Convert normal space/whitespace to non-breaking space? - unicode

Question

This is a simple question, but I still can't figure out how to do it.
Say I have this string:
x := "this string"
The whitespace between 'this' and 'string' defaults to the regular unicode whitespace character 32/U+0020. How would I convert it into the non-breaking unicode whitespace character U+00A0 in Go?

Answer 1

Use the documentation to identify the standard strings package as a likely candidate, and then search it (or read through it all, you should know what's available in the standard library/packages of any language you use) to find strings.Map.
Then the obvious short simple solution to convert any white space would be:
package main
import (
"fmt"
"strings"
"unicode"
)
func main() {
const nbsp = '\u00A0'
result := strings.Map(func(r rune) rune {
if unicode.IsSpace(r) {
return nbsp
}
return r
}, "this string")
fmt.Printf("%s → %[1]q\n", result)
}
Playground
As previously mentioned, if you really only want to replace " " then perhaps strings.Replace.

Answer 2

I think a basic way to do it is by creating a simple function:
http://play.golang.org/p/YT8Cf917il
package main
import "fmt"
func ReplaceSpace(s string) string {
var result []rune
const badSpace = '\u0020'
for _, r := range s {
if r == badSpace {
result = append(result, '\u00A0')
continue
}
result = append(result, r)
}
return string(result)
}
func main() {
fmt.Println(ReplaceSpace("this string"))
}
If you need more advanced manipulations you could create something with
"golang.org/x/text/transform"
"golang.org/x/text/unicode/norm"
Read http://blog.golang.org/normalization for more information on how to use it