I'm using postgresql database and have a log table. I want to show the ticket information from this log table and want to sort by id. But ticket id has duplicate data, so I use distinct to filter, and then I can't sort by id when I use distinct.
How can I solve this issue? Thanks!
rows = db(db.log.ticket_id != '').select(db.log.ALL, orderby=~db.log.id, distinct=db.log.ticket_id , limitby=((page-1) * PAGE_ROWS, (page*PAGE_ROWS)))
I got the error message:
SELECT DISTINCT ON expressions must match initial ORDER BY expressions
And I try to:
rows = db(db.log.ticket_id != '').select(db.log.ALL, orderby=~db.log.id|db.log.ticket_id, distinct=db.log.ticket_id , limitby=((page-1) * PAGE_ROWS, (page*PAGE_ROWS)))
But still can't work...
Related
I am trying to select from one table using the select result from another table. I can run this in two queries but would like to optimize it into just one.
First query.. Select ids where matching other id
select id from lookuptable where paid = '547'
This results in something like this
6316352
6316353
6318409
6318410
6320468
6320469
6320470
6322526
6322527
6324586
6324587
6326648
I would like to then use this result to make another selection. I can do it manually like below. Note, there could be many rows with these values so I've been using a IN statement
select * from "othertable" where id in (6316352,6316353,6318409,6318410,6320468,6320469,6320470,6322526,6322527,6324586,6324587,6326648);
select
ot.*
from
"othertable" as ot
join
lookuptable as lt
on
ot.id = lt.id
where
lt.paid = '547'
The IN operator supports not just value lists but also subqueries, so you can literally write
select * from "othertable" where id in (select id from lookuptable where paid = '547');
I need to update a few thousand rows in my Postgres table using the result of a array_agg and spatial lookup.
The query needs to take the geometry of the parent table, and return an array of the matching row IDs in the other table. It may return no IDs or potentially 2-3 IDs.
I've tried to use an UPDATE FROM but I can't seem to pass into the subquery the parent table geom column for the SELECT. I can't see any way of doing a JOIN between the 2 tables.
Here is what I currently have:
UPDATE lrc_wales_data.records
SET lrc_array = subquery.lrc_array
FROM (
SELECT array_agg(wales_lrcs.gid) AS lrc_array
FROM layers.wales_lrcs
WHERE st_dwithin(records.geom_poly, wales_lrcs.geom, 0)
) AS subquery
WHERE records.lrc = 'nrw';
The error I get is:
ERROR: invalid reference to FROM-clause entry for table "records"
LINE 7: WHERE st_dwithin(records.geom_poly, wales_lrcs.geom, 0)
Is this even possible?
Many thanks,
Steve
Realised there was no need to use SET FROM. I could just use a sub query directly in the SET:
UPDATE lrc_wales_data.records
SET lrc_array = (
SELECT array_agg(wales_lrcs.gid) AS lrc
FROM layers.wales_lrcs
WHERE st_dwithin(records.geom_poly, wales_lrcs.geom, 0)
)
WHERE records.lrc = 'nrw';
I'm working on a project where I use Sphinx searchengine. But - as I realized - the Sphinx documentation is big but hard to understand.
So I was not able to find any information on how to use the WHERE clause to filter behind a MATCH-statement. What I tried yet is:
"SELECT *, country FROM all_gebrauchte_products WHERE MATCH('#searchtext (".$searchQuery.")') AND country='".$where."' ORDER BY WEIGHT() DESC LIMIT ".$page.", ".$limit." OPTION ranker=expr('sum(lcs)')"
If I use it without the country=$where clause, I get back many GUIDs but from different countries. So somehow I have to filter the country column;
If I use the above statement, I get error:
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 index all_gebrauchte_products: parse error: unknown column: country'
But I set the index like this:
sql_query_range = SELECT MIN(gebr_id), MAX(gebr_id) FROM all_gebrauchte_products
sql_range_step = 10000
sql_query = \
SELECT a.gebr_id AS guid, 'products' AS data_type, a.gebr_products AS products, a.gebr_user AS username, a.gebr_date AS datadate, CONCAT(a.gebr_hersteller,' ', a.gebr_modell,' ', a.gebr_ukat,' ', a.gebr_kat,' ', a.gebr_bemerkung) AS searchtext, a.gebr_bild1 AS image1, a.gebr_bild2 AS image2, a.gebr_bild3 AS image3, a.gebr_bild4 AS image4, a.gebr_bild5 AS image5, b.h_land AS country, b.h_web AS weblink, b.h_firmenname AS company, b.h_strasse AS street, b.h_plz AS zipcode, b.h_ort AS city, a.gebr_aktiv AS active \
FROM all_gebrauchte_products a, all_haendler b \
WHERE a.gebr_user = b.h_loginname AND a.gebr_id>=$start AND a.gebr_id<=$end
sql_attr_uint = active
Can anybody tell me what is going wrong? Or how do I have to filter for country?
Thnx. in advance for your help.
Any columns in the sql_query you dont make an ATTRIBUTE, is automatically a FIELD (except the first column is always the document-id).
FIELDs are 'full-text' indexed, they are what you can match in the query - ie the MATCH(...) clause.
ATTRIBUTES are what can be 'filtered' in WHERE, sorted by in ORDER BY, grouped in GROUP BY, or retrieved in the SELECT (or even used in ranking expressions).
So you need country to be an ATTRIBUTE to be able use it in WHERE filter
You don't say but guess it's a string. You can use sql_field_string to make a column BOTH a FIELD and ATTRIBUTE, if you are still interested in being able to full-text query the column too.
(also because its a string, need a very recent version of sphinx. Sphinx only recently gained ability to filter by strings attributes)
I'm using Flask-SQLAlchemy with PostgreSQL. I have the following two models:
class Course(db.Model):
id = db.Column(db.Integer, primary_key = True )
course_name =db.Column(db.String(120))
course_description = db.Column(db.Text)
course_reviews = db.relationship('Review', backref ='course', lazy ='dynamic')
class Review(db.Model):
__table_args__ = ( db.UniqueConstraint('course_id', 'user_id'), { } )
id = db.Column(db.Integer, primary_key = True )
review_date = db.Column(db.DateTime)#default=db.func.now()
review_comment = db.Column(db.Text)
rating = db.Column(db.SmallInteger)
course_id = db.Column(db.Integer, db.ForeignKey('course.id') )
user_id = db.Column(db.Integer, db.ForeignKey('user.id') )
I want to select the courses that are most reviewed starting with at least two reviews. The following SQLAlchemy query worked fine with SQlite:
most_rated_courses = db.session.query(models.Review, func.count(models.Review.course_id)).group_by(models.Review.course_id).\
having(func.count(models.Review.course_id) >1) \ .order_by(func.count(models.Review.course_id).desc()).all()
But when I switched to PostgreSQL in production it gives me the following error:
ProgrammingError: (ProgrammingError) column "review.id" must appear in the GROUP BY clause or be used in an aggregate function
LINE 1: SELECT review.id AS review_id, review.review_date AS review_...
^
'SELECT review.id AS review_id, review.review_date AS review_review_date, review.review_comment AS review_review_comment, review.rating AS review_rating, review.course_id AS review_course_id, review.user_id AS review_user_id, count(review.course_id) AS count_1 \nFROM review GROUP BY review.course_id \nHAVING count(review.course_id) > %(count_2)s ORDER BY count(review.course_id) DESC' {'count_2': 1}
I tried to fix the query by adding models.Review in the GROUP BY clause but it did not work:
most_rated_courses = db.session.query(models.Review, func.count(models.Review.course_id)).group_by(models.Review.course_id).\
having(func.count(models.Review.course_id) >1) \.order_by(func.count(models.Review.course_id).desc()).all()
Can anyone please help me with this issue. Thanks a lot
SQLite and MySQL both have the behavior that they allow a query that has aggregates (like count()) without applying GROUP BY to all other columns - which in terms of standard SQL is invalid, because if more than one row is present in that aggregated group, it has to pick the first one it sees for return, which is essentially random.
So your query for Review basically returns to you the first "Review" row for each distinct course id - like for course id 3, if you had seven "Review" rows, it's just choosing an essentially random "Review" row within the group of "course_id=3". I gather the answer you really want, "Course", is available here because you can take that semi-randomly selected Review object and just call ".course" on it, giving you the correct Course, but this is a backwards way to go.
But once you get on a proper database like Postgresql you need to use correct SQL. The data you need from the "review" table is just the course_id and the count, nothing else, so query just for that (first assume we don't actually need to display the counts, that's in a minute):
most_rated_course_ids = session.query(
Review.course_id,
).\
group_by(Review.course_id).\
having(func.count(Review.course_id) > 1).\
order_by(func.count(Review.course_id).desc()).\
all()
but that's not your Course object - you want to take that list of ids and apply it to the course table. We first need to keep our list of course ids as a SQL construct, instead of loading the data - that is, turn it into a derived table by converting the query into a subquery (change the word .all() to .subquery()):
most_rated_course_id_subquery = session.query(
Review.course_id,
).\
group_by(Review.course_id).\
having(func.count(Review.course_id) > 1).\
order_by(func.count(Review.course_id).desc()).\
subquery()
one simple way to link that to Course is to use an IN:
courses = session.query(Course).filter(
Course.id.in_(most_rated_course_id_subquery)).all()
but that's essentially going to throw away the "ORDER BY" you're looking for and also doesn't give us any nice way of actually reporting on those counts along with the course results. We need to have that count along with our Course so that we can report it and also order by it. For this we use a JOIN from the "course" table to our derived table. SQLAlchemy is smart enough to know to join on the "course_id" foreign key if we just call join():
courses = session.query(Course).join(most_rated_course_id_subquery).all()
then to get at the count, we need to add that to the columns returned by our subquery along with a label so we can refer to it:
most_rated_course_id_subquery = session.query(
Review.course_id,
func.count(Review.course_id).label("count")
).\
group_by(Review.course_id).\
having(func.count(Review.course_id) > 1).\
subquery()
courses = session.query(
Course, most_rated_course_id_subquery.c.count
).join(
most_rated_course_id_subquery
).order_by(
most_rated_course_id_subquery.c.count.desc()
).all()
A great article I like to point out to people about GROUP BY and this kind of query is SQL GROUP BY techniques which points out the common need for the "select from A join to (subquery of B with aggregate/GROUP BY)" pattern.
I have a table where I have added a new column, and I want to write a SQL statement to update that column based on existing information. Here are the two tables and the relevant columns
'leagues'
=> id
=> league_key
=> league_id (this is the new column)
'permissions'
=> id
=> league_key
Now, what I want to do, in plain English, is this
Set leagues.league_id to be permissions.id for each value of permissions.league_key
I had tried SQL like this:
UPDATE leagues
SET league_id =
(SELECT id FROM permissions WHERE league_key =
(SELECT distinct(league_key) FROM leagues))
WHERE league_key = (SELECT distinct(league_key) FROM leagues)
but I am getting an error message that says
ERROR: more than one row returned by a subquery used as an expression
Any help for this would be greatly appreciated
Based on your requirements of
Set leagues.league_id to be permissions.id for each value of permissions.league_key
This does that.
UPDATE leagues
SET league_id = permissions_id
FROM permissions
WHERE permissions.league_key = leagues.league_key;
When you do a subquery as an expression, it can't return a result set. Your subquery must evaluate to a single result. The error that you are seeing is because one of your subqueries returns more than one value.
Here is the relevant documentation for pg84: