This may be very obvious to someone out there but I'm having a lot of trouble trying to solve a bug in VBScript. Within the script, I am running through a bunch of .zip files in a directory and processing ones whose creation date is within a specified range.
For instance, if the user enters two arguments 9/3/2014 and 9/5/2014, I only want to process zip files within that date range.
Here is the if statement I am using:
If Mid(file.NAME,len(file.NAME)-3,4) = ".zip" AND
FormatDateTime(file.DateCreated, 2) >= Wscript.Arguments(1) AND
FormatDateTime(file.DateCreated, 2) <= Wscript.Arguments(2) then
I am using the FormatDateTime function to remove the times from the file creation date. That way I should just be left with a short date (mm/dd/yyyy).
The problem I am having is that I am processing dates outside of the given range. For example if the given range is 9/3/2014 to 9/5/2014 then I also end up processing 9/30/2014 for some reason. Can anyone help solve this?
Both the return value of FormatDateTime() and the items of .Argments are Strings. A string comparison of (stringyfied) numbers will give inconvenient results:
>> WScript.Echo CStr(5 < 30)
>> WScript.Echo CStr("5" < "30")
>>
True
False
Use CDate() to convert the .Arguments to Dates and DateDiff() to compare them against the .DateCreated.
Found the source of my problem. FormatDateTime returns a string. Furthermore, the arguments I was being passed were strings also. This means I was actually doing a string comparison instead of a date comparison. The if statement should be:
If Mid(file.NAME,len(file.NAME)-3,4) = ".zip" AND
CDate(FormatDateTime(file.DateCreated, 2)) >= CDate(Wscript.Arguments(1)) AND
CDate(FormatDateTime(file.DateCreated, 2)) <= CDate(Wscript.Arguments(2)) then
Related
I have a .csv file with the first column containing dates, a snippet of which looks like the following:
date,values
03/11/2020,1
03/12/2020,2
3/14/20,3
3/15/20,4
3/16/20,5
04/01/2020,6
I would like to import this data into Matlab (I think the best way would probably be using the readtable() function, see here). My goal is to bring the dates into Matlab as a datetime array. As you can see above, the problem is that the dates in the original .csv file are not consistently formatted. Some of them are in the format mm/dd/yyyy and some of them are mm/dd/yy.
Simply calling data = readtable('myfile.csv') on the .csv file results in the following, which is not correct:
'03/11/2020' 1
'03/12/2020' 2
'03/14/0020' 3
'03/15/0020' 4
'03/16/0020' 5
'04/01/2020' 6
Does anyone know a way to automatically account for this type of data in the import?
Thank you!
My version: Matlab R2017a
EDIT ---------------------------------------
Following the suggestion of Max, I have tried specifiying some of the input options for the read command using the following:
T = readtable('example.csv',...
'Format','%{dd/MM/yyyy}D %d',...
'Delimiter', ',',...
'HeaderLines', 0,...
'ReadVariableNames', true)
which results in:
date values
__________ ______
03/11/2020 1
03/12/2020 2
NaT 3
NaT 4
NaT 5
04/01/2020 6
and you can see that this is not working either.
If you are sure all the dates involved do not go back more than 100 years, you can easily apply the pivot method which was in use in the last century (before th 2K bug warned the world of the danger of the method).
They used to code dates in 2 digits only, knowing that 87 actually meant 1987. A user (or a computer) would add the missing years automatically.
In your case, you can read the full table, parse the dates, then it is easy to detect which dates are inconsistent. Identify them, correct them, and you are good to go.
With your example:
a = readtable(tfile) ; % read the file
dates = datetime(a.date) ; % extract first column and convert to [datetime]
idx2change = dates.Year < 2000 ; % Find which dates where on short format
dates.Year(idx2change) = dates.Year(idx2change) + 2000 ; % Correct truncated years
a.date = dates % reinject corrected [datetime] array into the table
yields:
a =
date values
___________ ______
11-Mar-2020 1
12-Mar-2020 2
14-Mar-2020 3
15-Mar-2020 4
16-Mar-2020 5
01-Apr-2020 6
Instead of specifying the format explicitly (as I also suggested before), one should use the delimiterImportoptions and in the case of a csv-file, use the delimitedTextImportOptions
opts = delimitedTextImportOptions('NumVariables',2,...% how many variables per row?
'VariableNamesLine',1,... % is there a header? If yes, in which line are the variable names?
'DataLines',2,... % in which line does the actual data starts?
'VariableTypes',{'datetime','double'})% as what data types should the variables be read
readtable('myfile.csv',opts)
because the neat little feature recognizes the format of the datetime automatically, as it knows that it must be a datetime-object =)
I am curious if it's possible to convert numbers to data. In below example the script would ask sth like this :
How long user will be active: <add number 30 - meaning for 30 days>
So there must be a variable that holds a current date and add days based on numbers from the input nd, for example, save these data to file. I would create a second script that reads this file and remove users if current days are equal do the current date.
I am not sure about conversion from adding days like this :
current-date + 30 days = date_in_thefuture :)
any example or where i should look ?
$numberofdays = 30
$Temp = (Get-date).AddDays($numberofdays)
Powershell has functions like Get-Date that gives methods such as AddDays() that allows you to do what you are looking for.
Microsoft documentation on Get-Date
If I have a group of .wav files and Im trying to pick only month wise or do daily/only night psd(power spectral density) averages etc or choose files belonging to a month how to go about? The following are first 10 .wav files in a .txt file that are read into matlab code-
AMAR168.1.20150823T200235Z.wav
AMAR168.1.20150823T201040Z.wav
AMAR168.1.20150823T201845Z.wav
AMAR168.1.20150823T202650Z.wav
AMAR168.1.20150823T203455Z.wav
AMAR168.1.20150823T204300Z.wav
AMAR168.1.20150823T205105Z.wav
AMAR168.1.20150823T205910Z.wav
AMAR168.1.20150823T210715Z.wav
yyyymmddTHHMMSSZ.wav is part of the format to get sense of some parameters.
Many thanks
You need to be more specific.
Do all files always start with "AMAR168.1." for instance?
Anyway, here's a general approach to get you started:
AllFilenames = fileread ('filenames.dat');
FileNames = strsplit (AllFilenames, '\n');
for i = FileNames
if ~isempty (strfind (i{:}, '20150823')); disp(i{:}); end
end
Your filename examples aren't very useful because they all have the same date, but, anyway, you get the point.
Alternatively, if the filenames always have the same format and size, you could do, e.g.:
AllFilenames = fileread ('filenames.dat');
AllFilenames = strvcat (strsplit (AllFilenames, '\n'));
LogicalIndices = categorical (cellstr (AllFilenames(:,15:16))) == '08';
to obtain all rows where the month is '08' for instance. This assumes that the month is always at position 15 to 16 in the string
So I'm reading multiple text files in Matlab that have, in their first columns, a column of "times". These times are either in the format 'MM:SS.milliseconds' (sorry if that's not the proper way to express it) where for example the string '29:59.9' would be (29*60)+(59)+(.9) = 1799.9 seconds, or in the format of straight seconds.milliseconds, where '29.9' would mean 29.9 seconds. The format is the same for a single file, but varies across different files. Since I would like the times to be in the second format, I would like to check if the format of the strings match the first format. If it doesn't match, then convert it, otherwise, continue. The code below is my code to convert, so my question is how do I approach checking the format of the string? In otherwords, I need some condition for an if statement to check if the format is wrong.
%% Modify the textdata to convert time to seconds
timearray = textdata(2:end, 1);
if (timearray(1, 1) %{has format 'MM.SS.millisecond}%)
datev = datevec(timearray);
newtime = (datev(:, 5)*60) + (datev(:, 6));
elseif(timearray(1, 1) %{has format 'SS.millisecond}%)
newtime = timearray;
You can use regular expressions to help you out. Regular expressions are methods of specifying how to search for particular patterns in strings. As such, you want to find if a string follows the formats of either:
xx:xx.x
or:
xx.x
The regular expression syntax for each of these is defined as the following:
^[0-9]+:[0-9]+\.[0-9]+
^[0-9]+\.[0-9]+
Let's step through how each of these work.
For the first one, the ^[0-9]+ means that the string should start with any number (^[0-9]) and the + means that there should be at least one number. As such, 1, 2, ... 10, ... 20, ... etc. is valid syntax for this beginning. After the number should be separated by a :, followed by another sequence of numbers of at least one or more. After, there is a . that separates them, then this is followed by another sequence of numbers. Notice how I used \. to specify the . character. Using . by itself means that the character is a wildcard. This is obviously not what you want, so if you want to specify the actual . character, you need to prepend a \ to the ..
For the second one, it's almost the same as the first one. However, there is no : delimiter, and we only have the . to work with.
To invoke regular expressions, use the regexp command in MATLAB. It is done using:
ind = regexp(str, expression);
str represents the string you want to check, and expression is a regular expression that we talked about above. You need to make sure you encapsulate your expression using single quotes. The regular expression is taken in as a string. ind would this return the starting index of your string of where the match was found. As such, when we search for a particular format, ind should either be 1 indicating that we found this search at the beginning of the string, or it returns empty ([]) if it didn't find a match. Here's a reproducible example for you:
B = {'29:59.9', '29.9', '45:56.8', '24.5'};
for k = 1 : numel(B)
if (regexp(B{k}, '^[0-9]+:[0-9]+\.[0-9]+') == 1)
disp('I''m the first case!');
elseif (regexp(B{k}, '^[0-9]+\.[0-9]+') == 1)
disp('I''m the second case!');
end
end
As such, the code should print out I'm the first case! if it follows the format of the first case, and it should print I'm the second case! if it follows the format of the second case. As such, by running this code, we get:
I'm the first case!
I'm the second case!
I'm the first case!
I'm the second case!
Without knowing how your strings are formatted, I can't do the rest of it for you, but this should be a good start for you.
I am trying to compare two dates.
But the temp always returns true.
Can you explain where i am going wrong
temp = (Format(CDate("27-Aug-09"), "dd-mmm-yy") > Format(CDate("07-Jul-12"), "dd-mmm-yy"))
You're formatting the values according to dd-mmm-yy - which is actually the format they're in to start with. So you're just comparing the strings "27-Aug-09" and "07-Jul-12"... at which point "2" is later than "0", so the comparison finishes really quickly.
I suspect you can just get rid of the Format calls, to compare the dates:
temp = (CDate("27-Aug-09") > CDate("07-Jul-12"))
That's assuming that CDate can handle the input, of course. (I expect that part is fine.)
If you really want to compare strings, you need to convert the dates into a naturally sortable format, e.g. yyyy-mm-dd.