I'm getting frustrated trying to convert a small part of the Golang templating language to Scala.
Below are the key parts of the lex.go source code: https://github.com/golang/go/blob/master/src/text/template/parse/lex.go
The tests are here: https://github.com/golang/go/blob/master/src/text/template/parse/lex_test.go
Basically this "class" takes a string and returns an Array of "itemType". In the template string, the start and end of special tokens is using curly braces {{ and }}.
For for example:
"{{for}}"
returns an array of 4 items:
item{itemLeftDelim, 0, "{{" } // scala case class would be Item(ItemLeftDelim, 0, "")
item{itemIdentifier, 0, "for"}
item{itemRightDelim, 0, "}}"}
item{itemEOF, 0, ""}
The actual call would look like:
l := lex("for", `{{for}}`, "{{", "}}") // you pass in the start and end delimeters {{ and }}
for {
item := l.nextItem()
items = append(items, item)
if item.typ == itemEOF || item.typ == itemError {
break
}
}
return
The key parts of the source code are below:
// itemType identifies the type of lex items.
type itemType int
const (
itemError itemType = iota // error occurred; value is text of error
itemEOF
itemLeftDelim // left action delimiter
// .............. skipped
)
const (
leftDelim = "{{"
rightDelim = "}}"
leftComment = "/*"
rightComment = "*/"
)
// item represents a token or text string returned from the scanner.
type item struct {
typ itemType // The type of this item.
pos Pos // The starting position, in bytes, of this item in the input string.
val string // The value of this item.
}
// stateFn represents the state of the scanner as a function that returns the next state.
type stateFn func(*lexer) stateFn
// lexer holds the state of the scanner.
type lexer struct {
name string // the name of the input; used only for error reports
input string // the string being scanned
leftDelim string // start of action
rightDelim string // end of action
state stateFn // the next lexing function to enter
pos Pos // current position in the input
start Pos // start position of this item
width Pos // width of last rune read from input
lastPos Pos // position of most recent item returned by nextItem
items chan item // channel of scanned items
parenDepth int // nesting depth of ( ) exprs
}
// lex creates a new scanner for the input string.
func lex(name, input, left, right string) *lexer {
if left == "" {
left = leftDelim
}
if right == "" {
right = rightDelim
}
l := &lexer{
name: name,
input: input,
leftDelim: left,
rightDelim: right,
items: make(chan item),
}
go l.run()
return l
}
// run runs the state machine for the lexer.
func (l *lexer) run() {
for l.state = lexText; l.state != nil; {
l.state = l.state(l)
}
}
// nextItem returns the next item from the input.
func (l *lexer) nextItem() item {
item := <-l.items
l.lastPos = item.pos
return item
}
// emit passes an item back to the client.
func (l *lexer) emit(t itemType) {
l.items <- item{t, l.start, l.input[l.start:l.pos]}
l.start = l.pos
}
// lexText scans until an opening action delimiter, "{{".
func lexText(l *lexer) stateFn {
for {
if strings.HasPrefix(l.input[l.pos:], l.leftDelim) {
if l.pos > l.start {
l.emit(itemText)
}
return lexLeftDelim
}
if l.next() == eof {
break
}
}
// Correctly reached EOF.
if l.pos > l.start {
l.emit(itemText)
}
l.emit(itemEOF)
return nil
}
// next returns the next rune in the input.
func (l *lexer) next() rune {
if int(l.pos) >= len(l.input) {
l.width = 0
return eof
}
r, w := utf8.DecodeRuneInString(l.input[l.pos:])
l.width = Pos(w)
l.pos += l.width
return r
}
// lexLeftDelim scans the left delimiter, which is known to be present.
func lexLeftDelim(l *lexer) stateFn {
l.pos += Pos(len(l.leftDelim))
if strings.HasPrefix(l.input[l.pos:], leftComment) {
return lexComment
}
l.emit(itemLeftDelim)
l.parenDepth = 0
return lexInsideAction
}
// lexRightDelim scans the right delimiter, which is known to be present.
func lexRightDelim(l *lexer) stateFn {
l.pos += Pos(len(l.rightDelim))
l.emit(itemRightDelim)
return lexText
}
// there are more stateFn
So I was able to write the item and itemType:
case class Item(typ: ItemType, pos: Int, v: String)
sealed trait ItemType
case object ItemError extends ItemType
case object ItemEOF extends ItemType
case object ItemLeftDelim extends ItemType
...
..
.
The stateFn and Lex definitions:
trait StateFn extends (Lexer => StateFn) {
}
I'm basically really stuck on the main parts here. So things seem to be kicked of like this:
A Lex is created, then "go l.run()" is called.
Run is a loop, which keeps looping until EOF or an error is found.
The loop initializes with lexText, which scans until it finds an {{, and then it sends a message to a channel with all the preceding text of type 'itemText', passing it an 'item'. It then returns the function lexLeftDelim. lexLeftDelim does the same sort of thing, it sends a message 'item' of type itemLeftDelim.
It keeps parsing the string until it reaches EOF basically.
I can't think in scala that well, but I know I can use an Actor here to pass it a message 'Item'.
The part of returning a function, I asked I got some good ideas here: How to model recursive function types?
Even after this, I am really frustrated and I can seem to glue these concepts together.
I'm not looking for someone to implement the entire thing for me, but if someone could write just enough code to parse a simple string like "{{}}" that would be awesome. And if they could explain why they did a certain design that would be great.
I created a case class for Lex:
case class Lex(
name: String,
input: String,
leftDelim: String,
rightDelim: String,
state: StateFn,
var pos: Int = 0,
var start: Int = 0,
var width: Int = 0,
var lastPos: Int = 0,
var parenDepth: Int = 0
) {
def next(): Option[String] = {
if (this.pos >= this.input.length) {
this.width = 0
return None
}
this.width = 1
val nextChar = this.input.drop(this.pos).take(1)
this.pos += 1
Some(nextChar)
}
}
The first stateFn is LexText and so far I have:
object LexText extends StateFn {
def apply(l: Lexer) = {
while {
if (l.input.startsWith(l.leftDelim)) {
if (l.pos > l.start) {
// ????????? emit itemText using an actor?
}
return LexLeftDelim
}
if (l.next() == None) {
break
}
}
if(l.pos > l.start) {
// emit itemText
}
// emit EOF
return None // ?? nil? how can I support an Option[StateFn]
}
}
I need guidance on getting the Actor's setup, along with the main run loop:
func (l *lexer) run() {
for l.state = lexText; l.state != nil; {
l.state = l.state(l)
}
}
This is an interesting problem domain that I tried to tackle using Scala, and so far I am a bit confused hoping some else finds it interesting and can work with what little I have so far and provide some code and critique if I am doing it correctly or not.
I know deep down I shouldn't be mutating, but I'm still on the first few pages of the functional book :)
If you translate the go code literally into Scala, you'll get very unidiomatic piece of code. You'll probably get much more maintainable (and shorter!) Scala version by using parser combinators. There are plenty of resources about them on the internet.
import scala.util.parsing.combinator._
sealed trait ItemType
case object LeftDelim extends ItemType
case object RightDelim extends ItemType
case object Identifier extends ItemType
case class Item(ty: ItemType, token: String)
object ItemParser extends RegexParsers {
def left: Parser[Item] = """\{\{""".r ^^ { _ => Item(LeftDelim, "{{") }
def right: Parser[Item] = """\}\}""".r ^^ { _ => Item(RightDelim, "}}") }
def ident: Parser[Item] = """[a-z]+""".r ^^ { x => Item(Identifier, x) }
def item: Parser[Item] = left | right | ident
def items: Parser[List[Item]] = rep(item)
}
// ItemParser.parse(ItemParser.items, "{{foo}}")
// res5: ItemParser.ParseResult[List[Item]] =
// [1.8] parsed: List(Item(LeftDelim,{{), Item(Identifier,foo), Item(RightDelim,}}))
Adding whitespace skipping, or configurable left and right delimiters is trivial.
Related
I created a function that recieves input and compare it to a list, when find a match it return the match, in this case this match is the attribute of a class that i created.
I understand that the problem is with the return statement, so in the beginning of the function I declare the return as "Any", further more than that I'm kinda lost.
The error is this: A 'return' expression required in a function with a block body ('{...}')
class Class1(var self: String)
var test_class = Class1("")
fun giver(){
test_class.self = "Anything"
}
class Funciones(){
fun match_finder(texto: String): Any{
var lista = listOf<String>(test_class.self)
var lista_de_listas = listOf<String>("test_class.self")
var count = -1
for (i in lista_de_listas){
count = count + 1
if (texto == i){
lista_de_listas = lista
var variable = lista_de_listas[count]
return variable
}
}
}
}
fun main(){
giver()
var x = "test_class.self"
var funcion = Funciones()
var y = funcion.match_finder(x)
println(y)
}
To explain you what the problem is, let's consider the following code:
class MyClass {
fun doSomething(): String {
val numbers = listOf(1, 2, 3)
for (number in numbers) {
if (number % 2 == 0) {
return "There is at least one even number in the list"
}
}
}
}
If you try compiling it you'll get the same error message as in your question: A 'return' expression required in a function with a block body ('{...}'). Why is that?
Well, we defined a function doSomething returning a String (it could be any other type) but we're returning a result only if the list of numbers contains at least one even number. What should it return if there's no even number? The compiler doesn't know that (how could it know?), so it prompts us that message. We can fix the code by returning a value or by throwing an exception:
class MyClass {
fun doSomething(): String {
val numbers = listOf(1, 2, 3)
for (number in numbers) {
if (number % 2 == 0) {
return "There is at least one even number in the list"
}
}
// return something if the list doesn't contain any even number
return "There is no even number in the list"
}
}
The same logic applies to your original code: what should the function return if there is no i such that texto == i?
Please also note that the solution you proposed may be syntactically correct - meaning it compiles correctly - but will probably do something unexpected. The for loop is useless since the if/else statement will always cause the function to return during the first iteration, so the value "There is no match" could be returned even if a match actually exists later in the list.
I searched online, if someone has the same problem, the correct code is as follows:
class Funciones(){
fun match_finder(texto: String): Any{
var lista = listOf<String>(test_class.self)
var lista_de_listas = listOf<String>("test_class.self")
var count = -1
var variable = " "
for (i in lista_de_listas){
count = count + 1
if (texto == i){
lista_de_listas = lista
var variable = lista_de_listas[count]
return variable
} else {
return "There is no match"
}
}
return variable
}
}
So I am working on a project where we are making a small compiler program but before I can move on to the other parts I am having troubles with getting the lexical analyzer to output anything after '\BEGIN' afterwards I debugged it and it seems the value is stuck in a loop where the condition is saying the next character is always a newline. Is it because I haven't added the pattern matching yet to the defined tokens?
Here is the code
import java.util
//import com.sun.javafx.fxml.expression.Expression.Parser.Token
/*Lexical analyzer will be responsible for the following:
- finds the lexemes
- Checks each given character determining the tokens
* */
class MyLexicalAnalyzer extends LexicalAnalyzer {
//Array full of the keywords
//val SpecialCharacters = List(']', '#', '*', '+', '\\', '[', '(',')', "![", '=')
val TEXT = "[a-z] | _ | 0-9 | [A-Z]:"
private var sourceLine: String = null
private val lexeme: Array[Char] = new Array[Char](999)
private var nextChar: Char = 0
private var lexLength: Int = 0
private var position: Int = 0
private val lexems: util.List[String] = new util.ArrayList[String]
def start(line: String): Unit = {
initializeLexems()
sourceLine = line
position = 0
getChar()
getNextToken()
}
// A helper method to determine if the current character is a space.
private def isSpace(c: Char) = c == ' '
//Defined and intialized tokens
def initializeLexems(): Any = {
lexems.add("\\BEGIN")
lexems.add("\\END")
lexems.add("\\PARAB")
lexems.add("\\DEF[")
lexems.add("\\USE[")
lexems.add("\\PARAE")
lexems.add("\\TITLE[")
lexems.add("]")
lexems.add("[")
lexems.add("\\")
lexems.add("(")
lexems.add(")")
lexems.add("![")
lexems.add("=")
lexems.add("+")
lexems.add("#")
}
//val pattern = new regex("''").r
def getNextToken() ={
lexLength = 0
// Ignore spaces and add the first character to the token
getNonBlank()
addChar()
getChar()
// Continue gathering characters for the token
while ( {
(nextChar != '\n') && (nextChar != ' ')
}) {
addChar()
getChar()
}
// Convert the gathered character array token into a String
val newToken: String = new String(lexeme)
if (lookup(newToken.substring(0, lexLength)))
MyCompiler.setCurrentToken(newToken.substring(0,lexLength))
}
// A helper method to get the next non-blank character.
private def getNonBlank(): Unit = {
while ( {
isSpace(nextChar)
}) getChar()
}
/*
Method of function that adds the current character to the token
after checking to make sure that length of the token isn't too
long, a lexical error in this case.
*/
def addChar(){
if (lexLength <= 998) {
lexeme({
lexLength += 1; lexLength - 1
}) = nextChar
lexeme(lexLength) = 0
}
else
System.out.println("LEXICAL ERROR - The found lexeme is too long!")
if (!isSpace(nextChar))
while ( {
!isSpace(nextChar)
})
getChar()
lexLength = 0
getNonBlank()
addChar()
}
//Reading from the file its obtaining the tokens
def getChar() {
if (position < sourceLine.length)
nextChar = sourceLine.charAt ( {
position += 1;
position - 1
})
else nextChar = '\n'
def lookup(candidateToken: String): Boolean ={
if (!(lexems.contains(candidateToken))) {
System.out.println("LEXICAL ERROR - '" + candidateToken + "' is not recognized.")
return false
}
return true
}
}
else nextChar = '\n'<- this is where the condition goes after rendering the first character '\BEGIN' then just keeps outputting in the debug console as listed below.
This is what the debug console it outputting after '\BEGIN' is read through
Can anyone please let me know why that is? This happens after I keep stepping into it many times as well.
Here is the driver class that uses the lexical analyzer
import scala.io.Source
object MyCompiler {
//check the arguments
//check file extensions
//initialization
//get first token
//call start state
var currentToken : String = ""
def main(args: Array[String]): Unit = {
val filename = args(0)
//check if an input file provided
if(args.length == 0) {
//usage error
println("USAGE ERROR: Must provide an input file. ")
System.exit(0)
}
if(!checkFileExtension(args(0))) {
println("USAGE ERROR: Extension name is invalid make sure its .gtx ")
System.exit(0)
}
val Scanner = new MyLexicalAnalyzer
val Parser = new MySyntaxAnalyzer
//getCurrentToken(Scanner.getNextToken())
//Parser.gittex()
for (line <- Source.fromFile(filename).getLines()){
Scanner.start(line)
println()
}
//.......
//If it gets here, it is compiled
//post processing
}
//checks the file extension if valid and ends with .gtx
def checkFileExtension(filename : String) : Boolean = filename.endsWith(".gtx")
def getCurrentToken() : String = this.currentToken
def setCurrentToken(t : String ) : Unit = this.currentToken = t
}
The code is operating as it is supposed to. The first line contains only the string \BEGIN so the lexical analyser is treating the end of the first line as an '\n' as shown in this method:
def getChar() {
if (position < sourceLine.length)
nextChar = sourceLine.charAt ( {
position += 1;
position - 1
})
else nextChar = '\n'
However, the comment directly above that method does not describe what the method actually does. This could be a hint as to where your confusion lies. If the comment says it should read from the file, but it is not reading from the file, maybe that's what you've forgotten to implement.
I am trying to learn swift by solving interview questions. One of the question that I am trying to solve is as follows.
Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n).
Example:
Input: S = "ADOBECODEBANC", T = "ABC"
Output: "BANC"
My implementation is as follows which holds t string characters and its corresponding index retrieved from s.
func minimumWindowSubstring(_ s: String, _ t: String) -> String{
let sChar = [Character](s)
let tChar = [Character](t)
var indexTemp = [[Character:Int]()]
for tc in tChar
{
for (j, sc) in sChar.enumerated()
{
if sc == tc
{
indexTemp.append([tc:j])
}
}
}
return ""
}
what I have in indexTemp array is as follows
Now I wonder how could I able to use this array to find the minimumwindow, I stuck.
I thought it was an interesting problem so I gave it a shot. Instead of using a dictionary I used a simple class to store the range of characters found, as well as a String that stores which characters haven't been found.
It only goes through the main string once, so it should be O(n).
You can run this in the playground.
(I know you wanted help in fixing your code and my answer doesn't do that, but I'm hoping it will provide enough insight for you to adjust your own code)
import Foundation
let string = "ADOBECODEBANC"
let sub = "ABC"
// Create a class to hold the start and end index of the current search range, as well as a remaining variable
// that will store which characters from sub haven't been found
class Container {
var start: Int
var end: Int?
var remaining: String
// Consume will attempt to find a given character within our remaining string, if it has found all of them,
// it will store the end index
func consume(character: Character, at index: Int) {
// If remaining is empty, we're done
guard remaining != "" else { return }
// We're assuming that sub won't have repeating characters. If it does we'll have to chage this
remaining = remaining.replacingOccurrences(of: String(character), with: "")
if remaining == "" {
end = index
}
}
init(start: Int, remaining: String) {
self.start = start
self.remaining = remaining
}
}
// ClosedContainer is similar to Container, but it can only be initialized by an existing container. If the existing
// container doesn't have an end value, the initialization will fail and return nil. This way we can weed out containers
// for ranges where we didn't find all characters.
class ClosedContainer {
let start: Int
let end: Int
init?(container: Container) {
guard let end = container.end else { return nil }
self.start = container.start
self.end = end
}
var length: Int {
return end - start
}
}
var containers = [Container]()
// Go through each character of the string
string.enumerated().forEach { index, character in
// Look for matches in sub
if sub.contains(character) {
// Allow each existing container to attempt to consume the character
containers.forEach { container in
container.consume(character: character, at: index)
}
// Create a new container starting on this index. It's remaining value will be the sub string without the
// character we just found
let container = Container(start: index, remaining: sub.replacingOccurrences(of: String(character), with: ""))
containers.append(container)
}
}
// Convert Containers into ClosedContainers using compactMap, then find the one with the shortest length
let closedContainers = containers.compactMap(ClosedContainer.init)
let maybeShortest = closedContainers.min { $0.length < $1.length }
if let shortest = maybeShortest {
// Convert int to String indices
let start = string.index(string.startIndex, offsetBy: shortest.start)
let end = string.index(string.startIndex, offsetBy: shortest.end)
// Get the result string
let result = string[start...end]
print("Shortest substring of", string, "that contains", sub, "is", result)
} else {
// No range was found that had all characters in sub
print(string, "doesn't contain all characters in", sub)
}
For exercise I'm trying to implement a LinkedList in Scala.
Main problem is about Null reference.
But first some code:
class Node(xkey: String, xnext: Option[Node], xinfo: Int) {
val key: String = xkey;
var next = xnext.getOrElse(None);
var info: Int = xinfo;
def this(xkey: String, xinfo: Int) {
this(xkey, None, xinfo);
}
def this(xkey: String) {
this(xkey, None, -1);
}
#Override
override def toString: String = key + ":" + info
}
At this point, I'm already concerned about things.
I declare xnext in construct as a Option[Node], because the tail in this linkedList does not have a next.
In my first try, it was just a Node, but had problem with null object because compilator just told me that "null can't cast to Node" (or something like that, I do not remember now) - And so I switch to this Option.
But, is it ok? Because, you know, for me next should be a Node, not a Option, otherwise, I don't know, in the linkedList how to reference to next Node.
Whatever, second class (i.e. my Linked List)
class LinkedNode {
private var first: Option[Node] = None;
private var last: Option[Node] = None;
def addNode(newNode: Node) = {
if (first == null) {
first = Some(newNode);
last = Some(newNode);
first.next = last;
}
else {
last.next = newNode;
newNode.next = null;
last = newNode
}
}
def size(): Long = {
var currentNode : = first;
var size = 0L;
while (currentNode != null) {
size+=1;
currentNode = currentNode.next;
}
size
}
def findNodeByKey(key: String) : Node = {
var currentNode = first;
while(currentNode != null) {
if (currentNode.key.equals(key))
currentNode
else {
currentNode = currentNode.next;
}
}
currentNode;
}
def delNodeByKey(key : String) : Boolean = {
var currentNode = first;
var previousNode = first;
while(currentNode != null) {
if (currentNode.key.equals(key)) {
previousNode = currentNode.next;
return true;
}
previousNode = currentNode;
currentNode = currentNode.next;
}
return false;
}
}
And nothing. I'm already block to my constructor because first and last.
How should I declare them? Node? Or Option[Node]?
Problems are also in Add method.
When I add a node, I want to add a Node object, not an Option[Node].
And I don't get how to achieve things I want with all Option, Some and None classes.
I know I should not be so vague with my request, but any help?
P.S. I've already read this Q/A and it didn't help me
At this point, I'm already concerned about things. I declare xnext in construct as a Option[Node], because the tail in this linkedList does not have a next.
[...]
But, is ok? because, you know, for me next should be a Node, not a Option, otherwise, I don't know, in the linkedList how to reference to next Node.
This is a good solution to replacing null, which you definitely want to do to prevent null-pointer exceptions and the like. An Option[Node] is simply a Node wrapped in a container (or None). You can check whether or not it has a value with isEmpty or get its value with get (which will throw an exception if the Option is empty).
The only difference to null, as you'd use it in Java, is that you need to check if it isEmpty instead of checking for null, and that you need to unwrap (option.get) it explicitly when you're sure that it is not None.
A more paradigmatic (scala-typical) way of retrieving the value from an option is pattern matching:
option match {
case Some(x) => println(x)
case None => println("Whoops, no value :(")
}
Regarding your other questions, they are indeed a little vague.
How should I declere them? Node? or Option[Node]?
Use Option[Node] if the possibility exists that there's no value for the variable (i.e., if you'd set it to null sometimes in Java).
When I add a node, I want to add a Node object, not a Option[Node].
No, you want to add an Option[Node] internally, because you will need to check later on if a node is set or not. In Scala it is preferrable to do this via Option[Node].isEmpty compared to setting things to null. You're already doing this in some parts of your code (e.g., addNode), where you do Some(newNode) (I'd call this "wrapping the node in an Option", but I'm not entirely sure if that's the correct terminology).
And I don't get how to achieve things I want with all Option, Some and None class.
What you're doing in your addNode does seem correct to a degree, but you somehow try to use null again in the else branch. What about:
// We don't need Option[Node] for the parameter, because there
// _must_ be a Node value to be added
def addNode(newNode: Node) = {
if (first.isEmpty) {
first = Some(newNode)
last = Some(newNode)
first.next = last
} else {
newNode.next = None
last.next = Some(newNode)
last = Some(newNode)
}
}
(I didn't run that code, nor did I do an thorough check of your logic)
I was trying this code in Xcode Playground and noticed that the description getter method got called too many times.
The code is here: https://gist.github.com/T-Pham/4b72d17851162a32b2fc534f0618135d
First with both print lines, the code is run 3176 times.
Then with the first print commented out, the code is run 3164 times.
That means the first print would have to run the code 12 times.
However,
it is 148 times instead.
It is the playground that is messing with your head.
Playground is counting calls of its own for variables that have the CustomStringConvertibe protocol (probably to feed the information on the right side panel).
You can see this going on if you simply invoke mirror(tree) without printing at all.
If you count the actual number of invocations using your own counter, it will give a very different result:
var descCount = 0
extension Node: CustomStringConvertible {
var description: String
{
descCount += 1
return "id: \(id)\nleft: \(left)\nright: \(right)"
}
}
descCount = 0
print(tree)
descCount // 12
descCount = 0
print(mirror(tree))
descCount // 12
By the way, I had a little trouble understanding the mirror() function and I figured that a recursive one would probably be simpler to understand. How about adding a mirror() function to Node :
func mirror() -> Node
{
let result = Node()
result.id = id
result.left = right?.mirror()
result.right = left?.mirror()
return result
}
print(tree.mirror())
[EDIT] Here's a non-recursive mirror function (same logic as yours) with a somewhat clearer structure:
func mirror2(tree:Node) -> Node
{
// will return top of mirrored tree
let newTree = Node()
// node pair used for traversal and duplication
var original:Node! = tree
var mirrored:Node! = newTree
// traversal of tree structure left side first
// (uses mirrored tree to keep track of traversed nodes)
while original != nil
{
// carry node identifier (and contents eventually)
mirrored.id = original.id
// downwards, mirror left side first (if not already done)
if (original.left == nil) != (mirrored.right == nil)
{
original = original.left
mirrored.right = Node()
mirrored = mirrored.right
continue
}
// downwards, mirror right side second (if not already done)
if (original.right == nil) != (mirrored.left == nil)
{
original = original.right
mirrored.left = Node()
mirrored = mirrored.left
continue
}
// upwards from leaves and completed branches
original = original.parent
mirrored = mirrored.parent
}
return newTree
}
and some visual candy for tree descriptions:
extension Node: CustomStringConvertible
{
var indent:String
{ return " " + (parent?.indent ?? "") }
var description: String
{
return "\(id)\n"
+ ( left != nil ? "\(indent)L:\(left!)" : "" )
+ ( right != nil ? "\(indent)R:\(right!)" : "" )
}
}
resulting in an easier comparison of results:
print(tree)
// 0
// L:1
// L:3
// L:7
// R:8
// R:4
// L:9
// R:10
// R:2
// R:6
// L:13
// R:14
//
print(mirror2(tree))
// 0
// L:2
// L:6
// L:14
// R:13
// R:1
// L:4
// L:10
// R:9
// R:3
// L:8
// R:7