).MakeGenericType(service);
return _container.Resolve(typeToResolve) as Array;
}

Answer 1

Here is an example. I've added asserts to prove that the types returned from ResolveAll<T>(this IContainer self) are the same (and in the same order) as those returned from ResolveAll(this IContainer self, Type type):
using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using Autofac;
using Autofac.Core;
namespace AutofacTrial
{
public abstract class Base
{
public abstract string Name { get; }
public override string ToString()
{
return Name;
}
}
public sealed class Derived1: Base
{
public override string Name
{
get
{
return "Derived1";
}
}
}
public sealed class Derived2: Base
{
public override string Name
{
get
{
return "Derived2";
}
}
}
public sealed class Derived3: Base
{
public override string Name
{
get
{
return "Derived3";
}
}
}
static class Program
{
static void Main()
{
var builder = new ContainerBuilder();
builder.RegisterType<Derived1>().As<Base>();
builder.RegisterType<Derived2>().As<Base>();
builder.RegisterType<Derived3>().As<Base>();
var container = builder.Build();
var array1 = container.ResolveAll(typeof(Base));
var array2 = container.ResolveAll<Base>();
Trace.Assert(array1.Length == 3);
Trace.Assert(array2.Length == 3);
for (int i = 0; i < array1.Length; ++i)
{
Trace.Assert(array1[i].GetType() == array2[i].GetType());
Console.WriteLine(array1[i]);
}
}
public static T[] ResolveAll<T>(this IContainer self)
{
return self.Resolve<IEnumerable<T>>().ToArray();
}
public static object[] ResolveAll(this IContainer self, Type type)
{
Type enumerableOfType = typeof(IEnumerable<>).MakeGenericType(type);
return (object[]) self.ResolveService(new TypedService(enumerableOfType));
}
}
}
The underling implementation is the same
I also used Reflector to look at the implementation of Resolve<IEnumerable<T>>(), and it winds up doing this:
public static TService Resolve<TService>(this IComponentContext context, IEnumerable<Parameter> parameters)
{
return (TService) context.Resolve(typeof(TService), parameters);
}
which calls:
public static object Resolve(this IComponentContext context, Type serviceType, IEnumerable<Parameter> parameters)
{
return context.ResolveService(new TypedService(serviceType), parameters);
}
So the two must be equivalent, since they are implemented that way.

Answer 2

You can invoke _container.Resolve by calling your wrapped method via reflection (MSDN), but in doing so you will lose your compile-time type safety.
public class Container
{
public T[] ResolveAll<T>()
{
return _container.Resolve<IEnumerable<T>>().ToArray();
}
public object ResolveAllGeneric(Type t)
{
MethodInfo method = GetType().GetMethod("ResolveAll")
.MakeGenericMethod(new Type[] { t });
return method.Invoke(this, new object[] { });
}
}