I want to define time intervals like:
Each week, from Monday 12:00 a.m. to Sunday 11:59:59 p.m.
Each day from 12:00 a.m. to 11:59:59 p.m.
Each month from the first day of the month 12:00 a.m. to the last day of the month 11:59:59 p.m.
Is this possible using ISO 8601, or any other well-known standard?
You're asking for repeating periods of a week, a day and a month. The period should be defined as P1W, P1D or P1M respectively. Given an appropriate start point, I'd expect things such as the following to work:
R/2015-02-16/P1W - repeating weekly periods, starting on a known Monday.
R/2015-02-17/P1D - repeating daily periods, starting today
R/2015-02/P1M - repeating monthly periods, starting this month
These should be ISO 8601 compliant.
Related
The workday function should work for this. I have a Range called "Holidays". The problem is that workdays doesn't count the weekend days. I need to count the weekend days. BUT, if the 3rd day comes on a weekend or a holiday choose the next non-weekend or non-holiday day. A2 is the Effective Date of the contract, which is the start date. I'm trying to calculate the day on which the Earnest Money is due. See the attached chart as to how it should calculate.
=if(OR(A5="",A5>workday(A2,3,Holidays)),workday(A2,3,Holidays),"") is the formula I have but it works for Effective dates that fall on a Sunday, Monday, Tuesday and Wednesday, but not for Effective dates that fall on a Thursday, Friday, Saturday.
Starting from Today
Use this formula to get the dates starting from today
={ArrayFormula(
VLOOKUP(WEEKDAY(SEQUENCE(7,1,TODAY(),1),2),
{SEQUENCE(7),{"Monday";"Tuesday";"Wednesday";"Thursday";"Friday";"Saturday";"Sunday"}},2)),
BYROW(SEQUENCE(7,1,TODAY(),1),
LAMBDA(d, VLOOKUP(WEEKDAY(IF(IFNA(MATCH(d+3,F2:F13*1,0),"")="",d+3,d+4),2),
{SEQUENCE(7),{"Monday";"Tuesday";"Wednesday";"Thursday";"Friday";"Saturday";"Sunday"}},2)))}
Starting from Monday
={ArrayFormula(
VLOOKUP(WEEKDAY(SEQUENCE(7,1,TODAY()-WEEKDAY(TODAY(),3),1),2),
{SEQUENCE(7),{"Monday";"Tuesday";"Wednesday";"Thursday";"Friday";"Saturday";"Sunday"}},2)),
BYROW(SEQUENCE(7,1,TODAY()-WEEKDAY(TODAY(),3),1),
LAMBDA(d, VLOOKUP(WEEKDAY(IF(IFNA(MATCH(d+3,F2:F13*1,0),"")="",d+3,d+4),2),
{SEQUENCE(7),{"Monday";"Tuesday";"Wednesday";"Thursday";"Friday";"Saturday";"Sunday"}},2)))}
Starting from Monday using Lambda
Starting from the current week monday.
=ArrayFormula(LAMBDA(vl,wd,
{VLOOKUP(WEEKDAY(wd,2),vl,2),
BYROW(wd,LAMBDA(d, VLOOKUP(WEEKDAY(IF(IFNA(MATCH(d+3,F2:F13*1,0),"")="",d+3,d+4),2),vl,2)))})
({SEQUENCE(7),{"Monday";"Tuesday";"Wednesday";"Thursday";"Friday";"Saturday";"Sunday"}},
SEQUENCE(7,1,TODAY()-WEEKDAY(TODAY(),3),1)))
Explanation
You need the Calendar Year 20xx Legal Public Holidays to skip one day if matched the legal holidays date after adding 3 days.
Used formulas help
BYROW - SEQUENCE - TODAY - LAMBDA - VLOOKUP - IF - IFNA - MATCH - ARRAYFORMULA
I need a Pipeline to trigger on the Monthend week (Tues, Wed, Thurs and Friday) of a month.
Monthend is defined as,
"Last but one" Friday Or
Second Friday from the end of the month.
For Example, For month of June 2021, 18th is the Monthend (Orange color as shown in the image)
Calendar Image
If its just on Monthend i.e. Second Friday from the end of calendar month, its easy. Just use Occurrance as -2 and day as Friday in the Scheduled trigger and add to a pipeline to trigger,
"schedule": {
"monthlyOccurrences": [
{
"day": "Friday",
"occurrence": -2
}
]
}
but I also need to run on the Tues, Wed and Thurs of the same week, which I find it difficult as these weekdays can be second or third from the end of the calendar month. For example: For June 2021, as shown in the image, I also need to run on 15th (Third Tuesday from the end of calendar month), 16th (Third Wednesday from the end of calendar month), 17th (Second Thursday from the end of calendar month).
Can you let me know if this can be implemented using triggers of Azure data factory? If not, any otherways of implementing? Thank You!
The scheduled trigger alone is not capable of that logic (as of 2021-05-04). Easiest solution would be to use some other scheduling application.
For a purely Data-Factory solution, schedule the trigger for all the days the desired days could possibly occur on. Then modify the pipeline to do logic to determine whether the current day is actually one of the desired days.
Implementation details and sample code
The logic:
Find the last day of the month (First of the next month less 1 day).
Subtract a week so you are in the second-to-last week
Loop over [0,-1,-2,-3,-4,-5,-6] as number of days to add to the date. This produces the dates of each day of the week.
Use the dayOfWeek function to change the date into which day of the week it is
Filter to get the Friday date
Ask whether today is between the Friday date and Friday date - 3 days
What iCal RRULE expression should I use to find a Friday after last Wednesday of month? So I need (RRULE:FREQ=MONTHLY;BYDAY=-1WE) + 2 days...
I agree with Evert that this is not possible with a single RRULE.
You can, however, achieve that with a combination of multiple RRULEs.
That way you can split your event into multiple events each one having one of the RRULEs below:
If Wednesday falls on the last or second last day of a month, our Friday will be the 1st or 2nd of the next month
FREQ=MONTHLY;BYMONTHDAY=1,2;BYDAY=1FR
In months with 31 days the earliest date for the last Wednesday is the 25th, so the next Friday will be one of day 27-31:
FREQ=MONTHLY;BYMONTH=1,3,5,7,8,10,12;BYMONTHDAY=27,28,29,30,31;BYDAY=FR
In months with 30 days the earliest date for the last Wednesday is the 24th, so the next Friday will be one of day 26-30:
FREQ=MONTHLY;BYMONTH=4,6,9,11;BYMONTHDAY=26,27,28,29,30;BYDAY=FR
February is a tricky one, because in non-leap years the the Friday we want will be between the 24th and 28th, but in leap years it's between the 25th and 29th. However, within the next 50 years there is only one leap year in which February 24th is a Friday, which is 2040 (check out the result of FREQ=MONTHLY;BYMONTHDAY=24;BYMONTH=2;BYDAY=FR), so the following RRULE will be correct until 2040:
FREQ=MONTHLY;BYMONTH=2;BYMONTHDAY=24,25,26,27,28,29;BYDAY=FR
If you're concerned about the leap years, add an EXDATE like below and you're good for the next 100 years (make these DATE-TIME values if your start date has a time):
EXDATE;VALUE=DATE:20400224,20680224,20960224,21080224
If you know for sure that your clients support multiple RRULEs (which has been deprecated halfheartedly in RFC 5545 but still was perfectly valid in RFC 2445) you could add them into a single event as well, but I wouldn't recommend that.
The MongoDB manual states the $week aggregation and %U operator in strftime work like this:
Returns the week of the year for a date as a number between 0 and 53.
Weeks begin on Sundays, and week 1 begins with the first Sunday of the
year. Days preceding the first Sunday of the year are in week 0. This
behavior is the same as the “%U” operator to the strftime standard
library function.
Does this conform to the ISO 8601 week of the year standard?
No. ISO 8601 does not have week 0.
According to the standard:
The ISO 8601 definition for week 01 is the week with the year's first Thursday in it.
...
If 1 January is on a Monday, Tuesday, Wednesday or Thursday, it is in week 01;
If 1 January is on a Friday, it is part of week 53 of the previous year;
If on a Saturday, it is part of week 52 (or 53 if the previous year was a leap year);
If on a Sunday, it is part of week 52 of the previous year.
There is an open ticket that suggests adding other options for week numeration; there's a suggestion for $isoweek in the comments:
https://jira.mongodb.org/browse/SERVER-7695
I'm querying information from a Facebook page for a small business using FQL and I'm trying to parse the business hours. The numbers I am getting back seem to represent seconds but I'm not sure when the epoch is. Wednesday and Thursday are the most confusing - open on Thursday is "57600" which would be 16 hours in seconds which would make 4pm Wednesday the epoch, but the closing hours on Wednesday - far past 4- are in the 600,000+ range.
Mon: 8:15am-12pm and 1pm - 5pm Tue: 8am-12pm and 1pm - 5pm Wed: 8am-12pm and 1pm - 9pm Thur:8am-12pm and 1pm - 5pm Fri:8am-12pm and 1pm - 5pm Sat:8am-12pm and 1pm - 5pm
<hours>
<mon_1_open>404100</mon_1_open>
<mon_1_close>417600</mon_1_close>
<tue_1_open>489600</tue_1_open>
<tue_1_close>504000</tue_1_close>
<wed_1_open>576000</wed_1_open>
<wed_1_close>590400</wed_1_close>
<thu_1_open>57600</thu_1_open>
<thu_1_close>72000</thu_1_close>
<fri_1_open>144000</fri_1_open>
<fri_1_close>158400</fri_1_close>
<sat_1_open>230400</sat_1_open>
<sat_1_close>244800</sat_1_close>
<sun_1_open>0</sun_1_open>
<sun_1_close>0</sun_1_close>
<mon_2_open>421200</mon_2_open>
<mon_2_close>435600</mon_2_close>
<tue_2_open>507600</tue_2_open>
<tue_2_close>522000</tue_2_close>
<wed_2_open>594000</wed_2_open>
<wed_2_close>622800</wed_2_close>
<thu_2_open>75600</thu_2_open>
<thu_2_close>90000</thu_2_close>
<fri_2_open>162000</fri_2_open>
<fri_2_close>176400</fri_2_close>
<sat_2_open>248400</sat_2_open>
<sat_2_close>262800</sat_2_close>
<sun_2_open>0</sun_2_open>
<sun_2_close>0</sun_2_close>
</hours>
If I change it to simply 8am-5pm Monday to Saturday I get an equally confusing response from FB
<hours>
<mon_1_open>403200</mon_1_open>
<mon_1_close>435600</mon_1_close>
<tue_1_open>489600</tue_1_open>
<tue_1_close>522000</tue_1_close>
<wed_1_open>576000</wed_1_open>
<wed_1_close>608400</wed_1_close>
<thu_1_open>57600</thu_1_open>
<thu_1_close>90000</thu_1_close>
<fri_1_open>144000</fri_1_open>
<fri_1_close>176400</fri_1_close>
<sat_1_open>230400</sat_1_open>
<sat_1_close>262800</sat_1_close>
<sun_1_open>0</sun_1_open>
<sun_1_close>0</sun_1_close>
<mon_2_open>0</mon_2_open>
<mon_2_close>0</mon_2_close>
<tue_2_open>0</tue_2_open>
<tue_2_close>0</tue_2_close>
<wed_2_open>0</wed_2_open>
<wed_2_close>0</wed_2_close>
<thu_2_open>0</thu_2_open>
<thu_2_close>0</thu_2_close>
<fri_2_open>0</fri_2_open>
<fri_2_close>0</fri_2_close>
<sat_2_open>0</sat_2_open>
<sat_2_close>0</sat_2_close>
<sun_2_open>0</sun_2_open>
<sun_2_close>0</sun_2_close>
</hours>
Am I missing some defacto standard time representation? How would someone go about parsing this as a legitimate time of day?
The Unix epoch is the time 00:00:00 UTC on 1 January 1970. Any time you see the term "epoch" used in relation to computer-based time, that's usually what it means.
In UTC, 404100 is Mon, 05 Jan 1970 16:15:00 GMT. Or, in the PST timezone, Mon, 05 Jan 1970 08:15:00 PST, which is the time you're expecting. Ignore the date; it's irrelevant, anyways.
You can test what I'm describing using this Epoch Converter.