I have two cell arrays "data1" "data2". For each line of "data1", I would find the number of lines that respects the condition on strings and numbers (see below) between "data1" and "data2". I tried to use the function "find" but I find that it is not very fast. Is there a function that is faster than "find" ? Here is my code:
for lineData1 = 1 : size(data1,1)
vectorData = find( ( cell2mat(data2(2:size(data2,1),1)) == data1{lineData1,2} | cell2mat(data2(2:size(data2,1),2)) == data1{lineData1,2} ) & ...
strcmp(data2(2:size(data2,1),4),data1{lineData1,3}) & ...
strcmp(data2(2:size(data2,1),5),data1{lineData1,4}) & ...
strcmp(data2(2:size(data2,1),6),data1{lineData1,5}) & ...
cell2mat(data2(2:size(data2,1),7)) == data1{lineData1,6} & ...
cell2mat(data2(2:size(data2,1),8)) == data1{lineData1,7} );
%%% vectorData = vectorData + 1;
data1{lineData1,1} = size(vectorData,1);
end
Thanks very much for your help.
Related
So I have arr = randi([0,20],20,1). I want to show: If there are numbers less than 5, fprintf('Yes\n') only once. Im using a for loop (for i = 1 : length(arr)) and indexing it.
As your description, maybe you need if statement within for loop like below
for i = 1:length(arr)
if arr(i) < 5
fprintf('Yes\n');
break
end
end
If you want to print Yes once, you can try
if any(arr < 5)
fprintf('Yes\n')
endif
If you don't want to use break, the code below might be an option
for i = 1:min(find(arr <5))
if (arr(i) < 5)
fprintf('Yes\n');
end
end
You can use a break statement upon finding the first value under 5 and printing the Yes statement.
Using a break Statement:
arr = randi([0,20],20,1);
for i = 1: length(arr)
if arr(i) < 5
fprintf("Yes\n");
break;
end
end
Extension:
By Using any() Function:
Alternatively, if you'd like to concise it down without the need for a for-loop the any() function can be used to determine if any values within the array meet a condition in this case arr < 5.
arr = randi([0,20],20,1);
if(any(arr < 5))
fprintf("Yes\n");
end
By Using a While Loop:
Check = 0;
arr = randi([0,20],20,1);
i = 1;
while (Check == 0 && i < length(arr))
if arr(i) < 5
fprintf("Yes\n");
Check = 1;
end
i = i + 1;
end
I'm using ag grid with angularjs and the filter does not work with formatted numbers. I use formatted numbers with currency values.
Below is the columndef code:
{ headerName:"GBO", field: "GBO", width: 200, editable:true, cellClass: "number-cell",filter:'agNumberColumnFilter',
cellRenderer : function(params){
if(params.value == "" || params.value == null)
return '-';
else return params.value;
}
}
Before assigning the data to the grid, I format the numbers using :
$scope.formatNumberOnly = function(num,c, d, t){
//console.log(num );
var n = getNumber(num);
//var n = this,
c = isNaN(c = Math.abs(c)) ? 2 : c,
d = d == undefined ? "." : d,
t = t == undefined ? "," : t,
s = n < 0 ? "-" : "",
i = parseInt(n = Math.abs(+n || 0).toFixed(c)) + "",
j = (j = i.length) > 3 ? j % 3 : 0;
return s + (j ? i.substr(0, j) + t : "") + i.substr(j).replace(/(\d{3})(?=\d)/g, "$1" + t) + (c ? d + Math.abs(n - i).toFixed(c).slice(2) : "");
};
});
The problem here is that the filter doesn't work with these formatted numbers and only seems to be working for values upto 999.
Can anyone please help me with a solution to this filtering problem?
If you want the filter to work on these formatted values, you should use a valueGetter instead of a valueFormatter
You should implement the above formatter function as a valueGetter in column Definition.
Also a number filter won't work as in order for your formatted number to be interpreted, it should be a text filter.
Here is an example from official docs.
I have a Matlab function. I need to generalize this function. This code’s aim is to check this IndicMPs are in the TableTemp, if it is there, then we extract relevant age limits, such as: Age_Limite_DC, Age_Limite_IT, Age_Limite_Ch and Transfert_Prime_IT_DC. My idea is to generalize, passing parameters to find out the "Type_pret" is.(May be I'm wrong) Since I'm beginner to Matlab can someone help me to encode a more generic function that can be used in a more general context?
function Structure = optimisation_function()
Data = load('Data.mat');
Structure = Data.Structure;
TableTemp = Data.TableTemp;
Age_Limite_DC = zeros(size(Structure,1),1);
Age_Limite_IT = zeros(size(Structure,1),1);
Age_Limite_CH = zeros(size(Structure,1),1);
Transfert_Prime_IT_DC = zeros(size(Structure,1),1);
for IndexMPAL = 1 : length(Structure.AnneeSouscription)
% Determine Type_Pret (Loan Type)
if ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'A'))
Type_Pret = 'A';
elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'B'))
Type_Pret = 'B';
elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'C'))
Type_Pret = 'C';
elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'D'))
Type_Pret = 'D';
elseif ~isempty(strfind(Structure.Type_Pret{IndexMPAL},'E'))
Type_Pret = 'E';
end
MP_CP = Structure.NomCodeProduit(IndexMPAL);
MP_AnSous = Structure.AnneeSouscription(IndexMPAL);
MP_TypePret = Type_Pret;
IndicCP = strcmp(MP_CP, TableTemp.CodeProduit);
IndicAS = MP_AnSous== TableTemp.AnneeSouscription;
IndicTP = strcmp(MP_TypePret, TableTemp.TypePret);
IndicMP = IndicCP & IndicAS & IndicTP;
if ~any(IndicMP)
Msg = strcat('CodeProduct:',MP_CP{1}, ', Année Souscription:', num2str(MP_AnSous), ', Type Prêt:', MP_TypePret);
error('Error', Msg)
else
Age_Limite_DC(IndexMPAL,1) = TableTemp.Age_Limite_DC(IndicMP,1);
Age_Limite_IT(IndexMPAL,1) = TableTemp.Age_Limite_IT(IndicMP,1);
Age_Limite_CH(IndexMPAL,1) = TableTemp.Age_Limite_CH(IndicMP,1);
Transfert_Prime_IT_DC(IndexMPAL,1)=
TableTemp.Transfert_Prime_IT_DC(IndicMP,1);
end
end
Structure.Age_Limite_DC = Age_Limite_DC;
Structure.Age_Limite_IT = Age_Limite_IT;
Structure.Age_Limite_CH = Age_Limite_CH;
Structure.Transfert_Prime_IT_DC = Transfert_Prime_IT_DC;
end
The if/elseif can be simplified with a cell array:
liststr = {'A','BB','C','D','E'}; % builds a cell array, each cell contains a string
Positive_matches = strfind(liststr,Structure.Type_Pret{IndexMPAL}) % returns a list for each cell of the indices where the element was found (empty if none)
Index = find(~cellfun('isempty', Positive_matches )) % converts the previous list into a logical 0/1 array indicating whether an item was found (1) or not (0)
% if isempty(Index); continue; end % If no index is found, to avoid an error in the next instruction, skips the rest of the code.
Type_Pret = liststr(Index(1));
If the Type_Pret are the same in your list and in Structure? , you can usestrcmp`:
liststr = {'A','B','C','D','E'};
if any(strcmp(Structure.Type_Pret,liststr))
Type_Pret = Structure.Type_Pret
else
% handle error
end
You can also work directly on Structure.Age_Limite_DC without using Age_Limite_DC.
function []= read_c3d_feat(output_list_relative)
dir_list = importdata(output_list_relative);
dim_feat = 512;
for i = 1 : size(dir_list, 1)
dir_str = char(dir_list(i));
feat_files = dir([dir_str, '/*.res5b']);
num_feat = length(feat_files);
feat = zeros(num_feat, dim_feat);
for j = 1 : num_feat
feat_path = strcat(dir_str, '/', feat_files(j).name);
...............
....................so on
Give me error like
Error using dir
Invalid path. The path must not contain a null character.
Error in read_c3d_feat (line 12)
feat_files = dir([dir_str, '/*.res5b']);
Your dir_list variable must have strings which contain null characters, as the error tells you. If you try using hard-coded strings you will see it works:
function read_c3d_feat(output_list_relative)
dir_list = {'21';'45';'18'};
for i = 1:size(dir_list, 1)
dir_str = dir_list{i}; % Loops through '21','45','18'
% The dir function now works because we know dir_str is a valid string
feat_files = dir([dir_str, '/*.res5b']);
end
end
This means you need to debug your code and find out what this line is actually assigning to dir_list:
dir_list = importdata(output_list_relative);
Note that if dir_list is a cell of text entries, you should be indexing it with curly braces as above. If instead it is a matrix (because all of the entries seem to be numerical anyway) then you should be using num2str when passing to dir:
function read_c3d_feat(output_list_relative)
dir_list = importdata(output_list_relative);
dim_feat = 512;
for i = 1:size(dir_list, 1)
feat_files = dir([num2str(dir_list(i)), '/*.res5b']);
% ...
I'm new to Matlab and now learning the basic grammar.
I've written the file GetBin.m:
function res = GetBin(num_bin, bin, val)
if val >= bin(num_bin - 1)
res = num_bin;
else
for i = (num_bin - 1) : 1
if val < bin(i)
res = i;
end
end
end
and I call it with:
num_bin = 5;
bin = [48.4,96.8,145.2,193.6]; % bin stands for the intermediate borders, so there are 5 bins
fea_val = GetBin(num_bin,bin,fea(1,1)) % fea is a pre-defined 280x4096 matrix
It returns error:
Error in GetBin (line 2)
if val >= bin(num_bin - 1)
Output argument "res" (and maybe others) not assigned during call to
"/Users/mac/Documents/MATLAB/GetBin.m>GetBin".
Could anybody tell me what's wrong here? Thanks.
You need to ensure that every possible path through your code assigns a value to res.
In your case, it looks like that's not the case, because you have a loop:
for i = (num_bins-1) : 1
...
end
That loop will never iterate (so it will never assign a value to res). You need to explicitly specify that it's a decrementing loop:
for i = (num_bins-1) : -1 : 1
...
end
For more info, see the documentation on the colon operator.
for i = (num_bin - 1) : -1 : 1