Get the macro to be executed in LISP - lisp

At the beginning, I create a class and accessor based on a macro as followed (this code his largely inspire from the book of Peter Seibel http://www.gigamonkeys.com/book/ )
(defun slot->defclass-slot (spec)
`(,spec :initarg ,(as-keyword spec) :accessor ,spec :initform 0))
(defmacro define-class (class-name class-slot)
`(defclass ,class-name ()
,(mapcar #'slot->defclass-slot class-slot)))
When I use the macro to generate the class, i have no fixed slots. The slots could be "name" and "id", or it could be "name", "id" and "description".
After, I had generate a class definition with the macro, i want to make several instance of that class. And again, I try to build a function as generic as possible, because the number of the slots in the class is variable.
For example, if I create a class with two slots "name" and "id". I might be interested to use this command:
(defun myfunction (slots)
`(make-instance 'myclass :name ,(first slots) :id ,(second slots)))
But, if my class has three slots "name","id" and "description", I might be interested to use this command:
(defun myfunction (slots)
`(make-instance 'myclass :name ,(first slots) :id ,(second slots) :description (third slots)))
Somehow, i succeed to define a function that creates a list with the command make-instance and the right number of slots. Here is how I proceed.
First I add in the macro definition a properties "slots" to the class that contains the list of slots.
(defmacro define-class (class-name class-slot id-slot)
`(progn
(eval-when (:compile-toplevel :load-toplevel :execute)
(setf (get ',class-name 'slots) ',class-slot))
(defclass ,class-name ()
,(mapcar #'slot->defclass-slot class-slot))
Then I could generate the command with the following text:
(defun make (slot-title slot-value)
`(,(as-keyword slot-title) ,slot-value))
(defun list->db (slots-instance)
`(make-instance 'model
,#(mapcan #'make (get 'model 'slots) slots-instance))))
(defmacro make-model (myslots)
(list->db myslots))
And when i execute list->db the following input ("a" "b"), i get the following result for example:
(make-instance 'myclass :name "a" :id "b")
But now, I wonder how i can make a function that take a list of list (e.g, (("k" "u") ("t" "j"))), and for each element of the list execute the command and create a class?

When you use backquote, you are creating a list, not executing it as an expression. It is often used to create macros. Macros transform code to other code. Code is represented as lists in Lisp.
What you have written is equivalent to:
(defun myfunction (slots)
(list 'make-instance ''myclass :name (first slots) :id (second slots)))
What you seem to intend is to just do it:
(defun myfunction (slots)
(make-instance 'myclass :name (first slots) :id (second slots)))
This mistake seems to stem from rote application of things you have seen elsewhere without understanding it at all. Don't do that. You might benefit a lot from reading a good book, e. g. Practical Common Lisp.

Related

How to call a macro with a parameter instead of list in LISP?

Based on the example provide in the practical common lisp reference, I define a macro to create a class as followed.
(defmacro define-class (class-name class-slot)
`(defclass ,class-name ()
,(mapcar #'slot->defclass-slot class-slot))))
The function slot->declass-slot take a single argument and generate a standard line describing a slot in a class. The code is the following:
(defun slot->defclass-slot (spec)
`(,spec :initarg ,(as-keyword spec) :accessor ,spec :initform 0))
For example,
(slot->defclass-slot 'nom)
(NOM :INITARG :NOM :ACCESSOR NOM :INITFORM 0)
All this work fine, when I create a class 'model' as follow:
(define-class model (nom id))
But suppose that I define a parameter instead.
(defparameter *test* '(nom id))
(define-class model *test*)
Then, the code end-up in an error:
The value *TEST* is not of type LIST.
What is wrong?
Your define-class macro does not evaluate its class-slots argument.
You can "fix" your code like this:
(defmacro define-class (class-name class-slots)
`(eval
`(defclass ,',class-name ()
,#(mapcar #'slot->defclass-slot ,class-slots))))
(macroexpand-1 '(define-class model '(nom id)))
(defparameter *test* '(nom id))
(define-class model *test*)
Note that you now have to quote the literal second argument to define-class.
Note also that you are now using eval (for a good reason, in this case).
Note finally that I seriously doubt that you truly want to do this. Chances are you don't need this level of dynamism, and you are just complicating your life for no good reason.
E.g., if you just want to get the list of class slots (using your *test* variable), you should use MOP instead.
In fact you can make your macro expand to the function ensure-class:
> (mop:ensure-class 'foo :direct-slots '((:name a)))
#<STANDARD-CLASS FOO>
but this relies on a somewhat brazen assumption that your implementation is MOP-compliant.
(defparameter *test* '(nom id))
(define-class model *test*)
You shouldn't try to do this, for the same reason that you never try to do:
(with-open-file '(...)
...)
The point of the macro is to not evaluate the arguments in order that you can do something with them. What you can do instead, if you do for some reason, need both a macro- version and non-macro- version, is to define the macro functionality in terms of a function, and then wrap the function in a macro when you need a macro. E.g., (for a not-particularly robust) with-open-file):
(defun %with-open-file (filename function &rest args)
(let ((file (apply 'open filename args)))
(prog1 (funcall function file)
(close file))))
(defmacro with-open-file ((var filename &rest args) &body body)
`(%with-open-file ,filename
(lambda (,var) ,#body)
,#args))
Then you can use the macro-version when you want it, and the function-version when you want it. In your case, though, that's not a perfect solution, since you're expanding to another macro call.

combining two variables into one function name in macro

I was toying around with macros and clos, where I created an "object" macro to create instances
(defmacro object (class &rest args)
`(make-instance ',class ,#args))
Now doing this, I also ended up kind of wanting to do something similar for accessor functions created by clos. Example:
(defclass person () ((name :accessor person-name :initarg :name)))
then creating the instance
(setf p1 (object person :name "tom"))
now to get the name from the object obviously I would call person-name, however just as with the object macro, I wanted to create a "gets" macro to do this. So ideally:
(gets person name p1) which then would return the name.
The problem then is the binding of person and name (person-name) and how to do that. Is there anyway to get those two arguments bound together in the macro? sort of like:
(defmacro gets (class var object)
`(,class-,var ,object))
I think I may have misunderstood the original intent. At first I thought you were asking how to generate the accessor names for the class definition, which third part of the answer addresses. After reading through a second time, it actually sounds like you want to generate a new symbol and call it with some argument. That's easy enough too, and is given in the second part of this answer. Both the second and third parts depend on being able to create a symbol with a name that's built from the names of other symbols, and that's what we start with.
"Concatenating" symbols
Each symbol has a name (a string) that you can obtain with symbol-name. You can use concatenate to create a new string from some old strings, and then use intern to get a symbol with the new name.
(intern (concatenate 'string
(symbol-name 'person)
"-"
(symbol-name 'name)))
;=> PERSON-NAME
Reconstructing an accessor name
(defmacro gets (class-name slot-name object)
(let ((accessor-name
(intern (concatenate 'string
(symbol-name class-name)
"-"
(symbol-name slot-name))
(symbol-package class-name))))
`(,accessor-name ,object)))
(macroexpand-1 '(gets person name some-person))
;=> (PERSON-NAME SOME-PERSON)
For a number of reasons, though, this isn't very robust. (i) You don't know whether or not the slot has an accessor of the form <class-name>-<slot-name>. (ii) Even if the slot does have an accessor of the form <class-name>-<slot-name>, you don't know what package it's in. In the code above, I made the reasonable assumption that it's the same as the package of the class name, but that's not at all required. You could have, for instance:
(defclass a:person ()
((b:name :accessor c:person-name)))
and then this approach wouldn't work at all. (iii) This doesn't work with inheritance very well. If you subclass person, say with north-american-person, then you can still call person-name with a north-american-person, but you can't call north-american-person-name with anything. (iv) This seems to be reïnventing slot-value. You can already access the value of a slot using the name of the slot alone with (slot-value object slot-name), and I don't see any reason that your gets macro shouldn't just expand to that. There you wouldn't have to worry about the particular name of the accessor (if it even has one), or the package of the class name, but just the actual name of the slot.
Generating accessor names
You just need to extract the names of the symbols and to generate a new symbol with the desired name.
If you want to automatically generate accessors with defstruct style names, you can do it like this:
(defmacro define-class (name direct-superclasses slots &rest options)
(flet ((%slot (slot)
(destructuring-bind (slot-name &rest options)
(if (listp slot) slot (list slot))
`(,slot-name ,#options :accessor ,(intern (concatenate 'string
(symbol-name name)
"-"
(symbol-name slot-name)))))))
`(defclass ,name ,direct-superclasses
,(mapcar #'%slot slots)
,#options)))
You can check that this produces the kind of code that you'd expect by looking at the macroexpansion:
(pprint (macroexpand-1 '(define-class person ()
((name :type string :initarg :name)
(age :type integer :initarg :age)
home))))
(DEFCLASS PERSON NIL
((NAME :TYPE STRING :INITARG :NAME :ACCESSOR PERSON-NAME)
(AGE :TYPE INTEGER :INITARG :AGE :ACCESSOR PERSON-AGE)
(HOME :ACCESSOR PERSON-HOME)))
And we can see that it works as expected:
(define-class person ()
((name :type string :initarg :name)
(age :type integer :initarg :age)
home))
(person-name (make-instance 'person :name "John"))
;=> "John"
Other comments on your code
(defmacro object (class &rest args)
`(make-instance ',class ,#args))
As Rainer pointed out this isn't very useful. For most cases, it's the same as
(defun object (class &rest args)
(apply 'make-instance class args))
except that you can (funcall #'object …) and (apply #'object …) with the function, but you can't with the macro.
Your gets macro isn't really any more useful than slot-value, which takes an object and the name of a slot. It doesn't require the name of the class, and it will work even if the class doesn't have a reader or accessor.
Don't (naïvely) create symbol names with format
I've been creating symbol names with concatenate and symbol-name. Sometimes you'll see people use format to construct the names, e.g., (format nil "~A-~A" 'person 'name), but that's prone to issues with capitalization settings that can be changed. For instance, in the following, we define a function foo-bar, and note that the format based approach fails, but the concatenate based approach works.
CL-USER> (defun foo-bar ()
(print 'hello))
FOO-BAR
CL-USER> (foo-bar)
HELLO
HELLO
CL-USER> (setf *print-case* :capitalize)
:Capitalize
CL-USER> (funcall (intern (concatenate 'string (symbol-name 'foo) "-" (symbol-name 'bar))))
Hello
Hello
CL-USER> (format nil "~a-~a" 'foo 'bar)
"Foo-Bar"
CL-USER> (intern (format nil "~a-~a" 'foo 'bar))
|Foo-Bar|
Nil
CL-USER> (funcall (intern (format nil "~a-~a" 'foo 'bar)))
; Evaluation aborted on #<Undefined-Function Foo-Bar {1002BF8AF1}>.
The issue here is that we're not preserving the case of the symbol names of the arguments. To preserve the case, we need to explicitly extract the symbol names, rather than letting the print functions map the symbol name to some other string. To illustrate the problem, consider:
CL-USER> (setf (readtable-case *readtable*) :preserve)
PRESERVE
;; The symbol-names of foo and bar are "foo" and "bar", but
;; you're upcasing them, so you end up with the name "FOO-BAR".
CL-USER> (FORMAT NIL "~{~A~^-~}" (MAPCAR 'STRING-UPCASE '(foo bar)))
"FOO-BAR"
;; If you just concatenate their symbol-names, though, you
;; end up with "foo-bar".
CL-USER> (CONCATENATE 'STRING (SYMBOL-NAME 'foo) "-" (SYMBOL-NAME 'bar))
"foo-bar"
;; You can map symbol-name instead of string-upcase, though, and
;; then you'll get the desired result, "foo-bar"
CL-USER> (FORMAT NIL "~{~A~^-~}" (MAPCAR 'SYMBOL-NAME '(foo bar)))
"foo-bar"
This function creates symbols from string designators:
(defun symb (&rest args)
(intern (format nil "~{~a~^-~}" (mapcar #'string args))))
The function uses format, yet passes Joshua's test:
CL-USER> (symb 'foo :bar "BAZ")
FOO-BAR-BAZ
NIL
CL-USER> (defun foo-bar ()
(print 'hello))
FOO-BAR
CL-USER> (foo-bar)
HELLO
HELLO
CL-USER> (setf *print-case* :capitalize)
:Capitalize
CL-USER> (funcall (symb 'foo 'bar))
Hello
Hello
If you want your gets to use accessor methods:
(defmacro gets (class var object)
`(,(intern (format nil "~a-~a" (symbol-name class) (symbol-name var))) ,object))
In general, what you're trying to accomplish is not really useful. make-instance is a well known symbol, easily greppable, part of the standard and optimized by some implementations when the class name is constant. So with your object macro, you're just saving a few characters and a single-quote. Usually, one hides make-instance in specific cases where you don't want to provide a direct way to initialize instances, or more likely, when you want to provide layers of initialization (e.g. phases of initialization, Lisp slots and foreign objects).
PS: I remember vaguely that someone prominent in the standardization of Common Lisp argued in favor of always wrapping/hiding make-instance in a function (e.g. make-<class-name>), but I can't find either a reference or the reasoning.
PPS: Here's a rather old discussion (2004) about it in comp.lang.lisp (and another one from 2002). The main reasons people cite in favor of constructor functions are:
Required arguments; achievable at runtime instead of at compile-time with :initform (error ...) in a slot that requires a provided initial value
Generally, hide implementation details: class instance, structure instance, cons, something else
2.1. Not wanting to export the actual class name
2.2. Being able to return an instance of some other class, usually a subclass
Convenient shorthand for a specific class
I striked always, because it seems proponents to constructor functions for CLOS objects don't necessarily want to hide the protocol that make-instance follows (allocate-instance, initialize-instance → shared-initialize) to implementers or extenders of the API or framework, although they might want to hide it to the consumers of the API or framework.
For something faster, you might want to access slots directly, but that doesn't use accessor methods, and hence doesn't support side-effects, e.g. :before and :after methods:
(defmacro gets (class var object)
(let ((object-var (gensym)))
`(let ((,object-var ,object))
(declare (optimize (speed 3) (safety 0) (debug 0))
(type ,class ,object-var))
(slot-value ,object-var ',var))))
This might be a direct slot access on some implementations.
Finally, you also have with-slots and with-accessors in the standard.
Try playing with something like this:
(let ((a 'a)
(dash '-)
(b 'b))
`(,a,dash,b))
The other possibilities is to use intern, or more user friendly, alexandria's symbolicate.

Call several functions with the same value

I have various functions and I want to call each function with the same value. For instance,
I have these functions:
(defun OP1 (arg) ( + 1 arg) )
(defun OP2 (arg) ( + 2 arg) )
(defun OP3 (arg) ( + 3 arg) )
And a list containing the name of each function:
(defconstant *OPERATORS* '(OP1 OP2 OP3))
So far, I'm trying:
(defun TEST (argument) (dolist (n *OPERATORS*) (n argument) ) )
I've tried using eval, mapcar, and apply, but these haven't worked.
This is just a simplified example; the program that I'm writing has eight functions that are needed to expand nodes in a search tree, but for the moment, this example should suffice.
Other answers have provided some idiomatic solutions with mapcar. One pointed out that you might want a list of functions (which *operators* isn't) instead of a list of symbols (which *operators* is), but it's OK in Common Lisp to funcall a symbol. It's probably more common to use some kind of mapping construction (e.g., mapcar) for this, but since you've provided code using dolist, I think it's worth looking at how you can do this iteratively, too. Let's cover the (probably more idiomatic) solution with mapping first, though.
Mapping
You have a fixed argument, argument, and you want to be able to take a function function and call it with that `argument. We can abstract this as a function:
(lambda (function)
(funcall function argument))
Now, we want to call this function with each of the operations that you've defined. This is simple to do with mapcar:
(defun test (argument)
(mapcar (lambda (function)
(funcall function argument))
*operators*))
Instead of operators, you could also write '(op1 op2 op3) or (list 'op1 'op2 'op3), which are lists of symbols, or (list #'op1 #'op2 #'op3) which is a list of functions. All of these work because funcall takes a function designator as its first argument, and a function designator is
an object that denotes a function and that is one of: a symbol (denoting the function named by that symbol in the global environment), or a function (denoting itself).
Iteratively
You can do this using dolist. The [documentation for actually shows that dolist has a few more tricks up its sleeve. The full syntax is from the documentation
dolist (var list-form [result-form]) declaration* {tag | statement}*
We don't need to worry about declarations here, and we won't be using any tags, but notice that optional result-form. You can specify a form to produce the value that dolist returns; you don't have to accept its default nil. The common idiom for collecting values into a list in an iterative loop is to push each value into a new list, and then return the reverse of that list. Since the new list doesn't share structure with anything else, we usually reverse it destructively using nreverse. Your loop would become
(defun test (argument)
(let ((results '()))
(dolist (op *operators* (nreverse results))
(push (funcall op argument) results))))
Stylistically, I don't like that let that just introduces a single value, and would probably use an &aux variable in the function (but this is a matter of taste, not correctness):
(defun test (argument &aux (results '()))
(dolist (op *operators* (nreverse results))
(push (funcall op argument) results)))
You could also conveniently use loop for this:
(defun test2 (argument)
(loop for op in *operators*
collect (funcall op argument)))
You can also do somewhat succinctly, but perhaps less readably, using do:
(defun test3a (argument)
(do ((results '() (list* (funcall (first operators) argument) results))
(operators *operators* (rest operators)))
((endp operators) (nreverse results))))
This says that on the first iteration, results and operators are initialized with '() and *operators*, respectively. The loop terminates when operators is the empty list, and whenever it terminates, the return value is (nreverse results). On successive iterations, results is a assigned new value, (list* (funcall (first operators) argument) results), which is just like pushing the next value onto results, and operators is updated to (rest operators).
FUNCALL works with symbols.
From the department of silly tricks.
(defconstant *operators* '(op1 op2 o3))
(defun test (&rest arg)
(setf (cdr arg) arg)
(mapcar #'funcall *operators* arg))
There's a library, which is almost mandatory in any anywhat complex project: Alexandria. It has many useful functions, and there's also something that would make your code prettier / less verbose and more conscious.
Say, you wanted to call a number of functions with the same value. Here's how you'd do it:
(ql:quickload "alexandria")
(use-package :alexandria)
(defun example-rcurry (value)
"Calls `listp', `string' and `numberp' with VALUE and returns
a list of results"
(let ((predicates '(listp stringp numberp)))
(mapcar (rcurry #'funcall value) predicates)))
(example-rcurry 42) ;; (NIL NIL T)
(example-rcurry "42") ;; (NIL T NIL)
(defun example-compose (value)
"Calls `complexp' with the result of calling `sqrt'
with the result of calling `parse-integer' on VALUE"
(let ((predicates '(complexp sqrt parse-integer)))
(funcall (apply #'compose predicates) value)))
(example-compose "0") ;; NIL
(example-compose "-1") ;; T
Functions rcurry and compose are from Alexandria package.

Common Lisp: Controlling macro expansion time

I was working with common lisp, and found myself typing up slot definitions of the following form quite a lot:
(name :initarg :name :accessor name)
And so I thought to concoct a macro to speed up this. I came up with the following:
(defmacro quickslot (name)
`(,name :initarg ,(intern (string-upcase name) "KEYWORD") :accessor ,name))
A dirty hack, no doubt, but functional. Or so I thought. When I tried to run my code, I cam across a snag: since defclass is a macro, the arguments are passed to it unevaluated. That means, instead of seeing
(x :initarg :x :accessor x)
It sees
(quickslot x)
Which, of course, signals an error.
The answer, it seems to me, would be to somehow control the order of macro expansion in order to make sure quickslot is expanded before defclass. Which brings me to my question: how would one accomplish this? Or, if you have a different solution to my initial conundrum, that would not go unappreciated either.
That's not really worthy of a macro. Macros typically take literal Lisp source code as their input.
Instead you could just use a function. From Practical Common Lisp, Ch.24:
(defun as-keyword (sym) (intern (string sym) :keyword))
(defun slot->defclass-slot (spec)
(let ((name (first spec)))
`(,name :initarg ,(as-keyword name) :accessor ,name)))
Then you could do something like (again adapted from PCL):
(defmacro my-defclass (name slots)
`(defclass ,name ()
,(mapcar #'slot->defclass-slot slots)))
No, you can't do it. You could write a macro around defclass instead though (that has some special syntax for your quickslots).
You could approach the problem entirely differently and come up with a reader-macro that instructs the reader to call macroexpand on the code that follows it, that would be more generic then just the one purpose for slots declaration in the class. But the complete solution would be somewhat involved, because you'd had to account for many peculiarities and demands of the reader, however, even something as ugly as this would do the job:
(defmacro quickslot (name)
`(,name :initarg ,(intern (string-upcase name) "KEYWORD") :accessor ,name))
(macroexpand '(defclass test-class ()
(#.(macroexpand '(quickslot some-slot)))))
So, what you'd have to do would be something like an alias to #.(macroexpand ...)
And... here you go:
(set-macro-character
#\{
#'(lambda (str char)
(declare (ignore char))
(let ((*readtable* (copy-readtable *readtable* nil))
(reading-p t))
(set-macro-character
#\}
#'(lambda (stream char)
(declare (ignore char stream))
(setf reading-p nil)))
(loop for exp = (read str nil nil t)
while reading-p
collect (macroexpand exp)))))
(read-from-string "'(defclass test-class ()
{(quickslot some-slot)
(quickslot some-other-slot)})")
'(DEFCLASS TEST-CLASS NIL
((SOME-SLOT :INITARG :SOME-SLOT :ACCESSOR SOME-SLOT)
(SOME-OTHER-SLOT :INITARG :SOME-OTHER-SLOT :ACCESSOR
SOME-OTHER-SLOT)))
:)

Treating the values from a list of slots and strings

I want to do a macro in common lisp which is supposed to take in one of its arguments a list made of slots and strings. Here is the prototype :
(defclass time-info ()
((name :initarg name)
(calls :initarg calls)
(second :initarg second)
(consing :initarg consing)
(gc-run-time :initarg gc-run-time)))
(defun print-table (output arg-list time-info-list) ())
The idea is to print a table based on the arg-list which defines its structure. Here is an example of a call to the function:
(print-table *trace-output*
'("|" name "||" calls "|" second "\")
my-time-info-list)
This print a table in ascII on the trace output. The problem, is that I don't know how to explicitely get the elements of the list to use them in the different parts of my macro.
I have no idea how to do this yet, but I'm sure it can be done. Maybe you can help me :)
I would base this on format. The idea is to build a format string
from your arg-list.
I define a helper function for that:
(defun make-format-string-and-args (arg-list)
(let ((symbols ()))
(values (apply #'concatenate 'string
(mapcar (lambda (arg)
(ctypecase arg
(string
(cl-ppcre:regex-replace-all "~" arg "~~"))
(symbol
(push arg symbols)
"~a")))
arg-list))
(nreverse symbols))))
Note that ~ must be doubled in format strings in order to escape them.
The printing macro itself then just produces a mapcar of format:
(defmacro print-table (stream arg-list time-info-list)
(let ((time-info (gensym)))
(multiple-value-bind (format-string arguments)
(make-format-string-and-args arg-list)
`(mapcar (lambda (,time-info)
(format ,stream ,format-string
,#(mapcar (lambda (arg)
(list arg time-info))
arguments)))
,time-info-list)))
You can then call it like this:
(print-table *trace-output*
("|" name "||" calls "|" second "\\")
my-time-info-list)
Please note the following errors in your code:
You need to escape \ in strings.
Second is already a function name exported from the common-lisp
package. You should not clobber that with a generic function.
You need to be more precise with your requirements. Macros and Functions are different things. Arrays and Lists are also different.
We need to iterate over the TIME-INFO-LIST. So that's the first DOLIST.
The table has a description for a line. Each item in the description is either a slot-name or a string. So we iterate over the description. That's the second DOLIST. A string is just printed. A symbol is a slot-name, where we retrieve the slot-value from the current time-info instance.
(defun print-table (stream line-format-description time-info-list)
(dolist (time-info time-info-list)
(terpri stream)
(dolist (slot-or-string line-format-description)
(princ (etypecase slot-or-string
(string slot-or-string)
(symbol (slot-value time-info slot-or-string)))
stream))))
Test:
> (print-table *standard-output*
'("|" name "||" calls "|" second "\\")
(list (make-instance 'time-info
:name "foo"
:calls 100
:second 10)
(make-instance 'time-info
:name "bar"
:calls 20
:second 20)))
|foo||100|10\
|bar||20|20\
First, you probably don't want the quote there, if you're using a macro (you do want it there if you're using a function, however). Second, do you want any padding between your separators and your values? Third, you're probably better off with a function, rather than a macro.
You also seem to be using "array" and "list" interchangeably. They're quite different things in Common Lisp. There are operations that work on generic sequences, but typically you would use one way of iterating over a list and another to iterate over an array.